C/C++ :: For Loop To Print Given Character Number Of Times Specified By Integer

Feb 11, 2014

The function uses a "for" loop to print the given character the number of times specified by the integer.

How can I make a for loop to do that?

So.. my code looks like this:

// cpp : Defines the entry point for the console application
//
#include "stdafx.h"
#include <iostream>
using namespace std;
void printMyInteger(int myInteger, char myChar) {

[Code] ....

So.. here is my error:

Error1error C2143: syntax error : missing ';' before ')'d:workspaceuniversity ools for games and animationworkshopsweek 6week 6week 6week 6.cpp101Week 6
Error2error C2143: syntax error : missing ';' before ')'d:workspaceuniversity ools for games and animationworkshopsweek 6week 6week 6week 6.cpp101Week 6
3IntelliSense: expected an expressiond:workspaceuniversity ools for games and animationworkshopsweek 6week 6week 6week 6.cpp107Week 6

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C++ :: Determine Number Of Times Change Each Specific Character In String To Make It Palindrome

Feb 19, 2015

I'm trying to determine the number of times I have to change each specific character in a string to make it a palindrome. You can only change a character one at a time from the end.

Example: "abc" -> "abb" -> "aba" should print 2. "aba" will print 0 because it's already a palindrome. "abcd" -> "abcc" -> "abcb" -> "abca" -> "abba" will print 4 because it took 4 changes to make a palindrome.

I'm not too sure how to approach this - I figured out the case where if it's a palindrome (if reversed string is the same) then it'll print out a 0.

int main() {
int number;
cin >> number; //expecting a number for first line user input
for (int i = 0; i < number; i++) {
string str;

[Code] ....

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I have been trying to make a program that asks for username and password, and if it is wrong it will loop back to the top. But i only want it to loop a set number of times, how can i do this? This is my code so far

string username;
string password;
cout << "Enter username: ";
getline(cin, username, '

[Code] ....

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Feb 17, 2013

How would I by any means print out the result of one number being added by two numbers 999999 times, the numbers both happen to be about 16500 digits long. It must display ALL digits in the number (all the digits the result ends up being). I know I can't use normal data-types, so what do I do?

Looks kinda like this:

for (int i = 0; i < 999999; ++i)
{
total += a;
total += b;
}

a and b being 2 different numbers with about 16500 digits.

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I am writing for loop with a switch so that scores can be inputted in by a judge. The issue that I am running into is that I will put out an the text then the test happens and the code puts out the switch statement 5 times with random number. Here is what I have written.

Code:
int main() {
int diver;
int option;
int Judge;
cout << "Enter Divers Name:";

[Code] ....

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In this program what i'm doing is to search for a number when the vector is in order, and count how many times that number appears, the problem is that count how many times the number does not appear, but when its appear the program stays in an "standby mode" and the cursor does not move.

int buscarNumOrdenado (int x [MAX]) //MAX is the define {
int num,d, LimiteInferior, LimiteSuperior,mitad;
d=0;
LimiteInferior = 0;
LimiteSuperior = MAX-1;

[Code] ....

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Sep 26, 2012

I'm running a game online and designing a program to generate Enemy Stats. Basically, it's supposed to generate 25 numbers between 0 and 7(to represent 8 Attributes on a 25 Point Buy system) and count how many times each number shows up.

Here's what the code looks like:

Code:
#include <iostream>
#include <ctime>
#include <cstdlib>
using namespace std;
int Generate() {
int r= rand();
int s= r%7;
[Code] ....

And here's two outputs.

1: Code:

12133089220 12133089220 12133089220 12133089220 12133089220 12133089220 12133089220 12133089220 12133089220 12133089220 12133089220 12133089220 12133089220 12133089220 12133089220 12133089220 12133089220 12133089220 12133089220 12133089220 12133089220 12133089220 12133089220 12133089220 12133089220 Stats[0]= 25 Stats[1]= 0 Stats[2]= 0 Stats[3]= 0 Stats[4]= 0 Stats[5]= 0 Stats[6]= 0 Stats[7]= 0 Stats[8]= 0 Disallowed system call: SYS_socketcall

2: Code:

14787708434 14787708434 14787708434 14787708434 14787708434 14787708434 14787708434 14787708434 14787708434 14787708434 14787708434 14787708434 14787708434 14787708434 14787708434 14787708434 14787708434 14787708434 14787708434 14787708434 14787708434 14787708434 14787708434 14787708434 14787708434 Stats[0]= 0 Stats[1]= 0 Stats[2]= 0 Stats[3]= 0 Stats[4]= 25 Stats[5]= 0 Stats[6]= 0 Stats[7]= 0 Stats[8]= 0 Disallowed system call: SYS_socketcall

Note that the number does change, but only between runs.

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I am trying to create an array with 3 numbers 5 times, resulting in a 2D array. The 3 numbers in a array are picked from 0 - 5. I enter createArray(5,3,5). Then these 5 arrays are compared with each other to see if there are repetitions. If there are, the whole process begins again, 5 arrays with 3 numbers each will be picked again and compared with each other. If there are no repetitions at last, there 5 arrays would be printed out.

void deleteArray(int** array){
delete[] array;
}
int** createArray(int simu_times, int randomrun,int numberofrun){
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[Code] ....

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testData8.dat:

Code:
12 9
13 756

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1
2
3
4
5
and not just 5.

First class

public static int count = 0;
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Second class
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[Code] ....

If i type in:
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Code:
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#include <math.h>
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