C++ :: How To Obtain Total Of Numbers Greater Than Average Without Using Array
Jul 27, 2014
I am facing a problem which i could not obtain the total numbers which is greater than the average value. For example:
#include <iostream>
using namespace std;
int main (){
int size , count;
double no, max, min ,total, sum , average;
[Code] ....
In this case im able to compute the average of the numbers but when it comes to capture the total of numbers which is greater than the average value, how to compile the code , because the average number is only been compute once all the value capture by the input of user is sum up.
array is a one-dimensional array of integers and n is the number of elements in that array that contain valid data values. Both of these are input parameters to the function. The function must calculate 1) the average of the n integers in array, storing the result in ave; 2) the average of the positive numbers (> 0), storing the result in avePos, and 3) the average of the negative numbers (< 0), storing the result in aveNeg.
void avgs (std::vector &array, int &ave, int &avePos, int &aveNeg) { int sum = 0, pos_sum = 0, neg_sum = 0, pos_count = 0, neg_count = 0; for (auto i : array) { sum += i; if (i > 0) { pos_sum += i; ++pos_count; }
#include<iostream> using namespace std; int main(){ int k,num,sum=0,GreaterNO=0; double average;
[Code] .....
above is my program, I have received an assignment which the lecturer request us to find a series of k numbers then
-display the average -display the total of numbers greater than the average
our lecturer request us do in 2 version, one is by using array, one is without using array, I have facing the coding problem when doing the VERSION WITHOUT USING ANY ARRAY to get the display the total numbers greater than the average, is there possible to get it?? because there are only one variable keep on looping, but the average will only get after get all the user input....?
I am doing my assignment that will calculate total tax amount per day and per week and finally sum those up.
One of the requirement is to filter out any number in the array that is less than 1000 to be assigned a value of zero instead of the stored value so as not to add it in the calculation. How to fulfill this requirement.
"Write a program that prompts the user for an integer number from the keyboard, and store it in a variable num. After each number is typed in, add num to a total.
Do this six times, each time adding num to a total. (Be sure to reuse the same variable named num for each of the six numbers entered.) When all six numbers have been entered from the keyboard, calculate an average. Display the total and average calculated. "
Here is what I have so far:
Code: #include<stdio.h> int main() { int num, total1, total2, total3, total4, total5, total6, avg;
I was trying to make a program that asks the number of grades, get the grades and then get the average. I know I have to save the grades in an array but i don't know exactly how.
I have written two separate programs; Program 1 calculates the average of an array of numbers which has been hard-coded into the program. Program 2 reads an array of numbers from a text file and displays them on the output.
I wish to combine these two programs into one by making Program 1 read the array of numbers from the file and then calculate the average using that instead of the array { 84, 92, 76, 81, 56 } as outlined below. I only wish to display the average in the output, not the number array as Program 2 does.
I have tried to do most of the work, I just need modifying the code slightly so it reads the number array from the file and calculates the average.
Program 1
#include <iostream> #include <cmath> #include <math.h> #include <fstream> #include <string> #include <numeric> using namespace std; int main() { const int nNumStudents = 5;
I am attempting to write a program " that has a function that is passed an array of int and its size, and with that it prints out only the numbers that are above average. "
I have included my code so far, but I am only getting one value as output, and that value seems to be completely off. I keep trying, but I am really stuck.
#include <iostream> using namespace std; int average(int values[],int size); int main(){ int size; int values[] = {1,2,3,4,5,6};
[Code] ....
Added the floats in the average() function. But there is still a value problem.
im trying to write a source code that find the smallest, largest and average of numbers in array. the code runs fine, but it is not giving the highest number and the the average should include only four number excluding highest and smallest number from the array.
void OlympicJudging() // Olympic Judging { int numbers [6]; double average, sum = 0; int temp; for(int i = 0; i < 6; i++){ cout << "Please type a value for scores: "; cin >> numbers[i];
How can I obtain the length of an array that has been sent throughout a function. In the following code, I obtain "2" as output, while I was expecting "5".
im trying to write a program that finds the max in an array and divedes it by two than oututs a modfied list with all the elements greater than the max/2.
I got the first part but just not sure how to find the elements greater than the max/2 and output them correctly into the modfied list.
#include <iostream> #include <iomanip> using namespace std;
I want to count all the numbers in my text file (read.txt). Read text file consist of floating and integer number. Answer for the above file would be integer=2 and float =10.
I have loaded and 1d array from a .dat file, calculated the average of all the numbers. Now I need to count every number in the array that is below the average and cout that number. This is the method in the class I have so far:
I have the random values down but when I try to assign randValue to another integer I get an error.I want to make an inner loop where I find 5 random number 50 times and print the average of those numbers.
I know I have the bare bones of the below, but without giving me a huge shove in the right direction can I have a poke? I have been programing for three months now. I have noticed when I do simple fun projects I learn more then what my professor assigned to me. The class is over but I want to keep building.C++ starts in one week...
I need to implement a C++ program that asks the user for four floating-point numbers. The program should then calculate the average using two different functions, one value returning and one void. The program should output the average of the four numbers. For this program I need to use float instead of int for the types of variables. Below is a proto-type code that I am able to use to do this program.
#include <iostream> using namespace std; int sum(int,int);
Write a C program that calculates the sum and average of a sequence of numbers. Assume the first number specifies the number of values remaining to be entered. If the first number is less than 1, then the program should display an "Invalid Entry ... Please enter a positive number." message.
THIS IS HOW IT SHOULD COME OUT... Enter the number of values to process 0
Invalid Entry ... Please enter a positive number.
Enter the number of values to process 3 Enter 3 numbers: 1 2 3
Sum: 6 Avg: 2
THIS IS THE CODE I HAVE SO FAR...
#include <stdio.h> int main(void) { int total=0; int howmany; int i; int value;
I made a program that is suppose to receive 20 numbers or less and find the average, then show all numbers entered but my average does not show. It shows as 0 and a line pops up after every number returned. I am stuck and dont know how to fix the logical errors.
#include <iostream> #include <cmath> using namespace std; int main() { float num[20]; int amount_num;
I needed to compute average median and mode for numbers in a vector. Im having a few issues I have already figured out how to calculate average and median just not mode. Also the program crashes when 0 is entered instead of exiting nicely. Also i keep getting a error on line 47 saying primary expression expected before else.
