C/C++ :: Making String Count Numbers / Blanks And Alphabetical Characters
Sep 20, 2014
I'm trying to create a program that counts the amount of alphabetical characters, numbers, blanks and total amount of characters in a string a user gets to enter. The user also quits the program manually by pressing CTRL + D (in linux terminal).
These are the results I get from the code so far by typing in "hello cplusplus 123 c++" CTRL + D.
The string had:
Alphabetical characters...: 0
Numbers...................: 0
Blanks....................: 3
Total amount of characters: 20
So I can't seem to find a way to count the amount of alphabetical characters and numeric characters.
Here's my code:
#include <iostream>
#include <string>
#include <iomanip>
#include <cctype>
#include <sstream>
using namespace std;
int main() {
string tecken;
[Code] ....
The reason why I declared cctype is that I think I should use the isalpha, isdigit and isblank functions but how I am supposed to do that.
I have a upcoming C++ exam. I would like to write a program to convert INDIVIDUAL digits into words.
E.g 678 = six seven eight[/size][/b]
I have the following code:
//Program to print individual digits in words #include<iostream> using namespace std; int main() { int num; cout << "Enter a number between 0 and 9999: ";
The thing is, when I don't create a prototype of count and straightaway define it before void main() my program runs, but it gives error in this program that "extra parameter in call to count()" But what to do then?
" Write a program that reads into a string object a name with three blanks between the first and last names. Then extract the first and last names and store them in separate string objects. Write a function subprogram that displays its string argument two times. Call this function display the first name for times and then to display the last name six times."
I completed coding the first part of this task with the strings and combining strings together. However, i have having trouble with the other half of this task. It begins from "Write a function subprogram to display the last name six times." This is where i have so far --
#include <iostream> #include <string> using namespace std; int main() { // Defining the strings
So I have been assigned a program that counts keystrokes, alphabetical characters, and vowels. I have the program working as desired but I just can't figure out how to make it end upon ONLY the "return" key being pressed.
Code: #include <stdio.h> #include <stdlib.h> #include <ctype.h> int main ( void ) {
My program reads a string of characters. Prints all occurrences of letters and numbers, sorted in alphabetical and numerical order. Letters will be converted to uppercase.Other characters are filtered out, while number of white spaces are counted.
the problem is it crushes when i run the program
Here is my code
#include <iostream> const int SIZE = 100; using namespace std; int main() { char *pStr, str[SIZE] = "", newStr[SIZE] = "", ch; int count = 0, i = 0, j;
I am trying to read information in from a file, each line of which contains a name in the form 'last, first middle'. I can successfully open the file and read it into an array that is roughly 2500 string in size. The problem comes when I try to sort the array into alphabetical order. I am using a sorting algorithm that we were instructed to use, found in our book. It is shown in the code. I would add the file that needs to be opened, but it is a few thousand lines long.
The error I am getting is: Unhandled exception at 0x00A28628 in PeopleSearch.exe: 0xC0000005: Access violation reading location 0x00CC400C.
and I know it has to do with the sorting algorithm from using break points and running the program with that section commented out. I am stumped to why it is giving this error, as it seems that it is trying to access the array outside of the bounds of the array, but it shouldn't be
So I been working on this c++ project and I need to be able to take three seperate strings and send them to function to put them in alphabetical order through a-z and use the swap function to return them in order. I been searching for problems like this but I haven't fame across any. I can copy my code onto here as well as a more detailed description of what I'm needing to do onto here if needed.
My goal is to create a program that reads a string and counts how many Uppercase, Lowercase, Spaces, and digits there are in the string. Right now this the output i get.
#include <stdio.h> #include <stdlib.h> #include <ctype.h> int main() { int iochar; char string;
I'm supposed to write a program to read a text file and display the following:
a) alphabetic letters //finished with b) digits // finished with c) other characters that are not alphabetic letters and not digits //finished with d) total characters read
The bold part above confused me, by total characters, does it mean the alphabetic letters + other characters? how would I put that in my code?
Code: #include <stdio.h> int main (void) { int curCh; int countCh = 0;
My problem is to count the characters in a file and define how many times each one occurs.Characters who are not found must not be included in the table; The output must be a table - like that -
”| character | ASCII- DEC | ASCI – HEX | how many times it occurs |”
This my function:
Code: int f2(FILE *p1) { FILE *g3; int char_count[256]={0}; char ch; int n=0; if(!(g3=fopen("D:zz.txt", "w"))){
[Code] ....
It must look like this: | D | 68 | 44 | 2 | | 2 | 50 | 32 | 1 | and so on...
so my question is i want to print characters,no string just an array of characters,i do this but it s not working,maybe i have to put the '' at the end?
Code:
int main() { int i; char ch[5]; for(i = 0; i < 5; i++) { scanf("%c",&ch[i]);
Im supposed to find the common characters between two string characters, assuming that the user wont input duplicate letters like ddog. When I run my code I get an output of a question mark upside down. Here is my code with comments on what each part is supposed to do
#include <stdio.h> #include <stdlib.h> #include <string.h> int main(){ char str1[20], str2[20],remp = ' '; int size1,i,j,temp; printf ("Input the first string");
Very new to programming, and I know that there must be another way on inputting a string into each array cells not by just inputting it one by one, but as a whole. My code at the meantime is: [URL]
4.1 Write a program that will count from 1 to 12 and print the count, and its square, for each count.
4.2 Write a program that counts from 1 to 12 and prints the count and its inversion to 5 decimal places for each count. This will require a floating point number.
4.3 Write a program that will count from 1 to 100 and print only those values between 32 and 39, one to a line. Use the incrementing operator for this program.
I wrote a program which sends a starting and ending range to other processes and the processes calculate the prime numbers in that range and return the count of prime numbers to the head process, process 0. But this is not working properly at the moment. I realize I still have to split up the range based on how many processes I have...I still have not figured out how I want to set that up. I
Code:
#include <stdio.h> #include <stdlib.h> #include <mpi.h> int isPrime(int num); int main(int argc, char **argv){ }
I have the codes for such a problem where, to create a program that counts how many times the second string appears on the first string. Yes it counts if you put 1 letter only, but if you put 2, it is an error. As an example. If the first string is Harry Partear, and the second string is ar, it must count as 3. Here's the code:
Code:
#include <iostream> #include <conio.h> using namespace std; int main ()
I want to calculate how many times the common number is repeated . So I have used freq[num] in that function. But I am getting the output like this-
Code:
The common number is = 5 The 5 repeated = 1 times The common number is = 6 The 6 repeated = 1 times
The common number is = 4 The 4 repeated = 1 times
The common number is = 5 The 5 repeated = 1 times
[code]....
So the freq[num] is only returning 1 instead of counting the total number of repeating which is wrong!! I would like to have somthing like this in my output -
Code:
The common number is = 5 The common number is = 6 The common number is = 4 The common number is = 5 The common number is = 5 The common number is = 8 The common number is = 9 The common number is = 6 The common number is = 6
iam trying to count the same numbers in an array just once like
38 38 40 38 40 37
the output should be 2 since 38 is repeated and 40 too but for my code the output is 3 thats an example of how it should be in a nutshell i want same number to be counted just once in the whole array
and here's my code :
#include <iostream> using namespace std; int main(){
I have loaded and 1d array from a .dat file, calculated the average of all the numbers. Now I need to count every number in the array that is below the average and cout that number. This is the method in the class I have so far:
