Ive been getting an odd error with this code when I try to compile it, as well as Im not quite sure as how to return my variable "compType" as a char type.
Main
#include <iostream>
#include "Shape.h"
#include <iomanip>
#include <cmath>
using namespace std;
void inputShape( char shape)
[Code] ....
I am writing a class Player which has several char arrays as private fields. I am trying to write a method which returns an array as a pointer, but doesn't alter the array in any way, thus the const.
Here is a snippet:
Code: class Player
{
private:
char state[MAX_STATE_CHAR + ONE_VALUE];
int rating;
char last[MAX_NAME_CHAR + ONE_VALUE];
char first[MAX_NAME_CHAR + ONE_VALUE];
int groupNumber = NEG_ONE;
public:
char * GetFirst() const
{
return first;
}
Visual studio is saying that the return type doesn't match.
I planned to build a four function fraction calculator adding some advance feature like error checking in input so that user are prompted to input correct numbers and operator.
I created a separate member function getOper() function for getting correct operator and getFrac() function for getting correct fraction.
My intention was just to get correct operator from getOper() function and returning the operator to switch in main() function to do specific calculation. But, i don't know why i am getting repeatedly error when inputting correct operator while debugging program.
Here's my complete code.
Code:
#include <iostream>
using namespace std;
char c;
class fraction {
private :
int num;
[Code] .....
I checked the program again by assigning char to variable "oper" and function "getOper(). But, result is same.And again i changed variable "oper" to default keyword operator, but, it really didn't worked as expected.
I'm beginners in C Programming, i have a question about Structure in C. i know in Function it is possible for
1. Sending the value of argument
2. Sending the address of the argument
3. Returning values from a function by return statement
Does in Structure it is possible for
1. returning structure from a function using by return statement
What the code below is not doing is returning a value for item to my variables (item1, item2, etc..) I'm not sure how I can make a function prototype that will ask for input and basically recycle after going through the program to a new value for each item. I also need to input individual tax for each item. I will also post it in this message:
double tax, item,salesTax;
double cost(double);
double CalcSalesTax(double);
main(){
double total,item1, item2, item3, item4, item5, tax1, tax2, tax3,tax4,tax5;
[Code].....
My code is supposed to read a five to four digit code of a resistor from a file and determine the resistor's nominal, lower and upper tolerance values. I have inputted my file's first resistor code as a string so I could run tests on it but the problem that occurs is that a get the wrong values from my switch-case statements. I have put printfs after the function call to see what the values were and they turned out wrong. If I could get my return values to be right then I could be on my way coding.
#include<stdlib.h>
#include<stdio.h>
double bandNum(char x); // function prototype that will read the resistor value for the first, second and possibly third band
double bandMult(char x); // function prototype that multiplies the resistor by some value of 10
double bandTol(char x); // function prototype that the tolerance of the resistor is multiplied by
[Code] ....
How to use a function twice to calculate two different variables. How to have a function compute the city tax, then it uses the function a second time to compute the county tax.
My program compiles, and runs fine, however it only outputs the city tax calculation. It seems it never attempts to calculate the county tax.
One thing: All of the directives I used is what we are limited to, no more, no less. He requires a set format and will dock points of you use anything but those directives and void main().
Here is my code so far:
/* function for city tax calculation */
#include <iostream>
using namespace std;
#include <string>
#include <cstdlib>
#include <cmath>
#include <iomanip>
const double city_tax_rate=0.03;
[Code] ....
I am using Visual studio 2010.
I am trying to return 2 numbers from my function to main(). They are both read in from an input file but it is not working out.
#include <fstream>
#include <iostream>
using namespace std;
ofstream outfile;
void heading(int);
int stuid(int,int);
[Code] ....
Which is more efficient in functions? Returning values or using pointers to redefine variables passed as arguments?
I mean either using:
void ptr_Func(int *x)
{
*x = *x+1
}
or
int ptr_Func(int x)
{
return x + 1;
}
In terms of speed, memory use etc.I want to know general efficiency, I know it will obviously vary with different uses and circumstances.
I'm having some problems with changing an array of numbers of type char to type int. Every time i try to sum 2 array indexed values it returns some letter or symbol. Also, if i change the type of the array in the functions the compiler gives me an error message. I would also like to add that the problem requires that the first two arrays be char so each individual number gets assigned to a different value.
My current code is:
Code:
#include <iostream>
void input(char a[], char b[], int& size_a, int& size_b);
void convert(char a[], int size);
void reverse(char a[], int size);
void add(char a[], char b[], int c[], int size);
int main()
[Code]....
how to convert an element of int type of an array to char type?
View 2 Replies View RelatedI am trying to return a char pointer so that i can re use it again. I am writing a vigenere function that takes a message, a key and an initialization vector where it performs the encryption, prints out the encrypted message and returns the encrypted message. I print out the process step by step and everything works, however i pass the answer and print it out again and only the first letter gets changed. I put my code below and my output right after that.
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <ctype.h>
#include <time.h>
void decrypt(char *to_encrypt, char *key, char* pct);
enum flag{encryption = 1, decryption = 0};
[code].....
I'm having trouble returning a char array by a function, here's the code. The problem is the 'reverse' function, the purpose of the function is to send two char arrays, 'newline' containing the char array, reverse it and place it in the 'rev' char array then output it back in main, however the output remains blank so I assume there must be something wrong with the reverse function.
Code:
#include <stdio.h>
#define MAXLINE 10
int fgetline(char line[], int maxline);
void copy(char to[], char from[]);
void reverse(char forw[], char rev[], int arrsize);
[Code] .....
Code:
charArr = new char[50];
cout << "put in value: ";
cin.getline(charArr, 50);
some_func(charArr);
[Code] ....
Let's say I enter a value: 101
It goes into the if statement but clearly I've enter 1s and 0s. When I debugged, at i = 0, the charArr[i] gives me a value of 49 when assigned to an int variable. But when I cout charArr[i] it gives me 1.
So I'm going to assume 49 is part of the address? How can I correctly check the if statement condition?
I am having problems with my function definition of a function that should return a structure value.
This is the error I get compute.cpp(9): error C2146: syntax error : missing ';' before identifier 's_advertisebus'
The error is on the line where I start my function definition typing my function type as a structure. A long time ago in c the keyword struct is used with the structure type like struct s_advertisebus s_readadbus(). I tried it both ways but I got errors.
// struct.h
#ifndef STRUCT_H
#define STRUCT_H
struct s_advertisebus {
int nnumberofads;
float fpercentused;
[Code] ....
Okay, I've been working on this Texture class that's going to be compatible with both SDL and OpenGL with the capability to create an array of textures within one class as opposed to multiple classes and such.
Now I've run into a slight issue if I want to return the value of a texture. There's two different types of textures: SDL_Texture, and a standard GLuint Texture. The problem I have is that one or the other is used, not both which is depending on whether or not the person is using OpenGL.
So when the user wants to get the texture, I need the ability to return either an SDL_Texture, or GLuint depending on whether or not OpenGL is being used.
I tried this with a template class, but it didn't work, but I'll post the code so you can see what I'm trying to do.
template <class Tex> Tex Texture::GetTexture(int TextureNumber)
{
if (TextureNumber > NumTextures || TextureNumber < 0)
return;
[Code]....
It basically just comes down to the last four lines of code. If the person is Using OpenGL return a GLuint, if the person is using SDL, return an SDL_Texture.
I would prefer to have the GetTexture function to be one function instead of two separate ones so I don't have to call a different function every time to check if I'm using SDL or OpenGL.
Im trying to run my program and it works fine until the very end where I want it to read "<name> is a <gender> citizen of <nation>." with the corresponding variables. Here is my work for the time being. Also is there a way to make it where if someone puts a M or m for gender, it will spit out Male instead of just m or M.
#include <iostream>
using namespace std;
int main()
{
char gender;
[Code].....
I want to return a char array to the main() function, but its returning garbage value.
#include<stdio.h>
//#include<conio.h>
#include<string.h>
char* strtrmm();
int main() {
char str1[100],c1[100];
[Code] .....
I'm trying to get an if/else statement to work using a character condition, but it is a no-go. After I input either a 'y' or 'n', the program just sits there until I press 'Enter' again, at which point it ends. It never actually goes through either of the 'if' statements. At first I only had a single '=' in the condition, but I found that that was wrong. When I corrected it to '==' it still didn't work. I also tried clearing the buffer by adding a 'getchar()' at the beginning of the program, but that didn't work either.
#include <stdio.h>
#define std_rate .8855
int main(void) {
char ans;
int counter = 1, euros = 5;
double dollars = 0, ex_rate;
[Code] .....
The compiler (Visual Studio 2013) requires me to use 'scanf_s' instead of just 'scanf' for some reason, and if I don't have two 'getchar()' commands at the end, then it won't stay open long enough for me to see the results.
Just making typical console game where hero moves with w a s d.
However, in my code, while a and w work (minusing), s and d dont work (adding). I have used a switch statement to change the char position of the hero based on kbhit.When you hit s or d, the buttons that add 1 to the 2nd dimension of the array, the screen goes crazy!
#include <iostream>
#include <string>
#include <conio.h>
#include <ctime>
#include <cstdlib>
using namespace std;
const char PLAYER = 'H';
[Code] .....
How do I compare two variables who do not have a predefined Type (i.e Templates).
If I just do a==b it only works for integers and not for strings. Is there any general method present for comparing templates.
how can we use modulus operator with double type variables
View 2 Replies View RelatedI need to find some sort of method to convert a series of char variables to a string, to be shown in a label. I've searched for two days and experimented myself just as long, and the closest I've gotten simply puts ASCII values into the string with the following command:
label1 -> Text = System::Convert::ToString(fdp8), System::Convert::ToString(fdp7),
System::Convert::ToString(fdp6), System::Convert::ToString(fdp5),
System::Convert::ToString(fdp4), System::Convert::ToString(fdp3),
System::Convert::ToString(fdp2), System::Convert::ToString(fdp1);
fdp1-fdp8 are all char variables.
I'm currently doing the exercises for the fifth chapter (Loops) and I've done all of them, but I wanted to go the extra mile on the last program I'm supposed to design. The program is a poll and all the input from the user will be with numbers. However when a letter is pressed then of course you get wrong behaviour from the program, it keeps looping endlessly.
Here is a fragment of what I think is the way of doing it - but of course it's not working
Code:
int p = 0
char anyLetter[]={"abcde"};//Initializing char variable
char a = anyLetter[p];
else if (userAnswer[n] == a)//if statement where char needs to be used.
{
cout << "Pressing a letter maybe? It's only with numbers. Try again." << endl;
continue;
}
I want to declare a char* array, and then make any future variables declared to be stored in a specific location within the char* array. Is this even possible, and if it is how would I go about doing it. (I plan on storing any primitive data type in it (not classes or structs), and they may signed or unsigned).....
View 12 Replies View RelatedI have the following code. According to this the values of pointers p[0] and p[1] remains unchanged since the swap is made to local variables in swap function.Now my doubt is how can I swap the pointers p[0] and p[1] inside the function swap??
Code:
#include<stdio.h>int main(){char*p[2]={"hello","good morning"};
swap(p[0],p[1]);
printf("%s %s",p[0],p[1]);return0;
}void swap(char*a,char*b){char*t; t=a; a=b; b=t;
}