I was given a question in my programming class to create a program to find the factorial of any number greater than zero and to use Gosper's formula to approximate it.
Code:
#include <stdio.h>
#include <math.h>
#define PI 3.14159265
double equation(int n);
int
[Code] ....
Write a C++ program that will input from the user a positive number n and find its factorial. Don’t forget to validate the input. The factorial of a positive integer n (denoted by n!) is defines as the product of the integers from 1 to n.
n! = 1* 2 * 3 * ... * (n - 1) * n
You should allow the user to continue working with your program for additional data sets.
Sample output:
Please enter a number: 5
5! = 120
Would you like to continue (Y/N)?Y
Please enter a number: 3
3! = 6
Would you like to continue (Y/N)?N
Good Bye!!
My code for what i think I'm doing is as follows:
#include <iostream>
using namespace std;
int main(){
int i=1;
int n;
[Code] ....
I am new to programming in C++, and have got a project on this.
Write a C++ program that accepts three numbers from the user (All are integers):
Such as:
Enter the first mark: 3
Enter the second mark: 25
Enter the third mark: 23
The program should find and print the average of the odd numbers greater than 5 and less than 100.
I have two numbers and a number that is final number. Which number is approximate the final number ?
For example:
Our final number is : -1/2 and the two numbers is 4 and 3. How can I compare it ?
Or i have numbers more than two like 5 number or 7 number or so foth numbers and final number is : -1/2
I wrote this code to find the factorial of any given function ., works fine but when i put it in a class... it gives me an error ::assignment of read only variable fact;
#include <iostream>
using namespace std;
const static int fact=1;
class My_Factorial {
public:
int x;
void Get_Number(){
cout<<"enter a number to find its factorial";
[Code] ....
#include<iostream>
using namespace std;
int main(){
int k,num,sum=0,GreaterNO=0;
double average;
[Code] .....
above is my program, I have received an assignment which the lecturer request us to find a series of k numbers then
-display the average
-display the total of numbers greater than the average
our lecturer request us do in 2 version, one is by using array, one is without using array, I have facing the coding problem when doing the VERSION WITHOUT USING ANY ARRAY to get the display the total numbers greater than the average, is there possible to get it?? because there are only one variable keep on looping, but the average will only get after get all the user input....?
It is given an integer "p". I have to find a number "n" for which "n factorial" has "p" numbers of zero at the end. Here is the solution i thought, but i am not sure if it is a solution for this problem. Do i have to make a function to calculate the factorial and another function to get the zeros?
int p;
int count5=0;
int i;
int copy_i;
printf("Enter p: ");
scanf("%d",&p);
for(i=1; ;i++) {
[Code] .....
I'm trying to run a factorial program but I'm getting the error statement has not effect.
here's the code
#include <iostream>
using namespace std;
int main() {
int fac = 0;
int sum = 0;
[Code] ....
the error happened in the int main section
I just want to practice in the language so i wrote this simple function that computes the factorial result of a certain number. The problem is that for all numbers > 20, the results are wrong ( < 20 all good).
I already learned that normal "long" type in c is more like 32 bit int and not 64 bit like a long type in java. so I used here a "long long" type.
why am I getting strange results above the number 20? isn't 64 bit enough to hold those numbers?
Code:
long long factorial(int n);
int main() {
long long result = factorial(20);
printf("%lld",result);
[code] ...
for 21 i get: -4249290049419214848
where the right result shoud be: 51,090,942,171,709,440,000
write a program that computes the factorial of a number and displays it. A factorial of a number (written N!) is defined as N * (N-1) * (N-2) * (N-3) ... *1 In other words, 5! = 5 * 4 * 3 * 2 * 1 = 120 and 3! = 3 * 2 * 1 + 6.
Example of output 15 is 1.30767e+012
Can't get it to display error when user enters a number lower than 2 or higher 60.
// Program to calculate factorial of a number
#include <iostream>
#include <iomanip>
[Code].....
I started to learn programming through this site two weeks or so ago. I've got a book with exercices and so on, and one of them involves calculating e within a tolerance given by the user.
The formula for calculating e is the summation of 1+(1/i!), where i -> n.
So, here's the code and I'll explain the problem below:
Code:
#include <stdio.h>
int main()
{
float error;
float terme;
float sumatori = 0;
int cicle_euler = 1;
int factorial;
[Code]...
For some reason, when I set factorial to cicle_factorial, factorial remains 0, which I find puzzling; the program always halts when 1 + sumatori is 2.0 no matter what error is.
This must be a common problem and I suspect it has to do with some distinction between variables inside a loop and variables outside it, but as I lack technical vocabulary I can't seem to find anything on Google.
I'm trying to write a program to calculate an approximate value of e using the formula e = 1 + 1/1! + 1/2! + ....... 1/n!...However, I'm always getting nearly 2.291481 as answer.Here is my code :
Code:
//Approximate the value of e
#include <stdio.h>
int main(void) {
int n, j;
printf("Please enter value of n : ");
scanf("%d", &n);
[code]....
I know I'm not supposed to use system("PAUSE"), but this is self-study.
Write a C program with a separate function which calculates the sine function from the first principles according to the formula below. The code should find the sine value in 5 stages and then final answer
formula below :
sin(x) = x −x3/3!+x5/5!−x7/7!+x9/9!
I have done the code and it just gives me a final sine wave
it should find a error then plus one so on till it gets the answer
Link:
These are images of what it should look like and the image of a the formula ....
Q. WAP to find the next palindrome number larger than the input number.
for eg:-
Input=25
Output=33
The program is giving correct output for number with all digits '9';
why is it not giving output.
#include<iostream>
#include<string>
using namespace std;
int main() {
int len,flag=1,count=0,num,ind;
[code]....
I have an extra credit project where I'm supposed to calculate an approximate the user's age based on the current date and their birthday. My problem is that I am not getting the proper date and time. C++ keeps giving me some random date. I looked up c++ time format on the internet because this is extra credit and not in my book.
I am currently using dev C++ 4.9.9.2. Here is my current code :
// included libraries
#include <cstdlib>
#include <iostream>
#include <iomanip>
#include <time.h>
#define cls system("cls")
#define pauseOutput system("pause")
void printM(int x);
void age(int m, int d, int y, int &yearAge, int &monthAge, int &dayAge);
[Code] ....
I want to find number of comparison and number of exchanges from a list or other than a list. My list is this
12 5 11 19 4 7 8 10 9 6 22 2 9 1 32
First, I am looking for number of comparisons from a list of 10 numbers with 21inversions made by selection sort, insertion sort, exchange sort.
Also, I like to find number of exchanges from a list of 10 numbers with 21inversions made by selection sort, insertion sort, exchange sort.
In the c pgm to find number of digits , if I am giving 001 as the input number ,why I am not getting the no. of digits as 3?
View 2 Replies View RelatedWrite the function itob(n,s,b) that converts the integer n into a base b character representation in the string s . In particular, itob(n,s,16) formats n as a hexadecimal integer in s .
Note that it says the result is formatted into a hexadecimal integer in the string s. Here is the example provided:
Code:
void itob(int n, char s[], int b) {
static char digits[] = "0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ";
int i, sign;
if ( b < 2 || b > 36 ) {
fprintf(stderr, "EX3_5: Cannot support base %d
[Code] ....
Why does digits array hold the full alphabet when the maximum digit for a hex number is f?
I was wondering if there was some sort of C++ equivalent for the IDL FIX function. For example, say I want to find all the elements of FLOAT ARRAY1[] that are greater than NUM1 and convert them to INT ARRAY2[].
The problem I have with writing this code myself is not knowing how many elements are going to be greater than NUM1, so I don't know how to initialize ARRAY2[?].
im trying to write a program that finds the max in an array and divedes it by two than oututs a modfied list with all the elements greater than the max/2.
I got the first part but just not sure how to find the elements greater than the max/2 and output them correctly into the modfied list.
#include <iostream>
#include <iomanip>
using namespace std;
[Code].....
Where is problem in my code, it is a flappy bird. I dont know why put me that problem when click Start on game show me on 99 line error 'maxValue' must be greater than zero. Parameter name: maxValue
I copy exception to clipboard
System.ArgumentOutOfRangeException was unhandled
HResult=-2146233086
Message='maxValue' must be greater than zero.
Parameter name: maxValue
Source=mscorlib
ParamName=maxValue
StackTrace:
[Code] .....
I've implemented a records system for a college assignment and everything works as intended. However upon increasing the amount of records to store in my array above 10, the program crashes upon adding a new employee and I can't work out why...
#include <stdio.h>
#include <errno.h>
#include <ctype.h>
#include <stdlib.h>
#include <string.h>
#define esize 10 /* Change max-records */
[Code] .....
I am trying to find the max number entered by the user, and it should terminate when a negative number is entered. For my code, it will just end when the user inputs a lower number than the previous. i.e.- 10 20 15 "The highest number is 20" when it should be "10 20 5 40 15 -1" "The highest number is 40". No arrays or do/while loops either.
#include <iostream>
using namespace std;
int Max(int x);
int main() {
int x;
[Code] ....
I am facing a problem which i could not obtain the total numbers which is greater than the average value. For example:
#include <iostream>
using namespace std;
int main (){
int size , count;
double no, max, min ,total, sum , average;
[Code] ....
In this case im able to compute the average of the numbers but when it comes to capture the total of numbers which is greater than the average value, how to compile the code , because the average number is only been compute once all the value capture by the input of user is sum up.
I am doing my assignment that will calculate total tax amount per day and per week and finally sum those up.
One of the requirement is to filter out any number in the array that is less than 1000 to be assigned a value of zero instead of the stored value so as not to add it in the calculation. How to fulfill this requirement.
create a program that asks the user to input 10 integers of an array the program will add the numbers greater or equal to 10.
View 6 Replies View Related