I must count the number of occurrence of all numbers in array , i wrote a code but it does not work properly
#include <iostream>
int main (){
int i,n,tmp,counter=0;
std::cout<<"Enter the size of the array:"<<std::endl;
std::cin>>n;
int *Array=new int [n];
int *counterArray=new int [n];
[Code] .....
i have a problem i cant find a way to count how many times a character occur in a character array the out put should be
a=2
b=1
but my output is
a=2
b=1
a=0
i cant find away to get rid of the other a letter i dont know what to do
#include <iostream>
using namespace std;
int main() {
char array[3] = {'a','b','a'};
char frequency[26] ={'a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z'};
[Code]...
My C programming class wants us to write a program to read integers into an array, sort the numbers and print out the occurrence of each number. I've tried everything that I can think of but the core dump is still occurring.
void countValues ( FILE *inf, int list[], int size ); /* Function prototypes. */
void printFrequencies( const int list[], int size );
int main (void) {
int status = EXIT_SUCCESS; /* defaulting status to success. */
FILE *inf = fopen( "numbers.txt", "r" ); /* input data file */
[Code] .....
Here is what i have so far:
#include<fstream>
#include<iostream>
#include<string>
[Code].....
I also need to do a loop that scan the count array and check if the element is bigger than the previous one.
iam trying to count the same numbers in an array just once like
38
38
40
38
40
37
the output should be 2 since 38 is repeated and 40 too but for my code the output is 3 thats an example of how it should be in a nutshell i want same number to be counted just once in the whole array
and here's my code :
#include <iostream>
using namespace std;
int main(){
[Code].....
So I already gave this a go and will post my code below. The question is about the last loop before the program cout's. i thought the count would keep track of the repeated numbers so i could display them but it does not. I italicized the loop i am referring to. or at least i tried to xD
#include <iostream>
#include <iomanip>
using namespace std;
int main() {
int inputs[30];
int numofloops;
int maxvalue = inputs[0];
[Code]...
I have
#define LessSymbol -1
#define MoreSymbol 1
#define NeitherSymbol 0
#define MAX_COLS 20
#define MAX_ROWS 20
#define MAX_CHAR 3
char averageMap[MAX_ROWS][MAX_COLS];
char rowCount[MAX_ROWS][MAX_CHAR];
char colCount[MAX_COLS][MAX_CHAR];
I have other stuff in the code, but basicly, at this stage i have a map of 1's,-1's and 0's in a 20 x 20 map. I just want to count the occurrences of each and basicly tally them in the 3 colums/rows at the end of the bloc. so far ive tried many different if statements, here is what i tried last.
for(row = 0; row < MAX_ROWS; row++){
rowCount[row][0]=0;
rowCount[row][1]=0;
rowCount[row][2]=0;
} for(col = 0; col < MAX_COLS; col++){
[Code] ....
Its outputting 20 as a result for each row. Its like its counting the symbol no matter what it is.
4.1 Write a program that will count from 1 to 12 and print the count, and its square, for each count.
4.2 Write a program that counts from 1 to 12 and prints the count and its inversion to 5 decimal places for each count. This will require a floating point number.
4.3 Write a program that will count from 1 to 100 and print only those values between 32 and 39, one to a line. Use the incrementing operator for this program.
I wrote a program which sends a starting and ending range to other processes and the processes calculate the prime numbers in that range and return the count of prime numbers to the head process, process 0. But this is not working properly at the moment. I realize I still have to split up the range based on how many processes I have...I still have not figured out how I want to set that up. I
Code:
#include <stdio.h>
#include <stdlib.h>
#include <mpi.h>
int isPrime(int num);
int main(int argc, char **argv){
}
[code]....
I am using this code that to check a set of values from a text file and show it on the output.
Code: void MatchNumber(int b) {
vector<Rect> rects;
ifstream theFile("CheckNumber.txt");
double x1,y1,x2,y2;
while(theFile >> x1 >> y1 >> x2 >> y2 ){
rects.push_back(Rect(x1,y1, x2,y2));
}
int num=0;
[code]....
I want to calculate how many times the common number is repeated . So I have used freq[num] in that function. But I am getting the output like this-
Code:
The common number is = 5
The 5 repeated = 1 times
The common number is = 6
The 6 repeated = 1 times
The common number is = 4
The 4 repeated = 1 times
The common number is = 5
The 5 repeated = 1 times
[code]....
So the freq[num] is only returning 1 instead of counting the total number of repeating which is wrong!! I would like to have somthing like this in my output -
Code:
The common number is = 5
The common number is = 6
The common number is = 4
The common number is = 5
The common number is = 5
The common number is = 8
The common number is = 9
The common number is = 6
The common number is = 6
[code]....
How can I do that?
I have loaded and 1d array from a .dat file, calculated the average of all the numbers. Now I need to count every number in the array that is below the average and cout that number. This is the method in the class I have so far:
int IntegerArray::countBelowAverage(int numBelowAvg) {
avg=IntegerArray::getAvg();
for(int ct=0; ct<avg; ++ct) {
numBelowAvg=ct;
}
return numBelowAvg;
}
My output from this is always 0 and I know that there are numbers below the avg.
I have a upcoming C++ exam. I would like to write a program to convert INDIVIDUAL digits into words.
E.g 678 = six seven eight[/size][/b]
I have the following code:
//Program to print individual digits in words
#include<iostream>
using namespace std;
int main() {
int num;
cout << "Enter a number between 0 and 9999: ";
[Code] ....
the text file looks like: one hello hi twenty-five billion fifty maths three thousand and two
output: count the number of text numbers: 4
i have read a lot of about lists but i dont understand this. I know its something like dogs on leash where we have
dog1->dog2->dog3->....
and
Code:
struct DOG
{char* (name of a dog of first leash)
DOG* (next dog ) } I have written something like this but this doesnt work as i wanted Code: #include <iostream>
using namespace std;
struct line {
[Code]....
I wanted to make program where i can type XX numbers , then cout those numbers without changing the order, and my next exercise is to change order in this programme from end to start.
I'm having trouble with how to find the count and sum of all numbers.
The file, called question1.txt, contains numbers:
1
2
3
4
5
0
0
0
-2
-2
Here's my code:
Code:
#include <stdio.h>
#include <stdlib.h>
int main (void)
{
FILE* spIn;
FILE* spOut; //for output file
int numIn;
[Code]...
I wrote a code that counts numbers of words in a sentence, simply by counting spaces... but instead of showing a true number it shows a wrong number.
#include <iostream.h>
#include <conio.h>
int check(char eh[10000]) {
int he=0;
for (int i=0; i<=10000 ;i++) {
[Code] ....
I'm trying to create a program that counts the amount of alphabetical characters, numbers, blanks and total amount of characters in a string a user gets to enter. The user also quits the program manually by pressing CTRL + D (in linux terminal).
These are the results I get from the code so far by typing in "hello cplusplus 123 c++" CTRL + D.
The string had:
Alphabetical characters...: 0
Numbers...................: 0
Blanks....................: 3
Total amount of characters: 20
So I can't seem to find a way to count the amount of alphabetical characters and numeric characters.
Here's my code:
#include <iostream>
#include <string>
#include <iomanip>
#include <cctype>
#include <sstream>
using namespace std;
int main() {
string tecken;
[Code] ....
The reason why I declared cctype is that I think I should use the isalpha, isdigit and isblank functions but how I am supposed to do that.
I have a text file like below read.txt:
1.0 2.0 3.0 4.0
2.0 3.0 4.0 6
5.0 7 1.0 5.0
calc.cpp:
void main() {
FILE *fp;
fp=fopen("read.txt","r");
double *read_feature = new double*[3];
[Code] ....
I want to count all the numbers in my text file (read.txt). Read text file consist of floating and integer number. Answer for the above file would be integer=2 and float =10.
Arrays are by far the most fun to work with and I really need see if its possible to enable an array to count apples, pears, peaches, from a group of three each.
If any of the fruit groups were chosen how might an algorithm be put together to count how many were chosen from each group. But lets take into consideration that these fruit groups are not supposed to be randomly generated, instead they belong as an array with certain amount of chosen occurrences. To show how many fruits were chosen from each group example, 1 from group 1, 2 from group 2, 3 from group 3 the out put is the important part because it shows the group and the occurrence of that group. the algorithm should be able to display the group with an occurrence as well
I have to count the letters from a text file into an array so the first spot is the number of A's second spot number of B's and so on then take the array and sort it in decending order how could i do this without loosing track of where the numbers go so if there are more b's than a's they switch but how will i know where each letter has moved in the array after it has been sorted?
View 1 Replies View Related#include <iostream>
using namespace std;
int main() {
int h;
double A[10][10];
[Code] .....
How can i count the total no of unique elements in an array? Like I have an array.
Code:
int array[]= { 2,1,4,0,3,3,0,0,1,2,1,1}
// As it has 0,1,2,3,4 as unique values so total no of unique values are=5
int unique =5;
I need to calculate how often each letter appears in a text file from a function that is called from main() with an array of pointers to char and how many pointers there are in the array. The code i have so far is:
#include<stdio.h>
#include<string.h>
#include<ctype.h>
#include<stdlib.h>
[Code]....
I get no errors and it runs but it gives me the wrong output. I know my array is correct because when i print it in main() it is correct but each letter is incorrectly counted. When i give it the input .txt file of:
This is one line of a string
This is another
This is the third one
Wow heres another one
It counts a as 8
b as 1
c as 3
etc.
I have hand traced it and cant figure out why it isnt giving me correct values
I am trying to write a function, and meet some issues. Why am I keep getting NULL error for my resultant string? Is my code anywhere giving me such an error?
View 6 Replies View Relatedi`m currently racking my brains out over this issue. How do i go about the x as the first occurrence of the letter?
lets say helxo , x is the 2nd occurrence of l. I will want to change back x into l
i have replaced it with x in the earlier step with this code...
string everySecondChar(const string &s,char source,char distance)
{
string t(s);
for(std::string::size_type even =0,pos=t.find(source,0);pos!=std::string::npos;pos=t.find(source,++pos))
{
[Code]....
i would like to reverse the process now, letting x becoming l again!
Supposed i have a word hammer.
how am i suppose to search for the 2nd occurrence of the letter and then replace it with x?
example hammer will become hamxer
I thought about using replace for it, however i`m lost on how to find 2 occurrences of the same letter in the word.
string formatEncrypt(string message) {
int msgLength=message.length();
for(int i=0;i<msgLength;i++) {
if(message[i] == 'j' {
message[i]='i';
[Code] .....
at line 31 i tried to put a z into the alphabet that occurs twice.
this is what i have done so far
example: hello world
It will turn out as helzlo world
However i want to make the output appear as helzo world