C :: Program That Will Allow A User To Enter Their Name
Jul 2, 2013
I am trying to make a program that will allow a user to enter their name, from this point, three options should be present for the user to choose, then from that point, two more options should be present. I have if else statements in a switch case and I get the "undeclared" error for the a in the first " if(specificage == a) ".
B. Circle in a Square Write a C++ program that will ask the user to enter the area of a square. Then the program will display the biggest area of a circle that will fit in a given square. Using math.h library is not allowed.
Write a C++ program that asks the user to enter an even number only. If the user enters an odd number the program should use input validation to ask the user to enter another number.
- The user can enter as many numbers as he wants
- The program should also keep a count of how many numbers entered and display how many odd and even numbers entered.
how can i make a program which allows a user to enter an input for a time interval for example i ask a question and sets the input to be entered within 10 seconds...
a program that allows the user to enter a statement and outputs statistics; number of vowels, number of constants, percentage of vowels and constants, number of words, number of punctuation characters
Write a program that prompts the user to enter an integer and then displays that integer as a product of its primes and if it is a prime then it should say so? Above is the question I have been given
#include <iostream> #include <vector> using namespace std; int main () { int num, result; cout << "Enter A Number " << endl; system ("pause"); return 0; }
This is what I have so far, do I have to use a for loop, a while loop or a do loop,
Write a program that asks the user to enter a student’s grades on four exams. The program should display the four grades and the average of the four grades,rounded to the nearest tenth. To add the grades, use a variable called total_grade, which you should initialize to zero.As the program prompts for and obtains each grade, add the grade to total_grade using the += operator.
Write a program that prompts the user to enter an item#, the program should determine if the item is in the file and print the price of the corresponding item. If the item is not in the file an error message should be printed.
All I have so far is
string item_no=0; cout<<"Enter a item#"; getline(cin,item_no); if stream openData;
My assignment is : Please use C type strings ( array representation of strings). Write a program that will ask the user to enter a string. It will then regard that string as a worked-on string and allow the user to perform the following editing functions on it:
s – search i – insert a – append d – delete a – append d – delete r – replace e – exit s – search
This option will allow the user to search for a specified string in the worked-on string. If the string is
found, it will display the starting index (position) of the searched string in the worked-on string.
here is what i have so far.
#include <iostream> #include <cstring> using namespace std; int main() { char a_string[80];
Okay, so my assignment for my C class is to generate a program that will allow the user to enter data for a stock and calculate the amount of stocks that ended up being positive, negative, and neutral.I tried to do this using one stock, here is my code;
I'm trying to create a program that allows the user to enter an unknown number of income and expense amounts. The program has to us see a while loop and display the income total, expense total, and total profit or loss. I've got it really close, but I'm doing the loop wrong. It counts the sentinel value (-1) towards the total, instead of just ending like it is supposed to.
#include <iostream> using namespace std; int main() { //declare variables double incomeInput; double expenseInput; double incomeTotal=0; double expenseTotal=0;
I am trying to write up something to have a user to enter a four digit number. Only four digits, Ex: 0001, 0116, or 9999. There is no getting around the selection 0001 or 0002. I understand if not done correctly, the first three 0's will be ignored.
I've been just playing around with what I have below but I just don't remember how to do it nor can I find a good example online to figure it out. I know it is not correct just typing to try to remember. I am aware that it is gibberish right now, this is just me brainstorming.
int number; cout<<("Please enter the four digit number(Ex: 0001): "); cin>> setw(2) >> number; cout<<)"Please enter four digit date. Two digits for month and two digits for year: "); cin>> date; if (number< || number > 30) cout << "Invalid choice. Try again." << endl; cin.clear();
I'm trying to validate my input. I require for the user to enter six doubles and if they don't then I want them to re-enter the information. Here is my code:
Code: while (1>0) { printf("Please enter arguments in the order: negative mass, positive mass, initial x-position, initial y-position, initial x-velocity, initial y-velocity: ");
if ( scanf("%lf %lf %lf %lf %lf %lf",&MassMinus,&MassPlus,&Pos[0][0],&Pos[0][1],&Vel[0][0],&Vel[0][1]) != 6) { printf("Not all numbers were assigned!
[Code] .....
At the moment it just waits if you enter less than six numbers and if you enter any more than 6 it just ignores anything after the sixth number (so pretty much does nothing). Also if I entered 1 2 a b 3 4 instead of entering six numbers it would register that as 1 2 0 0 3 4 but I want it to make the user input the numbers again. I'm also aware that "while (1>0)" isn't good programming form but I'm not really sure what to use instead?
I am simply trying to prompt a user to enter M for Male or F for Female. However, when I test run the program (what I've got so far below), any letter inputted is accepted and continues the program..?
#include <iostream> using namespace std; int main() { char gender; int maleBodyWeight;
When the user gives no input, they have to press enter twice before "Done." is printed.
cout << "What do you want the name of your page to be? "; std::getline(cin, pageTitle); if (cin.get() == ' ') pageTitle = "Welcome to Website."; cout << "Done. ";
Is there a way to print "Done." after pressing enter once?
I'm doing an exercise which involves for the user to enter the size of the dynamic array and then enter the numbers, but then it needs to create another dynamic array with the same numbers expect if the number repeats it only has one of it. I've done the first part of the exercise but I'm having trouble with creating the new array.
Having problem with my code. i keep getting an error towards the bottom of the code. i need the user to enter a word. and with that word convert it to numbers. once i have convert it if it is bigger than 20 i have to add the two digits together and get print out the array that response to it.
example" ALEX A=1 L=12 E=5 X=23
1+12+5+23= 41 //since its bigger than 20 you add 4 and 1 together so it will be 5. after that you print the 5th element of array
#include <iomanip> #include <iostream> #include <string> using namespace std; int main() { string name;
My program was to allow the user to enter a value as a C string in the form: xxx,xxx,xxx,xxx,xxx.xx, where x can be any digit. Well, so far here is my attempt. I think the question is, would I have to implement a switch statement for the digits, the comma, and the decimal, so that when a user inputs, let say 52,000.00 the switch statements would read the 1st digit, checks for decimals/commas and if not, proceed to read 2nd digit, and repeat?
Code: #include <iostream> #include <string> int main() { using namespace std; char buffer[256]; char tempBuff[256] = {'
Enter as many numbers as you want as long as the user doesn't type 'e' to exit.
Problem: When I enter a number, it works fine, but if I enter e then it'll go in an infinite loop since the letter is being stored in an int variable. How can I (when I press 'e') make it convert to a char to make it end the program?
#include <iostream> using namespace std; int main() { int num; cout << "Enter a number or press e to exit:";
[Code] ....
Our class has just started c++ and we have not learned arrays and classes yet, so I'm guessing there is a way to do this without it? Or no?
Create a program that will ask the user to enter a decimal value (1-999999) then display its corresponding binary numbers. Repeat this process until the value entered is equal to 0. Use the following Function Prototype:
void BinCodes(int value); Sample Input/Output: Enter a Decimal: 35 Binary: 100011 Enter a Decimal: 184 Binary: 10111000 Enter a Decimal: 0
What I want to do is create a file that will ask the user to enter his info,n then store it in a text file The screen will ask the user if he wants to update his info. if he says yes then the screen will be cleared and the old info will be printed on the screen. The user will enter his new info that will be stored in a new file. My problem is that once the user finishes entering his input the program just closes D: and the rest of the program won't run.
Code:
int main() { string ans; ofstream Xfile("original.txt"); cout <<"Enter your name and address please"<<endl; cout<<"Press Ctrl+Z+Enter when you are done"<<endl; string name_and_street;
