I try to use "rand" to create 100 string, I'm happy I succeed, but next step i wanna know how to count each number of letters and the frequency it shows.
Here is the code:
#include <stdlib.h> #include <string.h> #include <time.h> #include <iostream> // using namespace std; int main() { const char *c = "abcdefghijklmnopqrstuvwxyz";
I'm just trying to find out if the way I've setup my code currently allows me to count the letters as they occur? I don't yet see how to do it but I need clarification. Ideally the function letterCounter would do the counting but atm I'm just trying to figuring it out in the display function.
I have to count the letters from a text file into an array so the first spot is the number of A's second spot number of B's and so on then take the array and sort it in decending order how could i do this without loosing track of where the numbers go so if there are more b's than a's they switch but how will i know where each letter has moved in the array after it has been sorted?
This is a command line lotto program. My first problem is trying to increment letters per line of the array. So for example, if the user types: ./mega_million 10
The output would be something like:
Mega Million ________________Mega A 17 30 32 33 38 30 B 14 21 23 45 52 16 C 03 08 17 42 44 30 D 01 11 27 35 45 29 E 07 12 16 32 46 06 F 17 39 50 52 53 44 G 13 32 49 52 53 39 H 16 41 53 54 55 11 I 14 45 46 53 54 28 J 36 37 42 53 55 39
I am new to c++ and have started creating a dummy program to perform a simple task of writing a few strings to the console, which are first generated using random generation. When I execute the code, an extra line for each generated object appears in the console.
int gemNum; cout << "This program calculates the value and type of gems "; cout << "Please enter the number of gems: "; cin >> gemNum; vector<int> gemVector(gemNum); vector<int> gemCollection = fillGemCollection(gemNum); vector<int> gemSort = sortGems(gemCollection); vector<string> gemResult = finalGemValue(gemNum, gemSort); for(int i = 0; i<gemResult.size();i++){ string gemString = gemResult[i]; cout << gemString << endl; }
This program calculates the value and type of gems..Please enter the number of gems: 4
10 hematite 40 carnelian 60 onyx 120 silver pearl Press "e" and enter to end program
In this program what i'm doing is to search for a number when the vector is in order, and count how many times that number appears, the problem is that count how many times the number does not appear, but when its appear the program stays in an "standby mode" and the cursor does not move.
int buscarNumOrdenado (int x [MAX]) //MAX is the define { int num,d, LimiteInferior, LimiteSuperior,mitad; d=0; LimiteInferior = 0; LimiteSuperior = MAX-1;
I'm running a game online and designing a program to generate Enemy Stats. Basically, it's supposed to generate 25 numbers between 0 and 7(to represent 8 Attributes on a 25 Point Buy system) and count how many times each number shows up.
Here's what the code looks like:
Code: #include <iostream> #include <ctime> #include <cstdlib> using namespace std; int Generate() { int r= rand(); int s= r%7; [Code] ....
#include <stdio.h> /* function that will identify if line is empty or not */ is_empty(char *buffer) { while(isspace(*buffer)) buffer++; if(*buffer==0x00) return 1;
Just wrote this extremely simple program but it seems to be malfunctioning. It counts correctly the number of uppercase letters in a string so long as i don't use the space-bar. once I add a space it only counts the number of uppercase letters of the first word..
printf("I ..........ing love programming");
Code:
#include <stdio.h> main() { char text[200]; int i = 0; int uppercase = 0; printf("Enter text:"); scanf("%s", text);
The following fuction from a class is supposed to count the number less then the average of all number combined. but it does not do that, now the fun part if you change it to count the number greater then the average it works great.
void IntegerArray::countBelowAverage() { avrg=calcAverage(avg); int count=0; for(int x=0; x<100; x++) { if (list[x]<avrg)
write a C program which repeatedly reads in sentences from the user and reports on how many capital letters are in the sentence and how many punctuation characters. Your program will stop asking for input once the user has entered in a blank line. Consider the following example usage with the program. User input is marked in underline:
Enter a sentence: John and Mary went to Fred's house. You used 3 capital letters and 2 punctuation characters. Enter a sentence: I like A&W more than McDonald's. You used 5 capital letters and 3 punctuation characters. Enter a sentence: Good bye!
Hint: make use of the standard C functions ispunct and isupper. Other requirements. You must make two functions.
Make a function called find_characters, which has a return type of void, and which has three parameters: one of type char * (a string to find characters in), one of type int * (a reference to int variable indicating how many capital letters are in the string) and the last one also of type int * (a reference to an int variable indicating how many punctuation characters are in the string). Your find_characters function should scan the string and update the two variables it has references to.Make a main function.
This function should repeatedly read in a string from the user, call your find_characters function, and output the information returned to it by the find_characters function indicating how many capital letters and how many punctuation characters were in the string. Your main function should stop reading in input when the user enters in a blank string (i.e., the user just hits enter without entering anything else in). You may assume that the user will not enter in a sentence longer than 100 characters
I have to code a simple program who determining the number of Characters (A character could be any alphabets, digits, punctuation marks, or special , Operators ( Operators are those symbols that are used in mathematica expression, such as,'+', '*', '/', '-', and so on.), Uppercase letters (Uppercase characters are those from A..Z) and Numerical digits ( A digit is any of the Hindu-Arabic numerals from 0..9). Why the output is wrong!
#include <iostream> #include <string> #include <fstream> #include <cstdlib> #include <iomanip> using namespace std ; int main() { char text;
[Code] .....
This is my input file This is a possible factorial function in a programming language called LISP
(defun factorial (n) (if (< n 2) 1 (* n (factorial (1- n)))))
This is my output:
The number of characters = 113 The number of operators = 3 The number of numerical digits = 3 Uppercase letters = 5
I think that "characters" is wrong, but I do not know why !
4.1 Write a program that will count from 1 to 12 and print the count, and its square, for each count.
4.2 Write a program that counts from 1 to 12 and prints the count and its inversion to 5 decimal places for each count. This will require a floating point number.
4.3 Write a program that will count from 1 to 100 and print only those values between 32 and 39, one to a line. Use the incrementing operator for this program.
i am writing a program that accepts a decimal number from the user and convert it to binary numbers. After the conversion, i should count the number of 1's and 0's in the said binary number. I got upto converting and counting 1's using Brian Kernighan’s Algorithm. But, i can't seem to get it to count the number of 0's.
#include <iostream> #include<bitset> using namespace std; int main() { int num,count=0,Zero,count1 =0; cout<<"Enter the number:"; cin>>num; string binary;
I am trying to create a word counter program that asks for the price per letter and then asks for the sentence they are writing. The app should then calculate the number of letters and give the total cost similar to:
You have 40 letters at $3.45 per letter, and your total is $138.00.
Everything compiles fine but when I run it the inputs don't work and it outputs:
You have -1 per letter, and your total cost is $-0.
I was wondering how to limit error message to one only.
For example
cin.getline(stringname,7); for(int i=0;i<size;i++){ if(strcmp(stringname, "hello")=0) cout<<"Found!"<<endl; else cout<<"not found"<<endl; } not found not found .......