I was wondering how to limit error message to one only.
For example
cin.getline(stringname,7);
for(int i=0;i<size;i++){
if(strcmp(stringname, "hello")=0)
cout<<"Found!"<<endl;
else
cout<<"not found"<<endl;
}
not found
not found
.......
In my program, i have a function, example: bool open(string szString); this function i have known it's fix address, example: 0x12345678 Because of my computer which has low capability, if this function is called 1000 times per second it will be hanged, slow. So i want limit the number of function call down to 500 times per second. how will i do with C/C++?
In this program what i'm doing is to search for a number when the vector is in order, and count how many times that number appears, the problem is that count how many times the number does not appear, but when its appear the program stays in an "standby mode" and the cursor does not move.
int buscarNumOrdenado (int x [MAX]) //MAX is the define { int num,d, LimiteInferior, LimiteSuperior,mitad; d=0; LimiteInferior = 0; LimiteSuperior = MAX-1;
I'm running a game online and designing a program to generate Enemy Stats. Basically, it's supposed to generate 25 numbers between 0 and 7(to represent 8 Attributes on a 25 Point Buy system) and count how many times each number shows up.
Here's what the code looks like:
Code: #include <iostream> #include <ctime> #include <cstdlib> using namespace std; int Generate() { int r= rand(); int s= r%7; [Code] ....
The following fuction from a class is supposed to count the number less then the average of all number combined. but it does not do that, now the fun part if you change it to count the number greater then the average it works great.
void IntegerArray::countBelowAverage() { avrg=calcAverage(avg); int count=0; for(int x=0; x<100; x++) { if (list[x]<avrg)
4.1 Write a program that will count from 1 to 12 and print the count, and its square, for each count.
4.2 Write a program that counts from 1 to 12 and prints the count and its inversion to 5 decimal places for each count. This will require a floating point number.
4.3 Write a program that will count from 1 to 100 and print only those values between 32 and 39, one to a line. Use the incrementing operator for this program.
i am writing a program that accepts a decimal number from the user and convert it to binary numbers. After the conversion, i should count the number of 1's and 0's in the said binary number. I got upto converting and counting 1's using Brian Kernighan’s Algorithm. But, i can't seem to get it to count the number of 0's.
#include <iostream> #include<bitset> using namespace std; int main() { int num,count=0,Zero,count1 =0; cout<<"Enter the number:"; cin>>num; string binary;
I want to count number of words from my textfile and then make the first word ToUpper and second word ToLower and do that for the rest of the textfile.
using System; using System.Collections.Generic; using System.Linq; using System.Text; using System.Threading.Tasks; using System.IO; namespace ConsoleApplication3 { internal class Program { private static void Main(string[] args) {
I want know if the query returned zero rows or not.
Don't want to use count(*)
sql = "select * from TABLE where employeefirstname = @First order by EmploymentStatusDescription"; using (SqlCommand cmd = new SqlCommand(sql, conn)) { cmd.Parameters.AddWithValue("@First", First); reader = cmd.ExecuteReader(); } while (reader.Read())
In above XMl if you check the ParentProductCat is prefixed with ns1:,ns2:,ns3:....
My XSLT code only checkes for the ParentProductCat but since it is prefixed with "ns*:" (* is integer) it fails to find it. So that in C# code replace function is used to replace ns*: a for loop is used for this and it goes until 1000
But now my response crossed the 1000 mark and this time the XML contains total 14500 lines.So I want to replace all ns:*
For this I want to count the number of lines present in the XML so that the for loop will run until that line number. how to do that?
I am forking 3 times in a loop like this but the variable "count" does not increment, it stays on '1' and therefore this is an infinite loop, and this simple thing dont make sense to me.
I have checked so that the pointer address is the correct one every loop.
Code: void increase(int* x) { *x += 1; } main() { int pid, i, number = 0;
How we will write a program that will count a number of notes. I mean if i have 5676 rupees and i want to find the number of 5 thousand pak currency ,the number of 1000 notes, the number of 500 notes and the number of 100 notes. How we design such a program of if rlse structure to perform the above task.
I've been currently stuck on a C++ problem. Here's the question:
Write a program that generates one hundred random integers between 0 and 9 and displays the count for each number. (Hint: Use rand()
% 10 to generate a random integer between 0 and 9. Use an array of ten integers, say counts, to store the counts for the number of O's, l 's, . .. , 9's.)
I think I'm pretty close, but I keep on getting "0" for the occurrences (or counts) of each random integer.
#include <iostream> #include <cstdlib> #include <ctime> #include <conio.h> #include <fstream> using namespace std; const int SIZE = 100;
I try to use "rand" to create 100 string, I'm happy I succeed, but next step i wanna know how to count each number of letters and the frequency it shows.
Here is the code:
#include <stdlib.h> #include <string.h> #include <time.h> #include <iostream> // using namespace std; int main() { const char *c = "abcdefghijklmnopqrstuvwxyz";
now using sba or Set Based Algorithm I have to pair it out and towards the end find the size of the resulting set
#include <iostream> #include <set> int main()
[Code]......
this is the code just reads the edges that's 3... that is when we input the code. But what if its in a file? how do I read from there and show the paired count and the time taken?
Also I have the file that works and reads any txt file..but how do i get the code from it?
[URL]
this is the file..you have to run it as ./edgecount for it to work