My break; isn't ending the for statement. User should only get 3 choices but they get to input more than 3.
int playGame() {
int count =0; int x = (rand()%10)+1; int y;
for(int i=0;i<3;i++) {
cout << "Guess the number 1-10: ";
cin >> y;
if (x==y)
[Code] ......
I seem to be having a bit of problem with my if statements in a for loop.
My code involves asking the user for the name of an element (chemistry), searching a text file line by line for an element that matches the input, and outputting other information regarding that element.
One line of the text file looks like this: Helium,He,2,4.00
I've tried running the code without the if loop and it outputs normally (If I ask it to output elementname[0] it will output the first element Hydrogen, which is correct.) but I am not sure what goes wrong when I add the if statement. For some reason, it always follows the "else" statement (It always outputs Invalid search even when I input the right elements).
const int ELEMENTS = 118; //number of elements
ifstream File;
string elementname[ELEMENTS], atomicsymbol[ELEMENTS], atomicnumber[ELEMENTS], atomicmass[ELEMENTS];
string elemname, atomsym, atomnum, atommass;
string search;
[Code] ....
I got insert statment inside loop like this:
if (ds.Tables.Count != 0)
{
for (Row = 0; Row <= ds.Tables[0].Rows.Count - 1; Row++)
InsertLSP(ElemStartTimeInPrograme, ..........) <-----------------------
[Code]....
i would like to check whether first insert call inside ds loop if is failed e.g due to connection problem this will be ended. What is best way to implement that?
I was wondering how I could use a continue statement that continues in a nested loop. For example if I have
for (int i=0;i<amount;i++) {
for (int j=0;j<I[i];j++) {
for (int k=j+1;k<I[i];k++) {
if (P[i][j]+P[i][k]==C[i]) {
//What should be here?
}
}
}
}
If the condition is met then the most outer loop (in i) should continue to the next iteration.
If i simply fill in continue; in before the comment then it only continues the loop in k so that is not what I want.
I have more programming before this, but everything else works fine. My else loop has an infinite output. i also want it to output an error message if the value is not an integer and return to the input
cout << "Select number corresponding material for fencing:" << endl;
cout << "wood = 1" << endl;
cout << "stone = 2" << endl;
cout << "aluminium = 3" << endl;
cin >> material;
if (material == 2){
cost = 100 * perimeter;
[code]....
I'm trying to put an if-else statement in a do-while loop and when I put the correct answer in the if statement I get that error. Here's the program:
#include <iostream>
using namespace std;
int main() {
int answer;
char repeat;
[Code] .....
Basically I'm supposed to use a while loop to generate a random number and use a switch statement to output the appropriate information. I feel like I'm missing a few things that are very simple.
The errors are:
warning C4244: 'argument' : conversion from 'time_t' to 'unsigned int', possible loss of data
warning C4700: uninitialized local variable 'randomNumber' used
#include <iostream>
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
using namespace std;
int main(){
int i = 0;
unsigned int randomNumber;
[Code] .....
I am working on a small simple program my program fills up a air plane with customers there is 2 levels 1 and 2 and it will put that person in the spot depending on being picked.
So far i made a boolean airplane with 10 spots I can enter 1 person into the airplane with no problem but then after he sits down i get a infinite loop? I assume i maybe have to use the continue statement I feel like there is something simple that im missing i want to add more people. here is what i have
class Program
{
static void Main(string[] args)
{ bool[] planeSeats = {false, false, false, false, false, false, false, false, false, false };
[Code]......
Write a for loop statement to print the numbers from 1 to 10 in reverse order separated by star :
10*9*8*7*6*5*4*3*2*1
i try to do it but it show me like this :
10*9*8*7*6*5*4*3*2*1*
how do i write to show me like the first one ?
I am writing for loop with a switch so that scores can be inputted in by a judge. The issue that I am running into is that I will put out an the text then the test happens and the code puts out the switch statement 5 times with random number. Here is what I have written.
Code:
int main() {
int diver;
int option;
int Judge;
cout << "Enter Divers Name:";
[Code] ....
How to make if else code below into SWITCH STATEMENT?
cout << "Enter the temperature: ";
cin >> temp;
cout << "Enter the pressure: ";
cin >> pressure;
cout <<endl;
[Code]....
We are making a program--but every time we input a value for scanf, the following for loop does not work and the program quits without displaying the for loop's function. We are not getting any errors.
View 11 Replies View RelatedI have tried to submit this topic before but i didn't submit my whole code and it was removed. So here it is. All I am trying to do is load form2 from form1 then back to form1 from form2 for a certain number of times the get out of the loop. I am new to C-Sharp and it seems as though I cant seem to figure out a way to do this.
Here is form1 and form2 code. I have commented out a few things I have tried.
using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
[Code]....
Code:
#include <stdio.h>
#include<ctype.h>
void try5t(){
char choice;
int choiceint;
[Code] .....
Loop is repeated an additional time as shown in the screenshot:
This while statement is not cooperating and I am not really sure why. I tried to say while not equal to true and later false, but both produce a never ending loop. I know I posted this before and I got several comments back about different issues with this program. However this question is specific about the while statement.
Code:
#include <iostream>
#include <vector>
#include <string>
using namespace std;
[Code] ....
I'm having a really dumb moment and I cant seem to remember how an if statement works, with only the variable name as the condition..
Code:
if(var){
//then do something
}
Well for some reason this doesn't work.
Code:
#include <stdio.h>#include <ctype.h>
int main(void)
{
int lottoNums[150];
int num;
[Code]....
how would i got about making an if statement for an array so it prints what u enter
Code:
example:
struct input{
float peopleseen;
float creditrate;
char insurprov[12];
[Code] ....
When I do this:
Code:
#include <stdio.h>
#include <stdlib.h>
int main () {
int guess ;
int number = 5 ;
[Code] .....
But when I do this:
Code:
#include <stdio.h>
#include <stdlib.h>
int main () {
int guess ;
int number = 5 ;
[Code] ....
Why does the compiler say that there is an else without a previous if ??? ... Does this mean that I cannot use "scanf" in an if/else statement?
I was wondering how you would put this if else statement to a switch statement.
void PlayerDB::AddPlayer(const Player& avatarPlayer) {
char * playerName = new char[avatarPlayer.lenName()];
Player*player = NULL;
[Code] ....
i am trying to make a ticktacktoe game. I made a simple one with no ai but i decide to add an option to play against computer. And i code like that(i know this is really bad):
/*
Name: TickTackToeFinal
Copyright:
Author:
Date: 26.06.13 20:41
Description:
*/
#include <iostream>
#include <string>
[code].....
when i run the game its always play randomly(last if statements in bilgisayar functions.
not:bilgisayar means computer
zor means hard
orta means medium
kolay means easy
oyuncu means player
tur means round
oyun means game
I have written a C++ program in which a user need to input a character. My problem is it's working fine for the first time but as it goes through the code second time, it skips the cin statement and takes the previous defined value. how can i make cin statement work for the second time also?
View 5 Replies View RelatedI just want to say that I just started learning the language and this is my very first shot at writing a simple program that is not "Hello World" So I recently learnt the basics of the if statement and how to loop in a console application, here's what it looks like:
namespace Testing_IF_Statement
{
class Program
{
[Code].....
And again, this is just what I wrote in a few minutes without putting any thought into it.
Questions:
1)I have heard that the way I'm looping by using the goto statement is considered quite ancient, why is this and how else could I loop the program?
2)I declared a as an integer and asked the user to type 1,2,3,4 to perform mathematical functions, but when I tried declaring a as a string and searching if a == "PLUS" etc it would throw an error. Is there any mistake in how I approached this?
3)I know this is a bit premature to ask, but instead of writing _________ in the console to separate the loop is there any professional way to add a separator?
4)In general how can I improve the code?
#include <stdio.h>
#include <math.h>
int main(void)
{
[Code]....
That's my code above and I'm getting an error saying that I'm "implicitly declaring library function 'strcmp' with type 'int(const char*, const chat*)". When i run this program and enter in Black for the first prompt, the program stops. I'm trying to make this program so that when I enter Black as the answer for the first prompt, the program will display the value 10.
I want to set an integer to zero when it easy equal to another integer, but it seems that the program for some reason won't set the integer to zero. Here is the example of that code:
#include <iostream>
using namespace std;
int main () {
int n = 2;
int r = 2;
if(n==r)
n++;
r*0;
cout << " n is " << n << endl;
cout << " r is " << r << endl;
}
What am I doing wrong, it should say that "n is 3" and "r is 0".
I have this case statement that is not performing as expected. For some reason ASE_OK and ASE_NotPresent both print out. Why is this? ASE_OK is a return value of 0 while ASE_NotPresent is -1.
Code: // Try to create the buffers and store it
switch (theAsioDriver->createBuffers(info, numChannels, bufferSize, callbacksInfo)) {
case ASE_OK:
std::cout << "ASE_OK";
input->bufferSize = output->bufferSize = bufferSize; // Buffer size is stored in both input and output
case ASE_NotPresent:
std::cout << "ASE_NotPresent";
errorMessage = "Could not find input or output devices.";
return NO_DEVICES_FOUND;
[code]....
