Basically I'm having trouble reading more than one character.I want the user to input character traits(ie, w, a), if two traits are entered they get the job.
But I cannot get my program to read more than one character input.
This is what I have so far...
#include <iostream>
using namespace std;
int main(){
char input;
int count = 0;
[Code] .....
I am trying to enter data to a structure some 8 times, but not able to do so. Here is my code.
Code: #include<stdio.h>
struct _Timer {
unsigned int HH;
unsigned int MM;
}Time[8];
[code]...
But when I enter any data and press enter , the .exe file stops working and not able to enter data.
Consider below statements:
int x;
scanf("%d", &x);
After running, It's supposed to enter an integer for x. what will happen if I enter a char instead of integer? which value will be in &x and x itself? I have a script and I get strange result while entering a char instead of integer for x.
I am having issues getting this working. This is a simple program that is designed to ask a user if he would like to enter a string, if yes, the user is prompted to enter it and its stored in a char array. User is then asked if he wants to enter another string... Once user responds no, the program outputs the strings and the program ends...
Note: I'm using in.getline(myarray[i], MAX, ' '), to avoid white space problems if user enters a space. Lastly I would like the option of letting user enter any number of strings, but how would you do this when declaring the 2 dimensional char array?
#include <iostream>
#include <string>
using namespace std;
const int MAX = 81; //max char is sting is 80
int main(){
string y_n;
bool go = true;
[Code] ....
I'm trying to get an if/else statement to work using a character condition, but it is a no-go. After I input either a 'y' or 'n', the program just sits there until I press 'Enter' again, at which point it ends. It never actually goes through either of the 'if' statements. At first I only had a single '=' in the condition, but I found that that was wrong. When I corrected it to '==' it still didn't work. I also tried clearing the buffer by adding a 'getchar()' at the beginning of the program, but that didn't work either.
#include <stdio.h>
#define std_rate .8855
int main(void) {
char ans;
int counter = 1, euros = 5;
double dollars = 0, ex_rate;
[Code] .....
The compiler (Visual Studio 2013) requires me to use 'scanf_s' instead of just 'scanf' for some reason, and if I don't have two 'getchar()' commands at the end, then it won't stay open long enough for me to see the results.
I wrote a program that reads user input string using fgets() function. After this, program will ask if the user wants to save the string to file or does the user want to change the string or quit without saving. If user wants to change the string this must be made possible by asking for the string again. After this, menu will be printed again printing the choices available.
I had to flush stdin before getting changing input! However, problem is "Why do I have to hit return key 2 times, when I choose 2 and input string again." (I use code block 13.12 with windows 8.1 laptop) */
Code:
#include <stdio.h>
#include <string.h>
#define MAX 50
[Code]....
When the program is processing/sleeping, those char input at that time would not goes into the buffer until the next input request (such as calling istream::get). The program below shows this.
#include <iostream>
#include <streambuf>
#include <chrono>
#include <thread>
int main() {
std::cout << "Sleeping...
[Code] ....
I wonder if there is a way to distinguish between the input comes from the time that does not request it (i.e., during processing or sleeping) and those comes after the time does request it (in the example, after "Input something: ").
I'm trying to validate my input. I require for the user to enter six doubles and if they don't then I want them to re-enter the information. Here is my code:
Code:
while (1>0) {
printf("Please enter arguments in the order: negative mass, positive mass, initial x-position, initial y-position, initial x-velocity, initial y-velocity:
");
if ( scanf("%lf %lf %lf %lf %lf %lf",&MassMinus,&MassPlus,&Pos[0][0],&Pos[0][1],&Vel[0][0],&Vel[0][1]) != 6) {
printf("Not all numbers were assigned!
[Code] .....
At the moment it just waits if you enter less than six numbers and if you enter any more than 6 it just ignores anything after the sixth number (so pretty much does nothing). Also if I entered 1 2 a b 3 4 instead of entering six numbers it would register that as 1 2 0 0 3 4 but I want it to make the user input the numbers again. I'm also aware that "while (1>0)" isn't good programming form but I'm not really sure what to use instead?
When the user gives no input, they have to press enter twice before "Done." is printed.
cout << "What do you want the name of your page to be? ";
std::getline(cin, pageTitle);
if (cin.get() == '
')
pageTitle = "Welcome to Website.";
cout << "Done.
";
Is there a way to print "Done." after pressing enter once?
Code:
#include<iostream.h>
#include<conio.h>
#include<string.h>
void main() {
clrscr();
int i=0,flag=1;
cout<<"Enter the password.";
[Code] ....
When I input the password, the Backspace and the Enter keys are not working as they should. Also, I want to know if I can press enter only once to input the password, not twice.
Compiler is Turbo C++ 3.0 on Windows 7.
how can i make a program which allows a user to enter an input for a time interval for example i ask a question and sets the input to be entered within 10 seconds...
View 4 Replies View RelatedHow would you be able to show both outputs celsius and Fahrenheit and my temperature conversion is coming up wrong when i enter in the input. here is my code...
#include<iostream>
using namespace std;
int main(){
double celsius;
double fahrenheit;
[code].....
It seems to be going null. I can't get a null value, I want it to accept input till the user hits enter with no text typed. I've tried checking to see if the input is NULL, "", and " " all to no avail.
Code:
#include <stdio.h>
#include <sys/shm.h>
#include <sys/stat.h>
#include <iostream>
#include <fstream>
#include <string.h>
#include <cstring>
using namespace std;
int main() {
string info = "";
[Code] ....
Some of my loop is not working. How messed up is this code.. Commented non working code
// ADIT.cpp : Defines the entry point for the console application.
#include "stdafx.h"
#include "windows.h"
[Code]....
My code:
#include <stdlib.h>
#include <stdio.h>
#include <string.h>
int factorial(int n);
int main() {
int n,num;
do {
[Code] ....
My while loop is not working... it exits after 1 input...
Why my output screen for this program does not want to stay open. It only opens for a split of a second and it's gone. The program is supposed to take numbers from a input file and display and save the manipulation in the output file. Here is the program.
Code:
#include<iostream>
#include<fstream>
#include<iomanip>
usingnamespace std;
[Code] ....
I wrote code for printing a double triangle. Its woking fine upto input is 7. but when the input is 8 the output is disturbed. the code is this.
#include<iostream>
using namespace std;
int main() {
int a;
cout<<"Enter a number"<<endl;
[Code] ....
I'm having troubles with this program I made. Put it simply, it's a basic program using Queues. Whenever I try to input a value, my compiler(Dev C) suddenly stops working. The .exe file crashes and I've no way on how I can execute my program.
Code :
#include<iostream>
using namespace std;
int *queue;
int rear, front, queueSize;
void enqueue();
void dequeue();
void display();
[Code] ....
I'm trying to write a C++ program that will allow a user to input a number from the keyboard. Then using a loop, that will perform 10 times, multiply the entered number by the loop counter. Print out the loop counter, the entered number and the product of the loop counter and the entered number. A one-time heading should be displayed before information is printed.
This kinda of what I have so far:
#include <iosteam>
using namespace std;
int main () {
Start
Declare: numScores, sum, score, avg, SENTINEL = 200
numScores = 0
[Code] ....
All the programs I have tried to make are not working?
I wrote this program to create a list of medical resources and their attributes, a task I have been performing repeatedly lately. I'm still fairly new to C++, so I thought to create a structure "Resource", and then an array of those structures "city[300]". My problem is that the input doesn't seem to be happening: the program runs, but when it prints to screen/writes to the file at the end, all the shows is:
Resource Type:
Name:
Address:
Phone:
Website:
for every resource that was input. All the fields are blank.
#include <iostream>
#include <fstream>
#include <string>
using namespace std;
struct Resource {
string typeID;
string name;
[Code] ....
In GCC v4.6, I am encountering a strange problem. If I try to get a character input and a int input like this:
Code:
int main()
{
int a;
char b;
scanf("%d",&a);
scanf("%c",&b);
}
the compiled program asks for input only one time. On the other hand, if I do the char scanf earlier like this:
Code:
int main()
{
int a;
char b;
scanf("%c",&b);
scanf("%d",&a);
}
it asks for input twice.
I'm extremely rusty at C but is this the best way to store an input string into a char*?
Code:
int length = 100; //initial size Code: char * name = malloc(length * sizeof(char)); //allocate mem for 100 chars
int count = 0; //to keep track of how many chars have been used
char c; // to store the current char
while((c = getchar()) != '
'){ //keep reading until a newline
if(count >= length)
name = realloc(name, (length += 10) * sizeof(char)); //add room for 10 more chars
name[count++] = c
}
Is this a good way and what could be better?
I am writing a program that asks the user for their gender. I know that atoi converts arrays into integers, but I need the input from the user in the form of F or M into a char, and return it to the main function to be displayed at the end of the program.
string Employee::getgender(char gen)
{
cout << "Please enter your Gender: " << endl;
//atoi function would go here, what for char?
getline(cin,gen)
return gen;
}
I'm trying to write a program that takes input from the user (thats a char) and outputs it to the monitor in hex form.The program is meant to continuously take input from the user then output to the monitor in hex form until an EOF is detected this triggers the program to close.The following code does this except that I get a lower case 'a' at the end of each output.I think the 'a' has to do with the enter key and if that is the case how can i tell the program to ignore this input from the user.
Example: input from user: ABC output to monitor: 41 42 43 a
Code:
#include <stdio.h>
int main(void) {
char myChar;
while(EOF != (myChar = getchar())) {
printf("%x ",myChar);
}
system("pause");
return 0;
}
I've been experimenting with char arrays and getting user input through different methods.
int main() {
char userInput[21];
/*I understand that over here, a maximum of 20 letters can be input, and only letters before a space will be stored in userInput*/
std::cin >> userInput;
std::cout << userInput << std::endl;
[Code] ....
As I was testing, whenever I would input a single word for userInput (for example "hi"), the program would work as expected: it would output "hi" and I'd be able to input a sentence of sorts for userInput2 (for example "hello world") and have it outputted.
But if I were to input more than one word for user Input (for example "hi how are you"), the program would output "hi" as expected, but it wouldn't let me input anything for userInput2 and would just output the rest of the first input; in this case, "how are you" would be outputted and the program would end. I am not aware of the logic error at play.
So my question was:
Write a program to read in a sequence of characters one by one. Print out the characters in reverse. You should use a char[]. (Remember single quotes are used for char)
For example:
Please enter characters one by one: (Enter 0 to exit)
h
e
l
l
o
0
You entered: hello.
The reverse of that is olleh.
and this is currently my code
#include <iostream>
#include <cstdlib>
#include <cstdio>
#include <ctime>
#include <cmath>
using namespace std;
int main() {
char entry[20];
[code]....
im just not sure how to set that value and still make the for loops work