I have been trying to make a program that asks for username and password, and if it is wrong it will loop back to the top. But i only want it to loop a set number of times, how can i do this? This is my code so far
string username;
string password;
cout << "Enter username: ";
getline(cin, username, '
[Code] ....
The function uses a "for" loop to print the given character the number of times specified by the integer.
How can I make a for loop to do that?
So.. my code looks like this:
// cpp : Defines the entry point for the console application
//
#include "stdafx.h"
#include <iostream>
using namespace std;
void printMyInteger(int myInteger, char myChar) {
[Code] ....
So.. here is my error:
Error1error C2143: syntax error : missing ';' before ')'d:workspaceuniversity ools for games and animationworkshopsweek 6week 6week 6week 6.cpp101Week 6
Error2error C2143: syntax error : missing ';' before ')'d:workspaceuniversity ools for games and animationworkshopsweek 6week 6week 6week 6.cpp101Week 6
3IntelliSense: expected an expressiond:workspaceuniversity ools for games and animationworkshopsweek 6week 6week 6week 6.cpp107Week 6
I am writing for loop with a switch so that scores can be inputted in by a judge. The issue that I am running into is that I will put out an the text then the test happens and the code puts out the switch statement 5 times with random number. Here is what I have written.
Code:
int main() {
int diver;
int option;
int Judge;
cout << "Enter Divers Name:";
[Code] ....
In this program what i'm doing is to search for a number when the vector is in order, and count how many times that number appears, the problem is that count how many times the number does not appear, but when its appear the program stays in an "standby mode" and the cursor does not move.
int buscarNumOrdenado (int x [MAX]) //MAX is the define {
int num,d, LimiteInferior, LimiteSuperior,mitad;
d=0;
LimiteInferior = 0;
LimiteSuperior = MAX-1;
[Code] ....
I'm running a game online and designing a program to generate Enemy Stats. Basically, it's supposed to generate 25 numbers between 0 and 7(to represent 8 Attributes on a 25 Point Buy system) and count how many times each number shows up.
Here's what the code looks like:
Code:
#include <iostream>
#include <ctime>
#include <cstdlib>
using namespace std;
int Generate() {
int r= rand();
int s= r%7;
[Code] ....
And here's two outputs.
1: Code:
12133089220 12133089220 12133089220 12133089220 12133089220 12133089220 12133089220 12133089220 12133089220 12133089220 12133089220 12133089220 12133089220 12133089220 12133089220 12133089220 12133089220 12133089220 12133089220 12133089220 12133089220 12133089220 12133089220 12133089220 12133089220 Stats[0]= 25 Stats[1]= 0 Stats[2]= 0 Stats[3]= 0 Stats[4]= 0 Stats[5]= 0 Stats[6]= 0 Stats[7]= 0 Stats[8]= 0 Disallowed system call: SYS_socketcall
2: Code:
14787708434 14787708434 14787708434 14787708434 14787708434 14787708434 14787708434 14787708434 14787708434 14787708434 14787708434 14787708434 14787708434 14787708434 14787708434 14787708434 14787708434 14787708434 14787708434 14787708434 14787708434 14787708434 14787708434 14787708434 14787708434 Stats[0]= 0 Stats[1]= 0 Stats[2]= 0 Stats[3]= 0 Stats[4]= 25 Stats[5]= 0 Stats[6]= 0 Stats[7]= 0 Stats[8]= 0 Disallowed system call: SYS_socketcall
Note that the number does change, but only between runs.
I create a loop that would repeat itself many times a second? Trying to do extremely basic graphics with a grid and system("cls") every time I run a command, but it still looks very jumpy. I realize system calls are evil. Any way to get rid of this too.
View 1 Replies View RelatedAssume all variable are declared correctly, the following for loop executes how many times?
for (i = 0; i <= 20; i++)
cout << I;
I think 20 but am not sure.
I tried my best but I can't figure out the problem. At the last part of "createArray", I output the final array created. I mean it to repeat once but then it repeat more times than I expect. createArray is an iterative function. If it repeats 3 times, than at last the array created which fulfil the criterion would be printed out 3+1 times.
I am trying to create an array with 3 numbers 5 times, resulting in a 2D array. The 3 numbers in a array are picked from 0 - 5. I enter createArray(5,3,5). Then these 5 arrays are compared with each other to see if there are repetitions. If there are, the whole process begins again, 5 arrays with 3 numbers each will be picked again and compared with each other. If there are no repetitions at last, there 5 arrays would be printed out.
void deleteArray(int** array){
delete[] array;
}
int** createArray(int simu_times, int randomrun,int numberofrun){
vector<Int_t>fChosenRun;
int** Array = new int*[simu_times];
[Code] ....
I'm having trouble getting my loop to work correctly. If I iterate the for loop once it works as expected and displays proper output. When I try to iterate two times or more the program gets stuck in an infinite loop.
testData8.dat:
Code:
12 9
13 756
I'm trying to create a program that loops "x" number of times, where "x" is going to be a user-input number.
View 2 Replies View RelatedI want to write how many times a method is called. The first class houses a method that I want to count from the second class how many times it is called. what I am able to achieve so far is that it only writes out how many times it is called but what I want is that it should be like a counter like this: if called ofr 5 times it should print:
1
2
3
4
5
and not just 5.
First class
public static int count = 0;
public void Login(String LoginUsername, String LoginPassword) {
count++;
}
Second class
int i = LoginReusables.count;
i++;
System.IO.File.WriteAllText(@"C:Usersken4wardDesktopTidyWriteLines.txt", i.ToString());
I want to have one case of my switch statement to print out how many times the user has chosen other cases in the switch statement. Such as "You have pressed 2 6 times and 4 3 times."
View 3 Replies View RelatedI wrote the following program shown below that produces a normally distributed random number several times, and then takes the average of them. The problem that I have been having though is that the output it has been producing is 0.0288385 despite the fact that I set the mean of the normal distribution to be 0.1. Why this output value would be so far off from 0.1 despite having averaged over such a large number of random numbers namely 10,000 of them? Also, how to randomly seed this random number generator such that it gives a different value each time its run perhaps by seeding it with the windows timer? Below is the program.
#include <iostream>
#include <random>
using namespace std;
int main() {
default_random_engine generator;
normal_distribution<double> distribution1(0.1,3.0);
double number1,sum,n;
[code].....
Ok, so I am writing this program with 10 different functions, and one of those functions needs to count how many times 0 appears in a text file. I've done this before, but I am so stumped right now. Should I get the numbers from the 2d array I have, or should I just use the text file here? Here is what I have right now:
int toursMissed(int scores[][COLS]){
int counter;
for(counter=0;counter<=96;counter++){
if(scores==0){
counter++;
return counter;
}
}
I'm trying to write a function in C that calculates the average test score given by the user an arbitrary number of times...
View 14 Replies View Relatedso i have a loop that will run x number of times and each time it will produce a prize which is a certain sum of money. I need to a way to sum all the money earned. I am thinking there should be a way to extract the prize one for each time the loop runs but i am not sure how to do that.
#include <iostream>
#include <string>
#include <cstdlib>
#include <cmath>
using namespace std;
int main() {
cout <<"Option A: Drop one chip into one slot" << endl;
[Code] .....
How would I by any means print out the result of one number being added by two numbers 999999 times, the numbers both happen to be about 16500 digits long. It must display ALL digits in the number (all the digits the result ends up being). I know I can't use normal data-types, so what do I do?
Looks kinda like this:
for (int i = 0; i < 999999; ++i)
{
total += a;
total += b;
}
a and b being 2 different numbers with about 16500 digits.
I wrote a code that mimics a dice, my code so far will ask for the user to input a number at which they want to hold or no longer throw the dice, it will also ask the user how many roll simulations they would like to do.
If a 1 is rolled the turn is over and the score is 0
After this input is recieved the code goes into a loop until the values have been met.
I would to add probability to my code so I need to know how many times a certain number was rolled and this is where I am stuck.
An example of how I would like my code to work, let's suppose hold at number is 17
We role the dice until we roll a 17 or larger, but if we roll a 1, then our score is 0.
Let's suppose the number of simulations is 5 and for simulation 1 we roll
2 + 5 + 6 + 4 = 17
and for simulation 2 we roll
5 + 4 + 1, but since we rolled a 1, the score is 0,
for simulation 3 we roll
3 + 4 + 5 + 6 = 18
for simulation 4 we roll
4 + 4 + 6 + 6 = 20
for simulation 5 we roll
3 + 4 + 5 + 5 = 17 so that means we got
0: 1 time 1/5 = .20
17: 2 times 2/5 = .40
18: 1 time 1/5 = .20
19: 0 times 0/5 = .00
20: 1 time 1/5 = .20
21: 0 times 0/5 = .00
22: 0 times 0/5 = .00
In other words the idea is to roll a 17 or larger (or whatever the hold number happens to be), but if you roll a 1, then your score is a 0.
#include <iostream>
#include <cstdlib>
#include <ctime>
using std::cout;
using std::cin;
using std::endl;
int dieRoll();
[Code] ....
I'm trying to determine the number of times I have to change each specific character in a string to make it a palindrome. You can only change a character one at a time from the end.
Example: "abc" -> "abb" -> "aba" should print 2. "aba" will print 0 because it's already a palindrome. "abcd" -> "abcc" -> "abcb" -> "abca" -> "abba" will print 4 because it took 4 changes to make a palindrome.
I'm not too sure how to approach this - I figured out the case where if it's a palindrome (if reversed string is the same) then it'll print out a 0.
int main() {
int number;
cin >> number; //expecting a number for first line user input
for (int i = 0; i < number; i++) {
string str;
[Code] ....
I'm doing some exercises in c and i have to do one which shows me this output:
Quote
I=0 J=1
I=0 J=2
I=0 J=3
I=0.2 J=1.2
I=0.2 J=2.2
I=0.2 J=3.2
.....
I=2 J=?
I=2 J=?
I=2 J=?
I am supposed to have a loop that terminates when the difference between two successive values of 'e' differ by less than 0.0000001 (6 zeroes). So far I have written this much of the code:
#include <stdio.h>
double eCalc(int terms, double e);
int main() {
int dummy;
int terms;
double e;
[Code] ...
It will not even run. Compiler code errors are as such:
error C4700: uninitialized local variable 'e' used
how i can find the 5 without loop?
vector<int>i;
vector<int>j;
i.push_back(1);
i.push_back(2);
j.push_back(3);
j.push_back(4);
j.push_back(5);
[Code]...
I've researched this quite a bit and the overwhelming answer I've been seeing for a loop generating the same pseudo-random number is that you're seeing the random number generator inside the loop, but that is not the case with me . . . At least not that I can see.
Basically, as I mentioned, I have a loop "birthing" new bunnies in a loop. And all the new bunnies are being created with the same name and other details.
Here is the code:
void BunnyGraduation::breed() {
for (unsigned int male = 0; male < colony.size(); male++) {
if (colony.at(male).getSex() == Bunny::Sex::MALE && colony.at(male).getRadioactiveMutantVampireBunny() != true && colony.at(male).getAge() >= AGEOFCONSENT) {
for (unsigned int female = 0; female < colony.size(); female++) {
[Code] ....
srand(time(0)); is seeded ONCE in the constructor of the bunny object itself. . . Now, come to think of it, the constructor is called every time an object is created . . . And the constructor contains the srand() . . . and the constructor is being called in a loop. . . So therefore, yes, the srand() is being called inside the loop.
I need to calculate the expected time it takes to do an activity using a formula provided and after the loop is broken it needs to show the number of projects processed and the project with the longest expected time. I've got everything working except for finding the the project with the longest expected time. What I have here just keeps displaying the number of the last project processed regardless of if it was the largest or not, specifically lines 54-61 is what i can't seem to figure out.
#include <stdio.h>
int main( void ) {
unsigned int counter;
int projectnumber;
int optimistictime;
int realistictime;
[Code] .....
I've been working on a program on and off for around a week now and I've been struggling towards the end of the program.First of all, the program is a maths quiz which generates two random numbers per question.I'll give you one part of my code:
Code:
srand ( time(NULL) ); //seeds the random number generator
int score = 0;
int a = rand()%12 +1; //generates a random num between 1-12
int b = rand()%12 +1;
int c = a+b;
int d;
}
[code]....
I've basically copied the above code 10 times and changed the variables by going through the alphabet e.g.
Code:
int a = rand()%12 +1; //generates a random num between 1-12
int b = rand()%12 +1;
int c = a+b;
int d; all the way to
Code:
int an = rand()%12 +1;
int ao = rand()%12 +1;
int ap = rand()%12 +1;
int aq = an+ao-ap;
int ar;
Now what I'm going to do is remove all the declared variables and create a loop. But my problem is; If I wanted to declare four variables for e.g.
Code:
int a = rand()%12 +1;
int b = rand()%12 +1;
int c = rand()%12 +1;
int d = a+b-c;
Would I place the srand( time(NULL)); inside the loop? it's confusing because I know an example of a basic loop with an array would be:
Code:
#include <stdio.h>
#include <conio.h>
int main(void)
{
int test[5]={21,18,47,21,4};
int I;
int total=0;
for (I=0;i<5;i++)
total += test[I];
}
[code]....
how or where to include the random number generator in the loop and to make it ask 10 questions at random.
I want to create a specific number of for loops each in another loop, as in example:
for(i=0;i<9;i++)
{
for(j=0;j<9;j++)
{
for(k=0;k<9;k++)
{
//some stuff
}
}
}
In this example there are 3 loops, but what if i want to create e.g. 10 such loops, and program reads a number of loops from a txt? It is needed for checking numbers.
