I have a upcoming C++ exam. I would like to write a program to convert INDIVIDUAL digits into words.
E.g 678 = six seven eight[/size][/b]
I have the following code:
//Program to print individual digits in words #include<iostream> using namespace std; int main() { int num; cout << "Enter a number between 0 and 9999: ";
The thing is, when I don't create a prototype of count and straightaway define it before void main() my program runs, but it gives error in this program that "extra parameter in call to count()" But what to do then?
I'm trying to create a program that counts the amount of alphabetical characters, numbers, blanks and total amount of characters in a string a user gets to enter. The user also quits the program manually by pressing CTRL + D (in linux terminal).
These are the results I get from the code so far by typing in "hello cplusplus 123 c++" CTRL + D.
The string had: Alphabetical characters...: 0 Numbers...................: 0 Blanks....................: 3 Total amount of characters: 20
So I can't seem to find a way to count the amount of alphabetical characters and numeric characters.
Here's my code:
#include <iostream> #include <string> #include <iomanip> #include <cctype> #include <sstream> using namespace std; int main() { string tecken;
[Code] ....
The reason why I declared cctype is that I think I should use the isalpha, isdigit and isblank functions but how I am supposed to do that.
I have a text file which contains many sentences. I am trying to extract only the numerical values from the string that conatins characters,numbers and white spaces from the file. I want to seperate the characters and numbers into different parts.
for example: the file contains sentances as given below.
I have to go to school for 10min. You will come here in 15min. He stayed here for 20min.
from the above sentances, I want to seperate " I have to go to school for " and "10" and put them into two different variables and also 10 should be in integer format.
I wrote a program with function my own function which count the digits of entered number. The problem is whatever i type it shows 0 digits.Why is that?
Code: #include <iostream> using namespace std; int cikCipari (int skaitlis, int cipars); int main()
The output I'm getting here just counts every letter in the sentence and counts them as vowels. I'm trying to make the user defined function return the amount of vowels within the sentence.
I can not cope with the task.Create a function that will take a string of characters (including spaces) and print the numbers of characters (including commas, periods, etc.) in it. The output will be arranged alphabetically. Distinguish case sensitive!
I am attempting to write a recursive function that, given a string, recursively computes a new string where all the lowercase 'x' chars have been moved to the end of the string.
My goal is to create a program that reads a string and counts how many Uppercase, Lowercase, Spaces, and digits there are in the string. Right now this the output i get.
#include <stdio.h> #include <stdlib.h> #include <ctype.h> int main() { int iochar; char string;
I'm supposed to write a program to read a text file and display the following:
a) alphabetic letters //finished with b) digits // finished with c) other characters that are not alphabetic letters and not digits //finished with d) total characters read
The bold part above confused me, by total characters, does it mean the alphabetic letters + other characters? how would I put that in my code?
Code: #include <stdio.h> int main (void) { int curCh; int countCh = 0;
My problem is to count the characters in a file and define how many times each one occurs.Characters who are not found must not be included in the table; The output must be a table - like that -
”| character | ASCII- DEC | ASCI – HEX | how many times it occurs |”
This my function:
Code: int f2(FILE *p1) { FILE *g3; int char_count[256]={0}; char ch; int n=0; if(!(g3=fopen("D:zz.txt", "w"))){
[Code] ....
It must look like this: | D | 68 | 44 | 2 | | 2 | 50 | 32 | 1 | and so on...
so my question is i want to print characters,no string just an array of characters,i do this but it s not working,maybe i have to put the '' at the end?
Code:
int main() { int i; char ch[5]; for(i = 0; i < 5; i++) { scanf("%c",&ch[i]);
Im supposed to find the common characters between two string characters, assuming that the user wont input duplicate letters like ddog. When I run my code I get an output of a question mark upside down. Here is my code with comments on what each part is supposed to do