I want to create a specific number of for loops each in another loop, as in example:
for(i=0;i<9;i++)
{
for(j=0;j<9;j++)
{
for(k=0;k<9;k++)
{
//some stuff
}
}
}
In this example there are 3 loops, but what if i want to create e.g. 10 such loops, and program reads a number of loops from a txt? It is needed for checking numbers.
Say I want to exhaust all the possible combinations of 10 variables to find all the solutions to an equation with 10 variables.
I could write out 10 'for' loops, but it would take a lot of space in the code and of course would take a lot of time. Another reason why I want to know this is because it could possible allow me to change the amount of for loops just by changing a number.
I.e., how can I contract the following code into a simple, short form?
for (a[0]=0;a[0]<=9;a[0]++)
for (a[1]=0;a[1]<=9;a[1]++)
for (a[2]=0;a[2]<=9;a[2]++)
for (a[3]=0;a[3]<=9;a[3]++)
for (a[4]=0;a[4]<=9;a[4]++)
for (a[5]=0;a[5]<=9;a[5]++)
for (a[6]=0;a[6]<=9;a[6]++)
for (a[7]=0;a[7]<=9;a[7]++)
for (a[8]=0;a[8]<=9;a[8]++)
for (a[9]=0;a[9]<=9;a[9]++)
if (...)
cout << ... << endl;
i have two loops ie.
if (n==null)
{
do loop 1
}
else //(n=!null)
{
do loop2
}
now i have to update the above code, with a single loop ie. when n==null or n!=null do the loop 1
how can i update.?
can i do like this
if(n==null ||n=!null)
{
do loop 1
}
is || operator above does the job what i expected
Consider:
Code: template<unsigned int N>
class Test
{
private:
[Code]....
I just cannot understand why (clearly, we are calling <0, 0>, not <0, 8>). If I replace "N" with 8, it works as expected (at least for the beginning of the loop). I only tested on MSVC.
I'm using an animation program. In this program I've simulated a particle system. The particles are flying around at different and varying speeds. I've attached birds to the particles and I want to be able to control each bird's flapping animation based on its velocity; so birds moving faster will be flapping faster.
Initially, the bird's flapping animation is controlled by a parameter that goes from 0 to 100%. So not only do I need to drive the speed at which the animation goes from 0 to 100%, I need to set it on a loop so once it reaches 100%, it loops back to 0%. I'm extremely new to code so I don't think it would be wise for me to even provide a jumping off point, not that I could.
I'm trying to make a percentage counter inside a loop, printing each completed percent of the loop as it goes. I've managed to write such code, but when I run it the percentage output breaks down (becomes negative!) for large loops. I have an example below.
Code:
#include <iostream>
#include <sstream>
#include <string>
#include <stdlib.h>
#include <stdio.h>
using namespace std ;
int main() {
[code].....
Compiling and running the above yields the output:
Code:
...1% ...2% ...3% ...4% ...5% ...6% ...7% ...8% ...9% ...10% ...11% ...12% ...13% ...14% ...15% ...16% ...17% ...18% ...19% ...20% ...21% ...-21% ...-20% ...-19% ...-18% ...-17% ...-16% ...-15% ...-14% ...-13% ...-12% ...-11% ...-10% ...-9% ...-8% ...-7% ...-6% ...-5% ...-4% ...-3% ...-2% ...-1% ...0% ...1% ...2% ...3% ...4% ...5% ...6% ...7% ...8% ...9% ...10% ...11% ...12% ...13% ...14% ...15% ...16% ...17% ...18% ...19% ...20% ...21% ...-21% ...-20% ...-19% ...-18% ...-17% ...-16% ...-15% ...-14% ...-13% ...-12% ...-11% ...-10% ...-9% ...-8% ...-7% ...-6% ...-5% ...-4% ...-3% ...-2% ...-1% ...0% ...1% ...2% ...3% ...4% ...5% ...6% ...7% ...8% ...9% ...10% ...11% ...12% ...13% ...14%...100%
If I change the value of N to 1e7 instead of 1e8, the output is correct however!
Code:
...1% ...2% ...3% ...4% ...5% ...6% ...7% ...8% ...9% ...10% ...11% ...12% ...13% ...14% ...15% ...16% ...17% ...18% ...19% ...20% ...21% ...22% ...23% ...24% ...25% ...26% ...27% ...28% ...29% ...30% ...31% ...32% ...33% ...34% ...35% ...36% ...37% ...38% ...39% ...40% ...41% ...42% ...43% ...44% ...45% ...46% ...47% ...48% ...49% ...50% ...51% ...52% ...53% ...54% ...55% ...56% ...57% ...58% ...59% ...60% ...61% ...62% ...63% ...64% ...65% ...66% ...67% ...68% ...69% ...70% ...71% ...72% ...73% ...74% ...75% ...76% ...77% ...78% ...79% ...80% ...81% ...82% ...83% ...84% ...85% ...86% ...87% ...88% ...89% ...90% ...91% ...92% ...93% ...94% ...95% ...96% ...97% ...98% ...99%...100%
how would I write a while() loop that calculates the sum of all prime numbers from 1 - 50.
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View 2 Replies View RelatedI have a 64-bit uint64_t number:
Code:
Primitive<uint64_t> b = 0xCCCCCCCC00000000; I need to save the first 31 (most important) bits - 7FFFFFFE.
I found this solution in the Internet:
Code:
start = (((b)>>(first)) & ((1<<(((last+1)-(first))))-1)); but in my case for this code:
Code: Primitive<uint64_t> start = (((b)>>(32)) & ((1<<(((63+1)-(32))))-1));
I get an error: left shift count >= width of type
And even if I change 63 to 62:
Code:
Primitive<uint64_t> start = (((b)>>(32)) & ((1<<(((62+1)-(32))))-1));
I get: error: integer overflow in expression
In my calculator, I am trying to make it so that you put enter 1 to add, 2 to subtract, 3 to multiply, and 4 to divide. I am facing the issue of making it so that you must enter a number, however instead of it being any number, it must be 1, 2, 3, or 4, and if it is not any of those numbers, you must re-enter the number. Here is a little snippet of my code:
Code:
printf("Please enter 1 to add, 2 to subtract, 3 to multiply, or 4 to multiply: ");
while (scanf("%d", &input) != 1) {
while (getchar() != '
');
printf("Invalid option. Please try again: ");
[Code] ....
how I can make the loop affect specific numbers.
Ok, so I am writing this program with 10 different functions, and one of those functions needs to count how many times 0 appears in a text file. I've done this before, but I am so stumped right now. Should I get the numbers from the 2d array I have, or should I just use the text file here? Here is what I have right now:
int toursMissed(int scores[][COLS]){
int counter;
for(counter=0;counter<=96;counter++){
if(scores==0){
counter++;
return counter;
}
}
I have a string - a whole sentence that I want to assign a number to each letter, space, comma and period etc. So all "A's" will have the same number, all "B's" will have another number etc. I don't want to use the ASCII numbers because they all need to be sequential and some of the punctuation isn't. I have put the string into a char array to separate each character out and was thinking about running it through a loop with if statements for each letter and assigning numbers there and then saving the numbers in the order they appear into a list as a string but I keep coming up with errors so I don't know how to do it or if there is a better way to accomplish what I'm trying to do.
View 1 Replies View Relatedso i have a loop that will run x number of times and each time it will produce a prize which is a certain sum of money. I need to a way to sum all the money earned. I am thinking there should be a way to extract the prize one for each time the loop runs but i am not sure how to do that.
#include <iostream>
#include <string>
#include <cstdlib>
#include <cmath>
using namespace std;
int main() {
cout <<"Option A: Drop one chip into one slot" << endl;
[Code] .....
I don't know how to ask the user to enter the date in this format (DD/MM/YY) and ISBN number with hyphens.
After user enter date and ISBN number, it should look like this:
Date: 5/24/12
ISBN: 0-000-12345-0
#include <iostream>
#include <string>
using namespace std;
int main() {
string date;//MM/DD/YY Format
[Code] ....
I'm trying to determine the number of times I have to change each specific character in a string to make it a palindrome. You can only change a character one at a time from the end.
Example: "abc" -> "abb" -> "aba" should print 2. "aba" will print 0 because it's already a palindrome. "abcd" -> "abcc" -> "abcb" -> "abca" -> "abba" will print 4 because it took 4 changes to make a palindrome.
I'm not too sure how to approach this - I figured out the case where if it's a palindrome (if reversed string is the same) then it'll print out a 0.
int main() {
int number;
cin >> number; //expecting a number for first line user input
for (int i = 0; i < number; i++) {
string str;
[Code] ....
How do I make a specific character show up a specific amount of times?
Like I am generating a random number then I need to make "|" show up that many times on the screen.
what i think i need to create 2 int for the FOR loop to do the encryption but how am i to do it meaning the actual encryption itself what is that i check with?Also i think i need more than just the #include <stdio.h> library due to the file functions that i will need or is C having them built in? Also what is that about the program doing all this from DOS?
Create 2 programs with the names encrypt and decrypt that will encrypt and decrypt files respectively.The encryption and decryption will be done through a command line of DOS and the program should be as follows: encrypt file1 file2 key and decrypt file1 file2 key
Where:
file1 is the source file
file2 is the destination file
key is the word with which we encrypt/decrypt file1
So when the user executes the command encrypt f1 f2 sunnyday the program will create a file with the name f2 which will have the contents of f1 encrypted with the key sunnyday.When the user executes the command decrypt f1 f2 sunnyday the program will create a file with the name f2 which will have the contents of f1 decrypted with the key sunnyday.
If the user gives a wrong key the program will continue to decrypt file1 but since the key is wrong the results will be unexpected.Finally the program must print the corresponding error messages in case of errors for example (There is no file 1).The program is expected to work corectly with not only plain text files but executable (exe) files etc.Also The program must be fully commented.
Note: The way the encryption will work is yours to choose but it is recommended that you encrypt every letter of the file with every letter of the key with the (start to finish and begin) technique meaning that if the key has 8 letters then the first leeter of the file will be encrypted with the first letter of the key, the second letter of the file with the second of the key, ..., the ninth letter of the source file with the first letter of the key, the tenth letter of the source file with the second letter of the key etc.
In order to create 10 different zipcode where should i put the loop I tried put loop at every function it does not work and I tried put under the main method it create exactly 10 same zipcode here is my coding only create one zipcode
#include <iostream>
#include <stdio.h>
#include <stdlib.h>
#include <ctime>
#include <cmath>
using namespace std;
class Zipcode {
[Code] ...
So, I'm relatively new to programming.
I want to create a loop (for, while, do while) which can run the Collatz Conjecture when I give it any number.
The Collatz Conjecture consists of two functions (3n+1 for odd numbers and n/2 for even numbers) and it states that when applied to any positive number, the outcome will ultimately be 1. think of a loop/pseudocode to apply to this.
I create a loop that would repeat itself many times a second? Trying to do extremely basic graphics with a grid and system("cls") every time I run a command, but it still looks very jumpy. I realize system calls are evil. Any way to get rid of this too.
View 1 Replies View RelatedI need to create a loop to return a minimum value using a boolean variable but don't quite understand how to format my algorithm.
#include <iostream>
using namespace std;
int main() {
bool first = true;
while (first) {
cout << "Enter a number (X to exit): ";
int num;
[Code]....
I know its jacked up any comments in the code would be great I need to finish the program but also understand it.
I am trying to create a zipcode I write my code like that and it only show "-2" on the screen what happen to my code I can not find mistake!
#include <iostream>
#include <stdio.h>
#include <stdlib.h>
#include <ctime>
using namespace std;
class Zipcode {
[Code] ....
I working on a big program, and it involves character arrays. What I want my function to do is create a seperate array that consists of the same number of "*" as there are letters in the word from the text file. For example, if the word sarc was up, the function show make ****. This was my attempt at it. I managed to reach this far. I can only fit in one "*". This is part of jumble game program I'm trying to make, and its in C language.
insert Code: void partialWord(char current[]){
int n;
int i;
n = strlen(current);
for (i = 0; i < n; i++){
current[i] = strcpy(current,"*");
}
printf("%s
", current);
}
I must create a function with a integer number as parameterThis function use the parameter for a loop...example
n = 1
output
1
2
3
n = 2
1,1
1,2
1,3
2,1
2,2
2,3
3,1
3,2
3,3
Write a program that reads four integers from a file ‘input.txt’.
The program will then create a single integer number from the four integers. The output of the program will be the single number and single number + 600.
#include <iostream>
using namespace std;
int main () {
int number , a;
cout<<"enter en integer number";
cin>>number;
cout<<"add 600 to the number"
cin>>a=number+600;
return 0;
}
I have been trying to make a program that asks for username and password, and if it is wrong it will loop back to the top. But i only want it to loop a set number of times, how can i do this? This is my code so far
string username;
string password;
cout << "Enter username: ";
getline(cin, username, '
[Code] ....