im trying to write a program that finds the max in an array and divedes it by two than oututs a modfied list with all the elements greater than the max/2.
I got the first part but just not sure how to find the elements greater than the max/2 and output them correctly into the modfied list.
#include <iostream>
#include <iomanip>
using namespace std;
[Code].....
I was wondering if there was some sort of C++ equivalent for the IDL FIX function. For example, say I want to find all the elements of FLOAT ARRAY1[] that are greater than NUM1 and convert them to INT ARRAY2[].
The problem I have with writing this code myself is not knowing how many elements are going to be greater than NUM1, so I don't know how to initialize ARRAY2[?].
I am facing a problem which i could not obtain the total numbers which is greater than the average value. For example:
#include <iostream>
using namespace std;
int main (){
int size , count;
double no, max, min ,total, sum , average;
[Code] ....
In this case im able to compute the average of the numbers but when it comes to capture the total of numbers which is greater than the average value, how to compile the code , because the average number is only been compute once all the value capture by the input of user is sum up.
I am doing my assignment that will calculate total tax amount per day and per week and finally sum those up.
One of the requirement is to filter out any number in the array that is less than 1000 to be assigned a value of zero instead of the stored value so as not to add it in the calculation. How to fulfill this requirement.
create a program that asks the user to input 10 integers of an array the program will add the numbers greater or equal to 10.
View 6 Replies View RelatedWrite the function itob(n,s,b) that converts the integer n into a base b character representation in the string s . In particular, itob(n,s,16) formats n as a hexadecimal integer in s .
Note that it says the result is formatted into a hexadecimal integer in the string s. Here is the example provided:
Code:
void itob(int n, char s[], int b) {
static char digits[] = "0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ";
int i, sign;
if ( b < 2 || b > 36 ) {
fprintf(stderr, "EX3_5: Cannot support base %d
[Code] ....
Why does digits array hold the full alphabet when the maximum digit for a hex number is f?
#include<iostream>
using namespace std;
int main(){
int k,num,sum=0,GreaterNO=0;
double average;
[Code] .....
above is my program, I have received an assignment which the lecturer request us to find a series of k numbers then
-display the average
-display the total of numbers greater than the average
our lecturer request us do in 2 version, one is by using array, one is without using array, I have facing the coding problem when doing the VERSION WITHOUT USING ANY ARRAY to get the display the total numbers greater than the average, is there possible to get it?? because there are only one variable keep on looping, but the average will only get after get all the user input....?
Where is problem in my code, it is a flappy bird. I dont know why put me that problem when click Start on game show me on 99 line error 'maxValue' must be greater than zero. Parameter name: maxValue
I copy exception to clipboard
System.ArgumentOutOfRangeException was unhandled
HResult=-2146233086
Message='maxValue' must be greater than zero.
Parameter name: maxValue
Source=mscorlib
ParamName=maxValue
StackTrace:
[Code] .....
I've implemented a records system for a college assignment and everything works as intended. However upon increasing the amount of records to store in my array above 10, the program crashes upon adding a new employee and I can't work out why...
#include <stdio.h>
#include <errno.h>
#include <ctype.h>
#include <stdlib.h>
#include <string.h>
#define esize 10 /* Change max-records */
[Code] .....
Write a program using user-defined function which accepts an integer array and its size as arguments and assign the elements into a two dimensional array of integers in the following format: If the array is 1,2,3,4,5,6, the resultant 2D array is
1 2 3 4 5 6
1 2 3 4 5 0
1 2 3 4 0 0
1 2 3 0 0 0
1 2 0 0 0 0
1 0 0 0 0 0
Write a function that takes an array and returns true if all the elements in the array are positive, otherwise, it returns false.
View 6 Replies View RelatedI am new to programming in C++, and have got a project on this.
Write a C++ program that accepts three numbers from the user (All are integers):
Such as:
Enter the first mark: 3
Enter the second mark: 25
Enter the third mark: 23
The program should find and print the average of the odd numbers greater than 5 and less than 100.
I am having problem in writing the code for the problem "To assign the elements of 1-D integer array into 2-D array of integers such as if the array is 1,2,3,4,5,6 The resultant 2-D array should be like :
1 0 0 0 0 0
1 2 0 0 0 0
1 2 3 0 0 0
1 2 3 4 0 0
1 2 3 4 5 0
1 2 3 4 5 6
"
I was given a question in my programming class to create a program to find the factorial of any number greater than zero and to use Gosper's formula to approximate it.
Code:
#include <stdio.h>
#include <math.h>
#define PI 3.14159265
double equation(int n);
int
[Code] ....
I have just started learning C language, I have read that array name is the pointer to the first element of array.
So,technically both a and a[0] should have different memory address and a should hold address of a[0],
But when I declare an array and print the address:
int a[5]={2,4,6,8,10};
printf("The address of a and a[0] are &d and %d",&a,&a[0]);
Output is: The address of a and a[0] are 2358832 and 2358832
Why I am getting the same result, shouldn't I be getting different memory address for both a and a[0].
I've a file that looks like this:
84484-37.96-Castor, Kathy
39050-69.68-Chandler, Ben
26183-70.84-Costello, Jerry
I have successfully read each element the id, grade and name into 3 separate array. Now i need to add a new student with an id and grade
How do i do this?
This is what I have.
int addStudent( int Iarray[], double dArray[], string sArray[], int newID,
double newGrade, string newName, int size ) {
char ready;
int index;
cout << endl;
cout << "Enter new student ID number : ";
[Code]...
I have a question regarding the elements of an array. Suppose I have a 3 by 3 string array (char x[3][4] ) , and I initialize all the elements to x's , the array would then look like this :
xxx
xxx
xxx
I'm curious if there will be a value if I try to access and element outside the array. As I have to write a code to determine if I have reached the end of an array. The only way I can think of is to border the entire array with o's , making it look like this :
ooooo
oxxxo
oxxxo
oxxxo
ooooo
Is there any other way to do this?
Trying to concatenate the 1st and 2nd element from an array of chars. Then this to be used as a hex value.
so for example
specs[0]='f'
specs[1]='4'
concatenate_value=0xf4
Write the definition of a function reverse , whose first parameter is an array of integers and whose second parameter is the number of elements in thearray . The function reverses the elements of the array . The function does not return a value .
Code:
void reverse(int a[], int num) {
for ( int i=0; i <= num/2 ; i++){
int temp = a[i];
a[i] = a[num-i-1];
a[num-i-1] = temp;
} }
This is supposed to be the answer but I'm not quite sure why this is. I understand everything up until the actual loop. For one, shouldn't "int i" be declared outside the loop (I thought perhaps this was an error in the solutions)?
The main thing that I do not understand is the conditional statement.
Code: i<=num/2;
I don't understand why the "num/2" is necessary here. Also I can't really remember but is there a command that actually reverses an array?
I'm trying to set all the elements of my array to 0 but nothing seems to be working.
.h
#ifndef ServerGroup_h
#define ServerGroup_h
class ServerGroup {
public:
ServerGroup(const int&);
[Code] .....
I want to set each element of the array in servers to 0 based on what is passed into size by numArray.
I am trying to write a program that reverses the elements of an array by using an function 'myreverse'. The function should reverse original array and return nothing.
In my program, the function 'myreverse' is not getting invoked and the original array is being displayed as it is.
#include <iostream>
using namespace std;
void myreverse(int arr[],int n) {
int *p=&arr[n-1];
int temp;
for(int i=0;i<n;++i)
[Code] .....
I'm having trouble getting my array to add its values together. I have a similar program running fine with the exact same equation. I am not so naive as to believe that this means it should run with every program but I'm at a loss as to what to do.
#include <iostream>
#include <iomanip>
using namespace std;
[Code].....
im trying to get my array to display 5,1,2,3,4 from the original 1,2,3,4,5.
void values::movevalues()
{
cout << "postcondition
";
[Code]....
something in this part is making it go wrong, it displayes the original array fine but when it tries to shift it it goes haywire. EDIT: also how would i add elements onto the array?
I thought I'm done doing mg activity, but my professor said that we need to use a Temporary Variable for Swapping but where to put it.
Here is his activity:
Activity: Swapping Create a program that accepts a 10-element array of type int. Where the 1st user-input is stored in the 1st element of the array; the 2nd user-input is stored in the 2nd element of the array; so on so forth until the last user-input stored in the last element of the array. Your source code should be able to SWAP the values of the 1st and 10th; 2nd and 9th; 3rd and 8th; 4th and 7th; and 5th and 6th elements. It should display the values of the original and the swapped values of the array. example:
Enter 10 integer values:
array[0] = 1
array[1] = 2
array[2] = 3
array[3] = 4
[Code]....
I want to increase the value of some elements of an array according to a certain condition. For example the following code:
array <int, 100> myArray = {};
myArray.fill(0);
for(int i=1; i<5; i++)
*(myArray.being()+1) ++;
I was hoping myArray[1] = 5. But it actually did not work. But if I code:
int myVar = 0;
for(int i=1; i<5; i++)
myVar ++;
Result: myVar = 5.
I need to make a FOR loop for an array of 5 elements. (array[5]). The loop should pick the positions [1] and [4] and removes the integers positioned in it and the integers next to it should fill in the space like this:
Elements in Array:
23 24 25 26 27
Elements after deletion:
23 25 26 0 0
I'm having a hard time making one ....
Here's the code i tried to make (so far, i keep on failing):
#include<stdio.h>
#include<conio.h>
int main() {
void del(int*, int);
int array[5] = {23,24,25,26,27};
int z = 5;
[Code] ....