I need to write a complete program using "While Loop" to calculate 1! to 12! using just "int" variables. Only from 1 to 12 and there are no other inputs.. This is my first time using While loop.
View 2 Replies
int main() {
int x;
int y=1;
for(x=1 ; x<=12 ; x++ , y=y*x ) {
cout<<y<<'
';
}
}
This code give x! ( x factorial).
whenever ,in x<=12 , we change the 12 to any number n where n>=1 and n<=12
the code works and give the (x factorial)
for example 12!=479001600
the problem begins with the number 13.
when we put 13 like this x<=13 or for(x=1 ; x<=13 ; x++ , y=y*x )
the compiler gives a wrong result : it gives 1932053504 which is wrong because the true result is 6227020800
I have been working on a program to calculate the factorial of numbers. Part of my code is copied and modified from the FAQ about validating numbers in user input.
I have encountered a problem with the for loop that I am using near the end of my code. No matter what I do, it seems that my loop only does the multiplication of b = a*(a-1) and then prints. For example, inputting 5 will result in a print of 20, but the factorial is 120.
Code:
int main(void) {
char buf[BUFSIZ];
char *p;
long int a;
long int b;
long int i;
printf ("Enter a number to be factorialized: ");
[Code] ....
Code:
#include <stdio.h>
int find_next_prime(int num);
int is_prime(int num);
int main()
[Code]......
How would I go about counting the number of times a factorial has a specific prime number?
For example, 5! = (2^3)*(3^1)*(5^1), 6! = (2^4)*(3^2)*(5^1).
How would I begin to design my find_prime_count function in order to count how many times each occurs? My program is to read in a number between (2<=N<=100) from a text file and output the results exactly like above which I still have to figure out after, I'll assume I have to use fscanf.
The code works and comes out with a correct factorial up to 69! (But this is fine I only need it to work up to 60). I was wondering if this could be simplified or optimized in any way.
Code:
#include <stdio.h>
int main(){
int number[100]; /*Created array of size 100 */
int n=34; /*19931120 summed to make 34 */
int i;
[Code].....
calculate the factorial with function
The program should then calculate the factorial of the number n, where n!= n×(n −1)...× 2×1
the output like this:
Enter number: 4
Factorial of 4! = 24
Enter number: 6
Factorial of 6! = 720
Enter number: 3
Factorial of 3! = 6
Enter number: 0
Factorial of 0! = 1
Enter number: -5
Factorial of -5! = -1
Press any key to continue . ....
I put some checks in factorial program, I am confused how 27, 40 50 is coming in output and ans is 10.
#include<stdio.h>
int fact(int n) {
if(n==1) {
printf("hello1 %d
",n);
return 1;
[code].....
I have designed a code and still i dont get the desired output ....
#include <iostream>
using namespace std;
int fact(int,int);
int arr[200]={1};
int main() {
int n,t,len=0,i=0,j,a;
cin>>t;
[Code] ....
code of prime factorization. Example input:135 / The problem is I want to be an output of (3^3) (5^1) instead of 3,3,3,5.
here's the code:
#include <iostream>
#include <cstdlib>
#include <cmath>
using namespace std;
void get_divisors(int n);
[code]....
While running it gives the runtime error: "Extra parameter in call to factorial."
#include<iostream.h>
#include<conio.h>
int factorial(long int);
void main() {
clrscr();
long int a;
cout<<"This program displays the factorial of the number you enter."<<endl;
[Code] .....
double expression(int n, double x) {
double num=(pow((x),2*a));
double den=fact(n,a);
double sum=0;
for(int a=0; a>=0; a++)
sum=pow(x,n)*(num/den);
return sum;
}
I don't know why this isn't working. fact is a factorial function which I have tested and it works fine. But when I input, for example:
int main() {
cout<<expression(1,3)<<endl;
getch();
return 0;
}
it comes up with an error.
I'm trying to run a factorial program but I'm getting the error statement has not effect.
here's the code
#include <iostream>
using namespace std;
int main() {
int fac = 0;
int sum = 0;
[Code] ....
the error happened in the int main section
I wrote this code to find the factorial of any given function ., works fine but when i put it in a class... it gives me an error ::assignment of read only variable fact;
#include <iostream>
using namespace std;
const static int fact=1;
class My_Factorial {
public:
int x;
void Get_Number(){
cout<<"enter a number to find its factorial";
[Code] ....
I just want to practice in the language so i wrote this simple function that computes the factorial result of a certain number. The problem is that for all numbers > 20, the results are wrong ( < 20 all good).
I already learned that normal "long" type in c is more like 32 bit int and not 64 bit like a long type in java. so I used here a "long long" type.
why am I getting strange results above the number 20? isn't 64 bit enough to hold those numbers?
Code:
long long factorial(int n);
int main() {
long long result = factorial(20);
printf("%lld",result);
[code] ...
for 21 i get: -4249290049419214848
where the right result shoud be: 51,090,942,171,709,440,000
Write a C++ program that will input from the user a positive number n and find its factorial. Don’t forget to validate the input. The factorial of a positive integer n (denoted by n!) is defines as the product of the integers from 1 to n.
n! = 1* 2 * 3 * ... * (n - 1) * n
You should allow the user to continue working with your program for additional data sets.
Sample output:
Please enter a number: 5
5! = 120
Would you like to continue (Y/N)?Y
Please enter a number: 3
3! = 6
Would you like to continue (Y/N)?N
Good Bye!!
My code for what i think I'm doing is as follows:
#include <iostream>
using namespace std;
int main(){
int i=1;
int n;
[Code] ....
#include<iostream>
using namespace std;
int main() {
int a[9],x,f=1;
cout<<"Please enter an integer [0-10 only] : ";
[Code] ....
write a program that computes the factorial of a number and displays it. A factorial of a number (written N!) is defined as N * (N-1) * (N-2) * (N-3) ... *1 In other words, 5! = 5 * 4 * 3 * 2 * 1 = 120 and 3! = 3 * 2 * 1 + 6.
Example of output 15 is 1.30767e+012
Can't get it to display error when user enters a number lower than 2 or higher 60.
// Program to calculate factorial of a number
#include <iostream>
#include <iomanip>
[Code].....
I was given a question in my programming class to create a program to find the factorial of any number greater than zero and to use Gosper's formula to approximate it.
Code:
#include <stdio.h>
#include <math.h>
#define PI 3.14159265
double equation(int n);
int
[Code] ....
I started to learn programming through this site two weeks or so ago. I've got a book with exercices and so on, and one of them involves calculating e within a tolerance given by the user.
The formula for calculating e is the summation of 1+(1/i!), where i -> n.
So, here's the code and I'll explain the problem below:
Code:
#include <stdio.h>
int main()
{
float error;
float terme;
float sumatori = 0;
int cicle_euler = 1;
int factorial;
[Code]...
For some reason, when I set factorial to cicle_factorial, factorial remains 0, which I find puzzling; the program always halts when 1 + sumatori is 2.0 no matter what error is.
This must be a common problem and I suspect it has to do with some distinction between variables inside a loop and variables outside it, but as I lack technical vocabulary I can't seem to find anything on Google.
It is given an integer "p". I have to find a number "n" for which "n factorial" has "p" numbers of zero at the end. Here is the solution i thought, but i am not sure if it is a solution for this problem. Do i have to make a function to calculate the factorial and another function to get the zeros?
int p;
int count5=0;
int i;
int copy_i;
printf("Enter p: ");
scanf("%d",&p);
for(i=1; ;i++) {
[Code] .....
We are making a program--but every time we input a value for scanf, the following for loop does not work and the program quits without displaying the for loop's function. We are not getting any errors.
View 11 Replies View RelatedI have tried to submit this topic before but i didn't submit my whole code and it was removed. So here it is. All I am trying to do is load form2 from form1 then back to form1 from form2 for a certain number of times the get out of the loop. I am new to C-Sharp and it seems as though I cant seem to figure out a way to do this.
Here is form1 and form2 code. I have commented out a few things I have tried.
using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
[Code]....
Code:
#include <stdio.h>
#include<ctype.h>
void try5t(){
char choice;
int choiceint;
[Code] .....
Loop is repeated an additional time as shown in the screenshot:
Given a for loop:
int i;
for(i = 0; i < 1000; i++)
;
How many nanoseconds, or microseconds or milliseconds does it take for each iteration? And why do some use it as a timer mechanism?
I already made a nested for loop into a while loop (below this) and now I'm trying to make the outer for loop into a do while loop, but it's not working.
#include <iostream>
using namespace std;
int main () {
int len;
int j;
int i;
[Code]....
And I can't make this code do the same thing. It stops after one loop, instead of continuing to the end. Why won't the loops continue?
#include <iostream>
using namespace std;
int main(){
int len;
cout << "Enter a number: ";
[Code] ....
I need to convert the following while loop:
count = 1;
while (caloriesForItem != 0, count != numberOfItems )
{
cout<<"Enter the calories: ";
cin >> caloriesForItem;
totalCalories += caloriesForItem;
count++;
}
This is what I have come up with:
totalCalories += caloriesForItem;
for (count = 1; caloriesForItem != 0; count != numberOfItems)
{
cout<<"Enter the calories: ";
cin >> caloriesForItem;
count++;
cout << "Total calories eaten today = " << totalCalories << endl;
}
However the output is not the same?
