I have loaded and 1d array from a .dat file, calculated the average of all the numbers. Now I need to count every number in the array that is below the average and cout that number. This is the method in the class I have so far:
array is a one-dimensional array of integers and n is the number of elements in that array that contain valid data values. Both of these are input parameters to the function. The function must calculate 1) the average of the n integers in array, storing the result in ave; 2) the average of the positive numbers (> 0), storing the result in avePos, and 3) the average of the negative numbers (< 0), storing the result in aveNeg.
void avgs (std::vector &array, int &ave, int &avePos, int &aveNeg) { int sum = 0, pos_sum = 0, neg_sum = 0, pos_count = 0, neg_count = 0; for (auto i : array) { sum += i; if (i > 0) { pos_sum += i; ++pos_count; }
write a c++ program that reads an unknown number of integer values and then print count, sum and average of odd values, even values, positive values, negative values!!
The following fuction from a class is supposed to count the number less then the average of all number combined. but it does not do that, now the fun part if you change it to count the number greater then the average it works great.
void IntegerArray::countBelowAverage() { avrg=calcAverage(avg); int count=0; for(int x=0; x<100; x++) { if (list[x]<avrg)
I was trying to make a program that asks the number of grades, get the grades and then get the average. I know I have to save the grades in an array but i don't know exactly how.
I have the random values down but when I try to assign randValue to another integer I get an error.I want to make an inner loop where I find 5 random number 50 times and print the average of those numbers.
I know I have the bare bones of the below, but without giving me a huge shove in the right direction can I have a poke? I have been programing for three months now. I have noticed when I do simple fun projects I learn more then what my professor assigned to me. The class is over but I want to keep building.C++ starts in one week...
I need to implement a C++ program that asks the user for four floating-point numbers. The program should then calculate the average using two different functions, one value returning and one void. The program should output the average of the four numbers. For this program I need to use float instead of int for the types of variables. Below is a proto-type code that I am able to use to do this program.
#include <iostream> using namespace std; int sum(int,int);
Write a C program that calculates the sum and average of a sequence of numbers. Assume the first number specifies the number of values remaining to be entered. If the first number is less than 1, then the program should display an "Invalid Entry ... Please enter a positive number." message.
THIS IS HOW IT SHOULD COME OUT... Enter the number of values to process 0
Invalid Entry ... Please enter a positive number.
Enter the number of values to process 3 Enter 3 numbers: 1 2 3
Sum: 6 Avg: 2
THIS IS THE CODE I HAVE SO FAR...
#include <stdio.h> int main(void) { int total=0; int howmany; int i; int value;
I made a program that is suppose to receive 20 numbers or less and find the average, then show all numbers entered but my average does not show. It shows as 0 and a line pops up after every number returned. I am stuck and dont know how to fix the logical errors.
#include <iostream> #include <cmath> using namespace std; int main() { float num[20]; int amount_num;
I have written two separate programs; Program 1 calculates the average of an array of numbers which has been hard-coded into the program. Program 2 reads an array of numbers from a text file and displays them on the output.
I wish to combine these two programs into one by making Program 1 read the array of numbers from the file and then calculate the average using that instead of the array { 84, 92, 76, 81, 56 } as outlined below. I only wish to display the average in the output, not the number array as Program 2 does.
I have tried to do most of the work, I just need modifying the code slightly so it reads the number array from the file and calculates the average.
Program 1
#include <iostream> #include <cmath> #include <math.h> #include <fstream> #include <string> #include <numeric> using namespace std; int main() { const int nNumStudents = 5;
4.1 Write a program that will count from 1 to 12 and print the count, and its square, for each count.
4.2 Write a program that counts from 1 to 12 and prints the count and its inversion to 5 decimal places for each count. This will require a floating point number.
4.3 Write a program that will count from 1 to 100 and print only those values between 32 and 39, one to a line. Use the incrementing operator for this program.
I wrote a program which sends a starting and ending range to other processes and the processes calculate the prime numbers in that range and return the count of prime numbers to the head process, process 0. But this is not working properly at the moment. I realize I still have to split up the range based on how many processes I have...I still have not figured out how I want to set that up. I
Code:
#include <stdio.h> #include <stdlib.h> #include <mpi.h> int isPrime(int num); int main(int argc, char **argv){ }
I want to calculate how many times the common number is repeated . So I have used freq[num] in that function. But I am getting the output like this-
Code:
The common number is = 5 The 5 repeated = 1 times The common number is = 6 The 6 repeated = 1 times
The common number is = 4 The 4 repeated = 1 times
The common number is = 5 The 5 repeated = 1 times
[code]....
So the freq[num] is only returning 1 instead of counting the total number of repeating which is wrong!! I would like to have somthing like this in my output -
Code:
The common number is = 5 The common number is = 6 The common number is = 4 The common number is = 5 The common number is = 5 The common number is = 8 The common number is = 9 The common number is = 6 The common number is = 6
iam trying to count the same numbers in an array just once like
38 38 40 38 40 37
the output should be 2 since 38 is repeated and 40 too but for my code the output is 3 thats an example of how it should be in a nutshell i want same number to be counted just once in the whole array
and here's my code :
#include <iostream> using namespace std; int main(){
I am facing a problem which i could not obtain the total numbers which is greater than the average value. For example:
#include <iostream> using namespace std; int main (){ int size , count; double no, max, min ,total, sum , average;
[Code] ....
In this case im able to compute the average of the numbers but when it comes to capture the total of numbers which is greater than the average value, how to compile the code , because the average number is only been compute once all the value capture by the input of user is sum up.
I needed to compute average median and mode for numbers in a vector. Im having a few issues I have already figured out how to calculate average and median just not mode. Also the program crashes when 0 is entered instead of exiting nicely. Also i keep getting a error on line 47 saying primary expression expected before else.
I am attempting to write a program " that has a function that is passed an array of int and its size, and with that it prints out only the numbers that are above average. "
I have included my code so far, but I am only getting one value as output, and that value seems to be completely off. I keep trying, but I am really stuck.
#include <iostream> using namespace std; int average(int values[],int size); int main(){ int size; int values[] = {1,2,3,4,5,6};
[Code] ....
Added the floats in the average() function. But there is still a value problem.
So I already gave this a go and will post my code below. The question is about the last loop before the program cout's. i thought the count would keep track of the repeated numbers so i could display them but it does not. I italicized the loop i am referring to. or at least i tried to xD
#include <iostream> #include <iomanip> using namespace std; int main() { int inputs[30]; int numofloops; int maxvalue = inputs[0];
I must count the number of occurrence of all numbers in array , i wrote a code but it does not work properly
#include <iostream> int main (){ int i,n,tmp,counter=0; std::cout<<"Enter the size of the array:"<<std::endl; std::cin>>n; int *Array=new int [n]; int *counterArray=new int [n];
I have a upcoming C++ exam. I would like to write a program to convert INDIVIDUAL digits into words.
E.g 678 = six seven eight[/size][/b]
I have the following code:
//Program to print individual digits in words #include<iostream> using namespace std; int main() { int num; cout << "Enter a number between 0 and 9999: ";
I seem to have reached a dead end in a program I am attempting to write.The purpose of the program is find the smallest, largest, and average values in a collection of N numbers. It needs to get the value of N before scanning each value in the collection of N numbers.I'm having trouble creating comparisons for each set. I have a feeling because of the way I structured my program, I'm unable to make a proper comparison. Maybe my approach was wrong as soon as I got to the for statement to loop N sets and N numbers.Here is my code so far:
Code:
#include <stdio.h> int main (void) { int num_sets, num_of_integers; int count, count2, set, sum = 0; int num, avg; }
[code]....
/* Here is where I would continue to attempt to make a comparison between sets to determine smallest to largest */
