C++ :: Generalizing Condition In If Statement
Jul 29, 2014
I want to write an if statement which has condition like
if(i%1==0 && i%2==0 && i%3==0 && i%4==0 && i%5==0 &&
i%6==0 && i%7==0 && i%8==0 && i%9==0 && i%10==0 &&
i%11==0 && i%12==0 && i%13==0 && i%14==0 && i%15==0
&& i%16==0 && i%17==0 && i%18==0 && i%19==0 && i%20==0)
This of course is not the right way to write it. How to generalize it so that I can check the condition not only till 20 but till any number without manually adding all conditions.
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Sep 24, 2013
I've tried retyping the code several times and didn't work for some reason the If wont accept both Q and q it just accepts Q.
Code:
#include <stdio.h>
int main(void)
{
printf("A menu will show up and you choose the number for the selection you want.
[Code].....
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Oct 17, 2014
I am try to make a menu for deliver order program.
The menu divide into 3 group which are breakfast, lunch and dinner. However breaker only available at 6.30am-10pm, lunch available at 11am-1.30pm and dinner only available at 6.00pm-8.30pm
Let say my current time on the system is 10.30am, and the user select breakfast order. It should not available at this time, and prompt a message to use that the order not available at this period.
How to write the program?
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Feb 3, 2015
I'm trying to get an if/else statement to work using a character condition, but it is a no-go. After I input either a 'y' or 'n', the program just sits there until I press 'Enter' again, at which point it ends. It never actually goes through either of the 'if' statements. At first I only had a single '=' in the condition, but I found that that was wrong. When I corrected it to '==' it still didn't work. I also tried clearing the buffer by adding a 'getchar()' at the beginning of the program, but that didn't work either.
#include <stdio.h>
#define std_rate .8855
int main(void) {
char ans;
int counter = 1, euros = 5;
double dollars = 0, ex_rate;
[Code] .....
The compiler (Visual Studio 2013) requires me to use 'scanf_s' instead of just 'scanf' for some reason, and if I don't have two 'getchar()' commands at the end, then it won't stay open long enough for me to see the results.
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Dec 20, 2014
I'm working on a game with an entity-component system. I have a Manager class that is handling all of the components by feeding them into vectors set up for each type of component. Right now I have a lot of repeated code for each kind of component.
void add_pos_comp(shared_ptr<Position> pos_comp);
shared_ptr<Position> get_pos_comp(int id);
const vector<shared_ptr<Position>>& get_pos_comps();
void add_vel_comp(shared_ptr<Velocity> vel_comp);
shared_ptr<Velocity> get_vel_comp(int id);
const vector<shared_ptr<Velocity>>& get_vel_comps();
I've tried generalizing this with templates, but I've been confused by how I should organize the collection of vectors for each component. I had it setup so that they were all in an unordered_map, but how to get the templated functions to find the right map slot to use based simply on the template's parameters.
The full project is here for reference: [URL] ....
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Oct 6, 2014
I've written a bit of code :
#include <iostream>
#include <cmath>
#include <cstdio>
int main() {
for(int i=1; i<=1000; i++)
for(int j=i+1; j<=1000; j++)
for(int k=j+1; k<=1000; k++)
[Code] ...
Now why does defining the if condition as if(pow(i,2) + pow(j,2) == pow(k,2)) doesnt work (ie. doesn't print anything) while defining it as if(i*i + j*j == k*k) works flawlessly - by working I mean printing out single set of 3 numbers.
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Mar 22, 2013
I wanted to input some numbers with scanf function, i can enter some numbers and if I input -1 to the scanf, the input must end. And the scanf function has limited input, the max that I can input is 40 numbers.example if enter 1 2 4 6 5 4 -1 the scanf function will ended and the result will be appear.I wanted to know how the scanf function is like that would be best for this problem, Code: scanf("%d", &n); the result if I input those number will be like
|
||
||||
||||||
|||||
||||
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May 23, 2014
I found a for loop in an example that I don't understund fully.
Code:
for (i=64; i; i/=2)
printf("i: %d
",i);
Now this is dividing by 2 until it reach '1' and stops. But why does this stops?
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Sep 13, 2014
I have two table the first is called Imprrests and the second is called ]IprestsPays. There is an Imprest_ID column that is primary key in [icode]Imprests[/code] table and foreign key in ImprestsPays table
Imprests table consists the following columns:
Imprest_ID, Impres_value, Imprest_date, Employee_ID
Where Employee_ID column is primary key in Employees table and foreign key in Imprests table.
ImprestsPays table consists the following columns:
ID, Payment_value, Payment_date, Imprest_ID
My problem is in the buttonadd_click event in Imprsts form.
I want to prevent user from insert any new imprest for employee in Imprests table if employee haven't paid all payments in ImprestsPays table for old imprest...
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Mar 5, 2013
I am trying to write a simple program that produces different outputs based on entered age of two different users. Program should tell who is older and behave different if both users are older than 100.
Here is my program: Code: #include <iostream>
using namespace std;
int main()
{
[Code].....
Why program executes this when both users are obviously more than 100
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Dec 8, 2014
The while loop part of my program isn't working right. stringOriginal is an array. If a large amount of characters passed the max 80 im processing is typed, it goes into a infinite loop. Also the condition doesn't work i type in quit and the loop continues.
while(stringOriginal != "quit"){
std::cout << "Enter a string of characters you would like to reverse
";
cin.getline(stringOriginal,79,'
');
}
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Oct 26, 2013
I need to do make a loop inside a condition. Can it be done? I don't want to call another function to do it. Any way at all without calling separate function inside the if? I just want to do:
if (
for (int i = 0; i<=10; i++)
{
//stuff related to the for loop
} )
{
//stuff related to the initial if condition
};
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Jan 30, 2013
I have always written like a>='0'&&a<='9'&&a>='a'&&a<='z' in loops etc, but no more. Basically add whatever you want to condition, and if you want point a to point b just separate them with a '-' sign. Simply
while(!isCharInside(x,"|a-zA-Z0-9.*/=|-|")){/*code*/}
bool isCharInside(char check,string condition="a-zA-Z*/+=|-|0-9"){
for(unsigned int x=0,z=getLenght(condition);x<z;++x){
if(condition[x+1]=='-'&&(condition[x]!='|'&&condition[x+2]!='|')){
if(condition[x]>condition[x+2])swap(condition[x],condition[x+2]);
for(;condition[x]<=condition[x+2];++condition[x]){if(condition[x]==check)return true;};x+=2;}
else if(check==condition[x])return true;
}
return false;}
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Aug 11, 2014
I'm writing a delete function for a linked list, and I'm having issues with this bit of code:
void deleteNode(int data){
node* del = NULL;
t = h;
n = h;
while(n != NULL && n->_data != data){
t = n;
n = n->next;
}
}
Or more precisely, this portion:
&& n->_data != data
n is my new node variable, _data is the storage variable in the private section of my class, and data is the information being searched for that needs to be deleted. Everything works without this section of the code. My assumption is that n->_data is somehow wrong, but I don't see how. I've tried everything I can think of- using parenthesis, using the variable rather than the pointer, I've tried expressing the pointer in a different way, I've tried using my t variable rather than n, and I've found examples online that use this exact same expression without any issues.
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May 18, 2013
Write a program to calculate the Loan Balance, where a person borrows an amount A and in return he/she agrees to make N payments per year, each of amount P. While the person is repaying the loan, interest will accumulate at an annual percentage rate of R, and this interest will be compounded N times a year (along with each payment). Therefore, the person must continue paying these installments of amount P until the original amount and any accumulated interest is repaid.
NOTE: The formula to calculate the amount that the person needs to repay after T years is-
Balance Amount after T years = A[(1+R/N)^NT]-P
-----------------------------------------------------------
I have a few doubts :
1. I think that the "balance amount" formula can directly give the "loan balance" for the person. I'm not sure if it's correct but in that case the question would serve no purpose. Maybe I'm wrong.
2. If there should be a loop to calculate the loan balance, what condition should I give and which loop will be better to use?
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Jan 13, 2015
#include <iostream>
#include <fstream>
#include <string>
using namespace std;
int check_Pythag(int DIMA, int DIMB, int DIMC) {
[Code] .....
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Dec 8, 2014
I'm parsing a text file, and I'd like to detect when a certain Compilation Condition - i.e. #ifdef - begins. The challenge is, that the condition can take any of the following patterns:
#ifdef (FLAG)
#if defined (FLAG)
#if (defined (FLAG))
(And perhaps I missed more)
I'd of course need to treat them all the same, as they are indeed the same. How would you know to treat them all the same?
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Sep 7, 2013
How to make if else code below into SWITCH STATEMENT?
cout << "Enter the temperature: ";
cin >> temp;
cout << "Enter the pressure: ";
cin >> pressure;
cout <<endl;
[Code]....
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Mar 7, 2013
I am trying to implement a Task scheduler where i have n number of tasks. The Idea behind my task scheduler is that in a loop of queues of a vector, task should get enqueued to the shortest queue among the loop of queues, which is done by the following code.
#include <vector>
#include <queue>
std::vector<std::queue<int> > q
int min_index = 0;
task t // implemented in the other part of the program
[Code] ....
Next i am trying to extend this paradigm to reduce the overhead time of the scheduler, Instead of searching the shortest queue every time, search after some condition ie. search the shortest queue after 5 tasks gets enqueued to the shortest queue.
i need to do something like this
#include <vector>
#include <queue>
std::vector<std::queue<int> > q
task t // implemented in the other part of the program
while(q[min_index].size()!=q[min_index].size()+5) // check whether current min_index queue's size is increased 5 more times if not goto enqueue
[code].....
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Sep 22, 2013
This while statement is not cooperating and I am not really sure why. I tried to say while not equal to true and later false, but both produce a never ending loop. I know I posted this before and I got several comments back about different issues with this program. However this question is specific about the while statement.
Code:
#include <iostream>
#include <vector>
#include <string>
using namespace std;
[Code] ....
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Apr 30, 2013
I'm having a really dumb moment and I cant seem to remember how an if statement works, with only the variable name as the condition..
Code:
if(var){
//then do something
}
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Oct 21, 2013
Well for some reason this doesn't work.
Code:
#include <stdio.h>#include <ctype.h>
int main(void)
{
int lottoNums[150];
int num;
[Code]....
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Nov 17, 2013
how would i got about making an if statement for an array so it prints what u enter
Code:
example:
struct input{
float peopleseen;
float creditrate;
char insurprov[12];
[Code] ....
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Aug 7, 2013
When I do this:
Code:
#include <stdio.h>
#include <stdlib.h>
int main () {
int guess ;
int number = 5 ;
[Code] .....
But when I do this:
Code:
#include <stdio.h>
#include <stdlib.h>
int main () {
int guess ;
int number = 5 ;
[Code] ....
Why does the compiler say that there is an else without a previous if ??? ... Does this mean that I cannot use "scanf" in an if/else statement?
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Mar 6, 2013
I was wondering how you would put this if else statement to a switch statement.
void PlayerDB::AddPlayer(const Player& avatarPlayer) {
char * playerName = new char[avatarPlayer.lenName()];
Player*player = NULL;
[Code] ....
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Jun 26, 2013
i am trying to make a ticktacktoe game. I made a simple one with no ai but i decide to add an option to play against computer. And i code like that(i know this is really bad):
/*
Name: TickTackToeFinal
Copyright:
Author:
Date: 26.06.13 20:41
Description:
*/
#include <iostream>
#include <string>
[code].....
when i run the game its always play randomly(last if statements in bilgisayar functions.
not:bilgisayar means computer
zor means hard
orta means medium
kolay means easy
oyuncu means player
tur means round
oyun means game
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