C :: Locates Last Occurrence Of Ch In String
Mar 16, 2014I am trying to write a function, and meet some issues. Why am I keep getting NULL error for my resultant string? Is my code anywhere giving me such an error?
View 6 RepliesI am trying to write a function, and meet some issues. Why am I keep getting NULL error for my resultant string? Is my code anywhere giving me such an error?
View 6 Replieshow to recognize the occurrences of different alphabets in a string and print the occurrences of each alphabet in string..
View 1 Replies View RelatedI am trying to form unique string from other string which is having multiple presence of same word as,
string testA = "one
two
three
four
one
seven wo";
now new string should contain single occurrence of words "one" and "two" so that new string will look like,
string testB = "one
two
three
four
seven"
i`m currently racking my brains out over this issue. How do i go about the x as the first occurrence of the letter?
lets say helxo , x is the 2nd occurrence of l. I will want to change back x into l
i have replaced it with x in the earlier step with this code...
string everySecondChar(const string &s,char source,char distance)
{
string t(s);
for(std::string::size_type even =0,pos=t.find(source,0);pos!=std::string::npos;pos=t.find(source,++pos))
{
[Code]....
i would like to reverse the process now, letting x becoming l again!
Supposed i have a word hammer.
how am i suppose to search for the 2nd occurrence of the letter and then replace it with x?
example hammer will become hamxer
I thought about using replace for it, however i`m lost on how to find 2 occurrences of the same letter in the word.
string formatEncrypt(string message) {
int msgLength=message.length();
for(int i=0;i<msgLength;i++) {
if(message[i] == 'j' {
message[i]='i';
[Code] .....
at line 31 i tried to put a z into the alphabet that occurs twice.
this is what i have done so far
example: hello world
It will turn out as helzlo world
However i want to make the output appear as helzo world
counting the occurrence of a number in my program.
Here's My Code:
void sort(int num[], int& count)
{
//cout << " Using Sort!";
for(int i =0; i <= count; i++)
[Code].....
How Can I continuously call the Count(); Function again after the first number?
what compiler that change all variable in one occurrence?
View 5 Replies View Relatedit's not my primary language, so my code variables are in my language.
Code:
FILE *eng;
eng = fopen("eng.txt", "r");
if(eng == NULL){
[Code]....
fclose(eng); It's a piece of my code. Some explanation: From file, where is full of words under selves. I cut it on word and from word i'm printing:
1) word
2) how many letters in the word
3) word backwards and
4) viz. problem is down
For first: There i have warning: while(feof(eng) == NULL); like (comparison between pointer and integer) i don't get it. For second i have a big problem. I must from every word print the most recurring character.
For example: nondeterministically -> the most are N and I. And if, there is more then one most reccuring char, you choose one of them.
I have
#define LessSymbol -1
#define MoreSymbol 1
#define NeitherSymbol 0
#define MAX_COLS 20
#define MAX_ROWS 20
#define MAX_CHAR 3
char averageMap[MAX_ROWS][MAX_COLS];
char rowCount[MAX_ROWS][MAX_CHAR];
char colCount[MAX_COLS][MAX_CHAR];
I have other stuff in the code, but basicly, at this stage i have a map of 1's,-1's and 0's in a 20 x 20 map. I just want to count the occurrences of each and basicly tally them in the 3 colums/rows at the end of the bloc. so far ive tried many different if statements, here is what i tried last.
for(row = 0; row < MAX_ROWS; row++){
rowCount[row][0]=0;
rowCount[row][1]=0;
rowCount[row][2]=0;
} for(col = 0; col < MAX_COLS; col++){
[Code] ....
Its outputting 20 as a result for each row. Its like its counting the symbol no matter what it is.
i have a problem i cant find a way to count how many times a character occur in a character array the out put should be
a=2
b=1
but my output is
a=2
b=1
a=0
i cant find away to get rid of the other a letter i dont know what to do
#include <iostream>
using namespace std;
int main() {
char array[3] = {'a','b','a'};
char frequency[26] ={'a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z'};
[Code]...
I must count the number of occurrence of all numbers in array , i wrote a code but it does not work properly
#include <iostream>
int main (){
int i,n,tmp,counter=0;
std::cout<<"Enter the size of the array:"<<std::endl;
std::cin>>n;
int *Array=new int [n];
int *counterArray=new int [n];
[Code] .....
Repeat the vowel Problem 3 (0 / 0)Write a program that will repeat k times each single occurrence of a vowel in the input file "sp.txt" to a new file "output.txt". The first line of the input file contains only the parameter k. The first line (containing the parameter k) should not to be written in the output file.
I wrote the code but i cant figure out something. i read the file, i found the vowels but then i cant print them.
Code:
#include <stdio.h>#include <string.h>
#include <ctype.h>
#define MAX 100
int checkvowel(char c)
[Code].....
c++ program which reads an input stream from the keyboard that counts the frequency of occurrence of all the letters of the alphabet
View 5 Replies View RelatedI need to create a program that asks the user for the filename, then counts the number of occurrence of each letter in that file.
Ex. if the file contains
Absacsac
asdasda
Output will be
a = 6
b = 1
c = 2
.
.
.
z = 0
This has been my program so far:
#include <iostream>
#include <fstream>
#include <string>
using namespace std;
#include <cstdlib>
void countingFunction(string sentence) {
[Code] .....
Here is what i have so far:
#include<fstream>
#include<iostream>
#include<string>
[Code].....
I also need to do a loop that scan the count array and check if the element is bigger than the previous one.
My C programming class wants us to write a program to read integers into an array, sort the numbers and print out the occurrence of each number. I've tried everything that I can think of but the core dump is still occurring.
void countValues ( FILE *inf, int list[], int size ); /* Function prototypes. */
void printFrequencies( const int list[], int size );
int main (void) {
int status = EXIT_SUCCESS; /* defaulting status to success. */
FILE *inf = fopen( "numbers.txt", "r" ); /* input data file */
[Code] .....
write a program in c to read a sequence of N integers and print the number that appears the maximum number of times in the sequence.
View 1 Replies View RelatedI'm doing a project where I have to store information gathered (temperature and the time it was taken in seconds) in two separate vectors. After an unknown amount of data has been entered, and the end-of-file has been reached, I have to display the highest temperature and the time(s) it occured (bear in mind that the highest temperature may be recorded more than once). The output of that part should be as follows:
Highest temperature: 51
Recorded at time(s):
22:45
2:27
Something like that. The time should also be converted to hours and minutes. To the point: I've done some research on bubble sorting, but they only use it for arrays.
What is the efficiency of the two assignments (line 1 and 2), i.e. (function calls, number of copies made, etc), also the Big O notation. I know there are function calls for retrieving the size of each string in order to produce a new buffer for the concatenated string...any difference between line 1 and 2 in terms of efficiency?
String s("Hello");
String t("There");
1. s = s + t;
2. s += t;
Ok, so I'm writing this code and when I build it keeps saying cannot implicitely convert type int to string even though I declared my variables as string. Why is it giving me this error?
private static string Repair()
{
string result="";
string beep;
string spin;
Console.WriteLine("Does your computer beep on startup?:(y,n)");
[Code]...
I would like to understand a function on strings. Below is a code that I took from my teacher where the user inputs a string and prints out the length of the string.
Code:
#include <stdio.h>
#include <string.h>
int main() {
char str[100];
int i = 0;
[Code] ....
Now I understand that it returns the count in "int" so my question is:
Let's say i declared
Code: int count = 0;
at the beginning of the code and then made
Code: count = strlen(str);
why wouldn't i have the same result? Is there a way to do it also?
I have this string d ="3 J JD, K" and i want to split the string to individual string. I have this code which eliminates the comma but doesn't split the string into individual string.
#include <iostream>
#include <string>
#include <sstream>
using namespace std;
int main() {
string str = "3 J JD,K";
stringstream ss(str);
[Code] ....
Output of the code is
3 J JD
k
but I want
3
J
JD
K
Also after I split the string is there any way to put the split string into individual string variables.
Very new to programming, and I know that there must be another way on inputting a string into each array cells not by just inputting it one by one, but as a whole. My code at the meantime is: [URL]
View 1 Replies View RelatedI have problem with string compare. I want to compare the string user input with a string in binary. And I don't know how to do it. Problem in function login();Here is the code: And you also can download file in attachment too..
Code:
#include<conio.h>#include<dos.h>
#include<stdio.h>
#include<process.h>
#include<string.h>
char nsb=1;
char ch, password[20], passlogin[20], inputpass[20], checked[20];
FILE *fp;
}
[code]....
In this code, i declared a string constant and trying to print the length of string. I know that if i write char a1[7] or char a1[] than it runs and give aggregate output, but in this case it is giving double length of string.
Code:
#include<stdio.h>
#include<conio.h>
#include<string.h>
void main()
}
[code]....
I wrote a program that reads a list from a file and stores it in a string type vector. Now, I want the user to input a word so that the program can search the vector to see if that word already exists. I have used every possible way of reading input from the console and storing it in order to compare with the vector but it never results in a match. When I print the input string and the vector string they are exactly the same thing (or at least print to the console as if they were). I've tried using getline; using cin direct to a string var; using cin to a char array and then casting to string using string str(arr); I even added a newline at the end just in case and STILL I cannot get a match.
vector <string> currentSet; //read a list in from a file and has 9 items in it
cin.ignore();
string line;
getline(cin, line);
if(line == vector[0]){//if printed to console line is HEAT and vector[0] is HEAT
cout<<"match"<<endl;
}