C++ :: Continue Statement In Nested Loop
Feb 9, 2014
I was wondering how I could use a continue statement that continues in a nested loop. For example if I have
for (int i=0;i<amount;i++) {
for (int j=0;j<I[i];j++) {
for (int k=j+1;k<I[i];k++) {
if (P[i][j]+P[i][k]==C[i]) {
//What should be here?
}
}
}
}
If the condition is met then the most outer loop (in i) should continue to the next iteration.
If i simply fill in continue; in before the comment then it only continues the loop in k so that is not what I want.
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Nov 25, 2013
Is there a way to tell the program to continue reading the next line of code within a nested IF statement?
The reason I want to do this is because the two "else" statements in the following sample (the main and the nested else) will contain the same exact code and I don't want to repeat it twice. I know I can do this by creating a function and calling it from each else statement but I was just wondering if what I'm asking is even possible without using a function.
if(1 < 2) {
// yes 1 is less than 2
if(5 > 10) {
// do something
} else {
// no, 5 in not greater than 10
// here is where I want to tell the program to continue reading the next else statement
[Code] ....
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Nov 25, 2013
I need to promote user to enter y/n in switch statement to continue or not for an other conversion after showing results of each conversion.
#include <iostream>
using namespace std;
int main() {
char a;
double n, r1, r2;
cout<<"Please Chose the Temperature Unit to Convert: "<<endl<<endl;
[Code]....
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Apr 3, 2014
I wrote this code, and everything was working well, but part of the assignment is that it must include nested loops. Once I added the nested while loop, which is basically an if statement, my life was ruined. I am trying to nest a loop in the code that will basically tell the compiler that if the value "loopVol" were to exceed the value of "final" after adding an increment, to run the program for the "final". How can I do that?
Example:
initial = 10
final = 123
increment = 10
as of now, the program would stop at 120, but I want to nest a loop that will tell the compiler to calculate at the final if this happens.
#include <iostream>
#include <iomanip>
#include <stdio.h>
[Code]......
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Jul 30, 2013
I've been having problems with my loop that asks if the user wishes to continue or not. The required input should either be 'y' or 'Y', or 'n' or 'N'. Anything else should be counted as invalid, and repeat the prompt for input. The first few times I ran my program, the compiler does not read it as a loop. The next few times just won't work properly.
Here is the prompt:
Code:
void question() {
char option;
printf("
Do you want to continue? {Y|N) ");
scanf("%c", &option);
[Code] ......
As it is, it immediately runs the else option, but otherwise runs just fine. I suspect it could be because I have not specified a size for the option variable, but I try doing that, and the prompt relegates everything to the else.
(And also, here's the rest of the code. Basically, it just assigns a value to the letters of the word (a/A = 1, b/B = 2, etc.), adds these values, and determines if a word is prime or not based on the sum.)
Code:
#include <stdio.h>
#include <string.h>
#define size 30
int main() {
char letter, word[size], lower, upper, option;
int i, value, ans = 0, a, choice = 1;
[Code] .....
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Mar 17, 2015
what do I do if the while loop repeat iterating and do not stop running even if it did meet the conditions required?
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Mar 25, 2013
This code is used in scientific calculation for optimization problem.
Basically a particle is moving in a three dimensional space, its position is (x,y,z).
At each position, there is a fitness value associated with that position.
The fitness value is given by fitness(x,y,z) (code line 12~19).
We need to find out, when the particle moves around randomly, what is the highest possible fitness value.
To solve this, below code is used, and it produces correct result.
#define DIMENSION 3
#define MAXX 4
#define MINX 0
#define MESHsize 1
#include <iostream>
using namespace std;
float maxValue = 0.0;
[Code] ....
The output of the code:
[ fitness(0,0,0) = 0] [ fitness(0,0,1) = 1] [ fitness(0,0,2) = 4] [ fitness(0,0,3) = 9]
[ fitness(0,1,0) = 1] [ fitness(0,1,1) = 2] [ fitness(0,1,2) = 5] [ fitness(0,1,3) = 10]
[ fitness(0,2,0) = 4] [ fitness(0,2,1) = 5] [ fitness(0,2,2) = 8] [ fitness(0,2,3) = 13]
[ fitness(0,3,0) = 9] [ fitness(0,3,1) = 10] [ fitness(0,3,2) = 13] [ fitness(0,3,3) = 18]
..... so on
Answer: highest fitness = 27
Note: In this case, the values of x,y and z is integers from 0 to 3 inclusive.
For 3-dimensional space above, actually the code had run through 3 nested "for" loops.
Question: Above code works for 3-dimensional space. How to generalize the code, so that it works also for N-dimensional space, where N is an arbitrary integer?
( Note: possibly N = 30 )
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Nov 3, 2014
I'm trying to output a pattern using loops. The pattern is a plus symbol made of 3 rows of 5 x's followed by 3 rows of 15 x's and finally 3 rows of 5 x's.
I can get the program to output all 9 rows with 5 x's but I don't know how to do the 3 rows of 15 in the middle. I have tried a while loop and also an if statement but nothing seems to work.
#include "stdafx.h"
#include <iostream>
#include <iomanip>
[Code]....
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Mar 14, 2014
Code:
while(x==1){
for (i=0;i<j;i++)
{if (word1[i] == word2[i])
{prefix[i]= word2[i];
counter++;}
else
x=2;}
Basically after the 3rd run of the for loop, it encounters a contradiction. I want it to exit right there and then. Instead it continues to run the for loop. What can I do?
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Mar 13, 2013
How to make triangles using c++, in nested while loops.
The triangles were:
*
**
***
****
*****
******
*******
********
*********
**********
I have made a code for this:
int counter=1;
while (counter<=10){
int counter2=1;
while (counter2<counter){
[Code] .....
I was not quite sure about this one.
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Jan 6, 2014
how to draw a flow chart for following nested loop?
for(int r=1;r<=5;r++){
for(int c=1;c<=r;++c){
cout<<c;
}
cout<<endl;
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Feb 17, 2013
I'm writing a series of basic decipher programs and I have run into an issue where I get the correct answer when I start the loops at the iteration that contains the correct answer.
Code:
// generate key "words" with length of 3
for (int x = 0; x < 26; x++){
for (int y = 0; y < 26; y++){
for (int z = 0; z < 26; z++){
[Code] ....
This is the essence of the loop, I've attached the program in its entirety if necessary. Basically what happens is if I start the loops at x = 17, y = 7, z = 12, then I get the correct decipher shifts but if I start at 0,0,0 whenever it gets to that iteration (12,000 ish) the shifts are off by 2 or 3. "koq" should translate to "the" but im getting "dcz". Is this a simple bug in the or is something moving to fast for something else to keep up?
l3_ws.txt
main.cpp
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Mar 17, 2013
I am attempting to read a file with 2 numbers in it. The first indicates the number of rows the second, the number of columns. So for a file (Data.txt) that contains the numbers 5 7, I want to display
0 0 0 0 0 0 0
1 1 1 1 1 1 1
0 0 0 0 0 0 0
1 1 1 1 1 1 1
0 0 0 0 0 0 0
and write that output to a file.I can display the correct number of rows and columns but I can't figure out how to display alternating rows of 0's and 1's.
#include <iostream>
#include <fstream>
using namespace std;
int main() {
ifstream inFile;//declare file
[code]....
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Feb 28, 2013
What does the following nested loop output ?
count = 1;
while (count <= 11) {
innerCount = 1
while innerCount <= (12 - count) / 2) {
cout << " ";
innerCount++;
} innerCount = 1;
while (innerCount <= count) {
cout << "@";
innerCount++;
} cout << endl;
count++;
}
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Jun 3, 2014
I would like to do something like this:
for (int i=0; i<5; i ++)
{
for (int j=0; j<5; j++)
{
//* CREATE A NEW FILE FOR WRITING * //
}
}
I don't know how to create a new file that doesn't get overwritten each time the loop runs.
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Nov 15, 2012
My program involves trajectory planning using cubic spline method for a robotic arm. In the process, I had to calculate joint angles for each point in the path. In the last few lines of the code I need to write the values for counter and theta1 into a text file which I called "Test.txt". I am doing this using a nested for loop(the counter runs until it reaches 19 and hence need 19 theta1 values corresponding to it). However, I can't get all the theta1 values transferred to the text file.The statement within my inner loop is wrong and don't know how to fix it.
for(i=0;i<num_via;i++){
current_time = GetTickCount();
//joint[0] = mult_joint[i][0];
//joint[1] = mult_joint[i][1];
//joint[2] = mult_joint[i][2];
//joint[3] = mult_joint[i][3];
[code]....
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Oct 29, 2014
We were discussing how to find average time complexity of different algorithms. Suppose I've a the following nested loop
for(int i=0;i<n;i++)
{
min = i;
[Code].....
Now the outer loop will iterate N times. the inner loop will always iterate 3 times no matter what the value of N is. so the worst case time complexity should be O(n^2) but what about the average case and the best case? I mean in terms of searching we can figure out and distinguish between the worst,best and average as it depends upon the number of comparisons. But here how can the average and best case be different then the worst case.
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Jan 20, 2014
So I have this problem with not being able to iterate over a vector in a nested for-loop. Here's the nested for-loop:
bool innerHit = false;
for (std::vector<Sprite*>::iterator outerIter = sprites.begin(); outerIter != sprites.end() && (!sprites.empty()); outerIter++) {
Sprite* spriteOne = *outerIter;
for (std::vector<Sprite*>::reverse_iterator innerIter = sprites.rbegin(); innerIter != sprites.rend() && (!sprites.empty()); innerIter++) {
Sprite* spriteTwo = *innerIter;
[Code] .....
What happens is, after having called the collisionDestroy-function and the program tries to execute the nest loop in the outer for-loop, it all crashes with the text "Expression: vector iterator not decrementable", which I understand is because the iterator will have already become useless. The question is: know this, how do I fix it? I can't seem to get a hang of it.
Here's the collisionDestroy-function (the collisionReaction does nothing but sets a few local variables):
void Enemy::collisionDestroy(std::vector<Sprite*>& sprites) {
for (std::vector<Sprite*>::iterator iter = sprites.begin(); iter != sprites.end(); iter++) {
Enemy* tmp = dynamic_cast<Enemy*>(*iter);
if (this == tmp && collisionType == 3 || collisionType == 1) {
sprites.erase(iter);
break;
}
}
}
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Oct 5, 2013
I seem to be having a bit of problem with my if statements in a for loop.
My code involves asking the user for the name of an element (chemistry), searching a text file line by line for an element that matches the input, and outputting other information regarding that element.
One line of the text file looks like this: Helium,He,2,4.00
I've tried running the code without the if loop and it outputs normally (If I ask it to output elementname[0] it will output the first element Hydrogen, which is correct.) but I am not sure what goes wrong when I add the if statement. For some reason, it always follows the "else" statement (It always outputs Invalid search even when I input the right elements).
const int ELEMENTS = 118; //number of elements
ifstream File;
string elementname[ELEMENTS], atomicsymbol[ELEMENTS], atomicnumber[ELEMENTS], atomicmass[ELEMENTS];
string elemname, atomsym, atomnum, atommass;
string search;
[Code] ....
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Apr 30, 2012
My break; isn't ending the for statement. User should only get 3 choices but they get to input more than 3.
int playGame() {
int count =0; int x = (rand()%10)+1; int y;
for(int i=0;i<3;i++) {
cout << "Guess the number 1-10: ";
cin >> y;
if (x==y)
[Code] ......
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Sep 10, 2014
I got insert statment inside loop like this:
if (ds.Tables.Count != 0)
{
for (Row = 0; Row <= ds.Tables[0].Rows.Count - 1; Row++)
InsertLSP(ElemStartTimeInPrograme, ..........) <-----------------------
[Code]....
i would like to check whether first insert call inside ds loop if is failed e.g due to connection problem this will be ended. What is best way to implement that?
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Dec 12, 2014
I have more programming before this, but everything else works fine. My else loop has an infinite output. i also want it to output an error message if the value is not an integer and return to the input
cout << "Select number corresponding material for fencing:" << endl;
cout << "wood = 1" << endl;
cout << "stone = 2" << endl;
cout << "aluminium = 3" << endl;
cin >> material;
if (material == 2){
cost = 100 * perimeter;
[code]....
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Jul 28, 2013
I'm trying to put an if-else statement in a do-while loop and when I put the correct answer in the if statement I get that error. Here's the program:
#include <iostream>
using namespace std;
int main() {
int answer;
char repeat;
[Code] .....
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Jun 12, 2014
Basically I'm supposed to use a while loop to generate a random number and use a switch statement to output the appropriate information. I feel like I'm missing a few things that are very simple.
The errors are:
warning C4244: 'argument' : conversion from 'time_t' to 'unsigned int', possible loss of data
warning C4700: uninitialized local variable 'randomNumber' used
#include <iostream>
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
using namespace std;
int main(){
int i = 0;
unsigned int randomNumber;
[Code] .....
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Feb 19, 2014
I am working on a small simple program my program fills up a air plane with customers there is 2 levels 1 and 2 and it will put that person in the spot depending on being picked.
So far i made a boolean airplane with 10 spots I can enter 1 person into the airplane with no problem but then after he sits down i get a infinite loop? I assume i maybe have to use the continue statement I feel like there is something simple that im missing i want to add more people. here is what i have
class Program
{
static void Main(string[] args)
{ bool[] planeSeats = {false, false, false, false, false, false, false, false, false, false };
[Code]......
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Apr 21, 2013
Write a for loop statement to print the numbers from 1 to 10 in reverse order separated by star :
10*9*8*7*6*5*4*3*2*1
i try to do it but it show me like this :
10*9*8*7*6*5*4*3*2*1*
how do i write to show me like the first one ?
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