C :: Replace Repeated Elements Within 2D (10x10) Int Array
Mar 20, 2014
I have generated a 10x10 integer matrix, by way of a 2 dimensional array, the elements are randomly generated and lie on 1 <= z <= 5. I am in need of an efficient method of setting all adjacent "duplicates" (repeating elements) of length 3 or greater to the integer six (6). The source for the brute method follows for clarity.
Code:
46 for(row=0;row<10;row++)
47 {
48 for(col=0;col<10;col++)
49 {
50 board[row][col]=rand()%4+1; //filling matrix here
[Code] .....
I know there must exist a much more elegant approach than listing out all permutations.
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Mar 20, 2014
how to do this? ask the user to input entries of 10x10 array. sort each column into increasing order. print out the array with sorted columns?
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Nov 4, 2014
I have a text file, like that:
(A1*
*
*
*A1)
*
(AM-MNR*AM-MNR)
(V*V)
(C-A1*
*
*
*
C-A1)
Now, I would like to replace some elements, follow the rule:
-(A1* ---> B- A1
- characters "*" following is replace by I-A1
- *A1) ---> I- A1
The output like that:
B- A1
I- A1
I- A1
I- A1
*
B-AM-MNR
(V*V)
B-C-A1
I-C-A1
I-C-A1
I-C-A1
I-C-A1
How can I do now?
My text file have 220 663 lines and 858 995 characters (I used Linux commands : wc to count them. If I use array to store data, I think it's too large array. But if use fstream, I dont know to access each element in stream to compare and replace. I dont know How many labels such as: A1, C- A1, AM- MNR... which I have to replace.
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Mar 23, 2014
Printing duplicate 2D array elements
if for 1D array
for (int i = 0; i<0; i++){
for (int j = i+1; j<0; i++)
{
if (arra[i] == arra[j]){
cout<<arra[i]<<endl
}
}
}
how would i do for 2D
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Jan 30, 2015
So I already gave this a go and will post my code below. The question is about the last loop before the program cout's. i thought the count would keep track of the repeated numbers so i could display them but it does not. I italicized the loop i am referring to. or at least i tried to xD
#include <iostream>
#include <iomanip>
using namespace std;
int main() {
int inputs[30];
int numofloops;
int maxvalue = inputs[0];
[Code]...
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Aug 26, 2014
With out sorting and if the array size is changed and filled with different elements, mayb some that are all duplicates(in that case display message that says "No nonrepeated digits".
This seemed like a simple task but im failing to grasp some concept. if the array is 2,0,38,2,3,1,3 the first non repeated is 0.
nested loop is how i went. i feel like im going to far with the counters than need be. just need first non repeated. if n equals 2 an o equals 0. and it iterates comparing 0,38,2,3,1,3 to n which is 2. repCount will b 1. if repcount was 0 then n would be the first non repeated number. im trying to consolidate my if else statements so there are not so many. This program fails if the array gets bigger say 2,45,2,7,1,8,9,45,1,10 .....
for (n=0; n<sizeof(digits)/sizeof(int); n++) {
if(repCount<2) {
// nonRepCount=0;
for (o=n+1; o<sizeof(digits)/sizeof(int); o++)
[Code] .....
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Dec 8, 2014
I'm trying to find first non zero element in an array then replace the zero with nextCard. it just will not work.
void addToHand(int hand[], int cardToAdd) {
int i=0;
while (hand[i]!=0) {
i++;
} hand[i]=cardToAdd;
}
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Jan 10, 2015
Write a program using user-defined function which accepts an integer array and its size as arguments and assign the elements into a two dimensional array of integers in the following format: If the array is 1,2,3,4,5,6, the resultant 2D array is
1 2 3 4 5 6
1 2 3 4 5 0
1 2 3 4 0 0
1 2 3 0 0 0
1 2 0 0 0 0
1 0 0 0 0 0
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Jan 21, 2013
Write a function that takes an array and returns true if all the elements in the array are positive, otherwise, it returns false.
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Sep 27, 2013
I am having problem in writing the code for the problem "To assign the elements of 1-D integer array into 2-D array of integers such as if the array is 1,2,3,4,5,6 The resultant 2-D array should be like :
1 0 0 0 0 0
1 2 0 0 0 0
1 2 3 0 0 0
1 2 3 4 0 0
1 2 3 4 5 0
1 2 3 4 5 6
"
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Aug 13, 2014
I have just started learning C language, I have read that array name is the pointer to the first element of array.
So,technically both a and a[0] should have different memory address and a should hold address of a[0],
But when I declare an array and print the address:
int a[5]={2,4,6,8,10};
printf("The address of a and a[0] are &d and %d",&a,&a[0]);
Output is: The address of a and a[0] are 2358832 and 2358832
Why I am getting the same result, shouldn't I be getting different memory address for both a and a[0].
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Apr 5, 2013
I've a file that looks like this:
84484-37.96-Castor, Kathy
39050-69.68-Chandler, Ben
26183-70.84-Costello, Jerry
I have successfully read each element the id, grade and name into 3 separate array. Now i need to add a new student with an id and grade
How do i do this?
This is what I have.
int addStudent( int Iarray[], double dArray[], string sArray[], int newID,
double newGrade, string newName, int size ) {
char ready;
int index;
cout << endl;
cout << "Enter new student ID number : ";
[Code]...
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Oct 27, 2014
I have a question regarding the elements of an array. Suppose I have a 3 by 3 string array (char x[3][4] ) , and I initialize all the elements to x's , the array would then look like this :
xxx
xxx
xxx
I'm curious if there will be a value if I try to access and element outside the array. As I have to write a code to determine if I have reached the end of an array. The only way I can think of is to border the entire array with o's , making it look like this :
ooooo
oxxxo
oxxxo
oxxxo
ooooo
Is there any other way to do this?
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Jul 12, 2013
I am using this code that to check a set of values from a text file and show it on the output.
Code: void MatchNumber(int b) {
vector<Rect> rects;
ifstream theFile("CheckNumber.txt");
double x1,y1,x2,y2;
while(theFile >> x1 >> y1 >> x2 >> y2 ){
rects.push_back(Rect(x1,y1, x2,y2));
}
int num=0;
[code]....
I want to calculate how many times the common number is repeated . So I have used freq[num] in that function. But I am getting the output like this-
Code:
The common number is = 5
The 5 repeated = 1 times
The common number is = 6
The 6 repeated = 1 times
The common number is = 4
The 4 repeated = 1 times
The common number is = 5
The 5 repeated = 1 times
[code]....
So the freq[num] is only returning 1 instead of counting the total number of repeating which is wrong!! I would like to have somthing like this in my output -
Code:
The common number is = 5
The common number is = 6
The common number is = 4
The common number is = 5
The common number is = 5
The common number is = 8
The common number is = 9
The common number is = 6
The common number is = 6
[code]....
How can I do that?
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Aug 3, 2014
I'm currently on an exercise that specifies that I find any repeated words, "the the" for example, in a string, print the word that is repeated and how many times said word is repeated using a while loop that reads one word at a time and break statements when a repeated word is found. Having a bit of a falling out with iterators tonight and I'm not doing to well.
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Oct 19, 2013
this code :
#include <cstdlib>
#include <iostream>
#define TRUE 1
#define FALSE 0
using namespace std;
typedef int Bool;
[Code] ....
Gives repeated digits in an integer but only in one condition : Only if the repeated digit is the result of n%10 where n is the integer the user writes. If the repeated digit is not the result of n%10 , then the compiler gives a wrong result.
so the question is : how to make this code gives the repeated digit in an integer (regardless the fact that the repeated digit is the result of n%10 or not and especially with making the minimum of changes on the code)????????? ?????
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Apr 18, 2014
Given the matrix MxN, check if there are repeated numbers.
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Jul 12, 2013
This function check a set of values from a text file and show it on the output.
void MatchNumber(int b){
vector<Rect> rects;
ifstream theFile("CheckNumber.txt");
[Code]......
I want to calculate how many times the number is repeated. So I have used freq[num] in that function. But I am getting the output like this-
The common number is = 5
The 5 repeated = 1 times
The common number is = 6
The 6 repeated = 1 times
The common number is = 4
The 4 repeated = 1 times
The common number is = 5
The 5 repeated = 1 times
The common number is = 5
The 5 repeated = 1 times
The common number is = 8
The 8 repeated = 1 times
The common number is = 9
The 9 repeated = 1 times
The common number is = 6
The 6 repeated = 1 times
The common number is = 6
The 6 repeated = 1 times
The common number is = 8
The 8 repeated = 1 times
So the value of freq[num] only shows 1 instead of calculating the number of repetition.
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Feb 10, 2014
I have to write a code that will read in n amount of names and the names. Then it will tell me if the first name entered has been repeated or not.
This is my input:
5 Bush Reagan Lincoln Bush Obama
This is my output:
First name in list is not repeated.
First name in list is not repeated.
First name in list is repeated.
First name in list is not repeated.
I would like to just give one answer; if it is repeated then the output should simply be "First name in list is repeated."
If the answer is that it was not repeated, I would like the output to say once "First name in list is not repeated."
// lastnames.c
#include <stdlib.h>
#include <stdio.h>
int main(void) {
char FIRST[25];
[code]....
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Oct 19, 2013
Trying to concatenate the 1st and 2nd element from an array of chars. Then this to be used as a hex value.
so for example
specs[0]='f'
specs[1]='4'
concatenate_value=0xf4
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Apr 15, 2014
Write the definition of a function reverse , whose first parameter is an array of integers and whose second parameter is the number of elements in thearray . The function reverses the elements of the array . The function does not return a value .
Code:
void reverse(int a[], int num) {
for ( int i=0; i <= num/2 ; i++){
int temp = a[i];
a[i] = a[num-i-1];
a[num-i-1] = temp;
} }
This is supposed to be the answer but I'm not quite sure why this is. I understand everything up until the actual loop. For one, shouldn't "int i" be declared outside the loop (I thought perhaps this was an error in the solutions)?
The main thing that I do not understand is the conditional statement.
Code: i<=num/2;
I don't understand why the "num/2" is necessary here. Also I can't really remember but is there a command that actually reverses an array?
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Sep 18, 2013
I'm trying to set all the elements of my array to 0 but nothing seems to be working.
.h
#ifndef ServerGroup_h
#define ServerGroup_h
class ServerGroup {
public:
ServerGroup(const int&);
[Code] .....
I want to set each element of the array in servers to 0 based on what is passed into size by numArray.
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Apr 11, 2014
I am trying to write a program that reverses the elements of an array by using an function 'myreverse'. The function should reverse original array and return nothing.
In my program, the function 'myreverse' is not getting invoked and the original array is being displayed as it is.
#include <iostream>
using namespace std;
void myreverse(int arr[],int n) {
int *p=&arr[n-1];
int temp;
for(int i=0;i<n;++i)
[Code] .....
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Sep 28, 2013
I'm having trouble getting my array to add its values together. I have a similar program running fine with the exact same equation. I am not so naive as to believe that this means it should run with every program but I'm at a loss as to what to do.
#include <iostream>
#include <iomanip>
using namespace std;
[Code].....
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Dec 20, 2013
im trying to get my array to display 5,1,2,3,4 from the original 1,2,3,4,5.
void values::movevalues()
{
cout << "postcondition
";
[Code]....
something in this part is making it go wrong, it displayes the original array fine but when it tries to shift it it goes haywire. EDIT: also how would i add elements onto the array?
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Dec 11, 2013
im trying to write a program that finds the max in an array and divedes it by two than oututs a modfied list with all the elements greater than the max/2.
I got the first part but just not sure how to find the elements greater than the max/2 and output them correctly into the modfied list.
#include <iostream>
#include <iomanip>
using namespace std;
[Code].....
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