C++ :: Print Out Result Of One Number Being Added By Two Numbers 999999 Times
Feb 17, 2013
How would I by any means print out the result of one number being added by two numbers 999999 times, the numbers both happen to be about 16500 digits long. It must display ALL digits in the number (all the digits the result ends up being). I know I can't use normal data-types, so what do I do?
Looks kinda like this:
for (int i = 0; i < 999999; ++i)
{
total += a;
total += b;
}
a and b being 2 different numbers with about 16500 digits.
The function uses a "for" loop to print the given character the number of times specified by the integer.
How can I make a for loop to do that?
So.. my code looks like this:
// cpp : Defines the entry point for the console application // #include "stdafx.h" #include <iostream> using namespace std; void printMyInteger(int myInteger, char myChar) {
[Code] ....
So.. here is my error:
Error1error C2143: syntax error : missing ';' before ')'d:workspaceuniversity ools for games and animationworkshopsweek 6week 6week 6week 6.cpp101Week 6 Error2error C2143: syntax error : missing ';' before ')'d:workspaceuniversity ools for games and animationworkshopsweek 6week 6week 6week 6.cpp101Week 6 3IntelliSense: expected an expressiond:workspaceuniversity ools for games and animationworkshopsweek 6week 6week 6week 6.cpp107Week 6
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[Code] ....
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[code] ...
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