I've tried retyping the code several times and didn't work for some reason the If wont accept both Q and q it just accepts Q.
Code:
#include <stdio.h>
int main(void)
{
printf("A menu will show up and you choose the number for the selection you want.
[Code].....
I want to write an if statement which has condition like
if(i%1==0 && i%2==0 && i%3==0 && i%4==0 && i%5==0 &&
i%6==0 && i%7==0 && i%8==0 && i%9==0 && i%10==0 &&
i%11==0 && i%12==0 && i%13==0 && i%14==0 && i%15==0
&& i%16==0 && i%17==0 && i%18==0 && i%19==0 && i%20==0)
This of course is not the right way to write it. How to generalize it so that I can check the condition not only till 20 but till any number without manually adding all conditions.
I am try to make a menu for deliver order program.
The menu divide into 3 group which are breakfast, lunch and dinner. However breaker only available at 6.30am-10pm, lunch available at 11am-1.30pm and dinner only available at 6.00pm-8.30pm
Let say my current time on the system is 10.30am, and the user select breakfast order. It should not available at this time, and prompt a message to use that the order not available at this period.
How to write the program?
I'm trying to get an if/else statement to work using a character condition, but it is a no-go. After I input either a 'y' or 'n', the program just sits there until I press 'Enter' again, at which point it ends. It never actually goes through either of the 'if' statements. At first I only had a single '=' in the condition, but I found that that was wrong. When I corrected it to '==' it still didn't work. I also tried clearing the buffer by adding a 'getchar()' at the beginning of the program, but that didn't work either.
#include <stdio.h>
#define std_rate .8855
int main(void) {
char ans;
int counter = 1, euros = 5;
double dollars = 0, ex_rate;
[Code] .....
The compiler (Visual Studio 2013) requires me to use 'scanf_s' instead of just 'scanf' for some reason, and if I don't have two 'getchar()' commands at the end, then it won't stay open long enough for me to see the results.
#include <iostream>
#include <fstream>
#include <string>
using namespace std;
int check_Pythag(int DIMA, int DIMB, int DIMC) {
[Code] .....
I need to create a if else statement to check multiple model numbers (200+)... How can i build this? I basically want the user to enter their model number and if its on the list they get a approved or denied message.
So far I have this, the "if(model == 9002||1002)" doesnt seem right, it needs to basically check 200+ model numbers... am I even on the right track?
Code:
#include <iostream>
using namespace std;
int main(){
int model;
cout << "Enter model" << endl;
[Code] .....
I'm having an issue coming up with an if() statement to check if a word match the one in the value of a pointer's address. So far the best I've come up with only matches the first letter of the words, you'll find it in the code below.
#include"Header.h"
int Colour(struct MyStruct *ArrayPointer, int ArraySize) //ArraySize = 3 for this run. {
int ColourCount = 0;
for (int i = 0; i < ArraySize; i++) {
[Code] ....
An example run you can see in attached pic.
I want to have an if statement that only accepts "Red" and not the occasional "Ravaged_Anus".
I'm using MVS Express 2013, .c source files, and the C++ compiler.
Attached image(s)
I've written a bit of code :
#include <iostream>
#include <cmath>
#include <cstdio>
int main() {
for(int i=1; i<=1000; i++)
for(int j=i+1; j<=1000; j++)
for(int k=j+1; k<=1000; k++)
[Code] ...
Now why does defining the if condition as if(pow(i,2) + pow(j,2) == pow(k,2)) doesnt work (ie. doesn't print anything) while defining it as if(i*i + j*j == k*k) works flawlessly - by working I mean printing out single set of 3 numbers.
I wanted to input some numbers with scanf function, i can enter some numbers and if I input -1 to the scanf, the input must end. And the scanf function has limited input, the max that I can input is 40 numbers.example if enter 1 2 4 6 5 4 -1 the scanf function will ended and the result will be appear.I wanted to know how the scanf function is like that would be best for this problem, Code: scanf("%d", &n); the result if I input those number will be like
|
||
||||
||||||
|||||
||||
I found a for loop in an example that I don't understund fully.
Code:
for (i=64; i; i/=2)
printf("i: %d
",i);
Now this is dividing by 2 until it reach '1' and stops. But why does this stops?
I have two table the first is called Imprrests and the second is called ]IprestsPays. There is an Imprest_ID column that is primary key in [icode]Imprests[/code] table and foreign key in ImprestsPays table
Imprests table consists the following columns:
Imprest_ID, Impres_value, Imprest_date, Employee_ID
Where Employee_ID column is primary key in Employees table and foreign key in Imprests table.
ImprestsPays table consists the following columns:
ID, Payment_value, Payment_date, Imprest_ID
My problem is in the buttonadd_click event in Imprsts form.
I want to prevent user from insert any new imprest for employee in Imprests table if employee haven't paid all payments in ImprestsPays table for old imprest...
I am trying to write a simple program that produces different outputs based on entered age of two different users. Program should tell who is older and behave different if both users are older than 100.
Here is my program: Code: #include <iostream>
using namespace std;
int main()
{
[Code].....
Why program executes this when both users are obviously more than 100
The while loop part of my program isn't working right. stringOriginal is an array. If a large amount of characters passed the max 80 im processing is typed, it goes into a infinite loop. Also the condition doesn't work i type in quit and the loop continues.
while(stringOriginal != "quit"){
std::cout << "Enter a string of characters you would like to reverse
";
cin.getline(stringOriginal,79,'
');
}
I need to do make a loop inside a condition. Can it be done? I don't want to call another function to do it. Any way at all without calling separate function inside the if? I just want to do:
if (
for (int i = 0; i<=10; i++)
{
//stuff related to the for loop
} )
{
//stuff related to the initial if condition
};
I have always written like a>='0'&&a<='9'&&a>='a'&&a<='z' in loops etc, but no more. Basically add whatever you want to condition, and if you want point a to point b just separate them with a '-' sign. Simply
while(!isCharInside(x,"|a-zA-Z0-9.*/=|-|")){/*code*/}
bool isCharInside(char check,string condition="a-zA-Z*/+=|-|0-9"){
for(unsigned int x=0,z=getLenght(condition);x<z;++x){
if(condition[x+1]=='-'&&(condition[x]!='|'&&condition[x+2]!='|')){
if(condition[x]>condition[x+2])swap(condition[x],condition[x+2]);
for(;condition[x]<=condition[x+2];++condition[x]){if(condition[x]==check)return true;};x+=2;}
else if(check==condition[x])return true;
}
return false;}
I'm writing a delete function for a linked list, and I'm having issues with this bit of code:
void deleteNode(int data){
node* del = NULL;
t = h;
n = h;
while(n != NULL && n->_data != data){
t = n;
n = n->next;
}
}
Or more precisely, this portion:
&& n->_data != data
n is my new node variable, _data is the storage variable in the private section of my class, and data is the information being searched for that needs to be deleted. Everything works without this section of the code. My assumption is that n->_data is somehow wrong, but I don't see how. I've tried everything I can think of- using parenthesis, using the variable rather than the pointer, I've tried expressing the pointer in a different way, I've tried using my t variable rather than n, and I've found examples online that use this exact same expression without any issues.
Write a program to calculate the Loan Balance, where a person borrows an amount A and in return he/she agrees to make N payments per year, each of amount P. While the person is repaying the loan, interest will accumulate at an annual percentage rate of R, and this interest will be compounded N times a year (along with each payment). Therefore, the person must continue paying these installments of amount P until the original amount and any accumulated interest is repaid.
NOTE: The formula to calculate the amount that the person needs to repay after T years is-
Balance Amount after T years = A[(1+R/N)^NT]-P
-----------------------------------------------------------
I have a few doubts :
1. I think that the "balance amount" formula can directly give the "loan balance" for the person. I'm not sure if it's correct but in that case the question would serve no purpose. Maybe I'm wrong.
2. If there should be a loop to calculate the loan balance, what condition should I give and which loop will be better to use?
I'm parsing a text file, and I'd like to detect when a certain Compilation Condition - i.e. #ifdef - begins. The challenge is, that the condition can take any of the following patterns:
#ifdef (FLAG)
#if defined (FLAG)
#if (defined (FLAG))
(And perhaps I missed more)
I'd of course need to treat them all the same, as they are indeed the same. How would you know to treat them all the same?
How to make if else code below into SWITCH STATEMENT?
cout << "Enter the temperature: ";
cin >> temp;
cout << "Enter the pressure: ";
cin >> pressure;
cout <<endl;
[Code]....
I am trying to implement a Task scheduler where i have n number of tasks. The Idea behind my task scheduler is that in a loop of queues of a vector, task should get enqueued to the shortest queue among the loop of queues, which is done by the following code.
#include <vector>
#include <queue>
std::vector<std::queue<int> > q
int min_index = 0;
task t // implemented in the other part of the program
[Code] ....
Next i am trying to extend this paradigm to reduce the overhead time of the scheduler, Instead of searching the shortest queue every time, search after some condition ie. search the shortest queue after 5 tasks gets enqueued to the shortest queue.
i need to do something like this
#include <vector>
#include <queue>
std::vector<std::queue<int> > q
task t // implemented in the other part of the program
while(q[min_index].size()!=q[min_index].size()+5) // check whether current min_index queue's size is increased 5 more times if not goto enqueue
[code].....
I'm using SDL to try to create a Run and Shoot game. But I do not know how to check if a key is down while the user is HOLDING it.
I do know how to check if a key was pressed.
I have tried with the "event.key.keysym.sym" and "Uint8 *keystate = GetKeyState(NULL)" both worked to check if a key was down but I thought that the GetKeyState(); Function would even check when a key where HELD down
I want my player to move while holding down left or right arrow. So I did something like:
Code:
Uint8 *keystate = GetKeyState(NULL);
if (keystate[SDLK_RIGHT]) {
apply_surface(x++, y, player, screen);
}
How to check if a key is held down?
I am writing a console program for a class. I have satisfied the assignment, but I want to clear up what is mostly a cosmetic problem. The program prints a form to the console and places the cursor at a location on the form where the user inputs data. The problem occurs when the user presses the enter key without entering data. The cursor goes to the beginning of the next line. If the user enters data after this, the program functions correctly. I want to know how I can reposition the cursor if the user enters no data.
This is the code that reads one of the values:
Code:
void getHousing(HANDLE screen, MonthlyBudget &inputBudget) {
placeCursor(screen, HOUSING_ROW, ACTUAL_COL);
cin >> inputBudget.housing;
while (!validateEntry(screen, inputBudget.housing)) {
placeCursor(screen, HOUSING_ROW, ACTUAL_COL);
cout << SEVEN_SPACES << endl;
placeCursor(screen, HOUSING_ROW, ACTUAL_COL);
cin >> inputBudget.housing;
}
}
validateEntry checks that the entered value is >= 0 SEVEN_SPACES is a string of seven spaces to cover up the previous entry.
I'm currently trying to write a while loop that checks if the text file has read all the contents inside. I've tried using
while(!in.eof())
but as usual it executes my loop an extra iteration, printing my last output twice. I am reading my data in from a method inside a class, so I cannot use getline as my while test to check if the file has read input or not. Is there any way to force my loop to check if the end of file has been read before the eof() test is executed?
write a program to check the number is even or odd using (For loop) in c++ ?
View 10 Replies View RelatedThis while statement is not cooperating and I am not really sure why. I tried to say while not equal to true and later false, but both produce a never ending loop. I know I posted this before and I got several comments back about different issues with this program. However this question is specific about the while statement.
Code:
#include <iostream>
#include <vector>
#include <string>
using namespace std;
[Code] ....
I'm having a really dumb moment and I cant seem to remember how an if statement works, with only the variable name as the condition..
Code:
if(var){
//then do something
}