Visual C++ :: Allow User To Enter A Value As C String In Certain Form
Oct 14, 2013
My program was to allow the user to enter a value as a C string in the form: xxx,xxx,xxx,xxx,xxx.xx, where x can be any digit. Well, so far here is my attempt. I think the question is, would I have to implement a switch statement for the digits, the comma, and the decimal, so that when a user inputs, let say 52,000.00 the switch statements would read the 1st digit, checks for decimals/commas and if not, proceed to read 2nd digit, and repeat?
Code:
#include <iostream>
#include <string>
int main() {
using namespace std;
char buffer[256];
char tempBuff[256] = {'
[Code] ....
View 3 Replies
ADVERTISEMENT
Oct 24, 2014
/* Program is to let the user enter a string and will output the sting in all uppercase letters. */
#include <cctype>
#include <iostream>
#include <string>
using namespace std;
char str1[80];
[Code] ....
I am trying to get the cin.get working where the user is allowed to enter an 80 character string and how to do that.
View 1 Replies
View Related
Oct 18, 2014
My assignment is : Please use C type strings ( array representation of strings). Write a program that will ask the user to enter a string. It will then regard that string as a worked-on string and allow the user to perform the following editing functions on it:
s – search
i – insert
a – append
d – delete
a – append
d – delete
r – replace
e – exit
s – search
This option will allow the user to search for a specified string in the worked-on string. If the string is
found, it will display the starting index (position) of the searched string in the worked-on string.
here is what i have so far.
#include <iostream>
#include <cstring>
using namespace std;
int main() {
char a_string[80];
[Code] .....
View 4 Replies
View Related
Nov 9, 2014
What I want to do is create a file that will ask the user to enter his info,n then store it in a text file The screen will ask the user if he wants to update his info. if he says yes then the screen will be cleared and the old info will be printed on the screen. The user will enter his new info that will be stored in a new file. My problem is that once the user finishes entering his input the program just closes D: and the rest of the program won't run.
Code:
int main()
{
string ans;
ofstream Xfile("original.txt");
cout <<"Enter your name and address please"<<endl;
cout<<"Press Ctrl+Z+Enter when you are done"<<endl;
string name_and_street;
[Code]...
View 3 Replies
View Related
Jan 28, 2015
Code:
#include<stdio.h>
#include<stdlib.h>
#include<ctype.h>
#include<string.h>
int main(void) {
int i;
char *str;
int len = 1;
[Code]...
View 3 Replies
View Related
Aug 8, 2014
How can I create in my C++ program so a user can paste a text and then choose a character on specific line and place?. The above thing isn't that important. I just want to place a character on a specific line and place.
I mean something like this:
Enter a character:
You choosed " / "
On which line do want the character?
You choosed "Line 1 and 2"
Where do you want the the to appear on the line? (left or right)
You choose left.
Results:
Line 1. / hello
Line 2. / hello
View 8 Replies
View Related
Sep 14, 2013
I'm expected to write a c program for this question :
Using these header files
#include <stdio.h>
#include <conio.h>
Question : Write a program that will prompt the user to enter an integer value and a character code to indicate whether they want to do a Kilogram to Pounds conversion (A) or a Pounds to Kilogram (B) conversion. Note that 1 kg = 2.2 pounds. The program should then do the necessary conversion indicated by the code and display the newly converted value to the screen.
View 1 Replies
View Related
Apr 22, 2014
I hav created mdi parent form that contain one user control. I want to access that user control from one of the child form
View 4 Replies
View Related
Oct 9, 2013
I am trying to write a program that ask the user to enter a sentence and then a word to be searched for in the sentence. The program must then search for the word in the sentence in a loop and continue to output each place the word is found. For example if the sentence is : I like pickles, pickles, pickles
and you searched for pickles it would return pickles found at 7, pickles found at 16, pickles found at 25.
I am having trouble writing the equation to make the find keep searching after each occurrence of the word being searched. Here is the code I have so far
HTML Code:
#include <iostream>
#include <string>
using namespace std;
int main() {
string paragraph;
[Code] ....
View 5 Replies
View Related
Sep 8, 2014
Write a program to enter data into a table and display on the screen in tabular form. I want to know where are the errors.
#include<iostream>
using namespace std;
int main() {
int table[3][4];
int r,c,i;
r=c=0;
while(r<=2)
[Code] .....
View 3 Replies
View Related
Jul 2, 2013
I am trying to make a program that will allow a user to enter their name, from this point, three options should be present for the user to choose, then from that point, two more options should be present. I have if else statements in a switch case and I get the "undeclared" error for the a in the first " if(specificage == a) ".
NOTE: I use Code::Blocks.
Here is the code:
Code:
#include <stdio.h>
#include <string.h>
int main(){
char name[50];
char ageclass[50];
char specificage[50];
[Code] ....
View 3 Replies
View Related
Mar 29, 2014
Ok so I searched this site, and google string arrays, but I couldn't find anything on how to create an array to accept string input. In other words the strings are unknown, until the user inputs them..
so code would say input a name..user enters Tom, and its inserted into the array.. and if another name is entered ..lets say Lisa..Lisa is added to the array..so now in the array we have tom and Lisa..
Everything I read only shows the array already having the strings declared...
string n;
string name[n]={};
View 1 Replies
View Related
Aug 22, 2014
I am trying to write up something to have a user to enter a four digit number. Only four digits, Ex: 0001, 0116, or 9999. There is no getting around the selection 0001 or 0002. I understand if not done correctly, the first three 0's will be ignored.
I've been just playing around with what I have below but I just don't remember how to do it nor can I find a good example online to figure it out. I know it is not correct just typing to try to remember. I am aware that it is gibberish right now, this is just me brainstorming.
int number;
cout<<("Please enter the four digit number(Ex: 0001):
");
cin>> setw(2) >> number;
cout<<)"Please enter four digit date. Two digits for month and two digits for year:
");
cin>> date;
if (number< || number > 30)
cout << "Invalid choice. Try again." << endl;
cin.clear();
View 2 Replies
View Related
Mar 3, 2014
For my code, I want the user to enter 4 integers, which get stored in an array. Here are the lines I wrote relevant to this part:
Code:
printf("Enter 4 integers:
");
scanf("%d %d %d %d," &a, &b, &c, &d);
z[4] = { a, b, c, d};
Would this be correct?
View 5 Replies
View Related
Dec 20, 2014
I'm trying to validate my input. I require for the user to enter six doubles and if they don't then I want them to re-enter the information. Here is my code:
Code:
while (1>0) {
printf("Please enter arguments in the order: negative mass, positive mass, initial x-position, initial y-position, initial x-velocity, initial y-velocity:
");
if ( scanf("%lf %lf %lf %lf %lf %lf",&MassMinus,&MassPlus,&Pos[0][0],&Pos[0][1],&Vel[0][0],&Vel[0][1]) != 6) {
printf("Not all numbers were assigned!
[Code] .....
At the moment it just waits if you enter less than six numbers and if you enter any more than 6 it just ignores anything after the sixth number (so pretty much does nothing). Also if I entered 1 2 a b 3 4 instead of entering six numbers it would register that as 1 2 0 0 3 4 but I want it to make the user input the numbers again. I'm also aware that "while (1>0)" isn't good programming form but I'm not really sure what to use instead?
View 11 Replies
View Related
Dec 24, 2014
I am simply trying to prompt a user to enter M for Male or F for Female. However, when I test run the program (what I've got so far below), any letter inputted is accepted and continues the program..?
#include <iostream>
using namespace std;
int main() {
char gender;
int maleBodyWeight;
[Code] .....
View 2 Replies
View Related
Feb 11, 2013
B. Circle in a Square Write a C++ program that will ask the user to enter the area of a square. Then the program will display the biggest area of a circle that will fit in a given square. Using math.h library is not allowed.
View 1 Replies
View Related
Aug 25, 2013
When the user gives no input, they have to press enter twice before "Done." is printed.
cout << "What do you want the name of your page to be? ";
std::getline(cin, pageTitle);
if (cin.get() == '
')
pageTitle = "Welcome to Website.";
cout << "Done.
";
Is there a way to print "Done." after pressing enter once?
View 2 Replies
View Related
Mar 23, 2014
Write a C++ program that asks the user to enter an even number only. If the user enters an odd number the program should use input validation to ask the user to enter another number.
- The user can enter as many numbers as he wants
- The program should also keep a count of how many numbers entered and display how many odd and even numbers entered.
View 1 Replies
View Related
Apr 22, 2013
I'm doing an exercise which involves for the user to enter the size of the dynamic array and then enter the numbers, but then it needs to create another dynamic array with the same numbers expect if the number repeats it only has one of it. I've done the first part of the exercise but I'm having trouble with creating the new array.
View 10 Replies
View Related
Jan 28, 2015
Having problem with my code. i keep getting an error towards the bottom of the code. i need the user to enter a word. and with that word convert it to numbers. once i have convert it if it is bigger than 20 i have to add the two digits together and get print out the array that response to it.
example" ALEX
A=1
L=12
E=5
X=23
1+12+5+23= 41 //since its bigger than 20 you add 4 and 1 together so it will be 5. after that you print the 5th element of array
#include <iomanip>
#include <iostream>
#include <string>
using namespace std;
int main()
{
string name;
[Code]...
View 2 Replies
View Related
Oct 27, 2013
Enter as many numbers as you want as long as the user doesn't type 'e' to exit.
Problem: When I enter a number, it works fine, but if I enter e then it'll go in an infinite loop since the letter is being stored in an int variable. How can I (when I press 'e') make it convert to a char to make it end the program?
#include <iostream>
using namespace std;
int main() {
int num;
cout << "Enter a number or press e to exit:";
[Code] ....
Our class has just started c++ and we have not learned arrays and classes yet, so I'm guessing there is a way to do this without it? Or no?
View 2 Replies
View Related
Apr 23, 2014
how can i make a program which allows a user to enter an input for a time interval for example i ask a question and sets the input to be entered within 10 seconds...
View 4 Replies
View Related
Mar 22, 2013
I'm stuck because I can make the calculator just find but the user will have to press enter after every number, what is s solution to this?
#include <iostream>
#include <string>
using namespace std;
int a = 1, b, c;
string symbol;
int multiplyFunction();
[Code] .....
View 6 Replies
View Related
Dec 12, 2013
a program that allows the user to enter a statement and outputs statistics; number of vowels, number of constants, percentage of vowels and constants, number of words, number of punctuation characters
View 2 Replies
View Related
Sep 13, 2013
Create a program that will ask the user to enter a decimal value (1-999999) then display its corresponding binary numbers. Repeat this process until the value entered is equal to 0. Use the following Function Prototype:
void BinCodes(int value);
Sample Input/Output:
Enter a Decimal: 35
Binary: 100011
Enter a Decimal: 184
Binary: 10111000
Enter a Decimal: 0
View 4 Replies
View Related