C++ :: How To Check Equivalent Of Randomly Generated Alphabets
Mar 23, 2014
//This code gives randomly generated alphabets and if equal will cout the alphabet which is equal
1 #include <iostream>
2 #include <cstdlib>
3 #include <ctime>
4 using namespace std;
5 int main()
6 {
7 int a;
8 char array[10];
[Code] .....
My question is how to check that randomly generated alphabets are equal e.g in 22 number line it should give output of equal alphabets if they are equal but it does not give equal alphabets what wrong in this code mention the wrong statement, how will i get right answer?
I can't get the sum of two randomly generated numbers - I don't believe the program is adding wrong what I think might be happening is upon hitting enter its adding two new randomly generated numbers -
Code: // Program functions as a math tutor #include <cstdlib> #include <iostream> #include <ctime> using namespace std; int main() { // Constants const int Min_Value = 1;
The program is supposed to be printing 21 different numbers that are randomly generated. Why am I getting the same number 21 times? Using dev C++ compiler.
Code:
/*prints random numbers between 1 - 99*/ #include <stdio.h> #include <stdlib.h> #include <time.h>
How do i define a new color that is randomly generated in allegro.
I have this code here in the header file.
Code:
//FILE : circledefs.h //PURP : Define some constants for circle & background #ifndef CIRCLEDEFS_H #define CIRCLEDEFS_H #define NUMCIRCLES 3 //The frames per second for the timer #define FPS 60
[Code]...
And what i want to do here is learn how to create a random number gen. Now a few questions if you don't mind telling me is.
1 - can I create 3 random generators in this header file? Or do I have to do this in main.
2 - If I do have to do this in main can I still create this defined RANDOM as a color.
3 - I am sooooo new to this all i know is cin and cout code for C++, so will i need to know more about pointers to do this.
4 - for fun how hard would it be to make a game in allegro that uses music to define how the enemy moves and attacks. (yes that would be the final project.
I have a error with one of my programs. I'm supposed to get rid of negative numbers when there are numbers that are randomly generated. Here is the middle part of the code.
{ int vectorLength = 10; vector<int> bothSigns(vectorLength); cout << " Input vector: "; for (int i = 0; i < vectorLength; i = i + 1) { bothSigns[i] = rand()%201 - 100;
[code] .....
The part where i'm supposed to start is after the /////'s. However, whenever I input a number for the random numbers(not put in part of code), i keep getting a segmentation error.
I've been trying to create a roguelike, and I was trying to create randomly generated rooms like in Rogue. I'm seperating my map array into sections and giving it a 50% chance of spawning a room, but right now it doesn't do anything but spawn solid rock. What am I doing wrong?
int MapSizeX = 100; int MapSizeY = 100; char map[100][100] = {}; char wall = 178; int ViewDistance = 10;
I have a struct called Array and I'm to create a function to create a dynamic array that's fill with randomly generated integers from 0 to 50 (inclusive) and a function to destroy the array for freeing its memory. Below the code that I have written so far.
Code:
* Struct */ typedef struct {int *pArray; //the dynamic array int length; //the size of the dynamic array}Array; /* Function to create a dynamic array */ Array *initializeArray (int length) {int i; }
I am unable to create an array which has to content elements(1E, 2E, 3E, 4E). I tried using char however I am unable to display as it only shows the letter E.
I have this homework where i am implementing a code which does error checking
so basically i have 3 variables and i assigned them as integer. so my error check is asking that if i type a value for instance 1.2 it should output "X"...
My program reads a string of characters. Prints all occurrences of letters and numbers, sorted in alphabetical and numerical order. Letters will be converted to uppercase.Other characters are filtered out, while number of white spaces are counted.
The problem is it crashes when i run the program. Here is my code
#include <iostream> const int SIZE = 100; using namespace std; int main() { char *pStr, str[SIZE] = "", newStr[SIZE] = "", ch; int count = 0, i = 0, j;
What I want to do is simple, however I can not find a way to do it in c++ and I don't know for sure that it is possible. I want to create a function that creates a simple short-hand for printf(x); Such as:
void echo(x){ printf(x); }
But when I call the function:
echo "hi";//I want it to look like this //instead of: echo("hi");// like this.
My program reads a string of characters. Prints all occurrences of letters and numbers, sorted in alphabetical and numerical order. Letters will be converted to uppercase.Other characters are filtered out, while number of white spaces are counted.
the problem is it crushes when i run the program
Here is my code
#include <iostream> const int SIZE = 100; using namespace std; int main() { char *pStr, str[SIZE] = "", newStr[SIZE] = "", ch; int count = 0, i = 0, j;
convert a positive integer code into its english name equivalent for digit. A valid code is of size between four (4) to six (6) digits inclusive. A zero is not allowed in the code.
example : if the input is 234056 the output is : INVALID CODE (PRESENCE OF ZERO) if the input is 23456 the output is : TWO THREE FOUR FIVE SIX if the input is 9349 the output is : NINE THREE FOUR NINE if the input is 245 the output is : INVALID CODE (3 DIGITS) if the input is 2344567 the output is : INVALID CODE (7 DIGITS)
step 1 : input code step 2 : count the number of digits in the code step 3 : if there is a zero in the code, "INVALID CODE (PRESENCE OF ZERO)" go to step 4 step 4 : if number of digits is mode or equal than 4 and less or equal than 6, go to step 5 else display the following message "INVALID CODE (<number of digits> DIGITS) step 5 : call a function called digit_name to convert each digit into its equivalent english name. display the result step 6 : print the digits in reverse order eg; if input is 13453, reverse order is 35431
I've reached a point in "Jumping into C++" where I need to make a program that converts input numbers into their word equivalent.
So far I've made it work for numbers 0-9999. I've tried implementing 10000-99999 but there are problems with the order of the words printed (57865 would print fifty thousand seven thousand eight hundred sixty five). But besides that, the program is absolutely enormous (for me) and I'm wondering if it can be shortened. Keep in mind I can only use loops and if statements so far. Here it is:
This C++ question is related to Temperatures and Our task is to : Write a well-documented C program that prints out a table of temperatures in Celsius, from 0 to 100, in steps of 5 degrees, with the equivalent Fahrenheit.
To convert temperatures from Celsius to Fahrenheit use the equation : Temp(F) = Temp(C)*9/5 + 32
Include headings on the columns of figures.
Use the following formatting in your printf to produce a tabulated output:
Printf(“%4.1f %4.1f ”, Cent, Fahr);
This format will print each variable in a fieldwidth of 4 digits, with one place of decimal. The ‘ ’ inserts a tab to space the columns. This is our code, but for some reason its not working.
#include<stdio.h> void main() { int Cent=1, Fahr=1; int Temp; int F; int C;
