Im trying to run my program and it works fine until the very end where I want it to read "<name> is a <gender> citizen of <nation>." with the corresponding variables. Here is my work for the time being. Also is there a way to make it where if someone puts a M or m for gender, it will spit out Male instead of just m or M.
#include <iostream>
using namespace std;
int main()
{
char gender;
[Code].....
I have more programming before this, but everything else works fine. My else loop has an infinite output. i also want it to output an error message if the value is not an integer and return to the input
cout << "Select number corresponding material for fencing:" << endl;
cout << "wood = 1" << endl;
cout << "stone = 2" << endl;
cout << "aluminium = 3" << endl;
cin >> material;
if (material == 2){
cost = 100 * perimeter;
[code]....
Why is my program outputting zero for the variable pop?
Code:
#include <iostream>
int main(void){
using namespace std;
//capture data
cout << "Enter the world's population: ";
[Code] ....
It's obviously not std::cout, but I'm thinking its the way I'm operating on long?
when i uncomment statements in the following ,it works perfectly fine for infix to postfix conversion.although comments are simple cout statements,, execution with cout statements as comments breaks in b/w.I have found this particularly with a^b-c.DevCPP is also showing similar behavior. I can't understand what's going on.I am working on code blocks.
#include<iostream>
#include<cstdio>
#include<conio.h>
using namespace std;
char stk[15];
[code]....
Here is the code:
// Creating and joining string objects
#include <iostream>
#include <string>
using std::cin;
using std::cout;
using std::endl;
using std::string;
using std::getline;
// List names and ages
void listnames(string names[], string ages[], size_t count) {
[Code] ....
I may be wrong, but the problem seems to be in the function "listnames". Specifically, the output statement inside the while loop. I don't understand , how the ++ operator is behaving in this statement. The output produced does not match what's printed in the book. I usually just type all the examples, but with this one I also downloaded the source code from the book's website to make sure the error wasn't due to mistyping.
So, if I'm right, computer store their data as binary values. So if I write int x = 5; , my computer converts the value of x from decimal (5) into binary (101) and stores it in memory as a a binary number. If I print that value on the screen that value is converted(by default) back into a decimal number before being printed on the screen.
Now, my question is if there is any way to print the value of x directly into binary(as it's stored in memory) without it being converted back into a decimal value?
Making a game of checkers on C++ win32, visual studio
when i want a piece to move, i type:
cout << "What piece do you want to move? (C4)" << endl;
i type in 'cin' after to get the players input, but how do i get it to store the players input in a certain variable? im going to have a list of variables:
string a1
string a2
string a3
etc
so if the user types in a2, it automatically goes to that variable and then asks the user "where do you want the piece to be moved to?".
I want to declare a char* array, and then make any future variables declared to be stored in a specific location within the char* array. Is this even possible, and if it is how would I go about doing it. (I plan on storing any primitive data type in it (not classes or structs), and they may signed or unsigned).....
View 12 Replies View RelatedI want to declare a char* array, and then make any future variables declared to be stored in a specific location within the char* array. Is this even possible, and if it is how would I go about doing it (I plan on storing any primitive data type in it (no classes or structs), and they may signed or unsigned). I want to be able to use the variables like any other variable, I just want the variable's address to be within the char* array.
I am trying to make a program that is similar to a virtual machine and an emulator put together, and it can only run one os (which will be hard-coded into to the program). The reason I wanted to do this is because it would be the easiest way to make sure that all variables in memory are in one contiguous block, that way the part that manages memory wouldn't have to store the locations of each variable (which would have been necessary for the virtual memory manager).
An example of what I am wanting to do is
char* ram [256]; // Address 0x00 to 0xff
// Code to make sure that new variables' addresses are in ram[] if necessary
unsigned short a = 5; // Gets stored at address 0x00
unsigned int b = a; // Gets stored at address 0x00+sizeof(a)
I'm playing around and wrote a tiny program.
Code:
char bracketin[] = "thisgetsbracketed.txt";
char bracketout[] = "bracketed.txt";
char testwalk[10] = "12345678";
[Code]....
I'm incrementing the pointer to buffer 150 bytes beyond its reserved 50. I see testwalk, followed by bracketout, followed by bracketin printed by the overflow on buffer.
The memory locations are ordered descending from their call order. Why is this the case?
One would think that they would be written in ascending order as I call them. I can only assume that they're compiled bottom up - where could I read about this process?
I have an array of structure that takes family information (name, age, and state) after it takes the users input it prints back all of the information that was input and then prints the family members that just live in Texas. After that I am trying to implement a function to average out the ages of all family members but I cant seem to get it right, whenever it gets to that part of the program it just outputs 0. I also tried adding an & sign prior to FAMILY[i].age and got an error of int from ptr with no cast.
Also I realize that the code only shows adding of the family members ages which is fine for now as I am concentrated on getting that to work in the first place.
Code:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
//Global Variables
int i=0, a=0, sum=0;
[Code].....
Ive been getting an odd error with this code when I try to compile it, as well as Im not quite sure as how to return my variable "compType" as a char type.
Main
#include <iostream>
#include "Shape.h"
#include <iomanip>
#include <cmath>
using namespace std;
void inputShape( char shape)
[Code] ....
This is what my code looks like
class Transaction{
private:
char type;
double amount;
double balance;
string description;
[Code] .....
This part is what I am having trouble with as this section is not printing anything.
for (int i = 0; i < transactions.size(); i++){
cout << transactions[i].gettype() << " ";
cout << transactions[i].getamount() << " ";
cout << transactions[i].getbalance() << " ";
cout << transactions[i].getdescription() << " ";
}
}
How to make if else code below into SWITCH STATEMENT?
cout << "Enter the temperature: ";
cin >> temp;
cout << "Enter the pressure: ";
cin >> pressure;
cout <<endl;
[Code]....
Other than the theoretical difference between cout and cerr where the former puts values to the monitor and the latter puts values related to errors to the monitor, is there any real difference here? Why not use cout when you want to send anything to monitor? Why use cerr at all?
View 7 Replies View RelatedHere is code first:
//fp_screen.h
class fp_screen{
public:
double fps;
double xx3;
[Code] .....
fps:1.16922e+006 // this will happen 80%
fps:900 // this is how it should be
if i do cout << "fps:" << (int)screen.fps << endl;
Somethings number is right like 800 or else
put sometimes its 5423423... something.
What is going on here?
Am having a problem with the following program not displaying the cout after the while loop, it doesn't ask if I want to enter another employee but just prompts for the employee payrate again.
#include <iostream>
using namespace std;
int main()
// Parameters: None
// Returns: Zero
// Calls: None
[Code] ....
Iam working with arrays and i cant get to the write solution to cout the characters.
the Question is : Write a program that inputs a character string from the user as an input (using cin.get())and store it in myStr[ ] array.Assume that the length of the input string is less than 100 characters and the string may contain lower case, upper case, and/or symbols.The program should then print the number of lower case, upper case, digits, and symbols along with the characters themselves.
my code :
#include <iostream>
#include <string>
#include<iomanip>
using namespace std;
int main() {
int ctr1=0, ctr2=0, i=0, ctr3=0;
[Code] ...
What i have now, how can i cout the uppercase characters and the lower case characters and the symbol characters !
Finally got to functions. Made a simple one that adds two numbers:
Code: int add(int a, int b){
cout<<"a+b=";
return a+b;
}
It refuses to give an output unless I use cout.
If I just call the function like so: "add(12, 24);", shouldn't it print out a+b=36? It only prints out "a+b=", unless I use "cout<<" ahead of the call.
My simple question is why does it need cout ahead of the call? Shouldn't "return" do its job and print out the number?
i ran the following code in the latest version of code::blocks and it tells me that the objects cout and cin are not declared in this scope. what is the problem?
I used to use Turbo C++ 3.0 and i had no problem whatsoever with that compiler. But now i am trying to move to code::blocks but it is proving very very hard as all the standards have been changed.
I am a school student and thus, we had been told to practice on Turbo C++ 3.0 and now i am unable to unlearn it. Also, if i use printf in place of cout there is no error but i want to use cout as it is what i am comfortable working with.
#include<fstream>
#include<conio.h>
int main() {
using namespace std;
char name[20];
[Code] ....
Is there some document to which i can refer so as to get the latest C++ standards which is C++0x i believe?
I m working calculating stuff in files, input and output data, etc..., the question is the following: I output double numbers with:
myFIle << fixed << setprecision(10) << double;
The problem i got is that when a numer is like 193123.2 it prints like 193123.200000..., so finally, ¿how can i print it with any additional 0 that i need?.
I'm trying to build a new project and i installed some new libraries in it but when i try to compile any code it doesn't give me any value just press any key to continue, i didn't make any files but one and even if i tried to do this simple task it doesn't cout any result:
#include<iostream>
using namespace std;
int main() {
cout <<("ha");
system("pause");
return 0;
}
I am beginner in C++ programming. I having a problem to show the output of all the element i store at a array called total_price. the output become unreadable.
#include <iostream>
using namespace std;
int main () {
float price[1]={0};
int qty;
[Code] ....
So I want to go from having 0 or 1 to having words like false or true. I did it with an if statement earlier today, but I had to get rid of the whole bool thing. I made the variable just a float. But he requires we use bool. Here is my code:
Car y;
cout << "Initial value for the Car: " << endl;
cout << "Age= " << y.getAge() << " years old. The Price= $" << y.getPrice() << endl;
y.setAge(8);
y.setPrice(12000);
y.setRaceCarStatus(true);
cout << "Modified value for the Car: " << endl;
[Code]...
I commented (//) the if statement that I had earlier. If I set RacecarStatus to True, is cout's 1. The starred (*) line right above the comments is the line that I was required to add. I want to cout the actual word true. The one I had this morning won't work anymore.
#include<iostream.h>
#include<conio.h>
main()
[Code]....
I tried to make the output look like this --> ENTER YOUR NAME:Victor Collin ENTER YOUR COURSE:BSComSci
but everytime I entered my name the course went to the next line.How to make the output in the same?
I'm making a very first program. It's very little more then a simplistic calculator, but i'm having a problem with the cout function. It won't display any text what could the reasons be?
#include <iostream>
#include <string>
#include <sstream>
using namespacestd;
int main () {
do {
int(a);
[Code]...
Oh and i'm aware it's still riddled with numerous problems, I just have been working on the cout thing first.