C++ :: Search For A Number When Vector Is In Order - Count How Many Times That Number Appears
Feb 6, 2014
In this program what i'm doing is to search for a number when the vector is in order, and count how many times that number appears, the problem is that count how many times the number does not appear, but when its appear the program stays in an "standby mode" and the cursor does not move.
int buscarNumOrdenado (int x [MAX]) //MAX is the define {
int num,d, LimiteInferior, LimiteSuperior,mitad;
d=0;
LimiteInferior = 0;
LimiteSuperior = MAX-1;
I wrote a code that mimics a dice, my code so far will ask for the user to input a number at which they want to hold or no longer throw the dice, it will also ask the user how many roll simulations they would like to do.
If a 1 is rolled the turn is over and the score is 0
After this input is recieved the code goes into a loop until the values have been met.
I would to add probability to my code so I need to know how many times a certain number was rolled and this is where I am stuck.
An example of how I would like my code to work, let's suppose hold at number is 17
We role the dice until we roll a 17 or larger, but if we roll a 1, then our score is 0.
Let's suppose the number of simulations is 5 and for simulation 1 we roll
2 + 5 + 6 + 4 = 17
and for simulation 2 we roll
5 + 4 + 1, but since we rolled a 1, the score is 0,
for simulation 3 we roll
3 + 4 + 5 + 6 = 18
for simulation 4 we roll
4 + 4 + 6 + 6 = 20
for simulation 5 we roll
3 + 4 + 5 + 5 = 17 so that means we got
0: 1 time 1/5 = .20 17: 2 times 2/5 = .40 18: 1 time 1/5 = .20 19: 0 times 0/5 = .00 20: 1 time 1/5 = .20 21: 0 times 0/5 = .00 22: 0 times 0/5 = .00
In other words the idea is to roll a 17 or larger (or whatever the hold number happens to be), but if you roll a 1, then your score is a 0.
#include <iostream> #include <cstdlib> #include <ctime> using std::cout; using std::cin; using std::endl; int dieRoll();
I'm running a game online and designing a program to generate Enemy Stats. Basically, it's supposed to generate 25 numbers between 0 and 7(to represent 8 Attributes on a 25 Point Buy system) and count how many times each number shows up.
Here's what the code looks like:
Code: #include <iostream> #include <ctime> #include <cstdlib> using namespace std; int Generate() { int r= rand(); int s= r%7; [Code] ....
I am writing this program that is supposed to read a file, put the data into an array, alphabetize, count how many times each word appears and print to an output function. I posted before on how my program had an error when I ran it but I have fixed that. Now my outputArray file is empty. It gets created but there's nothing in it.
Everytime I type a character, the number 1 appears in the next line. And i just keep getting the message "Wrong! I have more than that." even when I type a number bigger than 1023
Code:
#include <stdio.h> #include <stdlib.h> #include <time.h> int main(void) { srand(time(NULL));
The following fuction from a class is supposed to count the number less then the average of all number combined. but it does not do that, now the fun part if you change it to count the number greater then the average it works great.
void IntegerArray::countBelowAverage() { avrg=calcAverage(avg); int count=0; for(int x=0; x<100; x++) { if (list[x]<avrg)
i am writing a program that accepts a decimal number from the user and convert it to binary numbers. After the conversion, i should count the number of 1's and 0's in the said binary number. I got upto converting and counting 1's using Brian Kernighan’s Algorithm. But, i can't seem to get it to count the number of 0's.
#include <iostream> #include<bitset> using namespace std; int main() { int num,count=0,Zero,count1 =0; cout<<"Enter the number:"; cin>>num; string binary;
I have been trying to make a program that asks for username and password, and if it is wrong it will loop back to the top. But i only want it to loop a set number of times, how can i do this? This is my code so far
I want to write how many times a method is called. The first class houses a method that I want to count from the second class how many times it is called. what I am able to achieve so far is that it only writes out how many times it is called but what I want is that it should be like a counter like this: if called ofr 5 times it should print:
1 2 3 4 5 and not just 5.
First class
public static int count = 0; public void Login(String LoginUsername, String LoginPassword) { count++; } Second class int i = LoginReusables.count; i++; System.IO.File.WriteAllText(@"C:Usersken4wardDesktopTidyWriteLines.txt", i.ToString());
I want to have one case of my switch statement to print out how many times the user has chosen other cases in the switch statement. Such as "You have pressed 2 6 times and 4 3 times."
I wrote the following program shown below that produces a normally distributed random number several times, and then takes the average of them. The problem that I have been having though is that the output it has been producing is 0.0288385 despite the fact that I set the mean of the normal distribution to be 0.1. Why this output value would be so far off from 0.1 despite having averaged over such a large number of random numbers namely 10,000 of them? Also, how to randomly seed this random number generator such that it gives a different value each time its run perhaps by seeding it with the windows timer? Below is the program.
#include <iostream> #include <random> using namespace std; int main() { default_random_engine generator; normal_distribution<double> distribution1(0.1,3.0); double number1,sum,n;
Ok, so I am writing this program with 10 different functions, and one of those functions needs to count how many times 0 appears in a text file. I've done this before, but I am so stumped right now. Should I get the numbers from the 2d array I have, or should I just use the text file here? Here is what I have right now:
int toursMissed(int scores[][COLS]){ int counter; for(counter=0;counter<=96;counter++){ if(scores==0){ counter++; return counter; } }
The function uses a "for" loop to print the given character the number of times specified by the integer.
How can I make a for loop to do that?
So.. my code looks like this:
// cpp : Defines the entry point for the console application // #include "stdafx.h" #include <iostream> using namespace std; void printMyInteger(int myInteger, char myChar) {
[Code] ....
So.. here is my error:
Error1error C2143: syntax error : missing ';' before ')'d:workspaceuniversity ools for games and animationworkshopsweek 6week 6week 6week 6.cpp101Week 6 Error2error C2143: syntax error : missing ';' before ')'d:workspaceuniversity ools for games and animationworkshopsweek 6week 6week 6week 6.cpp101Week 6 3IntelliSense: expected an expressiond:workspaceuniversity ools for games and animationworkshopsweek 6week 6week 6week 6.cpp107Week 6
so i have a loop that will run x number of times and each time it will produce a prize which is a certain sum of money. I need to a way to sum all the money earned. I am thinking there should be a way to extract the prize one for each time the loop runs but i am not sure how to do that.
How would I by any means print out the result of one number being added by two numbers 999999 times, the numbers both happen to be about 16500 digits long. It must display ALL digits in the number (all the digits the result ends up being). I know I can't use normal data-types, so what do I do?
Looks kinda like this:
for (int i = 0; i < 999999; ++i) { total += a; total += b; }
a and b being 2 different numbers with about 16500 digits.
I am writing for loop with a switch so that scores can be inputted in by a judge. The issue that I am running into is that I will put out an the text then the test happens and the code puts out the switch statement 5 times with random number. Here is what I have written.
Code: int main() { int diver; int option; int Judge; cout << "Enter Divers Name:";
I'm trying to determine the number of times I have to change each specific character in a string to make it a palindrome. You can only change a character one at a time from the end.
Example: "abc" -> "abb" -> "aba" should print 2. "aba" will print 0 because it's already a palindrome. "abcd" -> "abcc" -> "abcb" -> "abca" -> "abba" will print 4 because it took 4 changes to make a palindrome.
I'm not too sure how to approach this - I figured out the case where if it's a palindrome (if reversed string is the same) then it'll print out a 0.
int main() { int number; cin >> number; //expecting a number for first line user input for (int i = 0; i < number; i++) { string str;
I was wondering how to limit error message to one only.
For example
cin.getline(stringname,7); for(int i=0;i<size;i++){ if(strcmp(stringname, "hello")=0) cout<<"Found!"<<endl; else cout<<"not found"<<endl; } not found not found .......
I want to count number of words from my textfile and then make the first word ToUpper and second word ToLower and do that for the rest of the textfile.
using System; using System.Collections.Generic; using System.Linq; using System.Text; using System.Threading.Tasks; using System.IO; namespace ConsoleApplication3 { internal class Program { private static void Main(string[] args) {
I want know if the query returned zero rows or not.
Don't want to use count(*)
sql = "select * from TABLE where employeefirstname = @First order by EmploymentStatusDescription"; using (SqlCommand cmd = new SqlCommand(sql, conn)) { cmd.Parameters.AddWithValue("@First", First); reader = cmd.ExecuteReader(); } while (reader.Read())
