I have tried writing a code which takes two numbers from the user and calculates their square root then the roots are added up to return the sum. The program is coming out with loads of errors.
#include<iostream>
#include<cmath>
float main(){
using namespace std;
float m1,m2,m3,m4,m5;
[Code] ....
this is what i have so far
#include <iostream>
#include <cmath>
using namespace std;
int main () {
int v;
[Code] ....
im trying to get the program to print this as an example if the user enters 5 (the rounding of the decimal is optional).
1 1.41 1.73 2 2.24
1 1.41 1.73 2
1 1.41 1.73
1 1.41
1
why its not reading my for loop for rows its only doing columns ...
I tried to check the rational or irrational numbers after we take the square root. i dont get the formula. for eg. squareroot of 64 is 8 and it is rational. square root of 2 is irrational. how to check it in c++..
View 10 Replies View RelatedSo I have to make a program that allows the user to enter both positive and negative numbers and the program is suppose to calculate the sum of only the positive values while ignoring the negative values. Also it is to be a sentinel-controlled loop with a number ending the set of values.
View 4 Replies View RelatedI am looking to create a table somthing like this output below but I am very new to this and my code is abit everywhere.
x sqrt(x) x ^ 2 x ^ 3
========================================
1 1 1 1
2 1.414 4 8
3 1.732 9 27
4 2 16 64
5 2.236 25 125
6 2.449 36 216
7 2.646 49 343
8 2.828 64 512
9 3 81 729
10 3.162 100 1000
========================================
Totals: 55 22.47 385 3025
========================================
This is the code I have I have got it to cal some of the values but numbers our everywhere. I am doing more Trial and error than anything.
#include "stdafx.h"
#include <iostream>
#include <cmath>
using namespace std;
[Code].....
i have written a function that gives me the square root of a number. Yes i know there is already a function in <cmath> that gives square roots but i thought it would be pretty challenging (and therefore fun) to try writing one on my own. I wrote my code while i was in school, listening to my Irish teacher ramble on and on about useless shit, so it's probably not the best possible way of finding the square root of a number.
double msqrt(double x) {
double adder=1;
double y = x;
for(int a=0; ; a++) {
if(y*y > x) y = y/2;
if(y*y <= x) break;
[code]....
Okay so I have to draw a square using "c" that draws according to the user input. Also, this has to be a function, and here is the code I have so far:
#include <stdio.h>
void DrawSquare(int length, char symbol);
void DrawSquare(int length, char symbol) {
int row;
int col;
[Code] .....
When I run this program it compiles fine but when the user input is recorded it just draws nothing but makes tons of spaces.
I am writing a program to find the square root of a number. I am using the Newton-Raphson method..Just to clarify a bit of the code.. fabs(1/(x+1)) < 0.001 is to check for relative error..
EXAMPLE: for user entry of 100 if the iteration process ends in 10.055 the answer will return as 10 which is correct. But it isn't doing that.
It compiles I then proceed to run it..prompts me "Enter a number to find the square root of: I type 100 then hit enter...
"The square root of 100 is -1077834936"
My first time writing a program from complete scratch.
And I know there is a sqrt() function...just wanted to write my own.
Code:
#include <stdio.h>
#include <math.h>
double mysqrt(double a);
int main()
{
double a, result;
printf("Enter a number to find the square root of: ");
[Code]...
I am trying to computed the time it takes for a projectile to hit the ground. The problem is that i need to square the input of velocity before i do the calculation. the question I have is that if it's possible to have multiple arguments inside the brackets after main.
#include <stdio.h>
#include <math.h>
double distance (double a, double v, double g);
int square(int y);
double height(double v, double a, double g);
double time (double v, double a, double g);
double sqrt(double num);
[Code] ....
How to write a function macro in C for finding the sqrt of a number?
View 2 Replies View RelatedI have been trying to write a Newton's Method program for the square root of a number and have been failing miserably...
#include <iostream>
#include <cmath>
using namespace std;
int main() {
double x1;
double y;
double x0;
[Code] .....
I having trouble with the rational class
here is my assignment:
Add a square root function to the rational class. Have your program print the square root of any rational number. I want to find the square root for numerator and denominator separatetly. divide the answer to get decimals and convert the decimal to fractions. i got till geting the decimal but i want to convert it back to a simplified fraction
// finding greatest common factor
int gcd(int a, int b)
{
if (b == 0)
return a;
else
return gcd(b, a % b);
}
[Code]...
I'm writing some functions pertaining to binary trees. I've used recursion once before while learning quicksort but am still quite new and unfamiliar with it. And this is my first time touching a binary tree. So my question: In my addnode function, will the return root statement at the end ever return a value other than the value passed to the function?
Code:
#include <stdlib.h>
struct tnode
{
int data;
struct tnode * left;
struct tnode * right;
}
[code]....
I have to make a program that displays a square of asterisks based on the users input. Here is what I have so far.
#include<iostream>
using namespace std;
int main(){
int number;
cout << "Enter a number: ";
cin >> number;
for (int i = 0; i < number; i++){
[Code] ....
But the square needs to be hollow like this. So if the user enters 5 then the following square will be shown.
*****
* *
* *
* *
*****
How to make it do this.
I'm working on a c program that generates approximations of square roots based on newton raphson method. I worked out the approximations with another method I learnt and I know this program does fine. But I don't get the concept of epsilon. Below is the code for the program
Code:
#include<stdio.h>
// function to compute absolute value
float absoluteValue(float x)
{
if(x < 0)
x = -x;
[code]....
The text I worked this code from uses the epsilon value arbitrarily. how is the epsilon value selected? I tried using this formula to derive the square root of 45. On paper I can go as far as 6.8 something. But once this value is reached it's still bigger than epsilon, so shouldn't the code keep running? The program generates 1.41 for 2, but since it could go further why does the while loop in squareRoot function terminate?
I wrote a program which sends a starting and ending range to other processes and the processes calculate the prime numbers in that range and return the count of prime numbers to the head process, process 0. But this is not working properly at the moment. I realize I still have to split up the range based on how many processes I have...I still have not figured out how I want to set that up. I
Code:
#include <stdio.h>
#include <stdlib.h>
#include <mpi.h>
int isPrime(int num);
int main(int argc, char **argv){
}
[code]....
Firstly, I'd like to say that I'm relatively new to functions and my course standards state that I'm now supposed to relay information from the user to the program via functions, this means that I'm no longer able to use 'printf/scanf' combos in the main function.
Is it possible to do it via functions? I've tried the following method for example, but to no avail.
Code:
#include <stdio.h>
int getlowR();
int main(void)
{
getlowR();
[Code] ....
I think the following works but then lowRange is native to the function, isn't it? How can I use it outside the function? For example, how would I go about actually printing the value acquired by the function in main?
In this exercise, write a rational number calculator that ask the user to enter two rational number:
a/b + c/d
and produce the result:
(ad+bc)/bd
exercise in c: write a program which calculates % of even numbers entered by a user in an array;
1) check if user hasn't entered float value; if has issue warning;
2) give the option for user to press "stop" to exit program any time.
int c,sk[100],i,sum1=0, sum2=0, rel;
printf ("How many numbers will you enter?
");
scanf ("%d", &c);
printf ("Enter %d numbers (to exit program press - stop)
", c);
[Code] ....
I'm having a problem with the two while statements in my UDF.
- 1. It will run both while loops twice...?
- 2. It now goes into a continuous loop.
- 3. When it did work, it would only return 1 value to the main()...?
#include <iostream> // for use of "cin" & "cout", endl...
#include <iomanip> // for formatting setw function
#include <cmath> // for the general math computations
#include <string> // for creating descriptive strings
#include <sstream> // used to convert a string to an integer
//user defined function
int userValue (int);
[code].....
I am trying to create a program that will calculate pi based on a user input for accuracy. If the user input .3 then when the leibniz infinite sum value at a particular i becomes less then the input of .3 then the loop will exit.
I have looked at a number of examples on the internet but I feel lost. I have put together working code that will infinitely output sums but I need the loop to stop when the sum value is less then the accuracy value.
My question is what is wrong with my while loop, why will it only give me infinite summations? How do I make it so that the loop will exit when my accuracy input is greater then the sum?
int main () {
double accuracy;
cout<<"Give an accurate number." << flush;//looks nice
cin>>accuracy;
int d;//initialize denominator
double pi = 0.0;
while(accuracy < d){
[Code]...
I'm trying to create a program that will take input from a user and calculate it in a do-while loop. The program does the calculation but the answer is wrong. The loop also doesn't work. The purpose of the program is to see how much an item will cost after a discount is taken off and tax is added.
#include <iostream>
#include <cmath>
using namespace std;
double original_cost;
double discount;
double tax;
double total;
char answer;
[Code]...
How to do the problem below using loop?
Input numbers until the user types a 0, then output the product of the non 0 numbers: e
E.g., if the user types 2 4 6 0, the program should output 48
I have created a program to calculate different measurements for a cylinder. Anyways, the end user has to input 3 variables.
Enter the lower radius: 6
Enter the upper radius: 5
Enter slant height: 2.236
The numbers are what "End User" would input. But I need to make it look like this when said "End User inputs the numbers.
Enter the lower radius: 6
Enter the upper radius: 5
Enter slant height: 2.236
Here is what I have for it, but I don't know what to put where.
printf("
Enter the lower radius: ");
scanf("%f", &lower_rad);
printf("Enter the upper radius: ");
scanf("%f", &upper_rad);
printf("Enter slant height: ");
scanf("%f", &slant_h);
I am trying to code a program that takes in user inputted data about percentages and using it to later on calculate a final grade. 4 percents are inputted, for Assignments, Midterm1, Midterm2, and Finals. If the percents dont add up to 1 (i tell the user to enter the decimal value) I set up and if statement to catch it and end the program. Except that if i type in
Assignments = .3
Midterm1 = .3
Midterm2 = .3
Finals = .1
the program doesn't recognize that they add up to 1. Heres the relevant portion of my code [URL] ....
Here's some examples of how it works [URL] ....
And heres what i dont understand [URL] ....
Why is it saying .3 + .3 + .3 + .1 != 1 when .1 + .3 + .3 + .3 == 1?
I'm trying to make a c++ program of this but i don't know how to use the bubble sorting.
Write a C++ application that asks the user to enter 10 numbers. The program then stores those numbers in an Array. The program should display the Mean , Median, and Mode.
Mean is the average of the 10 numbers.
Median is the average of the 5th and the 6th numbers. (But you have to arrange the numbers in ascending order first using Bubble Sort before calculating the Median.)
Mode is the most frequent number among the 10 numbers.