C++ :: Count The Repeated Numbers?
Jul 12, 2013
I am using this code that to check a set of values from a text file and show it on the output.
Code: void MatchNumber(int b) {
vector<Rect> rects;
ifstream theFile("CheckNumber.txt");
double x1,y1,x2,y2;
while(theFile >> x1 >> y1 >> x2 >> y2 ){
rects.push_back(Rect(x1,y1, x2,y2));
}
int num=0;
[code]....
I want to calculate how many times the common number is repeated . So I have used freq[num] in that function. But I am getting the output like this-
Code:
The common number is = 5
The 5 repeated = 1 times
The common number is = 6
The 6 repeated = 1 times
The common number is = 4
The 4 repeated = 1 times
The common number is = 5
The 5 repeated = 1 times
[code]....
So the freq[num] is only returning 1 instead of counting the total number of repeating which is wrong!! I would like to have somthing like this in my output -
Code:
The common number is = 5
The common number is = 6
The common number is = 4
The common number is = 5
The common number is = 5
The common number is = 8
The common number is = 9
The common number is = 6
The common number is = 6
[code]....
How can I do that?
View 3 Replies
ADVERTISEMENT
Jan 30, 2015
So I already gave this a go and will post my code below. The question is about the last loop before the program cout's. i thought the count would keep track of the repeated numbers so i could display them but it does not. I italicized the loop i am referring to. or at least i tried to xD
#include <iostream>
#include <iomanip>
using namespace std;
int main() {
int inputs[30];
int numofloops;
int maxvalue = inputs[0];
[Code]...
View 1 Replies
View Related
Apr 18, 2014
Given the matrix MxN, check if there are repeated numbers.
View 8 Replies
View Related
Jan 27, 2014
I found a card shuffling function on a long dead thread.
Code:
for (int x = 52; x > 0 ; x--)
{ y = rand() % x;
temp = deck[x];
deck[x] = deck[y];
deck[y] = temp; }
I do not understand how numbers are not repeated in the function. It seems like it would be possible to get 2 cards with the same number with the above function.
I also am getting incorrect numbers. It seems like I should only get numbers between 1 and 52 (which is what I want). However, I am getting the number 0, and some number between 1 and 52 will be missing, but I will have a total of 52 unique numbers.
I played around with using 51 instead of 52, x > 1, and changed to --x and none of those produced the desired results.
View 5 Replies
View Related
Dec 16, 2014
4.1 Write a program that will count from 1 to 12 and print the count, and its square, for each count.
4.2 Write a program that counts from 1 to 12 and prints the count and its inversion to 5 decimal places for each count. This will require a floating point number.
4.3 Write a program that will count from 1 to 100 and print only those values between 32 and 39, one to a line. Use the incrementing operator for this program.
View 2 Replies
View Related
Apr 28, 2013
I wrote a program which sends a starting and ending range to other processes and the processes calculate the prime numbers in that range and return the count of prime numbers to the head process, process 0. But this is not working properly at the moment. I realize I still have to split up the range based on how many processes I have...I still have not figured out how I want to set that up. I
Code:
#include <stdio.h>
#include <stdlib.h>
#include <mpi.h>
int isPrime(int num);
int main(int argc, char **argv){
}
[code]....
View 7 Replies
View Related
Jan 22, 2015
iam trying to count the same numbers in an array just once like
38
38
40
38
40
37
the output should be 2 since 38 is repeated and 40 too but for my code the output is 3 thats an example of how it should be in a nutshell i want same number to be counted just once in the whole array
and here's my code :
#include <iostream>
using namespace std;
int main(){
[Code].....
View 11 Replies
View Related
Mar 7, 2013
I have loaded and 1d array from a .dat file, calculated the average of all the numbers. Now I need to count every number in the array that is below the average and cout that number. This is the method in the class I have so far:
int IntegerArray::countBelowAverage(int numBelowAvg) {
avg=IntegerArray::getAvg();
for(int ct=0; ct<avg; ++ct) {
numBelowAvg=ct;
}
return numBelowAvg;
}
My output from this is always 0 and I know that there are numbers below the avg.
View 2 Replies
View Related
Sep 26, 2013
I must count the number of occurrence of all numbers in array , i wrote a code but it does not work properly
#include <iostream>
int main (){
int i,n,tmp,counter=0;
std::cout<<"Enter the size of the array:"<<std::endl;
std::cin>>n;
int *Array=new int [n];
int *counterArray=new int [n];
[Code] .....
View 2 Replies
View Related
Sep 2, 2014
I have a upcoming C++ exam. I would like to write a program to convert INDIVIDUAL digits into words.
E.g 678 = six seven eight[/size][/b]
I have the following code:
//Program to print individual digits in words
#include<iostream>
using namespace std;
int main() {
int num;
cout << "Enter a number between 0 and 9999: ";
[Code] ....
View 7 Replies
View Related
Jan 14, 2014
the text file looks like: one hello hi twenty-five billion fifty maths three thousand and two
output: count the number of text numbers: 4
View 1 Replies
View Related
Dec 17, 2013
i have read a lot of about lists but i dont understand this. I know its something like dogs on leash where we have
dog1->dog2->dog3->....
and
Code:
struct DOG
{char* (name of a dog of first leash)
DOG* (next dog ) } I have written something like this but this doesnt work as i wanted Code: #include <iostream>
using namespace std;
struct line {
[Code]....
I wanted to make program where i can type XX numbers , then cout those numbers without changing the order, and my next exercise is to change order in this programme from end to start.
View 7 Replies
View Related
Mar 10, 2013
I'm having trouble with how to find the count and sum of all numbers.
The file, called question1.txt, contains numbers:
1
2
3
4
5
0
0
0
-2
-2
Here's my code:
Code:
#include <stdio.h>
#include <stdlib.h>
int main (void)
{
FILE* spIn;
FILE* spOut; //for output file
int numIn;
[Code]...
View 1 Replies
View Related
Jan 22, 2014
I wrote a code that counts numbers of words in a sentence, simply by counting spaces... but instead of showing a true number it shows a wrong number.
#include <iostream.h>
#include <conio.h>
int check(char eh[10000]) {
int he=0;
for (int i=0; i<=10000 ;i++) {
[Code] ....
View 8 Replies
View Related
Sep 20, 2014
I'm trying to create a program that counts the amount of alphabetical characters, numbers, blanks and total amount of characters in a string a user gets to enter. The user also quits the program manually by pressing CTRL + D (in linux terminal).
These are the results I get from the code so far by typing in "hello cplusplus 123 c++" CTRL + D.
The string had:
Alphabetical characters...: 0
Numbers...................: 0
Blanks....................: 3
Total amount of characters: 20
So I can't seem to find a way to count the amount of alphabetical characters and numeric characters.
Here's my code:
#include <iostream>
#include <string>
#include <iomanip>
#include <cctype>
#include <sstream>
using namespace std;
int main() {
string tecken;
[Code] ....
The reason why I declared cctype is that I think I should use the isalpha, isdigit and isblank functions but how I am supposed to do that.
View 1 Replies
View Related
Feb 16, 2013
I have a text file like below read.txt:
1.0 2.0 3.0 4.0
2.0 3.0 4.0 6
5.0 7 1.0 5.0
calc.cpp:
void main() {
FILE *fp;
fp=fopen("read.txt","r");
double *read_feature = new double*[3];
[Code] ....
I want to count all the numbers in my text file (read.txt). Read text file consist of floating and integer number. Answer for the above file would be integer=2 and float =10.
View 3 Replies
View Related
Aug 3, 2014
I'm currently on an exercise that specifies that I find any repeated words, "the the" for example, in a string, print the word that is repeated and how many times said word is repeated using a while loop that reads one word at a time and break statements when a repeated word is found. Having a bit of a falling out with iterators tonight and I'm not doing to well.
View 7 Replies
View Related
Oct 19, 2013
this code :
#include <cstdlib>
#include <iostream>
#define TRUE 1
#define FALSE 0
using namespace std;
typedef int Bool;
[Code] ....
Gives repeated digits in an integer but only in one condition : Only if the repeated digit is the result of n%10 where n is the integer the user writes. If the repeated digit is not the result of n%10 , then the compiler gives a wrong result.
so the question is : how to make this code gives the repeated digit in an integer (regardless the fact that the repeated digit is the result of n%10 or not and especially with making the minimum of changes on the code)????????? ?????
View 3 Replies
View Related
Mar 23, 2014
Printing duplicate 2D array elements
if for 1D array
for (int i = 0; i<0; i++){
for (int j = i+1; j<0; i++)
{
if (arra[i] == arra[j]){
cout<<arra[i]<<endl
}
}
}
how would i do for 2D
View 5 Replies
View Related
Jul 12, 2013
This function check a set of values from a text file and show it on the output.
void MatchNumber(int b){
vector<Rect> rects;
ifstream theFile("CheckNumber.txt");
[Code]......
I want to calculate how many times the number is repeated. So I have used freq[num] in that function. But I am getting the output like this-
The common number is = 5
The 5 repeated = 1 times
The common number is = 6
The 6 repeated = 1 times
The common number is = 4
The 4 repeated = 1 times
The common number is = 5
The 5 repeated = 1 times
The common number is = 5
The 5 repeated = 1 times
The common number is = 8
The 8 repeated = 1 times
The common number is = 9
The 9 repeated = 1 times
The common number is = 6
The 6 repeated = 1 times
The common number is = 6
The 6 repeated = 1 times
The common number is = 8
The 8 repeated = 1 times
So the value of freq[num] only shows 1 instead of calculating the number of repetition.
View 3 Replies
View Related
Feb 10, 2014
I have to write a code that will read in n amount of names and the names. Then it will tell me if the first name entered has been repeated or not.
This is my input:
5 Bush Reagan Lincoln Bush Obama
This is my output:
First name in list is not repeated.
First name in list is not repeated.
First name in list is repeated.
First name in list is not repeated.
I would like to just give one answer; if it is repeated then the output should simply be "First name in list is repeated."
If the answer is that it was not repeated, I would like the output to say once "First name in list is not repeated."
// lastnames.c
#include <stdlib.h>
#include <stdio.h>
int main(void) {
char FIRST[25];
[code]....
View 2 Replies
View Related
Mar 6, 2015
In the C++ book Programming: Principles and Practice Using C++, there's an example code like this for detecting repeated words:
Code:
#include "std_lib_facilities.h"
int main() {
int number_of_words = 0;
string previous = " "; // previous word; initialized to "not a word"
string current; // current word
while (cin >> current) // read a stream of words
[Code].....
The header file in there is sort of like a set of training-wheels for students who are complete beginners to the language; the function keep_window_open() is defined in there and it does just that on Windows systems where the output window closes too fast (in the case of the function, it's just like cin.ignore(), except it waits for you enter a character, like 'j', before it exits); programs on my Windows laptop work fine on Code::Blocks, but when I create a .exe file for them and double-click that file, it does actually close too quickly for me to be able to see the output (if it's a program like the generic "Hello World!" program that just outputs text to the screen and then exits - so all I see is the output window just flash-by really fast in those cases).
Anyway, as for the problem I'm having with the code: there are no error and compile- or link-time, but it does behave strangely at runtime, where the part inside the curly-braces of the while-loop doesn't execute at all.
View 3 Replies
View Related
Aug 26, 2014
I am working on a problem for the CS50 online course through the Harvard web site. I am trying to re-size a bmp image. They gave us a small program that copies a bmp image and we are to modify it to re-size the image. Here is the page [URL]..... Any way I am trying to move the file position indicator backwards so I can read the same line from the input file. So I can resize the file vertically I have the image resized horizontally but it keeps over writing the same lines vertically.
/**
* bmp.h
*
* Computer Science 50
* Problem Set 5
[Code]...
View 4 Replies
View Related
Aug 26, 2014
With out sorting and if the array size is changed and filled with different elements, mayb some that are all duplicates(in that case display message that says "No nonrepeated digits".
This seemed like a simple task but im failing to grasp some concept. if the array is 2,0,38,2,3,1,3 the first non repeated is 0.
nested loop is how i went. i feel like im going to far with the counters than need be. just need first non repeated. if n equals 2 an o equals 0. and it iterates comparing 0,38,2,3,1,3 to n which is 2. repCount will b 1. if repcount was 0 then n would be the first non repeated number. im trying to consolidate my if else statements so there are not so many. This program fails if the array gets bigger say 2,45,2,7,1,8,9,45,1,10 .....
for (n=0; n<sizeof(digits)/sizeof(int); n++) {
if(repCount<2) {
// nonRepCount=0;
for (o=n+1; o<sizeof(digits)/sizeof(int); o++)
[Code] .....
View 1 Replies
View Related
Mar 20, 2014
I have generated a 10x10 integer matrix, by way of a 2 dimensional array, the elements are randomly generated and lie on 1 <= z <= 5. I am in need of an efficient method of setting all adjacent "duplicates" (repeating elements) of length 3 or greater to the integer six (6). The source for the brute method follows for clarity.
Code:
46 for(row=0;row<10;row++)
47 {
48 for(col=0;col<10;col++)
49 {
50 board[row][col]=rand()%4+1; //filling matrix here
[Code] .....
I know there must exist a much more elegant approach than listing out all permutations.
View 1 Replies
View Related
Sep 23, 2013
Read in n, then n lastnames, and check to see if the first in the list is ever repeated again.Here's what I have so far:
Code:
#include <stdio.h>
#include <stdlib.h>
int strcmp(char *w1, char *w2);
int main() {
int j, n;
char string1[30], string2[30];
}
[code]....
I see the problem is that it lies within n amount of string that I am not going through every string to compare to the first one.How will do compare every string to the first one?
Current output:
3
alex
alex
alex
Not repeated
3
alex
ash
peter
Not repeated
View 2 Replies
View Related
