C/C++ :: Char Condition In If Statement Not Working
Feb 3, 2015
I'm trying to get an if/else statement to work using a character condition, but it is a no-go. After I input either a 'y' or 'n', the program just sits there until I press 'Enter' again, at which point it ends. It never actually goes through either of the 'if' statements. At first I only had a single '=' in the condition, but I found that that was wrong. When I corrected it to '==' it still didn't work. I also tried clearing the buffer by adding a 'getchar()' at the beginning of the program, but that didn't work either.
#include <stdio.h>
#define std_rate .8855
int main(void) {
char ans;
int counter = 1, euros = 5;
double dollars = 0, ex_rate;
[Code] .....
The compiler (Visual Studio 2013) requires me to use 'scanf_s' instead of just 'scanf' for some reason, and if I don't have two 'getchar()' commands at the end, then it won't stay open long enough for me to see the results.
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Sep 24, 2013
I've tried retyping the code several times and didn't work for some reason the If wont accept both Q and q it just accepts Q.
Code:
#include <stdio.h>
int main(void)
{
printf("A menu will show up and you choose the number for the selection you want.
[Code].....
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Jul 29, 2014
I want to write an if statement which has condition like
if(i%1==0 && i%2==0 && i%3==0 && i%4==0 && i%5==0 &&
i%6==0 && i%7==0 && i%8==0 && i%9==0 && i%10==0 &&
i%11==0 && i%12==0 && i%13==0 && i%14==0 && i%15==0
&& i%16==0 && i%17==0 && i%18==0 && i%19==0 && i%20==0)
This of course is not the right way to write it. How to generalize it so that I can check the condition not only till 20 but till any number without manually adding all conditions.
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Oct 17, 2014
I am try to make a menu for deliver order program.
The menu divide into 3 group which are breakfast, lunch and dinner. However breaker only available at 6.30am-10pm, lunch available at 11am-1.30pm and dinner only available at 6.00pm-8.30pm
Let say my current time on the system is 10.30am, and the user select breakfast order. It should not available at this time, and prompt a message to use that the order not available at this period.
How to write the program?
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Dec 8, 2014
The while loop part of my program isn't working right. stringOriginal is an array. If a large amount of characters passed the max 80 im processing is typed, it goes into a infinite loop. Also the condition doesn't work i type in quit and the loop continues.
while(stringOriginal != "quit"){
std::cout << "Enter a string of characters you would like to reverse
";
cin.getline(stringOriginal,79,'
');
}
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Jan 30, 2013
I have always written like a>='0'&&a<='9'&&a>='a'&&a<='z' in loops etc, but no more. Basically add whatever you want to condition, and if you want point a to point b just separate them with a '-' sign. Simply
while(!isCharInside(x,"|a-zA-Z0-9.*/=|-|")){/*code*/}
bool isCharInside(char check,string condition="a-zA-Z*/+=|-|0-9"){
for(unsigned int x=0,z=getLenght(condition);x<z;++x){
if(condition[x+1]=='-'&&(condition[x]!='|'&&condition[x+2]!='|')){
if(condition[x]>condition[x+2])swap(condition[x],condition[x+2]);
for(;condition[x]<=condition[x+2];++condition[x]){if(condition[x]==check)return true;};x+=2;}
else if(check==condition[x])return true;
}
return false;}
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Oct 21, 2013
Well for some reason this doesn't work.
Code:
#include <stdio.h>#include <ctype.h>
int main(void)
{
int lottoNums[150];
int num;
[Code]....
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Mar 6, 2015
I have this case statement that is not performing as expected. For some reason ASE_OK and ASE_NotPresent both print out. Why is this? ASE_OK is a return value of 0 while ASE_NotPresent is -1.
Code: // Try to create the buffers and store it
switch (theAsioDriver->createBuffers(info, numChannels, bufferSize, callbacksInfo)) {
case ASE_OK:
std::cout << "ASE_OK";
input->bufferSize = output->bufferSize = bufferSize; // Buffer size is stored in both input and output
case ASE_NotPresent:
std::cout << "ASE_NotPresent";
errorMessage = "Could not find input or output devices.";
return NO_DEVICES_FOUND;
[code]....
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Aug 16, 2014
okay so like case 2 and 3 is not working, also the program is still not finish but why isn't case 2 and 3 not functioning well on the switch part? case 1 works just fine
Code:
#include<stdio.h>
main ()
{
//passcode part (passcode is 1234)
[Code].....
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Nov 22, 2014
The switch statement is giving me trouble. Worked fine in the main, but when I had to put it in separate functions per my professor, I had several issues. I guessing I am not calling the function correctly. Our group worked on it but could not find a solution to fix the switch statement.
#include <iostream>
#include <iomanip>
#include <fstream>
#include <conio.h>
using namespace std;
//function prototypes
int menu(); //function to show main menu
void Seating_Chart(); //function to show seating chart
[Code] ....
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Jan 31, 2015
was making a somewhat of a Binary to Hex convertor but only 10/15 cases work and the non working are in the middle; 0010, 0011, 0100, 0101, 0110, 0111;;
// Test Code.cpp : Defines the entry point for the console application.
//
#include "stdafx.h"
#include <iostream>
#include <cmath>
#include <conio.h>
using namespace std;
int main(void)
{int A;
cout << "Enter the binary starting with the MSB
[code]....
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May 20, 2013
Why is my program outputting zero for the variable pop?
Code:
#include <iostream>
int main(void){
using namespace std;
//capture data
cout << "Enter the world's population: ";
[Code] ....
It's obviously not std::cout, but I'm thinking its the way I'm operating on long?
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Nov 10, 2014
So I tried creating a test code for reading a negative number and positive number but whenever I enter a negative number it read it as being positive.
#include <stdio.h>
#include <iostream>
#include <iomanip>
[Code].....
PS: I am using char over int because the program that I am testing for requires me to use 8 bit variable.
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Jan 23, 2015
Basically I'm having trouble reading more than one character.I want the user to input character traits(ie, w, a), if two traits are entered they get the job.
But I cannot get my program to read more than one character input.
This is what I have so far...
#include <iostream>
using namespace std;
int main(){
char input;
int count = 0;
[Code] .....
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Feb 17, 2014
Ive been getting an odd error with this code when I try to compile it, as well as Im not quite sure as how to return my variable "compType" as a char type.
Main
#include <iostream>
#include "Shape.h"
#include <iomanip>
#include <cmath>
using namespace std;
void inputShape( char shape)
[Code] ....
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Mar 25, 2014
Just making typical console game where hero moves with w a s d.
However, in my code, while a and w work (minusing), s and d dont work (adding). I have used a switch statement to change the char position of the hero based on kbhit.When you hit s or d, the buttons that add 1 to the 2nd dimension of the array, the screen goes crazy!
#include <iostream>
#include <string>
#include <conio.h>
#include <ctime>
#include <cstdlib>
using namespace std;
const char PLAYER = 'H';
[Code] .....
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Oct 6, 2014
I've written a bit of code :
#include <iostream>
#include <cmath>
#include <cstdio>
int main() {
for(int i=1; i<=1000; i++)
for(int j=i+1; j<=1000; j++)
for(int k=j+1; k<=1000; k++)
[Code] ...
Now why does defining the if condition as if(pow(i,2) + pow(j,2) == pow(k,2)) doesnt work (ie. doesn't print anything) while defining it as if(i*i + j*j == k*k) works flawlessly - by working I mean printing out single set of 3 numbers.
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Mar 22, 2013
I wanted to input some numbers with scanf function, i can enter some numbers and if I input -1 to the scanf, the input must end. And the scanf function has limited input, the max that I can input is 40 numbers.example if enter 1 2 4 6 5 4 -1 the scanf function will ended and the result will be appear.I wanted to know how the scanf function is like that would be best for this problem, Code: scanf("%d", &n); the result if I input those number will be like
|
||
||||
||||||
|||||
||||
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May 23, 2014
I found a for loop in an example that I don't understund fully.
Code:
for (i=64; i; i/=2)
printf("i: %d
",i);
Now this is dividing by 2 until it reach '1' and stops. But why does this stops?
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Sep 13, 2014
I have two table the first is called Imprrests and the second is called ]IprestsPays. There is an Imprest_ID column that is primary key in [icode]Imprests[/code] table and foreign key in ImprestsPays table
Imprests table consists the following columns:
Imprest_ID, Impres_value, Imprest_date, Employee_ID
Where Employee_ID column is primary key in Employees table and foreign key in Imprests table.
ImprestsPays table consists the following columns:
ID, Payment_value, Payment_date, Imprest_ID
My problem is in the buttonadd_click event in Imprsts form.
I want to prevent user from insert any new imprest for employee in Imprests table if employee haven't paid all payments in ImprestsPays table for old imprest...
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Mar 5, 2013
I am trying to write a simple program that produces different outputs based on entered age of two different users. Program should tell who is older and behave different if both users are older than 100.
Here is my program: Code: #include <iostream>
using namespace std;
int main()
{
[Code].....
Why program executes this when both users are obviously more than 100
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Oct 26, 2013
I need to do make a loop inside a condition. Can it be done? I don't want to call another function to do it. Any way at all without calling separate function inside the if? I just want to do:
if (
for (int i = 0; i<=10; i++)
{
//stuff related to the for loop
} )
{
//stuff related to the initial if condition
};
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Aug 11, 2014
I'm writing a delete function for a linked list, and I'm having issues with this bit of code:
void deleteNode(int data){
node* del = NULL;
t = h;
n = h;
while(n != NULL && n->_data != data){
t = n;
n = n->next;
}
}
Or more precisely, this portion:
&& n->_data != data
n is my new node variable, _data is the storage variable in the private section of my class, and data is the information being searched for that needs to be deleted. Everything works without this section of the code. My assumption is that n->_data is somehow wrong, but I don't see how. I've tried everything I can think of- using parenthesis, using the variable rather than the pointer, I've tried expressing the pointer in a different way, I've tried using my t variable rather than n, and I've found examples online that use this exact same expression without any issues.
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May 18, 2013
Write a program to calculate the Loan Balance, where a person borrows an amount A and in return he/she agrees to make N payments per year, each of amount P. While the person is repaying the loan, interest will accumulate at an annual percentage rate of R, and this interest will be compounded N times a year (along with each payment). Therefore, the person must continue paying these installments of amount P until the original amount and any accumulated interest is repaid.
NOTE: The formula to calculate the amount that the person needs to repay after T years is-
Balance Amount after T years = A[(1+R/N)^NT]-P
-----------------------------------------------------------
I have a few doubts :
1. I think that the "balance amount" formula can directly give the "loan balance" for the person. I'm not sure if it's correct but in that case the question would serve no purpose. Maybe I'm wrong.
2. If there should be a loop to calculate the loan balance, what condition should I give and which loop will be better to use?
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Jan 13, 2015
#include <iostream>
#include <fstream>
#include <string>
using namespace std;
int check_Pythag(int DIMA, int DIMB, int DIMC) {
[Code] .....
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Dec 8, 2014
I'm parsing a text file, and I'd like to detect when a certain Compilation Condition - i.e. #ifdef - begins. The challenge is, that the condition can take any of the following patterns:
#ifdef (FLAG)
#if defined (FLAG)
#if (defined (FLAG))
(And perhaps I missed more)
I'd of course need to treat them all the same, as they are indeed the same. How would you know to treat them all the same?
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