C++ :: Occurrence Of Different Alphabets In A String
Feb 28, 2014how to recognize the occurrences of different alphabets in a string and print the occurrences of each alphabet in string..
View 1 Replieshow to recognize the occurrences of different alphabets in a string and print the occurrences of each alphabet in string..
View 1 RepliesMy program reads a string of characters. Prints all occurrences of letters and numbers, sorted in alphabetical and numerical order. Letters will be converted to uppercase.Other characters are filtered out, while number of white spaces are counted.
the problem is it crushes when i run the program
Here is my code
#include <iostream>
const int SIZE = 100;
using namespace std;
int main() {
char *pStr, str[SIZE] = "", newStr[SIZE] = "", ch;
int count = 0, i = 0, j;
[Code] .....
I am trying to write a function, and meet some issues. Why am I keep getting NULL error for my resultant string? Is my code anywhere giving me such an error?
View 6 Replies View RelatedI am trying to form unique string from other string which is having multiple presence of same word as,
string testA = "one
two
three
four
one
seven wo";
now new string should contain single occurrence of words "one" and "two" so that new string will look like,
string testB = "one
two
three
four
seven"
I am unable to create an array which has to content elements(1E, 2E, 3E, 4E). I tried using char however I am unable to display as it only shows the letter E.
View 19 Replies View RelatedI have this homework where i am implementing a code which does error checking
so basically i have 3 variables and i assigned them as integer. so my error check is asking that if i type a value for instance 1.2 it should output "X"...
My program reads a string of characters. Prints all occurrences of letters and numbers, sorted in alphabetical and numerical order. Letters will be converted to uppercase.Other characters are filtered out, while number of white spaces are counted.
The problem is it crashes when i run the program. Here is my code
#include <iostream>
const int SIZE = 100;
using namespace std;
int main() {
char *pStr, str[SIZE] = "", newStr[SIZE] = "", ch;
int count = 0, i = 0, j;
[Code] .....
#include<iostream>
using namespace std;
int main() {
int choice[10] = { 0 };
int vote, highvote;
cout << "1 Lional Messi ";
[code]....
My problem is i have to stop the loop when i enter any alphabets, i tried a lot of method but still doesn't work.
//This code gives randomly generated alphabets and if equal will cout the alphabet which is equal
1 #include <iostream>
2 #include <cstdlib>
3 #include <ctime>
4 using namespace std;
5 int main()
6 {
7 int a;
8 char array[10];
[Code] .....
My question is how to check that randomly generated alphabets are equal e.g in 22 number line it should give output of equal alphabets if they are equal but it does not give equal alphabets what wrong in this code mention the wrong statement, how will i get right answer?
It should count from the text entered how many alphabets in uppercase and lowercase, digits, blank spaces and 'other symbols'.
This is the program below.
#include<iostream.h>
#include<conio.h>
#include<stdio.h>
[Code].....
i`m currently racking my brains out over this issue. How do i go about the x as the first occurrence of the letter?
lets say helxo , x is the 2nd occurrence of l. I will want to change back x into l
i have replaced it with x in the earlier step with this code...
string everySecondChar(const string &s,char source,char distance)
{
string t(s);
for(std::string::size_type even =0,pos=t.find(source,0);pos!=std::string::npos;pos=t.find(source,++pos))
{
[Code]....
i would like to reverse the process now, letting x becoming l again!
Supposed i have a word hammer.
how am i suppose to search for the 2nd occurrence of the letter and then replace it with x?
example hammer will become hamxer
I thought about using replace for it, however i`m lost on how to find 2 occurrences of the same letter in the word.
string formatEncrypt(string message) {
int msgLength=message.length();
for(int i=0;i<msgLength;i++) {
if(message[i] == 'j' {
message[i]='i';
[Code] .....
at line 31 i tried to put a z into the alphabet that occurs twice.
this is what i have done so far
example: hello world
It will turn out as helzlo world
However i want to make the output appear as helzo world
counting the occurrence of a number in my program.
Here's My Code:
void sort(int num[], int& count)
{
//cout << " Using Sort!";
for(int i =0; i <= count; i++)
[Code].....
How Can I continuously call the Count(); Function again after the first number?
what compiler that change all variable in one occurrence?
View 5 Replies View Relatedit's not my primary language, so my code variables are in my language.
Code:
FILE *eng;
eng = fopen("eng.txt", "r");
if(eng == NULL){
[Code]....
fclose(eng); It's a piece of my code. Some explanation: From file, where is full of words under selves. I cut it on word and from word i'm printing:
1) word
2) how many letters in the word
3) word backwards and
4) viz. problem is down
For first: There i have warning: while(feof(eng) == NULL); like (comparison between pointer and integer) i don't get it. For second i have a big problem. I must from every word print the most recurring character.
For example: nondeterministically -> the most are N and I. And if, there is more then one most reccuring char, you choose one of them.
I have
#define LessSymbol -1
#define MoreSymbol 1
#define NeitherSymbol 0
#define MAX_COLS 20
#define MAX_ROWS 20
#define MAX_CHAR 3
char averageMap[MAX_ROWS][MAX_COLS];
char rowCount[MAX_ROWS][MAX_CHAR];
char colCount[MAX_COLS][MAX_CHAR];
I have other stuff in the code, but basicly, at this stage i have a map of 1's,-1's and 0's in a 20 x 20 map. I just want to count the occurrences of each and basicly tally them in the 3 colums/rows at the end of the bloc. so far ive tried many different if statements, here is what i tried last.
for(row = 0; row < MAX_ROWS; row++){
rowCount[row][0]=0;
rowCount[row][1]=0;
rowCount[row][2]=0;
} for(col = 0; col < MAX_COLS; col++){
[Code] ....
Its outputting 20 as a result for each row. Its like its counting the symbol no matter what it is.
i have a problem i cant find a way to count how many times a character occur in a character array the out put should be
a=2
b=1
but my output is
a=2
b=1
a=0
i cant find away to get rid of the other a letter i dont know what to do
#include <iostream>
using namespace std;
int main() {
char array[3] = {'a','b','a'};
char frequency[26] ={'a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z'};
[Code]...
I must count the number of occurrence of all numbers in array , i wrote a code but it does not work properly
#include <iostream>
int main (){
int i,n,tmp,counter=0;
std::cout<<"Enter the size of the array:"<<std::endl;
std::cin>>n;
int *Array=new int [n];
int *counterArray=new int [n];
[Code] .....
Repeat the vowel Problem 3 (0 / 0)Write a program that will repeat k times each single occurrence of a vowel in the input file "sp.txt" to a new file "output.txt". The first line of the input file contains only the parameter k. The first line (containing the parameter k) should not to be written in the output file.
I wrote the code but i cant figure out something. i read the file, i found the vowels but then i cant print them.
Code:
#include <stdio.h>#include <string.h>
#include <ctype.h>
#define MAX 100
int checkvowel(char c)
[Code].....
c++ program which reads an input stream from the keyboard that counts the frequency of occurrence of all the letters of the alphabet
View 5 Replies View RelatedI need to create a program that asks the user for the filename, then counts the number of occurrence of each letter in that file.
Ex. if the file contains
Absacsac
asdasda
Output will be
a = 6
b = 1
c = 2
.
.
.
z = 0
This has been my program so far:
#include <iostream>
#include <fstream>
#include <string>
using namespace std;
#include <cstdlib>
void countingFunction(string sentence) {
[Code] .....
Here is what i have so far:
#include<fstream>
#include<iostream>
#include<string>
[Code].....
I also need to do a loop that scan the count array and check if the element is bigger than the previous one.
My C programming class wants us to write a program to read integers into an array, sort the numbers and print out the occurrence of each number. I've tried everything that I can think of but the core dump is still occurring.
void countValues ( FILE *inf, int list[], int size ); /* Function prototypes. */
void printFrequencies( const int list[], int size );
int main (void) {
int status = EXIT_SUCCESS; /* defaulting status to success. */
FILE *inf = fopen( "numbers.txt", "r" ); /* input data file */
[Code] .....
write a program in c to read a sequence of N integers and print the number that appears the maximum number of times in the sequence.
View 1 Replies View RelatedI'm doing a project where I have to store information gathered (temperature and the time it was taken in seconds) in two separate vectors. After an unknown amount of data has been entered, and the end-of-file has been reached, I have to display the highest temperature and the time(s) it occured (bear in mind that the highest temperature may be recorded more than once). The output of that part should be as follows:
Highest temperature: 51
Recorded at time(s):
22:45
2:27
Something like that. The time should also be converted to hours and minutes. To the point: I've done some research on bubble sorting, but they only use it for arrays.
What is the efficiency of the two assignments (line 1 and 2), i.e. (function calls, number of copies made, etc), also the Big O notation. I know there are function calls for retrieving the size of each string in order to produce a new buffer for the concatenated string...any difference between line 1 and 2 in terms of efficiency?
String s("Hello");
String t("There");
1. s = s + t;
2. s += t;