I'm trying to run a factorial program but I'm getting the error statement has not effect.
here's the code
#include <iostream>
using namespace std;
int main() {
int fac = 0;
int sum = 0;
[Code] ....
the error happened in the int main section
Write a C++ program that will input from the user a positive number n and find its factorial. Don’t forget to validate the input. The factorial of a positive integer n (denoted by n!) is defines as the product of the integers from 1 to n.
n! = 1* 2 * 3 * ... * (n - 1) * n
You should allow the user to continue working with your program for additional data sets.
Sample output:
Please enter a number: 5
5! = 120
Would you like to continue (Y/N)?Y
Please enter a number: 3
3! = 6
Would you like to continue (Y/N)?N
Good Bye!!
My code for what i think I'm doing is as follows:
#include <iostream>
using namespace std;
int main(){
int i=1;
int n;
[Code] ....
write a program that computes the factorial of a number and displays it. A factorial of a number (written N!) is defined as N * (N-1) * (N-2) * (N-3) ... *1 In other words, 5! = 5 * 4 * 3 * 2 * 1 = 120 and 3! = 3 * 2 * 1 + 6.
Example of output 15 is 1.30767e+012
Can't get it to display error when user enters a number lower than 2 or higher 60.
// Program to calculate factorial of a number
#include <iostream>
#include <iomanip>
[Code].....
It is given an integer "p". I have to find a number "n" for which "n factorial" has "p" numbers of zero at the end. Here is the solution i thought, but i am not sure if it is a solution for this problem. Do i have to make a function to calculate the factorial and another function to get the zeros?
int p;
int count5=0;
int i;
int copy_i;
printf("Enter p: ");
scanf("%d",&p);
for(i=1; ;i++) {
[Code] .....
I just want to practice in the language so i wrote this simple function that computes the factorial result of a certain number. The problem is that for all numbers > 20, the results are wrong ( < 20 all good).
I already learned that normal "long" type in c is more like 32 bit int and not 64 bit like a long type in java. so I used here a "long long" type.
why am I getting strange results above the number 20? isn't 64 bit enough to hold those numbers?
Code:
long long factorial(int n);
int main() {
long long result = factorial(20);
printf("%lld",result);
[code] ...
for 21 i get: -4249290049419214848
where the right result shoud be: 51,090,942,171,709,440,000
I was given a question in my programming class to create a program to find the factorial of any number greater than zero and to use Gosper's formula to approximate it.
Code:
#include <stdio.h>
#include <math.h>
#define PI 3.14159265
double equation(int n);
int
[Code] ....
I started to learn programming through this site two weeks or so ago. I've got a book with exercices and so on, and one of them involves calculating e within a tolerance given by the user.
The formula for calculating e is the summation of 1+(1/i!), where i -> n.
So, here's the code and I'll explain the problem below:
Code:
#include <stdio.h>
int main()
{
float error;
float terme;
float sumatori = 0;
int cicle_euler = 1;
int factorial;
[Code]...
For some reason, when I set factorial to cicle_factorial, factorial remains 0, which I find puzzling; the program always halts when 1 + sumatori is 2.0 no matter what error is.
This must be a common problem and I suspect it has to do with some distinction between variables inside a loop and variables outside it, but as I lack technical vocabulary I can't seem to find anything on Google.
I put some checks in factorial program, I am confused how 27, 40 50 is coming in output and ans is 10.
#include<stdio.h>
int fact(int n) {
if(n==1) {
printf("hello1 %d
",n);
return 1;
[code].....
I have been working on a program to calculate the factorial of numbers. Part of my code is copied and modified from the FAQ about validating numbers in user input.
I have encountered a problem with the for loop that I am using near the end of my code. No matter what I do, it seems that my loop only does the multiplication of b = a*(a-1) and then prints. For example, inputting 5 will result in a print of 20, but the factorial is 120.
Code:
int main(void) {
char buf[BUFSIZ];
char *p;
long int a;
long int b;
long int i;
printf ("Enter a number to be factorialized: ");
[Code] ....
#include<iostream>
using namespace std;
int main() {
int a[9],x,f=1;
cout<<"Please enter an integer [0-10 only] : ";
[Code] ....
I have to make a program that takes a number input from the user and prints the corresponding fibonacci sequence number. For example, for the input of 3, it should print 2 since the third term in the fibonacci sequence is 2.
I am not sure how to do this so for my attempt, I used the formula found in this website. A Formula for the nth Fibonacci number
Here is the program so far. It doesn't produce the correct output.
Code:
#include <stdio.h>
#include "genlib.h"
#include "simpio.h"
#include "math.h"
[Code]....
Write a program to make a table for any input number and then continuesly ask to press y to print more table and if you press any key other than y then program must be terminate using while loop and do while loop. How to start or end with it.
View 2 Replies View Related im writing a program that asks the user to input a number 1-10 and will transform it into the roman numeral of that number but it seems that its not after the user inouts the number nothing will output
#include <iostream>
#include<iomanip>
using namespace std;
[Code]....
The problem that I am having is that , the program outputs numbers that are perfect numbers and im not sure where i can add a statement to make it so that if it isn't a perfect number it doesn't output...
#include<iostream>// allows user input/output
#include<conio.h>
#include<fstream>//data file / result file
#include<iomanip>
#include<cmath> // math function
#define in_file "data.txt"
#define out_file "result.txt"
[Code] ....
Im trying to create a program that has the user input a 5 digit number. If it's between 10000 & 99999, it will do one thing..(just saying 'yes' for now. Outside those numbers will prompt the user to input again. However, if the user inputs the exact digits 76087, it should display 'term'.
This current code is displaying 'term' whenever the user inputs the 5 digits.
Code:
#include <iostream>
using namespace std;
int main() {
int pin;
cout << "Welcome to Movie Food
Enter your 5-digit pin code: " ;
[code]....
So I need to write a program which tells the user if the number they input is prime or not. I have done so and included the code below. My problem is that I need to allow the user to input if they want to enter another number after the first one using y or n and I am having trouble figure it out.
#include <cstdlib>
#include <iostream>
using namespace std;
[Code].....
I seem to be having a logical error but can not find the sources.
#include <iostream>
using namespace std;
int main() {
int student = 0;
int adult = 0;
[Code] ....
I'm trying to write a C++ program that will allow a user to input a number from the keyboard. Then using a loop, that will perform 10 times, multiply the entered number by the loop counter. Print out the loop counter, the entered number and the product of the loop counter and the entered number. A one-time heading should be displayed before information is printed.
This kinda of what I have so far:
#include <iosteam>
using namespace std;
int main () {
Start
Declare: numScores, sum, score, avg, SENTINEL = 200
numScores = 0
[Code] ....
All the programs I have tried to make are not working?
I need to create a program that prints a certain number of asterisks based on user input. The user inputs 5 and I want my program to output "*****". How would I do this in C? I've tried printf("%#**", myvariable) but this does not work it only prints "*".
View 1 Replies View Relatedit will not run and im not sure why. I have a couple of errors, but I'm not sure why.
Here is my code.
//Reads input from user to determine different discounts by number of units sold
#include <iostream>
#include <string>
using namespace std;
int main() {
//Declaration and Initialization of variables
int quantity;
double discount,price = 99.00,totalCost;
[Code] ....
I need to write a code in c++ , to input decimal number and the output to be number in Scientific notation with 32 bits .
View 1 Replies View RelatedQ. WAP to find the next palindrome number larger than the input number.
for eg:-
Input=25
Output=33
The program is giving correct output for number with all digits '9';
why is it not giving output.
#include<iostream>
#include<string>
using namespace std;
int main() {
int len,flag=1,count=0,num,ind;
[code]....
I need to write a complete program using "While Loop" to calculate 1! to 12! using just "int" variables. Only from 1 to 12 and there are no other inputs.. This is my first time using While loop.
View 2 Replies View RelatedCode:
#include <stdio.h>
int find_next_prime(int num);
int is_prime(int num);
int main()
[Code]......
How would I go about counting the number of times a factorial has a specific prime number?
For example, 5! = (2^3)*(3^1)*(5^1), 6! = (2^4)*(3^2)*(5^1).
How would I begin to design my find_prime_count function in order to count how many times each occurs? My program is to read in a number between (2<=N<=100) from a text file and output the results exactly like above which I still have to figure out after, I'll assume I have to use fscanf.
The code works and comes out with a correct factorial up to 69! (But this is fine I only need it to work up to 60). I was wondering if this could be simplified or optimized in any way.
Code:
#include <stdio.h>
int main(){
int number[100]; /*Created array of size 100 */
int n=34; /*19931120 summed to make 34 */
int i;
[Code].....
calculate the factorial with function
The program should then calculate the factorial of the number n, where n!= n×(n −1)...× 2×1
the output like this:
Enter number: 4
Factorial of 4! = 24
Enter number: 6
Factorial of 6! = 720
Enter number: 3
Factorial of 3! = 6
Enter number: 0
Factorial of 0! = 1
Enter number: -5
Factorial of -5! = -1
Press any key to continue . ....