C :: Program To Find The Square Root Of A Number

I am writing a program to find the square root of a number. I am using the Newton-Raphson method..Just to clarify a bit of the code.. fabs(1/(x+1)) < 0.001 is to check for relative error..

EXAMPLE: for user entry of 100 if the iteration process ends in 10.055 the answer will return as 10 which is correct. But it isn't doing that.

It compiles I then proceed to run it..prompts me "Enter a number to find the square root of: I type 100 then hit enter...

"The square root of 100 is -1077834936"

My first time writing a program from complete scratch.

And I know there is a sqrt() function...just wanted to write my own.

Code:

#include <stdio.h>
#include <math.h>
double mysqrt(double a);
int main()
{
double a, result;
printf("Enter a number to find the square root of: ");

[Code]...