C++ :: How To Count Repeated Numbers In Array
Jan 30, 2015
So I already gave this a go and will post my code below. The question is about the last loop before the program cout's. i thought the count would keep track of the repeated numbers so i could display them but it does not. I italicized the loop i am referring to. or at least i tried to xD
#include <iostream>
#include <iomanip>
using namespace std;
int main() {
int inputs[30];
int numofloops;
int maxvalue = inputs[0];
[Code]...
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Jul 12, 2013
I am using this code that to check a set of values from a text file and show it on the output.
Code: void MatchNumber(int b) {
vector<Rect> rects;
ifstream theFile("CheckNumber.txt");
double x1,y1,x2,y2;
while(theFile >> x1 >> y1 >> x2 >> y2 ){
rects.push_back(Rect(x1,y1, x2,y2));
}
int num=0;
[code]....
I want to calculate how many times the common number is repeated . So I have used freq[num] in that function. But I am getting the output like this-
Code:
The common number is = 5
The 5 repeated = 1 times
The common number is = 6
The 6 repeated = 1 times
The common number is = 4
The 4 repeated = 1 times
The common number is = 5
The 5 repeated = 1 times
[code]....
So the freq[num] is only returning 1 instead of counting the total number of repeating which is wrong!! I would like to have somthing like this in my output -
Code:
The common number is = 5
The common number is = 6
The common number is = 4
The common number is = 5
The common number is = 5
The common number is = 8
The common number is = 9
The common number is = 6
The common number is = 6
[code]....
How can I do that?
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Jan 22, 2015
iam trying to count the same numbers in an array just once like
38
38
40
38
40
37
the output should be 2 since 38 is repeated and 40 too but for my code the output is 3 thats an example of how it should be in a nutshell i want same number to be counted just once in the whole array
and here's my code :
#include <iostream>
using namespace std;
int main(){
[Code].....
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Sep 26, 2013
I must count the number of occurrence of all numbers in array , i wrote a code but it does not work properly
#include <iostream>
int main (){
int i,n,tmp,counter=0;
std::cout<<"Enter the size of the array:"<<std::endl;
std::cin>>n;
int *Array=new int [n];
int *counterArray=new int [n];
[Code] .....
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Apr 18, 2014
Given the matrix MxN, check if there are repeated numbers.
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Jan 27, 2014
I found a card shuffling function on a long dead thread.
Code:
for (int x = 52; x > 0 ; x--)
{ y = rand() % x;
temp = deck[x];
deck[x] = deck[y];
deck[y] = temp; }
I do not understand how numbers are not repeated in the function. It seems like it would be possible to get 2 cards with the same number with the above function.
I also am getting incorrect numbers. It seems like I should only get numbers between 1 and 52 (which is what I want). However, I am getting the number 0, and some number between 1 and 52 will be missing, but I will have a total of 52 unique numbers.
I played around with using 51 instead of 52, x > 1, and changed to --x and none of those produced the desired results.
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Mar 23, 2014
Printing duplicate 2D array elements
if for 1D array
for (int i = 0; i<0; i++){
for (int j = i+1; j<0; i++)
{
if (arra[i] == arra[j]){
cout<<arra[i]<<endl
}
}
}
how would i do for 2D
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Aug 26, 2014
With out sorting and if the array size is changed and filled with different elements, mayb some that are all duplicates(in that case display message that says "No nonrepeated digits".
This seemed like a simple task but im failing to grasp some concept. if the array is 2,0,38,2,3,1,3 the first non repeated is 0.
nested loop is how i went. i feel like im going to far with the counters than need be. just need first non repeated. if n equals 2 an o equals 0. and it iterates comparing 0,38,2,3,1,3 to n which is 2. repCount will b 1. if repcount was 0 then n would be the first non repeated number. im trying to consolidate my if else statements so there are not so many. This program fails if the array gets bigger say 2,45,2,7,1,8,9,45,1,10 .....
for (n=0; n<sizeof(digits)/sizeof(int); n++) {
if(repCount<2) {
// nonRepCount=0;
for (o=n+1; o<sizeof(digits)/sizeof(int); o++)
[Code] .....
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Mar 20, 2014
I have generated a 10x10 integer matrix, by way of a 2 dimensional array, the elements are randomly generated and lie on 1 <= z <= 5. I am in need of an efficient method of setting all adjacent "duplicates" (repeating elements) of length 3 or greater to the integer six (6). The source for the brute method follows for clarity.
Code:
46 for(row=0;row<10;row++)
47 {
48 for(col=0;col<10;col++)
49 {
50 board[row][col]=rand()%4+1; //filling matrix here
[Code] .....
I know there must exist a much more elegant approach than listing out all permutations.
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Dec 16, 2014
4.1 Write a program that will count from 1 to 12 and print the count, and its square, for each count.
4.2 Write a program that counts from 1 to 12 and prints the count and its inversion to 5 decimal places for each count. This will require a floating point number.
4.3 Write a program that will count from 1 to 100 and print only those values between 32 and 39, one to a line. Use the incrementing operator for this program.
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Apr 28, 2013
I wrote a program which sends a starting and ending range to other processes and the processes calculate the prime numbers in that range and return the count of prime numbers to the head process, process 0. But this is not working properly at the moment. I realize I still have to split up the range based on how many processes I have...I still have not figured out how I want to set that up. I
Code:
#include <stdio.h>
#include <stdlib.h>
#include <mpi.h>
int isPrime(int num);
int main(int argc, char **argv){
}
[code]....
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Mar 7, 2013
I have loaded and 1d array from a .dat file, calculated the average of all the numbers. Now I need to count every number in the array that is below the average and cout that number. This is the method in the class I have so far:
int IntegerArray::countBelowAverage(int numBelowAvg) {
avg=IntegerArray::getAvg();
for(int ct=0; ct<avg; ++ct) {
numBelowAvg=ct;
}
return numBelowAvg;
}
My output from this is always 0 and I know that there are numbers below the avg.
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Sep 2, 2014
I have a upcoming C++ exam. I would like to write a program to convert INDIVIDUAL digits into words.
E.g 678 = six seven eight[/size][/b]
I have the following code:
//Program to print individual digits in words
#include<iostream>
using namespace std;
int main() {
int num;
cout << "Enter a number between 0 and 9999: ";
[Code] ....
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Jan 14, 2014
the text file looks like: one hello hi twenty-five billion fifty maths three thousand and two
output: count the number of text numbers: 4
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Dec 17, 2013
i have read a lot of about lists but i dont understand this. I know its something like dogs on leash where we have
dog1->dog2->dog3->....
and
Code:
struct DOG
{char* (name of a dog of first leash)
DOG* (next dog ) } I have written something like this but this doesnt work as i wanted Code: #include <iostream>
using namespace std;
struct line {
[Code]....
I wanted to make program where i can type XX numbers , then cout those numbers without changing the order, and my next exercise is to change order in this programme from end to start.
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Mar 10, 2013
I'm having trouble with how to find the count and sum of all numbers.
The file, called question1.txt, contains numbers:
1
2
3
4
5
0
0
0
-2
-2
Here's my code:
Code:
#include <stdio.h>
#include <stdlib.h>
int main (void)
{
FILE* spIn;
FILE* spOut; //for output file
int numIn;
[Code]...
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Jan 22, 2014
I wrote a code that counts numbers of words in a sentence, simply by counting spaces... but instead of showing a true number it shows a wrong number.
#include <iostream.h>
#include <conio.h>
int check(char eh[10000]) {
int he=0;
for (int i=0; i<=10000 ;i++) {
[Code] ....
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Sep 20, 2014
I'm trying to create a program that counts the amount of alphabetical characters, numbers, blanks and total amount of characters in a string a user gets to enter. The user also quits the program manually by pressing CTRL + D (in linux terminal).
These are the results I get from the code so far by typing in "hello cplusplus 123 c++" CTRL + D.
The string had:
Alphabetical characters...: 0
Numbers...................: 0
Blanks....................: 3
Total amount of characters: 20
So I can't seem to find a way to count the amount of alphabetical characters and numeric characters.
Here's my code:
#include <iostream>
#include <string>
#include <iomanip>
#include <cctype>
#include <sstream>
using namespace std;
int main() {
string tecken;
[Code] ....
The reason why I declared cctype is that I think I should use the isalpha, isdigit and isblank functions but how I am supposed to do that.
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Feb 16, 2013
I have a text file like below read.txt:
1.0 2.0 3.0 4.0
2.0 3.0 4.0 6
5.0 7 1.0 5.0
calc.cpp:
void main() {
FILE *fp;
fp=fopen("read.txt","r");
double *read_feature = new double*[3];
[Code] ....
I want to count all the numbers in my text file (read.txt). Read text file consist of floating and integer number. Answer for the above file would be integer=2 and float =10.
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Jan 17, 2015
i have a problem i cant find a way to count how many times a character occur in a character array the out put should be
a=2
b=1
but my output is
a=2
b=1
a=0
i cant find away to get rid of the other a letter i dont know what to do
#include <iostream>
using namespace std;
int main() {
char array[3] = {'a','b','a'};
char frequency[26] ={'a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z'};
[Code]...
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Dec 27, 2013
Arrays are by far the most fun to work with and I really need see if its possible to enable an array to count apples, pears, peaches, from a group of three each.
If any of the fruit groups were chosen how might an algorithm be put together to count how many were chosen from each group. But lets take into consideration that these fruit groups are not supposed to be randomly generated, instead they belong as an array with certain amount of chosen occurrences. To show how many fruits were chosen from each group example, 1 from group 1, 2 from group 2, 3 from group 3 the out put is the important part because it shows the group and the occurrence of that group. the algorithm should be able to display the group with an occurrence as well
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May 10, 2014
I have to count the letters from a text file into an array so the first spot is the number of A's second spot number of B's and so on then take the array and sort it in decending order how could i do this without loosing track of where the numbers go so if there are more b's than a's they switch but how will i know where each letter has moved in the array after it has been sorted?
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Nov 20, 2012
#include <iostream>
using namespace std;
int main() {
int h;
double A[10][10];
[Code] .....
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Mar 19, 2013
How can i count the total no of unique elements in an array? Like I have an array.
Code:
int array[]= { 2,1,4,0,3,3,0,0,1,2,1,1}
// As it has 0,1,2,3,4 as unique values so total no of unique values are=5
int unique =5;
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Feb 28, 2015
I need to calculate how often each letter appears in a text file from a function that is called from main() with an array of pointers to char and how many pointers there are in the array. The code i have so far is:
#include<stdio.h>
#include<string.h>
#include<ctype.h>
#include<stdlib.h>
[Code]....
I get no errors and it runs but it gives me the wrong output. I know my array is correct because when i print it in main() it is correct but each letter is incorrectly counted. When i give it the input .txt file of:
This is one line of a string
This is another
This is the third one
Wow heres another one
It counts a as 8
b as 1
c as 3
etc.
I have hand traced it and cant figure out why it isnt giving me correct values
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Aug 3, 2014
I'm currently on an exercise that specifies that I find any repeated words, "the the" for example, in a string, print the word that is repeated and how many times said word is repeated using a while loop that reads one word at a time and break statements when a repeated word is found. Having a bit of a falling out with iterators tonight and I'm not doing to well.
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