This is the code i am working on: [URL] .... I had designed a cross platform grep and am revising it to making it more well for lack of a better word understandable, and clear.
The line
while(getline(file, currentLine))
Worked before but now it doesn't.
Code:
#include <stdio.h>
#include<ctype.h>
void try5t(){
char choice;
int choiceint;
[Code] .....
Loop is repeated an additional time as shown in the screenshot:
Hey I am trying to use the getline() function to read a line from a file. For some reason Visual Studio 2010 gives me the following error. "No instance of overloaded function "getline" matches the argument list". The piece of code that produces the error is in a class in a separate .h file and is executed as a method of the object. I'm almost certain it has something to do with either the compiler thinking I am calling another getline in a different namespace or my parameters for the function are incorrect. Here is the code:
Code:
#include <iostream>
#include <string>
#include <vector>
#include <fstream>
using namespace std;
class InsultGenerator
[Code] .....
I am trying to use getline as the conditional for a while loop as seen below.
string filename, guard_name;
int call_number;
vector <Seniority> SeniorityList;
ifstream SeniorityFile;
[Code] ....
However, when I compile the code, I get the following error message on the line with the while loop.
error C2780: 'std::basic_istream<_Elem,_Traits>
&std::getline(std::basic_istream<_Elem,_Traits>
&,std::basic_string<_Elem,_Traits,_Alloc>
&)' : expects 2 arguments - 3 provided
The program will be reading in a .csv file, so I need my program to be able to deal with values separated by commas. Is there a reason why it will not accept that conditional statement?
This program is meant as practice. However, it is not working as intended. The for loop is meant to take the argument from the user and use it as the amount of times to loop. Instead it simply outputting: . It is supposed to output i++ but does not.
Here is the code:
main.cpp:
#include <iostream>
#include <stdlib.h>
int main(int main, char* arg[], char* arg2[]) {
int iterator = atoi(arg2[0]);
std::string z = "-c";
[Code] ....
I am trying to write a simple program that produces different outputs based on entered age of two different users. Program should tell who is older and behave different if both users are older than 100.
Here is my program: Code: #include <iostream>
using namespace std;
int main()
{
[Code].....
Why program executes this when both users are obviously more than 100
I have to write a program in c which allow user store data in a file as well can edit it.... i have written the following program, but the program cannot read data after EOF command has been executed....
#include <stdio.h>
main() {
FILE *fp;
char c;
int ch;
char filename[20];
printf("enter filename");
[Code] ....
I need to write a ANSI program to print out each command line argument on a separate line using a for-loop. also it need to print the name of the executable .so far I have
Code:
#include <stdio.h>
int main(int argc, char **argv) {
int i;
printf("")
[code]....
Code:
#include <stdio.h>
main() {
int c, n1;
n1 = 0;
while ((c = getchar()) != EOF)
if (c == '')
++n1;
printf("%d", n1);
}
I have a more complicated program I'm wishing to have display the output, however, to save some time I'm using an example of a shorter version. count the lines in input and display the output in terminal when ./program is executed after compilation. To count and compute lines, words and within arrays.
I've just started learning from "Jumping into C++". Great book. Unfortunately, I've also encountered my first snag. Practice problem number 3 from chapter 4 tells me to make a small calculator that takes one of the four arithmetic operations and its two arguments as input and give the result as output. Here's what my newbie mind came up with:
Code:
#include <iostream>
#include <string>
using namespace std;
int main()
[Code] .....
The thing that I don't get is why doesn't the function "getline" work. It's worked in previous programs. The program seems to work if I simply replace getline with a simple "cin". I could easily use that as a cheap fix but I am interested in knowing why "getline" refuses to work anymore....
I'm currently trying to write a while loop that checks if the text file has read all the contents inside. I've tried using
while(!in.eof())
but as usual it executes my loop an extra iteration, printing my last output twice. I am reading my data in from a method inside a class, so I cannot use getline as my while test to check if the file has read input or not. Is there any way to force my loop to check if the end of file has been read before the eof() test is executed?
I am just trying to get a code going for a mock test and to get use to the getline and IF operations, but it seems I have ran into an issue[URL] is a link to the code I have written, and I can use getline to give a value to my variable, but it seems like it gets lost once I try to use the IF function. Am I not using the right variable type?
View 14 Replies View RelatedI'm using getline to read in from a file line by line but it skips the first two whitespaces.
Example input:
1 0.7 mountain and grant
How it's being stored:
10.7mountain and grant
I have just started working through "Jumping into C++". I am at the section on appending strings. The tutorial mentions the getline function but I can not seem to get it to activate. There is no mention of any other inclusions.
Code:
#include <iostream>
#include <string>
using namespace std;
[Code] ....
I note that the getline function color remains black while other functions are green. I presume this means that Codeblocks has not associated it with any of the listed header files. Has the tutorial omitted this detail?
How the getline function works.
Code:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int main() {
[Code] ......
getline(&inputstr, 128, NULL); getline gets a line in a data file.
I assume that inputstr[128] is the name of the file? why is the number of the array in the getline function....
why does this happen that if i use
string ans;
for(int i=1; i<3; i++)
{
cout << "enter an option" << endl;
getline(cin,ans)
}
in a loop it always skips the first time but in the next times it asks?
text file is
hello
there
void readFile(char[], ifstream&);
address records[numbersAdd];
int main(){
char xml[30];
cout<<"Enter file name ";
[code].....
I used getline to import EMPLOYEE's First and Last Name from a txt file. After calculating the weights ans stuff. Now when i try to write to output txt file am having the below issue in which its not putting it in one line.
***CODE***
fout << "Note: This report for " << employee << " was prepared according to the fair practice of the University." << endl ;
***THIS IS WHAT ITS PRINTING***
Note: This report for FIRSTNAME LASTNAME was prepared according to the fair practice of the University.
I also tried like this;
***CODE***
fout << "Note: This report for " << getline(fin, employee) <<" was prepared according to the fair practice of the University." << endl ;
***THIS IS WHAT ITS PRINTING***
Note: This report for 0 was prepared according to the fair practice of the University.
this second code puts everything in one line but its showing 0 (zero) instead of the employee's first and last name.
i got a file (teams.csv) which has the following content:
id,name
501,Abilene Chr
502,Air Force
503,Akron
504,Alabama
Now i want to read line by line using getline(). How will i do that?
I have a problem with the switch statement because it doesn't prompt me to input something.
#include <iostream>
#include <fstream>
#include<cstring>
using namespace std;
//Compiler: Dev C++ and cygwin
void rd() {
string txt;
[Code] ....
I want to get rid of this kind of output ...
I am currently having trouble to have getline to read line from the file. Error is: "no instance of overloaded function "getline" matches the argument list"
code is as follows:
std::ifstream config("config.txt");
string process[4];
int linecount = 1;
if (config.is_open)
{
while (config.peek() !=EOF)
{
getline(config, process);
linecount++;
}
}
Down on line 74, it does not wait cor an input, it simply says ...you failed.
#include <iostream>
#include <string>
#include <Windows.h>
#include <cstdlib>
using namespace std;
//prototyping--
void flater();
[Code] ....
I am reading a file of text. I want to read in every word, but no spaces or newlines. "word" is a string, and "c" is a char (used for getting rid of white space. The problem: I can get rid off spaces perfectly, but newlines remain in "word" if it comes before the terminating character ' '.
My code:
while(infile.good() && !infile.eof()) {
while(infile.peek() == ' ')
infile >> c;
while(infile.peek() == '
[Code] .....
I have a std::stringstream sstr I read data from with getline(sstr, s, ',').
Now I don't want it to cut off the leading blanks. How can I do that?
I'm trying to make a program where it reads a text file which contains "blocks" of questions like:
Type: multiple_choice
Question
Num_options: number of options
a) option1
b) option2
c) option3
d) option4
Letter of answer
and
Type: short_answer
Question
Answer text
what I'm trying to do is use parse those blocks and have it get handled by the classes, MultipleChoice and ShortAnswer.
I'm planning on using getline as a virtual function and have an if statement like
"if (string == "multiple choice)
** then get it handled by the MultipleChoice class "
How do I use a string in place of a character in the function getline?
For example,
getline(infile,lines,'}');
This works fine, but I want the delimiter of } to be "};", but I can't do this as it only takes in characters, not strings.
I want:
getline(infile,lines,"};");
Any way to get around this?