C++ :: Program Which Print Out All Prime Numbers Less Than Or Equal To Given Number
Nov 11, 2013how to make a programm in native c++ which print out all prime numbers less than or equal to given number????????
View 5 Replieshow to make a programm in native c++ which print out all prime numbers less than or equal to given number????????
View 5 RepliesI have a program that gets prime numbers that doesn't work. It looks like it works for all prime numbers except odd non-prime ones. Here is the code:
Code:
#include <iostream>
using namespace std;
bool isPrime(int prime) {
while(true) {
int track = 0;
[Code] ...
I need to write a program that will allow the user to enter a number "n" and the program tell you that the nth prime number is .....
EXAMPLE
user enters 55
printf("The 55th prime number is %i", variable");
I'm trying to write a program that prints all of the prime numbers to the screen. I'm getting angry because it only prints EVERY number. I think it has something to do with the bool change not being able to leave the for-loop but how to fix it.
Code:
#import <stdio.h>
#include <stdbool.h>
int main(void){
printf("
The Primes Are: 1");
[Code] ....
I calculate two numbers "R1",R2"
when i make
cout<<R1;
cout<<R2
i get
R1=51,9151
R2=51,915
when i make
Code: if (R1>R2) cout<<"i am here" he print the message
but they are equal. how i made limit the number of flottant to get equal numbers?
I'm a new coder for C++, and I've recently learned java before starting this programming language. I'm attempting to find all prime numbers up to the number a user enters (i.e. User enters 10, System shows "1,2,3,5,7"),
#include <iostream>
#include <cstdlib>
using namespace std;
int main(int argc, char** argv) {
int num;
cout << "Enter a positive number." << endl;
[Code] ....
I've been looking at my forloop, and I can't seem to pinpoint the problem with it.
Write a c++ program to print out the first n prime numbers and the sum of the first n prime numbers.
View 7 Replies View RelatedI am trying to print the prime numbers, so i put the numbers into the vector and then erase the non prime numbers. if i comment the break statement i get runtime error saying out of bound, but if i don't comment it out it prints the primes but it also prints the multiples of 3.
void Eratos( int length, vector< int > &v ) {
int i;
for (i=0; i<length; ++i) {
v.push_back(i);
cout <<v[i];
[Code] ....
int main()
{
int a=0, c, d, N, K;
bool stopBool = 0;
[Code]....
This is supposed to find take a number N and K and find all numbers between 0 and N that equal K and cout the number of pairs that fit it but it doesn't work.
/* Task: create a function that determines prime number and use it to print out prime numbers from 0-50: */
Function prototype: Should return a `bool` (because it answers a yes/no question) and should take in a single int (to ask whether it's prime).
- An int greater than 2 is prime if it is not divisible by any number between 2 and itself, not including itself.
- Use this function to print out the primes less than 50. Check it against my list:
2 3 5 7 11 13 17 19 23 29 31 37 41 43 47
#include <iostream>
using namespace std;
int prime(int&x) {
if(x%2==1)
[Code] ....
It is printing out the correct prime numbers but also printing this between each number: 1629974960
Write a program that prompts the user to enter a number larger than 2. The program should use the Number class to determine the prime numbers between 2 and the number entered, and display them in the console window.I've been stuck for a while now and just lost in implementing classes and contstructors.
#include <iostream>
using namespace std;
int main(int argc, char * argv[])
{
cout << "Enter a number larger than 2: " << endl;
int n;
cin >> n;
I have to write a code in which the addition of prime number gives the number user input..
for example if user enters 10 then
7+3 = 10
2+3+5 = 10
I have a very large number in word ~6million digits long
I wish to make a program to check if it is prime.
I wrote a program which sends a starting and ending range to other processes and the processes calculate the prime numbers in that range and return the count of prime numbers to the head process, process 0. But this is not working properly at the moment. I realize I still have to split up the range based on how many processes I have...I still have not figured out how I want to set that up. I
Code:
#include <stdio.h>
#include <stdlib.h>
#include <mpi.h>
int isPrime(int num);
int main(int argc, char **argv){
}
[code]....
I am trying to write code to find all the prime numbers before a user entered number. I started with a working program and when I tried to create a function, it got all messed up.
Code:
#include <stdio.h>
int is_prime( int num );
int get_positive_integer(void);
int main( ) {
int upper; /* upper limit to check */
int num; /* current number to check */
int isprime;
/* used to flag if number is prime or not */
[Code]...
It says the error is on line 23
This is a program that display prime numbers from 1 to 100. it has problem linking when i run the program.
#include <iostream>
class Prime {
public:
int PrimeNo();
int Display();
};
// class Prime number
int Prime::PrimeNo()
[Code] ....
Here is what I have:
#include <iostream>
#include <cmath>
using std::cout;
using std::endl;
using std::cin;
[Code] .....
This is the output after compiling when I enter 10 as 'x':
3
5
5
5
7
7
7
7
7
9
What is the minimum range of numbers which we need to go necessarily to check either a number is prime or not?(for all integers) ....
View 6 Replies View RelatedI have been writing a program to generate pairs of RSA keys using small prime numbers. I have been using mpz_invert() to get a value for d for the private key. On small prime numbers it calculates the correct value, but on larger primes it calculates incorrect values.
I'm assuming there must be an upper limit to the values the mpz_invert() function can handle? If so, what is this limit to avoid erroneous values?
In 83rd line message says: "Illegal Structure operation". But I didn't use any structures! How to correct it?
#include<iostream.h>
#include<conio.h>
#include<math.h>
int prime(int);
int reverse(int) ;
int power(int,int);
int rectangle(int,int);
int square(int);
int circle(int);
void tables(int);
[Code] ....
So I need to write a program which tells the user if the number they input is prime or not. I have done so and included the code below. My problem is that I need to allow the user to input if they want to enter another number after the first one using y or n and I am having trouble figure it out.
#include <cstdlib>
#include <iostream>
using namespace std;
[Code].....
I've written a program which takes a character string and then prints each character vertically so that for instance the string 123 can be written as
1
2
3
no what i need is for all the numbers from zero to the inputted number to print the numbers digits vertically but each number to be printed horizontally so that for instance an input of 11 prints
1 2 3 4 5 6 7 8 9 1 1
0 1
i've made it so that i can print all numbers up to the inputted number vertically; however, i am stuck with a method for making each number print horizontally as described above.
Coding for- To print all combinations of numbers that can compose a given number..
View 3 Replies View RelatedI want to make a program to print the product of even numbers between 1 and 30 and sum of odd numbers between 1 and 30. But the answer of product is negative. The photo shows the output of the code.
#include <stdio.h>
#include <conio.h>
void main ()
{
int i, even_product=1, odd_sum=0;
for(i=1;i<=30;i++) // For loop starts here!
[Code]...
How would I by any means print out the result of one number being added by two numbers 999999 times, the numbers both happen to be about 16500 digits long. It must display ALL digits in the number (all the digits the result ends up being). I know I can't use normal data-types, so what do I do?
Looks kinda like this:
for (int i = 0; i < 999999; ++i)
{
total += a;
total += b;
}
a and b being 2 different numbers with about 16500 digits.
In my program I am supposed to call isEqualTo with a user defined class type, and print out if my two numbers being compared are equal or not. I had to write two versions of this, one with just a template which works fine, but when I implemented the class, all the sudden my program just spews out true no matter if actually equal or not. Here is what I have so far:
#include "stdafx.h"
#include <iostream>
#include "UserClass.h"
using namespace std;
template<typename T>
bool isEqualTo(T value1, T value2){
if (value1 == value2)
[Code] ....