how can i make a program which allows a user to enter an input for a time interval for example i ask a question and sets the input to be entered within 10 seconds...
View 4 RepliesI am writing a C++ program which takes date & time input from the user. This is then parsed into a struct such as:
struct time
{
short year;
short month;
short day;
short hour;
short min;
};
My question is: how can I convert such a struct into a time_t object, which is an unsigned long giving the time as the number of seconds elapsed since the epoch Jan 1st 1970, 00:00, as set out in time.h.
I am wondering if this can be achieved using the standard library, or whether I just need to write a function to perform the appropriate arithmetic.
I have a certain piece of code that I want to run every 2 minutes. One of my ideas is to get the time and modules that with whatever number represents 2 minutes. Would this work?
View 4 Replies View RelatedI'm trying to validate my input. I require for the user to enter six doubles and if they don't then I want them to re-enter the information. Here is my code:
Code:
while (1>0) {
printf("Please enter arguments in the order: negative mass, positive mass, initial x-position, initial y-position, initial x-velocity, initial y-velocity:
");
if ( scanf("%lf %lf %lf %lf %lf %lf",&MassMinus,&MassPlus,&Pos[0][0],&Pos[0][1],&Vel[0][0],&Vel[0][1]) != 6) {
printf("Not all numbers were assigned!
[Code] .....
At the moment it just waits if you enter less than six numbers and if you enter any more than 6 it just ignores anything after the sixth number (so pretty much does nothing). Also if I entered 1 2 a b 3 4 instead of entering six numbers it would register that as 1 2 0 0 3 4 but I want it to make the user input the numbers again. I'm also aware that "while (1>0)" isn't good programming form but I'm not really sure what to use instead?
When the user gives no input, they have to press enter twice before "Done." is printed.
cout << "What do you want the name of your page to be? ";
std::getline(cin, pageTitle);
if (cin.get() == '
')
pageTitle = "Welcome to Website.";
cout << "Done.
";
Is there a way to print "Done." after pressing enter once?
It seems to be going null. I can't get a null value, I want it to accept input till the user hits enter with no text typed. I've tried checking to see if the input is NULL, "", and " " all to no avail.
Code:
#include <stdio.h>
#include <sys/shm.h>
#include <sys/stat.h>
#include <iostream>
#include <fstream>
#include <string.h>
#include <cstring>
using namespace std;
int main() {
string info = "";
[Code] ....
I am trying to make a program that will allow a user to enter their name, from this point, three options should be present for the user to choose, then from that point, two more options should be present. I have if else statements in a switch case and I get the "undeclared" error for the a in the first " if(specificage == a) ".
NOTE: I use Code::Blocks.
Here is the code:
Code:
#include <stdio.h>
#include <string.h>
int main(){
char name[50];
char ageclass[50];
char specificage[50];
[Code] ....
B. Circle in a Square Write a C++ program that will ask the user to enter the area of a square. Then the program will display the biggest area of a circle that will fit in a given square. Using math.h library is not allowed.
View 1 Replies View RelatedWrite a C++ program that asks the user to enter an even number only. If the user enters an odd number the program should use input validation to ask the user to enter another number.
- The user can enter as many numbers as he wants
- The program should also keep a count of how many numbers entered and display how many odd and even numbers entered.
a program that allows the user to enter a statement and outputs statistics; number of vowels, number of constants, percentage of vowels and constants, number of words, number of punctuation characters
View 2 Replies View RelatedWrite a program that prompts the user to enter an integer and then displays that integer as a product of its primes and if it is a prime then it should say so? Above is the question I have been given
#include <iostream>
#include <vector>
using namespace std;
int main () {
int num, result;
cout << "Enter A Number " << endl;
system ("pause");
return 0;
}
This is what I have so far, do I have to use a for loop, a while loop or a do loop,
I have to write a program for class in which users will be inputting:
start time = startTime
number of minutes = callDuration
so first off, teacher wants us to input time as a floating point number such as 09.00
How do I validate the time so that users cant input i.e. 09.61 for every hour? In other words, so the user cant input minutes 60-99 for every hour.
then, when calculating:
endTime = startTime + callDuration
how would I make endTime display a correct time in such a situation: endTime = 09.45 + 00.30
so that it displays 10.15 not 09.75
Code:
#include<iostream.h>
#include<conio.h>
#include<string.h>
void main() {
clrscr();
int i=0,flag=1;
cout<<"Enter the password.";
[Code] ....
When I input the password, the Backspace and the Enter keys are not working as they should. Also, I want to know if I can press enter only once to input the password, not twice.
Compiler is Turbo C++ 3.0 on Windows 7.
Write a program that asks the user to enter a student’s grades on four exams. The program should display the four grades and the average of the four grades,rounded to the nearest tenth. To add the grades, use a variable called total_grade, which you should initialize to zero.As the program prompts for and obtains each grade, add the grade to total_grade using the += operator.
View 3 Replies View RelatedWrite a program that prompts the user to enter an item#, the program should determine if the item is in the file and print the price of the corresponding item. If the item is not in the file an error message should be printed.
All I have so far is
string item_no=0;
cout<<"Enter a item#";
getline(cin,item_no);
if stream openData;
I need to finish the rest in pseudo code
My assignment is : Please use C type strings ( array representation of strings). Write a program that will ask the user to enter a string. It will then regard that string as a worked-on string and allow the user to perform the following editing functions on it:
s – search
i – insert
a – append
d – delete
a – append
d – delete
r – replace
e – exit
s – search
This option will allow the user to search for a specified string in the worked-on string. If the string is
found, it will display the starting index (position) of the searched string in the worked-on string.
here is what i have so far.
#include <iostream>
#include <cstring>
using namespace std;
int main() {
char a_string[80];
[Code] .....
Okay, so my assignment for my C class is to generate a program that will allow the user to enter data for a stock and calculate the amount of stocks that ended up being positive, negative, and neutral.I tried to do this using one stock, here is my code;
#define _CRT_SECURE_NO_WARNINGS
#include <iostream>
#include <stdio.h>
#include <math.h>
#include <stdlib.h>
Code:
void main()
{
float Neg;
float incst;
float shrs;
float bpps;
float crnt;
float crntcst;
float yrfes;
float pft;
float tpft;
}
[code]....
I'm trying to create a program that allows the user to enter an unknown number of income and expense amounts. The program has to us see a while loop and display the income total, expense total, and total profit or loss. I've got it really close, but I'm doing the loop wrong. It counts the sentinel value (-1) towards the total, instead of just ending like it is supposed to.
#include <iostream>
using namespace std;
int main() {
//declare variables
double incomeInput;
double expenseInput;
double incomeTotal=0;
double expenseTotal=0;
[code]....
I'm having a problem with my homework. The task is to write a program that will take time and date typed by user, and increase it by 1 minute. I should write 3 functions - first calls second function that updates time and calls third function, if time is 00:00.Time update works, but date update does not.My whole written code:
Code:
#include<stdio.h>
struct DateAndTime {
struct date {
int day;
int month;
int year;
[code]....
I should check if inputs are numbers only, so I tried including isdigit function from ctype.h library, but that didn't work either, after I was trying it for a good hour or so, but I kinda rage quit that...
I need to write a program that will allow the user to enter a number "n" and the program tell you that the nth prime number is .....
EXAMPLE
user enters 55
printf("The 55th prime number is %i", variable");
I need the program to do a calculation after the user inputs 10 numbers . This is what I have tried so far:
int count;
float value, high,low, sum,average;
sum=0;
count=0;
input:
printf("Enter a number (enter negative value to finish program):
");
scanf_s("%f",&value);
[Code] ....
output:
average=sum/count;
if(count==10) {
printf("total values :%d
",count);
printf("The Highest value :%f
Lowest Value: %f
",high,low);
printf("The average of the values is:%f
",average);
}
I built a program that accepts two input from the user, using a array inside a loop, it is pass to a function inside a class which will display the two number, the problem is when the user is inputting a number and it is 1 the program continuously as the user to input a number, and when 2 is entered the program ask another number and end, but for example you entered 2 and 3. . . it will then outpu 2 and 4 (so 3 + 1 ) and always the last number is plus one. here is the code.
main.cpp
#include <iostream>
#include "newclass.h"
using namespace std;
[Code].....
So we have a weekend assignment that is "Write a c++ program that will allow a user to input their first name into a string, and use the switch/case statement to produce the following output. Your Program should prompt the use rwith the numbers and the options for each (school, classification, and mood) allowing them to make a choice"
My issue is with the output. The output at the end is the number that they input and not the name of the case they chose, so if they chose option 1 for school it does not print out "BRCC" at the end for the output it prints a 1.
#include <iostream>
#include <string>
using namespace std;
int main(void) {
string name;
cout << "Please enter your name: ";
cin >> name;
[code].....
I need a program to run that will accept an input for user id. It will take the customer input and capitalize the letters, and return invalid id with the user inputted values. Then if it's valid it will add a counter counting the number of letters and numbers. It will keep track until the user puts in !. It seems when I try to pass values from the array to my toUpper function to capitalize it it doesn't seem to work right.
View 3 Replies View RelatedI am so close to finishing this program of games, but I'm running into some issues while debugging it.
I've attached the google drive folder since there are several files (ignore the ones with [conflict], etc)...
First, I have the main menu using a switch to select the game. The default was set to exit. If initially when immediately opening the program you put in for say, a letter, it would exit like its supposed to. But if you went and played any of the games ], went back to the main screen, and entered a letter then, it would crash. I've put in a testing line to make sure that you enter a number, and not anything else.
Now however, if you play a game and then want to go back to the main menu, it will simply skip over waiting for your response and close the program. The same thing happens in the slot machine, I want to have it spin the slot machine by pressing enter, but it simply skips over the input, and I'm not sure why.
[URL] ....
I need to create a command where the user inputs a character and it'll exit out the program rather than executing any of the other code.
For example :
If I wanted to do like
char key;
if (key == D || key == d)
{
}
What would I need to put in between those brackets under the if statement to allow the user to enter the letter D and it would close out the program?