C++ :: Place Nested Loop Where Nested Not Necessary?
Apr 3, 2014
I wrote this code, and everything was working well, but part of the assignment is that it must include nested loops. Once I added the nested while loop, which is basically an if statement, my life was ruined. I am trying to nest a loop in the code that will basically tell the compiler that if the value "loopVol" were to exceed the value of "final" after adding an increment, to run the program for the "final". How can I do that?
Example:
initial = 10
final = 123
increment = 10
as of now, the program would stop at 120, but I want to nest a loop that will tell the compiler to calculate at the final if this happens.
#include <iostream>
#include <iomanip>
#include <stdio.h>
[Code]......
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Mar 25, 2013
This code is used in scientific calculation for optimization problem.
Basically a particle is moving in a three dimensional space, its position is (x,y,z).
At each position, there is a fitness value associated with that position.
The fitness value is given by fitness(x,y,z) (code line 12~19).
We need to find out, when the particle moves around randomly, what is the highest possible fitness value.
To solve this, below code is used, and it produces correct result.
#define DIMENSION 3
#define MAXX 4
#define MINX 0
#define MESHsize 1
#include <iostream>
using namespace std;
float maxValue = 0.0;
[Code] ....
The output of the code:
[ fitness(0,0,0) = 0] [ fitness(0,0,1) = 1] [ fitness(0,0,2) = 4] [ fitness(0,0,3) = 9]
[ fitness(0,1,0) = 1] [ fitness(0,1,1) = 2] [ fitness(0,1,2) = 5] [ fitness(0,1,3) = 10]
[ fitness(0,2,0) = 4] [ fitness(0,2,1) = 5] [ fitness(0,2,2) = 8] [ fitness(0,2,3) = 13]
[ fitness(0,3,0) = 9] [ fitness(0,3,1) = 10] [ fitness(0,3,2) = 13] [ fitness(0,3,3) = 18]
..... so on
Answer: highest fitness = 27
Note: In this case, the values of x,y and z is integers from 0 to 3 inclusive.
For 3-dimensional space above, actually the code had run through 3 nested "for" loops.
Question: Above code works for 3-dimensional space. How to generalize the code, so that it works also for N-dimensional space, where N is an arbitrary integer?
( Note: possibly N = 30 )
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Nov 3, 2014
I'm trying to output a pattern using loops. The pattern is a plus symbol made of 3 rows of 5 x's followed by 3 rows of 15 x's and finally 3 rows of 5 x's.
I can get the program to output all 9 rows with 5 x's but I don't know how to do the 3 rows of 15 in the middle. I have tried a while loop and also an if statement but nothing seems to work.
#include "stdafx.h"
#include <iostream>
#include <iomanip>
[Code]....
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Mar 14, 2014
Code:
while(x==1){
for (i=0;i<j;i++)
{if (word1[i] == word2[i])
{prefix[i]= word2[i];
counter++;}
else
x=2;}
Basically after the 3rd run of the for loop, it encounters a contradiction. I want it to exit right there and then. Instead it continues to run the for loop. What can I do?
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Feb 9, 2014
I was wondering how I could use a continue statement that continues in a nested loop. For example if I have
for (int i=0;i<amount;i++) {
for (int j=0;j<I[i];j++) {
for (int k=j+1;k<I[i];k++) {
if (P[i][j]+P[i][k]==C[i]) {
//What should be here?
}
}
}
}
If the condition is met then the most outer loop (in i) should continue to the next iteration.
If i simply fill in continue; in before the comment then it only continues the loop in k so that is not what I want.
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Mar 13, 2013
How to make triangles using c++, in nested while loops.
The triangles were:
*
**
***
****
*****
******
*******
********
*********
**********
I have made a code for this:
int counter=1;
while (counter<=10){
int counter2=1;
while (counter2<counter){
[Code] .....
I was not quite sure about this one.
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Jan 6, 2014
how to draw a flow chart for following nested loop?
for(int r=1;r<=5;r++){
for(int c=1;c<=r;++c){
cout<<c;
}
cout<<endl;
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Feb 17, 2013
I'm writing a series of basic decipher programs and I have run into an issue where I get the correct answer when I start the loops at the iteration that contains the correct answer.
Code:
// generate key "words" with length of 3
for (int x = 0; x < 26; x++){
for (int y = 0; y < 26; y++){
for (int z = 0; z < 26; z++){
[Code] ....
This is the essence of the loop, I've attached the program in its entirety if necessary. Basically what happens is if I start the loops at x = 17, y = 7, z = 12, then I get the correct decipher shifts but if I start at 0,0,0 whenever it gets to that iteration (12,000 ish) the shifts are off by 2 or 3. "koq" should translate to "the" but im getting "dcz". Is this a simple bug in the or is something moving to fast for something else to keep up?
l3_ws.txt
main.cpp
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Mar 17, 2013
I am attempting to read a file with 2 numbers in it. The first indicates the number of rows the second, the number of columns. So for a file (Data.txt) that contains the numbers 5 7, I want to display
0 0 0 0 0 0 0
1 1 1 1 1 1 1
0 0 0 0 0 0 0
1 1 1 1 1 1 1
0 0 0 0 0 0 0
and write that output to a file.I can display the correct number of rows and columns but I can't figure out how to display alternating rows of 0's and 1's.
#include <iostream>
#include <fstream>
using namespace std;
int main() {
ifstream inFile;//declare file
[code]....
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Feb 28, 2013
What does the following nested loop output ?
count = 1;
while (count <= 11) {
innerCount = 1
while innerCount <= (12 - count) / 2) {
cout << " ";
innerCount++;
} innerCount = 1;
while (innerCount <= count) {
cout << "@";
innerCount++;
} cout << endl;
count++;
}
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Jun 3, 2014
I would like to do something like this:
for (int i=0; i<5; i ++)
{
for (int j=0; j<5; j++)
{
//* CREATE A NEW FILE FOR WRITING * //
}
}
I don't know how to create a new file that doesn't get overwritten each time the loop runs.
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Nov 15, 2012
My program involves trajectory planning using cubic spline method for a robotic arm. In the process, I had to calculate joint angles for each point in the path. In the last few lines of the code I need to write the values for counter and theta1 into a text file which I called "Test.txt". I am doing this using a nested for loop(the counter runs until it reaches 19 and hence need 19 theta1 values corresponding to it). However, I can't get all the theta1 values transferred to the text file.The statement within my inner loop is wrong and don't know how to fix it.
for(i=0;i<num_via;i++){
current_time = GetTickCount();
//joint[0] = mult_joint[i][0];
//joint[1] = mult_joint[i][1];
//joint[2] = mult_joint[i][2];
//joint[3] = mult_joint[i][3];
[code]....
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Oct 29, 2014
We were discussing how to find average time complexity of different algorithms. Suppose I've a the following nested loop
for(int i=0;i<n;i++)
{
min = i;
[Code].....
Now the outer loop will iterate N times. the inner loop will always iterate 3 times no matter what the value of N is. so the worst case time complexity should be O(n^2) but what about the average case and the best case? I mean in terms of searching we can figure out and distinguish between the worst,best and average as it depends upon the number of comparisons. But here how can the average and best case be different then the worst case.
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Jan 20, 2014
So I have this problem with not being able to iterate over a vector in a nested for-loop. Here's the nested for-loop:
bool innerHit = false;
for (std::vector<Sprite*>::iterator outerIter = sprites.begin(); outerIter != sprites.end() && (!sprites.empty()); outerIter++) {
Sprite* spriteOne = *outerIter;
for (std::vector<Sprite*>::reverse_iterator innerIter = sprites.rbegin(); innerIter != sprites.rend() && (!sprites.empty()); innerIter++) {
Sprite* spriteTwo = *innerIter;
[Code] .....
What happens is, after having called the collisionDestroy-function and the program tries to execute the nest loop in the outer for-loop, it all crashes with the text "Expression: vector iterator not decrementable", which I understand is because the iterator will have already become useless. The question is: know this, how do I fix it? I can't seem to get a hang of it.
Here's the collisionDestroy-function (the collisionReaction does nothing but sets a few local variables):
void Enemy::collisionDestroy(std::vector<Sprite*>& sprites) {
for (std::vector<Sprite*>::iterator iter = sprites.begin(); iter != sprites.end(); iter++) {
Enemy* tmp = dynamic_cast<Enemy*>(*iter);
if (this == tmp && collisionType == 3 || collisionType == 1) {
sprites.erase(iter);
break;
}
}
}
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Jun 1, 2013
What output would you expect from this program?" The output was not what I expected. I've psuedo-coded this out and I'm still missing something.
Code:
#include <stdio.h>
int main () {
int numbers[10] = { 1, 0, 0, 0, 0, 0, 0, 0, 0, 0 };
int i, j;
}
[code]....
The output: Code: 1 1 2 4 8 16 32 64 128 256 So when I look at this first loop I see that j = 0, which is less than 10, so then the program statement should commence, which is another for loop. So in this inner for loop I see that i = 0, which is not less than j, so this loop should terminate. Then the value of j increments by 1 and the first go around of the loop has completed.
Now I see that j = 1, so this is less than 10, and the inner for loop commences once again. This time though, i actually is less than j, so numbers[1] = numbers[1] + numbers [0], or numbers[1] = 0 + 1. Now the value of i is incremented by 1 and the first go around of this inner loop has completed. Then the value of j increments by 1 and another go around of that loop has completed.
So now j = 2, i = 1, and numbers[2] ( which is 0 ) = numbers[2] + numbers[1], or numbers[2] = 0 + 1. I was expecting the output to be an array full of 1's. However this is not the case..
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May 21, 2013
here is a nested stl map
typedef struct struct_RISCP {
float nSCPTotal;
int nSCPCount;
CString strIMEI;
std::map<UINT8, int> mapSection;
}RISCPSt;
map<stRncCellIdntyDmnType, RISCPSt>m_mapRISCP;
it occupied too much memory,i wanted to clear them(both outer map and inner map) ,some one told me you just need to call m_mapRISCP.clear(),then the mapSection (inner map) will be cleared automaticly,in other words, m_mapRISCP.clear() will clear both outer map and inner map.
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Mar 12, 2014
I'm working on a project involving nested classes and structs like this:
Code: class A {
public:class B {
public:f()
{A::C* iCanDoThis; //no errors.
iCanAlsoDoThis->root->.... //this also works fine.}private:A::C* iCannotDoThis //this is what I would like to do.
Has errors
A* iCanAlsoDoThis;};private:struct C
{..data..};
C* root;};
Is it possible make a pointer to struct C a private member of class B?
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Feb 4, 2014
So I think I am having syntactical problem with my code.
Code:
int main() {
vector<int> ivec;
int score;
[Code] ....
I get an error from my compiler on the ?10th? line (Nested condition line) that says |19|error: invalid operands of types 'int' and '<unresolved overloaded function type>' to binary 'operator<<'|
The purpose of the program is to take input and store it in a vector and then change the value to be between 1-6. I made this for the purpose of learning about nested conditional operations.
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Dec 7, 2013
Howi can made nested loops?
Code:
for (yax=0; yax<10; yax=yax+1) {
for (xax=0; xax<100; xax=xax+1) {
printf("%d
",yax);
}
}
way what i tired dont work. or maybe works but why this prints only zeros ?
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Nov 26, 2013
I have a nested record structure in C++ that contains a FileHeader record, a RecordHeader record and a DataRecord record. The last item is an array of unknown size (at compile time). I have to open a file and read the array size and then create the array.
I have worked on this for some time and can't figure out how to make it work. I know the sample data I am using has 85 records. I insert 85 into the array size and it works fine. But how do I create a dynamic array or define a vector within a nested structure?
1. What is the best (easiest) method to accomplish this (array or vector)?
2. How would it be implemented/how do you add data to it?
PreviousLogRecord.FaultRecord.push_back(field1); // does not work
PreviousLogRecord.FaultRecord[recordNumber].field1 = somedata; // works with 85 in array size.
struct LogFileHeaderRecordType {
QString field1;
int field2;
[Code] .....
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Sep 27, 2014
So in class our teacher assigned us a program where we have to use nested for loops to creates triangles. How does the 2nd for loop print more than 1 star? since the for loop will only run the cout 1 time until it gets to the escape sequence, how does it print more than 1 star on a line? this is what is confusing me. I feel like if i can grasp the understanding of that and what the for loops are doing i can finish the rest of this program with ease
#include<iostream>
using namespace std;
int main()
[Code].....
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Aug 27, 2013
I'm working with CGAL - Computational Geometry Algorithms Library, which is a library of geometry functions declared as several thousand header-only files. When I run a basic program (source code [URL] ) I get this output: [URL]
I have tried switching angle brackets to quotes. I have also started reading up on CMake.
Do I need to walk the dependency tree and add all of those files to my CMakeLists.txt? Or is there a way to tell the compiler to look in subdirectories?
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Feb 11, 2014
I'm trying to write some naive binary serialization code and wanted to cut down on repetition of logic for serializing/deserializing nested vectors or other STL containers to reduce the chance of typos etc, and thought templates might hold a solution for me.
Code:
template <typename T> void serializeField(IWriter& writer, const T& val) {
writer.write((char*)&val, sizeof(T));
}
template<typename U, typename V>
template <> void serializeField(IWriter& writer, const U<V>& collection)
[Code] ....
Is there a way to do something like this? It isn't a big deal for me to just manually write code to serialize my vectors to the needed depth, but it sure would be nice to get this working.
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Jan 22, 2015
I need to know how to access the nested structure using pointer, i mean i know how to do that when i have simple structure, for example:
Code:
struct person{
char fname[16], lname[16];
int age;
}
for this example i can use
Code: (*pointer).age
or
Code: pointer->age
But if i have structure like this:
Code:
struct date{
int day, month, year;
}
struct person{
char fname[16], lname[16];
struct date birthDate;
}
Then how can i access the birthDate using pointer?
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Jul 11, 2013
Getting close but I think I am stuck on the second loop. The input you put in will be doubled (and it's not supposed to).
Code:
int main() {
int n, i, j, k;
printf("What would you like the height to be? (Positive odd integer)
");
scanf("%d", &n);
[Code] .....
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Nov 5, 2013
You are to create a program using nested looping. Your program is to have a menu asking the user to select which pattern to create and how many rows to use (it should accept 1 to 10 rows and keep the aspect ratio of the pattern). The patterns are 1 - Box, 2 - V, 3 - Inverted V. Note, if I select pattern 1 with 10 rows, the box will have 10 asterisks in the first row.
Okay so i came up with the box but i have been getting stuck at getting the V or inverted V.
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