I am trying to write a simple program that produces different outputs based on entered age of two different users. Program should tell who is older and behave different if both users are older than 100.
Here is my program: Code: #include <iostream>
using namespace std;
int main()
{
[Code].....
Why program executes this when both users are obviously more than 100
This program that I've made works fine to find midpoint, but not distance. The distancefunction always returns a 1 (true). To try to see that it wasn't the math, I added cout.setf(cout.boolalpha) to see and got a result of "true".
//This program is a start to solve basic coordinatre plane distances and midpoints
#include <iostream>
#include <cstdio>
#include <cstdlib>
using namespace std;
[Code].....
is it true or false
a function like void myfun(int num){} can receive type "int var" but can't receive type "const int var"
AND
a function like void myfun(const int num){} can receive both type "int var" and also type "const int var"
I have always written like a>='0'&&a<='9'&&a>='a'&&a<='z' in loops etc, but no more. Basically add whatever you want to condition, and if you want point a to point b just separate them with a '-' sign. Simply
while(!isCharInside(x,"|a-zA-Z0-9.*/=|-|")){/*code*/}
bool isCharInside(char check,string condition="a-zA-Z*/+=|-|0-9"){
for(unsigned int x=0,z=getLenght(condition);x<z;++x){
if(condition[x+1]=='-'&&(condition[x]!='|'&&condition[x+2]!='|')){
if(condition[x]>condition[x+2])swap(condition[x],condition[x+2]);
for(;condition[x]<=condition[x+2];++condition[x]){if(condition[x]==check)return true;};x+=2;}
else if(check==condition[x])return true;
}
return false;}
The question is to write a recursive boolean function that compares two stacks and returns true if they are identical. This is where I get stuck:
If the top items of both stacks are the same, the recursive call always returns true, because 'true' is saved on top of the return stack.
Here is my code:
template<class Type>
bool identicals(stackType<Type> s1, stackType<Type> s2) {
if(!s1.isEmptyStack() && !s2.isEmptyStack()) {
if(s1.top() != s2.top())
[Code] ....
I was instructed to write a binary search function which would return true if an element, inputted by the user, was found in the array, and false if it was not. I'm not sure why, but my function always returns false. My code is as follows.
#include <iostream>
#include <cstdlib>
#include <ctime>
using namespace std;
//binary search function
bool search (int array[], int item)
[Code] ....
Why my code does not fulfill it's purpose???
Write a function that takes an array and returns true if all the elements in the array are positive, otherwise, it returns false.
View 6 Replies View RelatedThis is the code i am working on: [URL] .... I had designed a cross platform grep and am revising it to making it more well for lack of a better word understandable, and clear.
The line
while(getline(file, currentLine))
Worked before but now it doesn't.
I have to write a program in c which allow user store data in a file as well can edit it.... i have written the following program, but the program cannot read data after EOF command has been executed....
#include <stdio.h>
main() {
FILE *fp;
char c;
int ch;
char filename[20];
printf("enter filename");
[Code] ....
Code:
#include <stdio.h>
main() {
int c, n1;
n1 = 0;
while ((c = getchar()) != EOF)
if (c == '')
++n1;
printf("%d", n1);
}
I have a more complicated program I'm wishing to have display the output, however, to save some time I'm using an example of a shorter version. count the lines in input and display the output in terminal when ./program is executed after compilation. To count and compute lines, words and within arrays.
I've written a bit of code :
#include <iostream>
#include <cmath>
#include <cstdio>
int main() {
for(int i=1; i<=1000; i++)
for(int j=i+1; j<=1000; j++)
for(int k=j+1; k<=1000; k++)
[Code] ...
Now why does defining the if condition as if(pow(i,2) + pow(j,2) == pow(k,2)) doesnt work (ie. doesn't print anything) while defining it as if(i*i + j*j == k*k) works flawlessly - by working I mean printing out single set of 3 numbers.
I've tried retyping the code several times and didn't work for some reason the If wont accept both Q and q it just accepts Q.
Code:
#include <stdio.h>
int main(void)
{
printf("A menu will show up and you choose the number for the selection you want.
[Code].....
I wanted to input some numbers with scanf function, i can enter some numbers and if I input -1 to the scanf, the input must end. And the scanf function has limited input, the max that I can input is 40 numbers.example if enter 1 2 4 6 5 4 -1 the scanf function will ended and the result will be appear.I wanted to know how the scanf function is like that would be best for this problem, Code: scanf("%d", &n); the result if I input those number will be like
|
||
||||
||||||
|||||
||||
I found a for loop in an example that I don't understund fully.
Code:
for (i=64; i; i/=2)
printf("i: %d
",i);
Now this is dividing by 2 until it reach '1' and stops. But why does this stops?
I want to write an if statement which has condition like
if(i%1==0 && i%2==0 && i%3==0 && i%4==0 && i%5==0 &&
i%6==0 && i%7==0 && i%8==0 && i%9==0 && i%10==0 &&
i%11==0 && i%12==0 && i%13==0 && i%14==0 && i%15==0
&& i%16==0 && i%17==0 && i%18==0 && i%19==0 && i%20==0)
This of course is not the right way to write it. How to generalize it so that I can check the condition not only till 20 but till any number without manually adding all conditions.
I am try to make a menu for deliver order program.
The menu divide into 3 group which are breakfast, lunch and dinner. However breaker only available at 6.30am-10pm, lunch available at 11am-1.30pm and dinner only available at 6.00pm-8.30pm
Let say my current time on the system is 10.30am, and the user select breakfast order. It should not available at this time, and prompt a message to use that the order not available at this period.
How to write the program?
I have two table the first is called Imprrests and the second is called ]IprestsPays. There is an Imprest_ID column that is primary key in [icode]Imprests[/code] table and foreign key in ImprestsPays table
Imprests table consists the following columns:
Imprest_ID, Impres_value, Imprest_date, Employee_ID
Where Employee_ID column is primary key in Employees table and foreign key in Imprests table.
ImprestsPays table consists the following columns:
ID, Payment_value, Payment_date, Imprest_ID
My problem is in the buttonadd_click event in Imprsts form.
I want to prevent user from insert any new imprest for employee in Imprests table if employee haven't paid all payments in ImprestsPays table for old imprest...
I'm trying to get an if/else statement to work using a character condition, but it is a no-go. After I input either a 'y' or 'n', the program just sits there until I press 'Enter' again, at which point it ends. It never actually goes through either of the 'if' statements. At first I only had a single '=' in the condition, but I found that that was wrong. When I corrected it to '==' it still didn't work. I also tried clearing the buffer by adding a 'getchar()' at the beginning of the program, but that didn't work either.
#include <stdio.h>
#define std_rate .8855
int main(void) {
char ans;
int counter = 1, euros = 5;
double dollars = 0, ex_rate;
[Code] .....
The compiler (Visual Studio 2013) requires me to use 'scanf_s' instead of just 'scanf' for some reason, and if I don't have two 'getchar()' commands at the end, then it won't stay open long enough for me to see the results.
The while loop part of my program isn't working right. stringOriginal is an array. If a large amount of characters passed the max 80 im processing is typed, it goes into a infinite loop. Also the condition doesn't work i type in quit and the loop continues.
while(stringOriginal != "quit"){
std::cout << "Enter a string of characters you would like to reverse
";
cin.getline(stringOriginal,79,'
');
}
I need to do make a loop inside a condition. Can it be done? I don't want to call another function to do it. Any way at all without calling separate function inside the if? I just want to do:
if (
for (int i = 0; i<=10; i++)
{
//stuff related to the for loop
} )
{
//stuff related to the initial if condition
};
The task is to return the number of bits set to true.Here is my code:
Code:
int cardinalityBS(PBitSet _this) {
int s, counter = 0;
for(s = 0; s < 31; s++) {
counter += _this->bits & 1;
_this->bits <<= 1;
}
return counter;
}
[code]....
The code is not working, since whenever I set _this->bits to a number, it returns me the wrong result.
My assignment : "Input the answer as the words true or false and put the user's answer in a boolean alphabetic variable."
My code:
bool T;
cout << "Type 'true' for lowercase or 'false' for uppercase";
cin >> T;
if (T == "true") {
cout << "Enter a whole number in decimal base: ";
cin >> dec;
cout.setf(ios::showbase);
cout << "Decimal " << dec << " to Hexadecimal with lowercase: " << setbase(16) << dec;
}
I'm not sure how to get 'true' as user-input as true for bool.
I'm writing a delete function for a linked list, and I'm having issues with this bit of code:
void deleteNode(int data){
node* del = NULL;
t = h;
n = h;
while(n != NULL && n->_data != data){
t = n;
n = n->next;
}
}
Or more precisely, this portion:
&& n->_data != data
n is my new node variable, _data is the storage variable in the private section of my class, and data is the information being searched for that needs to be deleted. Everything works without this section of the code. My assumption is that n->_data is somehow wrong, but I don't see how. I've tried everything I can think of- using parenthesis, using the variable rather than the pointer, I've tried expressing the pointer in a different way, I've tried using my t variable rather than n, and I've found examples online that use this exact same expression without any issues.
I am again a bit confused with bool since we have not used them much. I understand it is suppose to return a true or false value that is represented by 0 and 1. so I have these two bool's
bool Triangle::isRight() {
if (pow(largestSide(), 2) == (pow(smallestSide(), 2) + (pow(middleSide(), 2)))) {
return true;
} else {
return false;
[Code] ....
and then I cout to display them
cout << "Is this a right triangle: " << t2.isRight() << endl;
cout << "is this a Triangle: " << t2.isTriangle() << endl;
and i get this
"Is this a right triangle: " 0
"Is this a triangle: " 1
Which i know is correct but I want to replace the 1 and 0 with my own string but the things iv tried tweaking with has not worked.
Also in the file attached has some requirements from my teacher but i was confused at the second last one, --- bool isEqual(Triangle &other) and it says return true if triangles are equal and false if triangles are not.
I dont know if this is just simply if one triangle equals another (however you determine that) or if its for the two bool's, isTriangle() and isRight() or what.
Attached image(s)
Write a program to calculate the Loan Balance, where a person borrows an amount A and in return he/she agrees to make N payments per year, each of amount P. While the person is repaying the loan, interest will accumulate at an annual percentage rate of R, and this interest will be compounded N times a year (along with each payment). Therefore, the person must continue paying these installments of amount P until the original amount and any accumulated interest is repaid.
NOTE: The formula to calculate the amount that the person needs to repay after T years is-
Balance Amount after T years = A[(1+R/N)^NT]-P
-----------------------------------------------------------
I have a few doubts :
1. I think that the "balance amount" formula can directly give the "loan balance" for the person. I'm not sure if it's correct but in that case the question would serve no purpose. Maybe I'm wrong.
2. If there should be a loop to calculate the loan balance, what condition should I give and which loop will be better to use?
#include <iostream>
#include <fstream>
#include <string>
using namespace std;
int check_Pythag(int DIMA, int DIMB, int DIMC) {
[Code] .....