When the user gives no input, they have to press enter twice before "Done." is printed.
cout << "What do you want the name of your page to be? ";
std::getline(cin, pageTitle);
if (cin.get() == '
')
pageTitle = "Welcome to Website.";
cout << "Done.
";
Is there a way to print "Done." after pressing enter once?
I'm stuck because I can make the calculator just find but the user will have to press enter after every number, what is s solution to this?
#include <iostream>
#include <string>
using namespace std;
int a = 1, b, c;
string symbol;
int multiplyFunction();
[Code] .....
Code:
#include<iostream.h>
#include<conio.h>
#include<string.h>
void main() {
clrscr();
int i=0,flag=1;
cout<<"Enter the password.";
[Code] ....
When I input the password, the Backspace and the Enter keys are not working as they should. Also, I want to know if I can press enter only once to input the password, not twice.
Compiler is Turbo C++ 3.0 on Windows 7.
Code:
#include<stdio.h>
#include<stdlib.h>
#include<ctype.h>
#include<string.h>
int main(void) {
int i;
char *str;
int len = 1;
[Code]...
How can i jump from textBox to next texBox when i press enterKey in c# , what i the event for that .....
View 2 Replies View RelatedI'm trying to validate my input. I require for the user to enter six doubles and if they don't then I want them to re-enter the information. Here is my code:
Code:
while (1>0) {
printf("Please enter arguments in the order: negative mass, positive mass, initial x-position, initial y-position, initial x-velocity, initial y-velocity:
");
if ( scanf("%lf %lf %lf %lf %lf %lf",&MassMinus,&MassPlus,&Pos[0][0],&Pos[0][1],&Vel[0][0],&Vel[0][1]) != 6) {
printf("Not all numbers were assigned!
[Code] .....
At the moment it just waits if you enter less than six numbers and if you enter any more than 6 it just ignores anything after the sixth number (so pretty much does nothing). Also if I entered 1 2 a b 3 4 instead of entering six numbers it would register that as 1 2 0 0 3 4 but I want it to make the user input the numbers again. I'm also aware that "while (1>0)" isn't good programming form but I'm not really sure what to use instead?
how can i make a program which allows a user to enter an input for a time interval for example i ask a question and sets the input to be entered within 10 seconds...
View 4 Replies View RelatedMy program closes after the out even though i've used cin.get():
I want the program to stay open at least until you press enter, even after the whole output.
Code:
#include <iostream>#include <string>
int main()
{
std::cout << "Please enter your name";
std::string name;
std::cin>> name;
// build the message that we intend to write
[Code] .....
It seems to be going null. I can't get a null value, I want it to accept input till the user hits enter with no text typed. I've tried checking to see if the input is NULL, "", and " " all to no avail.
Code:
#include <stdio.h>
#include <sys/shm.h>
#include <sys/stat.h>
#include <iostream>
#include <fstream>
#include <string.h>
#include <cstring>
using namespace std;
int main() {
string info = "";
[Code] ....
So I have been assigned a program that counts keystrokes, alphabetical characters, and vowels. I have the program working as desired but I just can't figure out how to make it end upon ONLY the "return" key being pressed.
Code:
#include <stdio.h>
#include <stdlib.h>
#include <ctype.h>
int main ( void ) {
[Code] .....
I have been trying to make a small program that I will be using in a larger program that will make the user press space to see the next line of output.
Not exactly sure what I'm doing wrong, but I'm pretty sure that I need to put the space that the user would enter into an output file, and the read the input file
It runs, but it doesn't allow me press space before showing the next line.
I added a getline(cin, charVar) before, but I got a whole bunch of errors.
#include <iostream>
#include <string>
#include <cctype>
#include <cstdlib>
#include <fstream>
using namespace std;
// function for dialouge
[Code] ....
Where in registry the Explorer stores tray icons visibility settings? (Always show, show only notifications, or always hide.)
I know that Microsoft doesn't want us to change these from a program, which may be OK for a home computer, but it becomes a major pain in the ___ for an enterprise environment (as there seems to be no GPO to do this either.) I've seen couple commercial products that were able to do this, so I'm sure there's a "hack" somewhere...
I am trying to make a program that will allow a user to enter their name, from this point, three options should be present for the user to choose, then from that point, two more options should be present. I have if else statements in a switch case and I get the "undeclared" error for the a in the first " if(specificage == a) ".
NOTE: I use Code::Blocks.
Here is the code:
Code:
#include <stdio.h>
#include <string.h>
int main(){
char name[50];
char ageclass[50];
char specificage[50];
[Code] ....
I wrote a program that reads user input string using fgets() function. After this, program will ask if the user wants to save the string to file or does the user want to change the string or quit without saving. If user wants to change the string this must be made possible by asking for the string again. After this, menu will be printed again printing the choices available.
I had to flush stdin before getting changing input! However, problem is "Why do I have to hit return key 2 times, when I choose 2 and input string again." (I use code block 13.12 with windows 8.1 laptop) */
Code:
#include <stdio.h>
#include <string.h>
#define MAX 50
[Code]....
I am trying to write up something to have a user to enter a four digit number. Only four digits, Ex: 0001, 0116, or 9999. There is no getting around the selection 0001 or 0002. I understand if not done correctly, the first three 0's will be ignored.
I've been just playing around with what I have below but I just don't remember how to do it nor can I find a good example online to figure it out. I know it is not correct just typing to try to remember. I am aware that it is gibberish right now, this is just me brainstorming.
int number;
cout<<("Please enter the four digit number(Ex: 0001):
");
cin>> setw(2) >> number;
cout<<)"Please enter four digit date. Two digits for month and two digits for year:
");
cin>> date;
if (number< || number > 30)
cout << "Invalid choice. Try again." << endl;
cin.clear();
For my code, I want the user to enter 4 integers, which get stored in an array. Here are the lines I wrote relevant to this part:
Code:
printf("Enter 4 integers:
");
scanf("%d %d %d %d," &a, &b, &c, &d);
z[4] = { a, b, c, d};
Would this be correct?
I am simply trying to prompt a user to enter M for Male or F for Female. However, when I test run the program (what I've got so far below), any letter inputted is accepted and continues the program..?
#include <iostream>
using namespace std;
int main() {
char gender;
int maleBodyWeight;
[Code] .....
B. Circle in a Square Write a C++ program that will ask the user to enter the area of a square. Then the program will display the biggest area of a circle that will fit in a given square. Using math.h library is not allowed.
View 1 Replies View RelatedWrite a C++ program that asks the user to enter an even number only. If the user enters an odd number the program should use input validation to ask the user to enter another number.
- The user can enter as many numbers as he wants
- The program should also keep a count of how many numbers entered and display how many odd and even numbers entered.
I'm doing an exercise which involves for the user to enter the size of the dynamic array and then enter the numbers, but then it needs to create another dynamic array with the same numbers expect if the number repeats it only has one of it. I've done the first part of the exercise but I'm having trouble with creating the new array.
View 10 Replies View RelatedHaving problem with my code. i keep getting an error towards the bottom of the code. i need the user to enter a word. and with that word convert it to numbers. once i have convert it if it is bigger than 20 i have to add the two digits together and get print out the array that response to it.
example" ALEX
A=1
L=12
E=5
X=23
1+12+5+23= 41 //since its bigger than 20 you add 4 and 1 together so it will be 5. after that you print the 5th element of array
#include <iomanip>
#include <iostream>
#include <string>
using namespace std;
int main()
{
string name;
[Code]...
My program was to allow the user to enter a value as a C string in the form: xxx,xxx,xxx,xxx,xxx.xx, where x can be any digit. Well, so far here is my attempt. I think the question is, would I have to implement a switch statement for the digits, the comma, and the decimal, so that when a user inputs, let say 52,000.00 the switch statements would read the 1st digit, checks for decimals/commas and if not, proceed to read 2nd digit, and repeat?
Code:
#include <iostream>
#include <string>
int main() {
using namespace std;
char buffer[256];
char tempBuff[256] = {'
[Code] ....
Basically I'm having trouble reading more than one character.I want the user to input character traits(ie, w, a), if two traits are entered they get the job.
But I cannot get my program to read more than one character input.
This is what I have so far...
#include <iostream>
using namespace std;
int main(){
char input;
int count = 0;
[Code] .....
When the program is processing/sleeping, those char input at that time would not goes into the buffer until the next input request (such as calling istream::get). The program below shows this.
#include <iostream>
#include <streambuf>
#include <chrono>
#include <thread>
int main() {
std::cout << "Sleeping...
[Code] ....
I wonder if there is a way to distinguish between the input comes from the time that does not request it (i.e., during processing or sleeping) and those comes after the time does request it (in the example, after "Input something: ").
Enter as many numbers as you want as long as the user doesn't type 'e' to exit.
Problem: When I enter a number, it works fine, but if I enter e then it'll go in an infinite loop since the letter is being stored in an int variable. How can I (when I press 'e') make it convert to a char to make it end the program?
#include <iostream>
using namespace std;
int main() {
int num;
cout << "Enter a number or press e to exit:";
[Code] ....
Our class has just started c++ and we have not learned arrays and classes yet, so I'm guessing there is a way to do this without it? Or no?
a program that allows the user to enter a statement and outputs statistics; number of vowels, number of constants, percentage of vowels and constants, number of words, number of punctuation characters
View 2 Replies View Related