C++ :: Enter As Many Numbers Until User Doesn't Type E To Exit
Oct 27, 2013
Enter as many numbers as you want as long as the user doesn't type 'e' to exit.
Problem: When I enter a number, it works fine, but if I enter e then it'll go in an infinite loop since the letter is being stored in an int variable. How can I (when I press 'e') make it convert to a char to make it end the program?
#include <iostream>
using namespace std;
int main() {
int num;
cout << "Enter a number or press e to exit:";
[Code] ....
Our class has just started c++ and we have not learned arrays and classes yet, so I'm guessing there is a way to do this without it? Or no?
I've seen some threads that include the information about what data types one has to use usually to put a number of 12digit. But honestly speaking none of them works for me & it takes me a lot suffering about the data type. Even I've googled but I didn't get any specific result.
So, which data type I'd have to use to enter 12digit number.
I'm writing a code to find the largest prime factor of the number 600851475143
My assignment is : Please use C type strings ( array representation of strings). Write a program that will ask the user to enter a string. It will then regard that string as a worked-on string and allow the user to perform the following editing functions on it:
s – search i – insert a – append d – delete a – append d – delete r – replace e – exit s – search
This option will allow the user to search for a specified string in the worked-on string. If the string is
found, it will display the starting index (position) of the searched string in the worked-on string.
here is what i have so far.
#include <iostream> #include <cstring> using namespace std; int main() { char a_string[80];
Having problem with my code. i keep getting an error towards the bottom of the code. i need the user to enter a word. and with that word convert it to numbers. once i have convert it if it is bigger than 20 i have to add the two digits together and get print out the array that response to it.
example" ALEX A=1 L=12 E=5 X=23
1+12+5+23= 41 //since its bigger than 20 you add 4 and 1 together so it will be 5. after that you print the 5th element of array
#include <iomanip> #include <iostream> #include <string> using namespace std; int main() { string name;
Create a program that will ask the user to enter a decimal value (1-999999) then display its corresponding binary numbers. Repeat this process until the value entered is equal to 0. Use the following Function Prototype:
void BinCodes(int value); Sample Input/Output: Enter a Decimal: 35 Binary: 100011 Enter a Decimal: 184 Binary: 10111000 Enter a Decimal: 0
So I have been assigned a program that counts keystrokes, alphabetical characters, and vowels. I have the program working as desired but I just can't figure out how to make it end upon ONLY the "return" key being pressed.
Code: #include <stdio.h> #include <stdlib.h> #include <ctype.h> int main ( void ) {
Thread 1 does some background work, and thread2 is waiting for the user's input. If I join thread1 then the app can never exit. If I neither join nor detach thread1 then I get "terminate called without an active exception Aborted" which is not a good thing to have. If I do detach on thread1 does thread1 ever terminate? If not, how to terminate it? Also, how do I check if it's terminated or not?
Thread1 does some background work, and thread2 is waiting for the user's input.
If I join thread1 then the app can never exit. If I neither join nor detach thread1 then I get "terminate called without an active exception Aborted" which is not a good thing to have.
If I do detach on thread1 does thread1 ever terminate? If not, how to terminate it? Also, how do I check if it's terminated or not? -- I realize it's platform specific, I am on Linux.
I have my Reverse Polish calculator compiling and everything but for the assignment I need to handle a few exceptions that I can't seem to get. First off I'm trying to make the program exit if the user enters only "0" but since the input i'm using is string, I cant figure out how to code
"If the first node is 0 and the next node = NULL, return true"
Here is my code: #include<iomanip> #include<iostream> #include<stdlib.h> #include<stdio.h> #include<string> #include<sstream> using namespace std;
basically we were asked to make a program that will print everything before the user hits the enter button. we cannot use fgets and we have to use pointers here.
not sure what exactly to do. We were told not to use fgets cause it's so easy and we need to incorporate pointers in this project..
I'm having some problems with changing an array of numbers of type char to type int. Every time i try to sum 2 array indexed values it returns some letter or symbol. Also, if i change the type of the array in the functions the compiler gives me an error message. I would also like to add that the problem requires that the first two arrays be char so each individual number gets assigned to a different value.
My current code is:
Code: #include <iostream> void input(char a[], char b[], int& size_a, int& size_b); void convert(char a[], int size); void reverse(char a[], int size); void add(char a[], char b[], int c[], int size); int main()
I am trying to make a program that will allow a user to enter their name, from this point, three options should be present for the user to choose, then from that point, two more options should be present. I have if else statements in a switch case and I get the "undeclared" error for the a in the first " if(specificage == a) ".
I am trying to write up something to have a user to enter a four digit number. Only four digits, Ex: 0001, 0116, or 9999. There is no getting around the selection 0001 or 0002. I understand if not done correctly, the first three 0's will be ignored.
I've been just playing around with what I have below but I just don't remember how to do it nor can I find a good example online to figure it out. I know it is not correct just typing to try to remember. I am aware that it is gibberish right now, this is just me brainstorming.
int number; cout<<("Please enter the four digit number(Ex: 0001): "); cin>> setw(2) >> number; cout<<)"Please enter four digit date. Two digits for month and two digits for year: "); cin>> date; if (number< || number > 30) cout << "Invalid choice. Try again." << endl; cin.clear();
I'm trying to validate my input. I require for the user to enter six doubles and if they don't then I want them to re-enter the information. Here is my code:
Code: while (1>0) { printf("Please enter arguments in the order: negative mass, positive mass, initial x-position, initial y-position, initial x-velocity, initial y-velocity: ");
if ( scanf("%lf %lf %lf %lf %lf %lf",&MassMinus,&MassPlus,&Pos[0][0],&Pos[0][1],&Vel[0][0],&Vel[0][1]) != 6) { printf("Not all numbers were assigned!
[Code] .....
At the moment it just waits if you enter less than six numbers and if you enter any more than 6 it just ignores anything after the sixth number (so pretty much does nothing). Also if I entered 1 2 a b 3 4 instead of entering six numbers it would register that as 1 2 0 0 3 4 but I want it to make the user input the numbers again. I'm also aware that "while (1>0)" isn't good programming form but I'm not really sure what to use instead?
I am simply trying to prompt a user to enter M for Male or F for Female. However, when I test run the program (what I've got so far below), any letter inputted is accepted and continues the program..?
#include <iostream> using namespace std; int main() { char gender; int maleBodyWeight;
B. Circle in a Square Write a C++ program that will ask the user to enter the area of a square. Then the program will display the biggest area of a circle that will fit in a given square. Using math.h library is not allowed.
When the user gives no input, they have to press enter twice before "Done." is printed.
cout << "What do you want the name of your page to be? "; std::getline(cin, pageTitle); if (cin.get() == ' ') pageTitle = "Welcome to Website."; cout << "Done. ";
Is there a way to print "Done." after pressing enter once?
Write a C++ program that asks the user to enter an even number only. If the user enters an odd number the program should use input validation to ask the user to enter another number.
- The user can enter as many numbers as he wants
- The program should also keep a count of how many numbers entered and display how many odd and even numbers entered.
I'm doing an exercise which involves for the user to enter the size of the dynamic array and then enter the numbers, but then it needs to create another dynamic array with the same numbers expect if the number repeats it only has one of it. I've done the first part of the exercise but I'm having trouble with creating the new array.
My program was to allow the user to enter a value as a C string in the form: xxx,xxx,xxx,xxx,xxx.xx, where x can be any digit. Well, so far here is my attempt. I think the question is, would I have to implement a switch statement for the digits, the comma, and the decimal, so that when a user inputs, let say 52,000.00 the switch statements would read the 1st digit, checks for decimals/commas and if not, proceed to read 2nd digit, and repeat?
Code: #include <iostream> #include <string> int main() { using namespace std; char buffer[256]; char tempBuff[256] = {'
