C++ :: Program That Will Ask User To Enter Area Of Square?
Feb 11, 2013
B. Circle in a Square Write a C++ program that will ask the user to enter the area of a square. Then the program will display the biggest area of a circle that will fit in a given square. Using math.h library is not allowed.
Area of the room. Your task is to write a program that will find the area of room in a given square maze.
Note. Use recursion for solving this problem.
Input: First line contains only one number N (3 <= N <= 10).The number that describes the size of the square maze. On the next N lines maze itself is inputed ('.' - empty cell,'*' - wall). And the last line contains two numbers - the row and column of the cell in the room those area you need to find.It is guaranteed that given cell is empty and that the maze is surrounded by walls on all sides.
Output: Output only one number - total amount of empty cells in the selected room.
Create a user-defined program that will compute the price per square inch of a cake using an “overloading”. The cake could be a circle or a square type. In the main function, ask for the price of a circle cake and its diameter, while for the square cake, ask for the price, its length and width. The process must be done inside the different function of each cake. (Note: two sub function for the computation of a circle and a rectangle)
Note that when I made this program something weird happen. After inserting the name, all things follow.
<code> #include "stdafx.h" #include <iostream> using namespace std; double areaRectangle(int l, int w); double radiusCircle(int r);
I am trying to make a program that will allow a user to enter their name, from this point, three options should be present for the user to choose, then from that point, two more options should be present. I have if else statements in a switch case and I get the "undeclared" error for the a in the first " if(specificage == a) ".
Write a C++ program that asks the user to enter an even number only. If the user enters an odd number the program should use input validation to ask the user to enter another number.
- The user can enter as many numbers as he wants
- The program should also keep a count of how many numbers entered and display how many odd and even numbers entered.
how can i make a program which allows a user to enter an input for a time interval for example i ask a question and sets the input to be entered within 10 seconds...
a program that allows the user to enter a statement and outputs statistics; number of vowels, number of constants, percentage of vowels and constants, number of words, number of punctuation characters
Write a program that prompts the user to enter an integer and then displays that integer as a product of its primes and if it is a prime then it should say so? Above is the question I have been given
#include <iostream> #include <vector> using namespace std; int main () { int num, result; cout << "Enter A Number " << endl; system ("pause"); return 0; }
This is what I have so far, do I have to use a for loop, a while loop or a do loop,
Write a program that asks the user to enter a student’s grades on four exams. The program should display the four grades and the average of the four grades,rounded to the nearest tenth. To add the grades, use a variable called total_grade, which you should initialize to zero.As the program prompts for and obtains each grade, add the grade to total_grade using the += operator.
Write a program that prompts the user to enter an item#, the program should determine if the item is in the file and print the price of the corresponding item. If the item is not in the file an error message should be printed.
All I have so far is
string item_no=0; cout<<"Enter a item#"; getline(cin,item_no); if stream openData;
My assignment is : Please use C type strings ( array representation of strings). Write a program that will ask the user to enter a string. It will then regard that string as a worked-on string and allow the user to perform the following editing functions on it:
s – search i – insert a – append d – delete a – append d – delete r – replace e – exit s – search
This option will allow the user to search for a specified string in the worked-on string. If the string is
found, it will display the starting index (position) of the searched string in the worked-on string.
here is what i have so far.
#include <iostream> #include <cstring> using namespace std; int main() { char a_string[80];
Okay, so my assignment for my C class is to generate a program that will allow the user to enter data for a stock and calculate the amount of stocks that ended up being positive, negative, and neutral.I tried to do this using one stock, here is my code;
I'm trying to create a program that allows the user to enter an unknown number of income and expense amounts. The program has to us see a while loop and display the income total, expense total, and total profit or loss. I've got it really close, but I'm doing the loop wrong. It counts the sentinel value (-1) towards the total, instead of just ending like it is supposed to.
#include <iostream> using namespace std; int main() { //declare variables double incomeInput; double expenseInput; double incomeTotal=0; double expenseTotal=0;
I have tried writing a code which takes two numbers from the user and calculates their square root then the roots are added up to return the sum. The program is coming out with loads of errors.
#include<iostream> #include<cmath> float main(){ using namespace std; float m1,m2,m3,m4,m5;
I am able to display a filled and hollow square by themselves, but I can't seem to be able to get them side by side.
So this is my code so far:
[/ #include <iostream> using namespace std; int main()
[Code]....
I can get the hollow square to show up, but the first square just shows up as a single line instead of a square. It seems that it ignores the first if statement in the second loop. I've tried not using an if statement in the second loop but it didn't seem to work either.
I am trying to write up something to have a user to enter a four digit number. Only four digits, Ex: 0001, 0116, or 9999. There is no getting around the selection 0001 or 0002. I understand if not done correctly, the first three 0's will be ignored.
I've been just playing around with what I have below but I just don't remember how to do it nor can I find a good example online to figure it out. I know it is not correct just typing to try to remember. I am aware that it is gibberish right now, this is just me brainstorming.
int number; cout<<("Please enter the four digit number(Ex: 0001): "); cin>> setw(2) >> number; cout<<)"Please enter four digit date. Two digits for month and two digits for year: "); cin>> date; if (number< || number > 30) cout << "Invalid choice. Try again." << endl; cin.clear();
I'm trying to validate my input. I require for the user to enter six doubles and if they don't then I want them to re-enter the information. Here is my code:
Code: while (1>0) { printf("Please enter arguments in the order: negative mass, positive mass, initial x-position, initial y-position, initial x-velocity, initial y-velocity: ");
if ( scanf("%lf %lf %lf %lf %lf %lf",&MassMinus,&MassPlus,&Pos[0][0],&Pos[0][1],&Vel[0][0],&Vel[0][1]) != 6) { printf("Not all numbers were assigned!
[Code] .....
At the moment it just waits if you enter less than six numbers and if you enter any more than 6 it just ignores anything after the sixth number (so pretty much does nothing). Also if I entered 1 2 a b 3 4 instead of entering six numbers it would register that as 1 2 0 0 3 4 but I want it to make the user input the numbers again. I'm also aware that "while (1>0)" isn't good programming form but I'm not really sure what to use instead?
I am simply trying to prompt a user to enter M for Male or F for Female. However, when I test run the program (what I've got so far below), any letter inputted is accepted and continues the program..?
#include <iostream> using namespace std; int main() { char gender; int maleBodyWeight;
When the user gives no input, they have to press enter twice before "Done." is printed.
cout << "What do you want the name of your page to be? "; std::getline(cin, pageTitle); if (cin.get() == ' ') pageTitle = "Welcome to Website."; cout << "Done. ";
Is there a way to print "Done." after pressing enter once?