I'm trying to set all the elements of my array to 0 but nothing seems to be working.
.h
#ifndef ServerGroup_h
#define ServerGroup_h
class ServerGroup {
public:
ServerGroup(const int&);
[Code] .....
I want to set each element of the array in servers to 0 based on what is passed into size by numArray.
Trying to get code to look like
Row 1: ^^^
Row 2: ^^^
Row 3: ^^^
const int siz = 3;
for (int t=0; t<siz;t++) {
cout << "Row" << t+1 << ":";
cout << endl;
[Code] ....
Also was wondering if i wanted to separately ask the user to choose a location to add a char who would i do that ?
( im thinking * cin << arry[][]; ? not sure but ask for them separately
array []1
array []2
= array [][]
Lets say i have an array with the values 1, 5, 9, and 3. is there anyway to make this so i can have an int with the value 1593 based on those numbers in the array?
View 8 Replies View RelatedI have the following situation:
Code:
void myFun(float *pfMyPtr) {
float Val[] = {0.234, 0,432, 0.322, 0762, 0.984};
pfMyPtr = Val;
}
int main() {
float *pfPtr;
pfPtr = (float*) calloc (5,sizeof(float));
myFun(pfPtr);
}
I would like pfPtr to contain the values of array Val. What am I missing here?
How do I set all of these string and double value(s) to 0?
Code:
#define MAXcharacters 12
#define MAXaccounts 100
struct Records {
char userid[MAXcharacters + 1];
char password[MAXcharacters + 1];
double balance;
};
[code]...
Okay so I've declared an array like this.
Foo *Blocks[100][100][10000] = {0};
And as far as my understanding goes This creates an array with every member set to NULL.
And then later on in my code some of these get given values using:
Blocks[a][b][c] = new Foo;
And then when I want to unload I would think that I could just go
Blocks = {0};
But obviously this doesn't work.
So I was wondering if there was a way of doing This, with out creating a loop and changing every one to NULL manually.
I am attempting to change a character in a character array.In the code below, there are three attempts to do this. Only the first one will succeed. The last two both segfaults. If I understand correctly, str_one is declared in the heap, and could therefore be manipulated; and in contrast, str_two is declared in the stack and is therefore immutable, thus the segfault, when update it is attempted. However, I understand that using malloc, one is able to assign a pointer and allocate space in heap memory. Thus, I should be able to manipulate the assigned variable str_three. Doing so, however, results in a segfault.
Code:
#include <stdio.h>
#include <stdlib.h>
int main (int argc, char const* argv[])
{
char str_one[4092] = "This is string number one";
char * str_two = "This is string number two";
[Code]...
Write a program using user-defined function which accepts an integer array and its size as arguments and assign the elements into a two dimensional array of integers in the following format: If the array is 1,2,3,4,5,6, the resultant 2D array is
1 2 3 4 5 6
1 2 3 4 5 0
1 2 3 4 0 0
1 2 3 0 0 0
1 2 0 0 0 0
1 0 0 0 0 0
Write a function that takes an array and returns true if all the elements in the array are positive, otherwise, it returns false.
View 6 Replies View RelatedI am having problem in writing the code for the problem "To assign the elements of 1-D integer array into 2-D array of integers such as if the array is 1,2,3,4,5,6 The resultant 2-D array should be like :
1 0 0 0 0 0
1 2 0 0 0 0
1 2 3 0 0 0
1 2 3 4 0 0
1 2 3 4 5 0
1 2 3 4 5 6
"
I have just started learning C language, I have read that array name is the pointer to the first element of array.
So,technically both a and a[0] should have different memory address and a should hold address of a[0],
But when I declare an array and print the address:
int a[5]={2,4,6,8,10};
printf("The address of a and a[0] are &d and %d",&a,&a[0]);
Output is: The address of a and a[0] are 2358832 and 2358832
Why I am getting the same result, shouldn't I be getting different memory address for both a and a[0].
I've a file that looks like this:
84484-37.96-Castor, Kathy
39050-69.68-Chandler, Ben
26183-70.84-Costello, Jerry
I have successfully read each element the id, grade and name into 3 separate array. Now i need to add a new student with an id and grade
How do i do this?
This is what I have.
int addStudent( int Iarray[], double dArray[], string sArray[], int newID,
double newGrade, string newName, int size ) {
char ready;
int index;
cout << endl;
cout << "Enter new student ID number : ";
[Code]...
I have a question regarding the elements of an array. Suppose I have a 3 by 3 string array (char x[3][4] ) , and I initialize all the elements to x's , the array would then look like this :
xxx
xxx
xxx
I'm curious if there will be a value if I try to access and element outside the array. As I have to write a code to determine if I have reached the end of an array. The only way I can think of is to border the entire array with o's , making it look like this :
ooooo
oxxxo
oxxxo
oxxxo
ooooo
Is there any other way to do this?
Trying to concatenate the 1st and 2nd element from an array of chars. Then this to be used as a hex value.
so for example
specs[0]='f'
specs[1]='4'
concatenate_value=0xf4
Write the definition of a function reverse , whose first parameter is an array of integers and whose second parameter is the number of elements in thearray . The function reverses the elements of the array . The function does not return a value .
Code:
void reverse(int a[], int num) {
for ( int i=0; i <= num/2 ; i++){
int temp = a[i];
a[i] = a[num-i-1];
a[num-i-1] = temp;
} }
This is supposed to be the answer but I'm not quite sure why this is. I understand everything up until the actual loop. For one, shouldn't "int i" be declared outside the loop (I thought perhaps this was an error in the solutions)?
The main thing that I do not understand is the conditional statement.
Code: i<=num/2;
I don't understand why the "num/2" is necessary here. Also I can't really remember but is there a command that actually reverses an array?
I am trying to write a program that reverses the elements of an array by using an function 'myreverse'. The function should reverse original array and return nothing.
In my program, the function 'myreverse' is not getting invoked and the original array is being displayed as it is.
#include <iostream>
using namespace std;
void myreverse(int arr[],int n) {
int *p=&arr[n-1];
int temp;
for(int i=0;i<n;++i)
[Code] .....
I'm having trouble getting my array to add its values together. I have a similar program running fine with the exact same equation. I am not so naive as to believe that this means it should run with every program but I'm at a loss as to what to do.
#include <iostream>
#include <iomanip>
using namespace std;
[Code].....
im trying to get my array to display 5,1,2,3,4 from the original 1,2,3,4,5.
void values::movevalues()
{
cout << "postcondition
";
[Code]....
something in this part is making it go wrong, it displayes the original array fine but when it tries to shift it it goes haywire. EDIT: also how would i add elements onto the array?
im trying to write a program that finds the max in an array and divedes it by two than oututs a modfied list with all the elements greater than the max/2.
I got the first part but just not sure how to find the elements greater than the max/2 and output them correctly into the modfied list.
#include <iostream>
#include <iomanip>
using namespace std;
[Code].....
I thought I'm done doing mg activity, but my professor said that we need to use a Temporary Variable for Swapping but where to put it.
Here is his activity:
Activity: Swapping Create a program that accepts a 10-element array of type int. Where the 1st user-input is stored in the 1st element of the array; the 2nd user-input is stored in the 2nd element of the array; so on so forth until the last user-input stored in the last element of the array. Your source code should be able to SWAP the values of the 1st and 10th; 2nd and 9th; 3rd and 8th; 4th and 7th; and 5th and 6th elements. It should display the values of the original and the swapped values of the array. example:
Enter 10 integer values:
array[0] = 1
array[1] = 2
array[2] = 3
array[3] = 4
[Code]....
I want to increase the value of some elements of an array according to a certain condition. For example the following code:
array <int, 100> myArray = {};
myArray.fill(0);
for(int i=1; i<5; i++)
*(myArray.being()+1) ++;
I was hoping myArray[1] = 5. But it actually did not work. But if I code:
int myVar = 0;
for(int i=1; i<5; i++)
myVar ++;
Result: myVar = 5.
I need to make a FOR loop for an array of 5 elements. (array[5]). The loop should pick the positions [1] and [4] and removes the integers positioned in it and the integers next to it should fill in the space like this:
Elements in Array:
23 24 25 26 27
Elements after deletion:
23 25 26 0 0
I'm having a hard time making one ....
Here's the code i tried to make (so far, i keep on failing):
#include<stdio.h>
#include<conio.h>
int main() {
void del(int*, int);
int array[5] = {23,24,25,26,27};
int z = 5;
[Code] ....
Let's say I have an array of 10 elements. I want user to enter 9 numbers so that they fill arrays 0 to 8 (9 numbers). Now I shift the arrays +1. so array[0] is now array[1] and so on. Now I ask user to enter 10th number (fills array 0).
Here's my code(it doesn't shift arrays and doesn't ask for 10th num)
#include <stdio.h>
int main() {
int a[10];
int i;
[code]....
I have this code and so far it does everything it should although I'd like to know how to actually delete the elements from the array so after the duplicates have been removed the size of the array should be 7 and not 10.
#include<iostream>
using namespace std;
int main(){
int nums[10] = {2,7,2,5,4,0,7,6,9,0};
int a, b, t;
int size;
size = 10; //array size
[Code]....
#include "stdio.h"
char t[16] = {0x8F,0x78, 0xC6, 0x12, 0xBA,0x98, 0xA2,0x16, 0x8F,0x78, 0xC6, 0x12, 0xBA, 0x98, 0xA2, 0x16} ;
char w[44];
void main(){
for(int i=0 ; i<4 ; i++){
w[i] = (t[4*i], t[4*i+1], t[4*i+2], t[4*i+3]);
printf("%0x ",w[i]);
}
}
i want to put some elements of the t array into the w array but when i do this, it prints only t[4*i+3]
i want the output to be something like this
w[0] = t[4*i], t[4*i+1], t[4*i+2], t[4*i+3] = 0x8F,0x78, 0xC6, 0x12
w[1] = 0xBA,0x98, 0xA2,0x16
and so on
I am trying to take the Array v[]={0,1,2,3,4,5,6,7,8,9} and put some of the numbers together so I can create a math problem. I have used next_permutation to get the possible combinations of the numbers. I am trying to check every combination to see if they work. Like v[1]v[2]v[4]v[0]v[3] to get then number 12403 (that is where I am having the problem) that I can subtract from v[7]v[2]v[0]v[1]= 7201 to get the answer 5202. How can you put v[1]v[2]v[4]v[0]v[3] together to get the number 12403?
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