C++ :: Produce Normal Distribution Random Number Several Times
Aug 22, 2014
I wrote the following program shown below that produces a normally distributed random number several times, and then takes the average of them. The problem that I have been having though is that the output it has been producing is 0.0288385 despite the fact that I set the mean of the normal distribution to be 0.1. Why this output value would be so far off from 0.1 despite having averaged over such a large number of random numbers namely 10,000 of them? Also, how to randomly seed this random number generator such that it gives a different value each time its run perhaps by seeding it with the windows timer? Below is the program.
#include <iostream>
#include <random>
using namespace std;
int main() {
default_random_engine generator;
normal_distribution<double> distribution1(0.1,3.0);
double number1,sum,n;
[code].....
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Mar 12, 2013
I am generating random number of normal distribution (0,1) but i suspect maybe I have done it wrong. The generator I use right now is
srand(time(0));
std::random_device rd;
std::mt19937 gen(rd());
std::default_random_engine generator;
std::normal_distribution<double> distribution(0,1);
Am I doing the right thing? Whether this is a real random number generator?
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Jun 26, 2013
I want to generate random numbers of normal distribution and use scentence like
std::default_random_engine generator;
std::normal_distribution<double> distribution(0,1);
arrayX[i][j]=distribution(generator);
But I find that each time the array I got are the same. So how should I generate random numbers with different seedings with normal distribution?
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Feb 6, 2013
Write a function that generates 1000 normally distributed (Gaussian Probability Distribution) random numbers. Range should be between -3 and +3. Numbers should be double floating point.
There's more to it than that, but I've got it from there.
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Sep 19, 2013
so i have a loop that will run x number of times and each time it will produce a prize which is a certain sum of money. I need to a way to sum all the money earned. I am thinking there should be a way to extract the prize one for each time the loop runs but i am not sure how to do that.
#include <iostream>
#include <string>
#include <cstdlib>
#include <cmath>
using namespace std;
int main() {
cout <<"Option A: Drop one chip into one slot" << endl;
[Code] .....
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May 27, 2013
How to generate a skew distribution random number? Or is there any place having refer the skew distribution random number?
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May 23, 2014
I'm implementing an normal_distribution to select objects on a vector. The thing is I can't use values greater then 1 or less then -1. Here is what could be done:
gausx=gaus_distributionx(generator);
while((gausx>1) || (gausx<-1))
gausx=gaus_distributionx(generator);
The question is if the distribution would loose it's power to be a normal distribution, because some of the gerated numbers wouldn't be used. Any way to set ranges for the distribution?
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Nov 8, 2013
I need creating a unique form of binary tree. I will eventually drop 256 balls into this to see the distribution, but its creating a pascals triangle recursively.
To create it I need to use two classes, a tree and a node class, and friend them create it recursively.
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Sep 26, 2012
I'm running a game online and designing a program to generate Enemy Stats. Basically, it's supposed to generate 25 numbers between 0 and 7(to represent 8 Attributes on a 25 Point Buy system) and count how many times each number shows up.
Here's what the code looks like:
Code:
#include <iostream>
#include <ctime>
#include <cstdlib>
using namespace std;
int Generate() {
int r= rand();
int s= r%7;
[Code] ....
And here's two outputs.
1: Code:
12133089220 12133089220 12133089220 12133089220 12133089220 12133089220 12133089220 12133089220 12133089220 12133089220 12133089220 12133089220 12133089220 12133089220 12133089220 12133089220 12133089220 12133089220 12133089220 12133089220 12133089220 12133089220 12133089220 12133089220 12133089220 Stats[0]= 25 Stats[1]= 0 Stats[2]= 0 Stats[3]= 0 Stats[4]= 0 Stats[5]= 0 Stats[6]= 0 Stats[7]= 0 Stats[8]= 0 Disallowed system call: SYS_socketcall
2: Code:
14787708434 14787708434 14787708434 14787708434 14787708434 14787708434 14787708434 14787708434 14787708434 14787708434 14787708434 14787708434 14787708434 14787708434 14787708434 14787708434 14787708434 14787708434 14787708434 14787708434 14787708434 14787708434 14787708434 14787708434 14787708434 Stats[0]= 0 Stats[1]= 0 Stats[2]= 0 Stats[3]= 0 Stats[4]= 25 Stats[5]= 0 Stats[6]= 0 Stats[7]= 0 Stats[8]= 0 Disallowed system call: SYS_socketcall
Note that the number does change, but only between runs.
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Jan 26, 2014
I am writing for loop with a switch so that scores can be inputted in by a judge. The issue that I am running into is that I will put out an the text then the test happens and the code puts out the switch statement 5 times with random number. Here is what I have written.
Code:
int main() {
int diver;
int option;
int Judge;
cout << "Enter Divers Name:";
[Code] ....
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Oct 9, 2014
Create a program that finds all numbers in an array that show up exactly 5 times. I am trying to solve this issue by making a frequency distribution via two loops and two arrays, but I am having trouble getting my loop to not recount a number it has already counted.
For example, if you enter ten 1's into the "entered Numbers" array I want it to store a count of 10 in frequencyarray[1]. Instead it is storing
frequencyarray[0]10
frequencyarray[1]9
frequencyarray[2]8
etc...
#include <iostream>
using namespace std;
void enternumber(long[], int);
int main() {
int size;
int numbers5=0;
[Code] .....
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Feb 5, 2014
I'm looking to code a completely random distribution of numbers that doesn't affect performance using rand. I believe this code would be ideal but I don't understand how to use it. Where would I input the range of numbers and the quantity?
double uniform_deviate ( int seed ){
return seed * ( 1.0 / ( RAND_MAX + 1.0 ) );
} int r = M + uniform_deviate ( rand() ) * ( N - M );
And for the seed...
unsigned time_seed(){
time_t now = time ( 0 );
unsigned char *p = (unsigned char *)&now;
unsigned seed = 0;
size_t i;
for ( i = 0; i < sizeof now; i++ )
seed = seed * ( UCHAR_MAX + 2U ) + p[i];
return seed;
} srand ( time_seed() );
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Feb 6, 2014
In this program what i'm doing is to search for a number when the vector is in order, and count how many times that number appears, the problem is that count how many times the number does not appear, but when its appear the program stays in an "standby mode" and the cursor does not move.
int buscarNumOrdenado (int x [MAX]) //MAX is the define {
int num,d, LimiteInferior, LimiteSuperior,mitad;
d=0;
LimiteInferior = 0;
LimiteSuperior = MAX-1;
[Code] ....
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Oct 29, 2013
I have been trying to make a program that asks for username and password, and if it is wrong it will loop back to the top. But i only want it to loop a set number of times, how can i do this? This is my code so far
string username;
string password;
cout << "Enter username: ";
getline(cin, username, '
[Code] ....
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Feb 20, 2015
I'm trying to create a program that loops "x" number of times, where "x" is going to be a user-input number.
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Mar 17, 2015
I want to write how many times a method is called. The first class houses a method that I want to count from the second class how many times it is called. what I am able to achieve so far is that it only writes out how many times it is called but what I want is that it should be like a counter like this: if called ofr 5 times it should print:
1
2
3
4
5
and not just 5.
First class
public static int count = 0;
public void Login(String LoginUsername, String LoginPassword) {
count++;
}
Second class
int i = LoginReusables.count;
i++;
System.IO.File.WriteAllText(@"C:Usersken4wardDesktopTidyWriteLines.txt", i.ToString());
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Sep 20, 2013
I want to have one case of my switch statement to print out how many times the user has chosen other cases in the switch statement. Such as "You have pressed 2 6 times and 4 3 times."
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Apr 11, 2015
Ok, so I am writing this program with 10 different functions, and one of those functions needs to count how many times 0 appears in a text file. I've done this before, but I am so stumped right now. Should I get the numbers from the 2d array I have, or should I just use the text file here? Here is what I have right now:
int toursMissed(int scores[][COLS]){
int counter;
for(counter=0;counter<=96;counter++){
if(scores==0){
counter++;
return counter;
}
}
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Feb 11, 2014
The function uses a "for" loop to print the given character the number of times specified by the integer.
How can I make a for loop to do that?
So.. my code looks like this:
// cpp : Defines the entry point for the console application
//
#include "stdafx.h"
#include <iostream>
using namespace std;
void printMyInteger(int myInteger, char myChar) {
[Code] ....
So.. here is my error:
Error1error C2143: syntax error : missing ';' before ')'d:workspaceuniversity ools for games and animationworkshopsweek 6week 6week 6week 6.cpp101Week 6
Error2error C2143: syntax error : missing ';' before ')'d:workspaceuniversity ools for games and animationworkshopsweek 6week 6week 6week 6.cpp101Week 6
3IntelliSense: expected an expressiond:workspaceuniversity ools for games and animationworkshopsweek 6week 6week 6week 6.cpp107Week 6
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Mar 15, 2015
I'm trying to write a function in C that calculates the average test score given by the user an arbitrary number of times...
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Feb 17, 2013
How would I by any means print out the result of one number being added by two numbers 999999 times, the numbers both happen to be about 16500 digits long. It must display ALL digits in the number (all the digits the result ends up being). I know I can't use normal data-types, so what do I do?
Looks kinda like this:
for (int i = 0; i < 999999; ++i)
{
total += a;
total += b;
}
a and b being 2 different numbers with about 16500 digits.
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Sep 27, 2014
I wrote a code that mimics a dice, my code so far will ask for the user to input a number at which they want to hold or no longer throw the dice, it will also ask the user how many roll simulations they would like to do.
If a 1 is rolled the turn is over and the score is 0
After this input is recieved the code goes into a loop until the values have been met.
I would to add probability to my code so I need to know how many times a certain number was rolled and this is where I am stuck.
An example of how I would like my code to work, let's suppose hold at number is 17
We role the dice until we roll a 17 or larger, but if we roll a 1, then our score is 0.
Let's suppose the number of simulations is 5 and for simulation 1 we roll
2 + 5 + 6 + 4 = 17
and for simulation 2 we roll
5 + 4 + 1, but since we rolled a 1, the score is 0,
for simulation 3 we roll
3 + 4 + 5 + 6 = 18
for simulation 4 we roll
4 + 4 + 6 + 6 = 20
for simulation 5 we roll
3 + 4 + 5 + 5 = 17 so that means we got
0: 1 time 1/5 = .20
17: 2 times 2/5 = .40
18: 1 time 1/5 = .20
19: 0 times 0/5 = .00
20: 1 time 1/5 = .20
21: 0 times 0/5 = .00
22: 0 times 0/5 = .00
In other words the idea is to roll a 17 or larger (or whatever the hold number happens to be), but if you roll a 1, then your score is a 0.
#include <iostream>
#include <cstdlib>
#include <ctime>
using std::cout;
using std::cin;
using std::endl;
int dieRoll();
[Code] ....
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Feb 19, 2015
I'm trying to determine the number of times I have to change each specific character in a string to make it a palindrome. You can only change a character one at a time from the end.
Example: "abc" -> "abb" -> "aba" should print 2. "aba" will print 0 because it's already a palindrome. "abcd" -> "abcc" -> "abcb" -> "abca" -> "abba" will print 4 because it took 4 changes to make a palindrome.
I'm not too sure how to approach this - I figured out the case where if it's a palindrome (if reversed string is the same) then it'll print out a 0.
int main() {
int number;
cin >> number; //expecting a number for first line user input
for (int i = 0; i < number; i++) {
string str;
[Code] ....
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Nov 21, 2013
I am working with C++ in Visual Studio. It's my first semester doing anything like this ever. Still, I am embarrassed that I am having trouble with this simple "coin flipping" program. The user tells the program how many times to "flip the coin" & then the program tells the user the results of each flip. You'll see I am randomly generating a 1 or a 2 within the function coinFlip to represent heads or tails. However, the problem is that if the user wants more than one coin flip, the "random" number stays the same for all of them, resulting in all heads or all tails. I am thinking this is an issue with the for loop that I have within the function coinFlip.
Code:
#include <iostream>
#include <iomanip>
#include <cstdlib>
#include <ctime>
using namespace std;
[Code] .....
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Nov 27, 2013
I'm trying to generate random number from 7 to 10 but all i got is "Error C2661: 'rand' : no overloaded function takes 1 argument"
there is my code:
#include "stdafx.h"
#include <iostream>
#include <cstdlib>
#include <time.h>
using namespace std;
void init_Function(); // init function
[Code] .....
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Nov 11, 2014
When I run this program it always generates the number 41 or 42. Why is this? Even if I add the code
magic = rand()%100 + 1;
to specify a range of 1 to 100 it's still always 41 or 42.
This is exactly the same code my book uses just without the cout << magic statement
#include<iostream>
#include<cstdlib>
using namespace std;
[Code].....
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