This while statement is not cooperating and I am not really sure why. I tried to say while not equal to true and later false, but both produce a never ending loop. I know I posted this before and I got several comments back about different issues with this program. However this question is specific about the while statement.
Code:
#include <iostream>
#include <vector>
#include <string>
using namespace std;
[Code] ....
How to make if else code below into SWITCH STATEMENT?
cout << "Enter the temperature: ";
cin >> temp;
cout << "Enter the pressure: ";
cin >> pressure;
cout <<endl;
[Code]....
I'm having a really dumb moment and I cant seem to remember how an if statement works, with only the variable name as the condition..
Code:
if(var){
//then do something
}
Well for some reason this doesn't work.
Code:
#include <stdio.h>#include <ctype.h>
int main(void)
{
int lottoNums[150];
int num;
[Code]....
how would i got about making an if statement for an array so it prints what u enter
Code:
example:
struct input{
float peopleseen;
float creditrate;
char insurprov[12];
[Code] ....
When I do this:
Code:
#include <stdio.h>
#include <stdlib.h>
int main () {
int guess ;
int number = 5 ;
[Code] .....
But when I do this:
Code:
#include <stdio.h>
#include <stdlib.h>
int main () {
int guess ;
int number = 5 ;
[Code] ....
Why does the compiler say that there is an else without a previous if ??? ... Does this mean that I cannot use "scanf" in an if/else statement?
I was wondering how you would put this if else statement to a switch statement.
void PlayerDB::AddPlayer(const Player& avatarPlayer) {
char * playerName = new char[avatarPlayer.lenName()];
Player*player = NULL;
[Code] ....
i am trying to make a ticktacktoe game. I made a simple one with no ai but i decide to add an option to play against computer. And i code like that(i know this is really bad):
/*
Name: TickTackToeFinal
Copyright:
Author:
Date: 26.06.13 20:41
Description:
*/
#include <iostream>
#include <string>
[code].....
when i run the game its always play randomly(last if statements in bilgisayar functions.
not:bilgisayar means computer
zor means hard
orta means medium
kolay means easy
oyuncu means player
tur means round
oyun means game
I seem to be having a bit of problem with my if statements in a for loop.
My code involves asking the user for the name of an element (chemistry), searching a text file line by line for an element that matches the input, and outputting other information regarding that element.
One line of the text file looks like this: Helium,He,2,4.00
I've tried running the code without the if loop and it outputs normally (If I ask it to output elementname[0] it will output the first element Hydrogen, which is correct.) but I am not sure what goes wrong when I add the if statement. For some reason, it always follows the "else" statement (It always outputs Invalid search even when I input the right elements).
const int ELEMENTS = 118; //number of elements
ifstream File;
string elementname[ELEMENTS], atomicsymbol[ELEMENTS], atomicnumber[ELEMENTS], atomicmass[ELEMENTS];
string elemname, atomsym, atomnum, atommass;
string search;
[Code] ....
I have written a C++ program in which a user need to input a character. My problem is it's working fine for the first time but as it goes through the code second time, it skips the cin statement and takes the previous defined value. how can i make cin statement work for the second time also?
View 5 Replies View RelatedI just want to say that I just started learning the language and this is my very first shot at writing a simple program that is not "Hello World" So I recently learnt the basics of the if statement and how to loop in a console application, here's what it looks like:
namespace Testing_IF_Statement
{
class Program
{
[Code].....
And again, this is just what I wrote in a few minutes without putting any thought into it.
Questions:
1)I have heard that the way I'm looping by using the goto statement is considered quite ancient, why is this and how else could I loop the program?
2)I declared a as an integer and asked the user to type 1,2,3,4 to perform mathematical functions, but when I tried declaring a as a string and searching if a == "PLUS" etc it would throw an error. Is there any mistake in how I approached this?
3)I know this is a bit premature to ask, but instead of writing _________ in the console to separate the loop is there any professional way to add a separator?
4)In general how can I improve the code?
#include <stdio.h>
#include <math.h>
int main(void)
{
[Code]....
That's my code above and I'm getting an error saying that I'm "implicitly declaring library function 'strcmp' with type 'int(const char*, const chat*)". When i run this program and enter in Black for the first prompt, the program stops. I'm trying to make this program so that when I enter Black as the answer for the first prompt, the program will display the value 10.
I want to set an integer to zero when it easy equal to another integer, but it seems that the program for some reason won't set the integer to zero. Here is the example of that code:
#include <iostream>
using namespace std;
int main () {
int n = 2;
int r = 2;
if(n==r)
n++;
r*0;
cout << " n is " << n << endl;
cout << " r is " << r << endl;
}
What am I doing wrong, it should say that "n is 3" and "r is 0".
My break; isn't ending the for statement. User should only get 3 choices but they get to input more than 3.
int playGame() {
int count =0; int x = (rand()%10)+1; int y;
for(int i=0;i<3;i++) {
cout << "Guess the number 1-10: ";
cin >> y;
if (x==y)
[Code] ......
I have this case statement that is not performing as expected. For some reason ASE_OK and ASE_NotPresent both print out. Why is this? ASE_OK is a return value of 0 while ASE_NotPresent is -1.
Code: // Try to create the buffers and store it
switch (theAsioDriver->createBuffers(info, numChannels, bufferSize, callbacksInfo)) {
case ASE_OK:
std::cout << "ASE_OK";
input->bufferSize = output->bufferSize = bufferSize; // Buffer size is stored in both input and output
case ASE_NotPresent:
std::cout << "ASE_NotPresent";
errorMessage = "Could not find input or output devices.";
return NO_DEVICES_FOUND;
[code]....
I'm trying to make a simple C++ program in which the user must try to guess a number, if they guess too high it says "too high" and if they guess too low it says "too low".
I also decided to add a feature which allows them to select how many tries they would like to guess the number. I tried to make "tries" type an enum so if the user could not pick an invalid number but for some reason i cannot use it in an if statement.
here is the code and i am getting the first error on line 27:
Code:
#include <iostream>
#include <ctime>
#include <cstdlib>
using namespace std;
int guess;
[Code]....
okay so like case 2 and 3 is not working, also the program is still not finish but why isn't case 2 and 3 not functioning well on the switch part? case 1 works just fine
Code:
#include<stdio.h>
main ()
{
//passcode part (passcode is 1234)
[Code].....
I've tried retyping the code several times and didn't work for some reason the If wont accept both Q and q it just accepts Q.
Code:
#include <stdio.h>
int main(void)
{
printf("A menu will show up and you choose the number for the selection you want.
[Code].....
If i declare a function as a void function. But for testing purpose if i use a return statement in the function definition. i have tested and found that the function does not return and executes the entire function. How does the function not return even if a return statement is available? Does the compiler removes this return statement or how it is?
View 2 Replies View RelatedI have tried writing a code and come across an issue where I'm not getting the desired result. It is to design a program that tells whether gas emissions from a car are too high, or permissible. The instructions are to design a code where there are four possible choices of pollutant, whether the emitted pollutant ratio is greater or less then a certain value, and the mileage on the car. All of these are supposed to determine whether the emissions are permissible or not, which would be displayed with printf. (The actual conditions of the assignment are described perfectly by the code below, so I didn't think it would be necessary to write it out. The problem is that I'm getting a logical error.) Here's the code:
Code:
#include <stdio.h>
int main() {
int poln, odr;
double gpm;
printf ("(1) Carbon Monoxide
[Code] ....
My error is that the program will proceed with the first four if/else statements, but once the 'poln' value changes to something other then one, it will not display the expected quotation.
Code:
/* Demonstrates using the gets() return value. */
#include <stdio.h>
/* Declare a character array to hold input, and a pointer. */
char input[257], *ptr;
[Code]....
I just got this from the book that I am using and it is for testing for input of a blank line and readers are being warned in using this format (line 18):
Code: while ( (*ptr = gets(input)) != NULL)
What is the correct syntax if a gcc compiler is to be used?
so I am trying to have an switch statement array. but every time i complete a case statement the whole process is returned. the thing is i want the menu to stay up even if i complete the case.
View 2 Replies View RelatedI need to use the output of my IF statement in a calculation. But how can i extract the output from the IF statement in my code?
#include <iostream>
#include <cmath>
using namespace std;
int main(int argc, char *argv[]) {
double x, y, z;
cout<<"Please enter the student's three test grades:"<<endl;
cin>>x>>y>>z;
[Code]...
I need to use the output in my average.
i am trying to write a program to print a statement without spaces in it.For example, if the statement is "Hello, i am Solidsnake", then it should print it as "Hello,iamsolidsnake".
View 4 Replies View RelatedThe sample output of this program would be:
Please select:
1 - Year
2 - Day
3 - Month
Input choice: 1
Input Number: 2
I'm a Sophomore!
Please select:
1 - Year
2 - Day
3 - Month
Input choice: 2
Input Number: 2
It's Tuesday.
Please select:
1 - Year
2 - Day
3 - Month
Input choice: 3
Input Number: 2
February. Heart's month!
Here is my code, I only typed the Year(levels) yet because when I tried to input 2(day) and 3(month) for the Input choice and after that, Inputting a number to 1-4 would yield the same result to case 1's year levels.
#include <stdio.h>
#include <conio.h>
using namespace std;
[Code].....
how to link the case 2 to days and case 3 to months?
I want to write an if statement which has condition like
if(i%1==0 && i%2==0 && i%3==0 && i%4==0 && i%5==0 &&
i%6==0 && i%7==0 && i%8==0 && i%9==0 && i%10==0 &&
i%11==0 && i%12==0 && i%13==0 && i%14==0 && i%15==0
&& i%16==0 && i%17==0 && i%18==0 && i%19==0 && i%20==0)
This of course is not the right way to write it. How to generalize it so that I can check the condition not only till 20 but till any number without manually adding all conditions.