C :: Check How Many Times Numbers In Array Are Listed
Dec 24, 2013How can I check how many times the numbers in the array are listed?
View 2 RepliesHow can I check how many times the numbers in the array are listed?
View 2 RepliesCreate a program that finds all numbers in an array that show up exactly 5 times. I am trying to solve this issue by making a frequency distribution via two loops and two arrays, but I am having trouble getting my loop to not recount a number it has already counted.
For example, if you enter ten 1's into the "entered Numbers" array I want it to store a count of 10 in frequencyarray[1]. Instead it is storing
frequencyarray[0]10
frequencyarray[1]9
frequencyarray[2]8
etc...
#include <iostream>
using namespace std;
void enternumber(long[], int);
int main() {
int size;
int numbers5=0;
[Code] .....
How would I by any means print out the result of one number being added by two numbers 999999 times, the numbers both happen to be about 16500 digits long. It must display ALL digits in the number (all the digits the result ends up being). I know I can't use normal data-types, so what do I do?
Looks kinda like this:
for (int i = 0; i < 999999; ++i)
{
total += a;
total += b;
}
a and b being 2 different numbers with about 16500 digits.
Code:
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
#include <math.h>
int main()
#define rows 9
#define columns 9
[code]....
I want to make a program that opens a text file and checks the usernames listed in the text files to see if the names are registered on a site such as twitter. How easy would this be to make, what things would I need to know?
View 4 Replies View RelatedI need to create a if else statement to check multiple model numbers (200+)... How can i build this? I basically want the user to enter their model number and if its on the list they get a approved or denied message.
So far I have this, the "if(model == 9002||1002)" doesnt seem right, it needs to basically check 200+ model numbers... am I even on the right track?
Code:
#include <iostream>
using namespace std;
int main(){
int model;
cout << "Enter model" << endl;
[Code] .....
How do I error check if the user is inputting letters and not numbers? For example, if the user inputs "Lab.txt" I need to display an error message. If they input "Lab2part2.txt" then this is correct and what I want.
I've found a lot of information online on how to error check for numbers or a single letter (EX: 1,2,3, etc. or 'A' 'B' 'C') but nothing for actual WORDS or maybe I should refer to it as a string of characters?
Is there any way to do this? Because my program requires I ask the user to input the name of the file. But the way my code is currently set up is even when the user inputs the wrong file name it still opens the file. I want to prevent this from happening so my thought was to error check user input.
/*Program to determine company's weekly payroll*/
#include <iostream>
#include <string>
#include <fstream>
using namespace std;
void OpenTheFile() {
ifstream inputFile;
string filename;
char letter;
int number;
[Code] .....
I tried to check the rational or irrational numbers after we take the square root. i dont get the formula. for eg. squareroot of 64 is 8 and it is rational. square root of 2 is irrational. how to check it in c++..
View 10 Replies View RelatedI am writing this program that is supposed to read a file, put the data into an array, alphabetize, count how many times each word appears and print to an output function. I posted before on how my program had an error when I ran it but I have fixed that. Now my outputArray file is empty. It gets created but there's nothing in it.
#include <iostream>
#include <fstream>
#include <sstream>
#include <string>
using namespace std;
//global to this file
[Code] .....
1. Input an dimension and elements of an array from the keyboard. Count the odd elements of an array and that number join to variable K, then sort the last K elements in decreasing order.
Code:
#include <stdio.h>
main ()
{
int A[100], i, n, j, K = 0;
printf ("Type in the dimension of an array:
");
scanf ("%d", &n);
[Code]....
I can have at most 3 structs in array, but it could be 0,1,2 or 3 structs in array. I am trying to avoid dynamic memory allocation. I initialize sensors to 3 to reserve space for them in memory, since there may be at most 3 elements in the array. But I am testing a condition where there will only be 2 elements:
Code:
#include <stdio.h>#include <stdlib.h>
#include <string.h>
typedef struct {
unsigned long long int address;
float current;
unsigned char pressure_units;
} sensor;
[Code]...
The problem is even though there are only 2 sensors out of 3 in the array, sizeof(sensors)/sizeof(sensors[0]) returns 3. I assume because when it allocates memory for 3, it includes that allocated memory even though it really doesn't contain the struct. How can I figure out how many elements were really inserted into array, not just allocated to array?
This program works but i need to build an additional loop that will re-prompt a user if his initial entry (int y_n) is other than 'Y', 'y', 'N', 'n'. For instance if a user tries to enter 'Yup', he will be prompted "That isn't a valid entry" and then re-asked to enter int y_n.
Note: If user answers Y he is asked to enter a value that is entered into an array. If the user at any point answers N, the program ends and final stats are cout.
#include <iostream>
using namespace std;
int main(){
char y_n;
int i = 0;
float input_value;
float myarray[100];
[Code] .....
If I have a char array that that looks like
char array[] = {'a', 'b', 'c'};
How can I check user input against all of these values at once?
I'll process the raw content of a stream which obviously will be loaded one chunk at a time into an buffer.I need to check if every chunk content is x00 filled. If it is, I'll increase the blank chunks counter of 1.On your personal opinion, which is the fastest an less cycles consuming manner to achieve such result?
I was wondering this: is it possible to make an instant XOR of all the buffer content to check if it does return 0 ?the only way is it to cycle through all the bytes and compare each one of them with 0?
This is an assignment question In C++, there is no check to determine whether the array
index is out of bounds.Design a class myArray that solves the out-of-bound array index problem and allows the user to begin the array index starting at any integer, positive or negative. Every object of type myArray should be an array of type int.
Part 1 processes only int arrays. Redesign the class myArray using class templates so that the class can be used in any application that requires arrays to process data.
I don't understand the second part. should i just change the array from int to char or something?
Find all the prime numbers between a given pair of numbers. Numbers should be read in from an input file called "numbers.txt" and find all the prime numbers between them. Store the prime numbers in an array, then sort the array from greatest to least. Display the array before and after the sort.
I'm stuck on how to put the prime numbers into an array.
The input file has the numbers 1 & 100.
Here's what I have so far.
#include <iostream>
#include <fstream>
using namespace std;
int main() {
ifstream fin;
fin.open("numbers.txt");
[Code] .....
How i could go about extracting and checking if the very first character in my string array is an alphabet
View 2 Replies View Relatedfinishing my program which needs to do the following:
(i) Write code to read in the dictionary into an array of words
(ii) Write code to check the spelling of a word entered by the use
(iii) Like Scrabble / Countdown the user enters the letters they have and my code must find the word using the highest number of those letters
I have completed a good bit so far but I'm stuck on my checkSpelling() and findWord() functions as well as part (iii)
#include "stdafx.h"
#include <stdio.h>
#include "string.h"
int countCharOccurence(char *string, char c);
int getOption();
int checkSpelling();
[Code]....
I am unable to check if the character in the 2D array is alpha
here is my code
#include<iostream>
#include<cctype>
#include<cassert>
#include<cstring>
const int maxChar = 20 ;
using namespace std ;
int main() {
int count = 0 ;
char d[2][20] = { "hi" , "di" } ;
[code]....
Question: How to find a duplicate numbers and numbers found once in array.
View 7 Replies View RelatedThe code below will generate combinations of numbers from 1 to 25 in an 15 numbers array. The only filter I've applied is that the sum of all the numbers in the vectors divided by 15 needs to be between 13 and 14.
I would like to count how many consecutive numbers there are in one combination, so that later i can apply another filter.. for example:
1 3 4 5 6 8 10 13 14 16 17 18 19 20 25
3 + 4 = 1
4 + 5 = 1
5 + 6 = 1
13 + 14 = 1
16 + 17 = 1
17 + 18 = 1
18 + 19 = 1
19 + 20 = 1
_____________
Count = 8, in this case..
I think it's not very difficult to do, but i just can't see how to do it.
#include <iostream>
#include <vector>
#include <numeric>
[Code]....
#include <iostream>
#include<fstream>
int decryption(int);
int multiply(int,int[][2]);
using namespace std;
main(){
int n;
ifstream inFile;
inFile.open ("out.txt");
[Code] .....
I was trying to store numbers read from a text file into 2D array but I am getting the error above.here is where the error occurs:
line 33: cout<<m[i][j]<<" ";
I have been trying to make a program that asks for username and password, and if it is wrong it will loop back to the top. But i only want it to loop a set number of times, how can i do this? This is my code so far
string username;
string password;
cout << "Enter username: ";
getline(cin, username, '
[Code] ....
I've got most of the program to work but its printing to the screen 5 times and I only want it to print once.
Eg:
cos1512: 57.00%
mat1512: 86.50%
inf1520: 65.10%
cos1521: 78.40%
inf1505: 89.10%
but I get:
Semester Marks:
================
cos1512: 57.00%
mat1512: 57.00%
inf1520: 57.00%
cos1521: 57.00%
inf1505: 57.00%
cos1512: 86.50%
.....
My code:
#include <iostream>
using namespace std;
class Module {
public:
void setModules(string module1, string module2, string module3, string module4, string module5);
void setMarks(int aMark1, int aMark2);
int updateMarks();
[Code] .....
I was wondering that why in the below code, the copy constructor is called 2 times.
Code:
class A {
private:
static int count;
int age;
public:
A()
[code].....
I think that when f(a) is called, since I am passing this as value, no copy constructor should be called. The copy constructor should called when the return object "x" is assigned to:
A b = x;
why copy constructor called 2 times?
so i have to read a text file with an unknown number of lines and allocate memory to for the number of items in the text file.currently i read the entire file(counting the number of lines). i allocate memory according to the number of lines read and then use fseek() with an offset of zero to allow for the second read .
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