I m working calculating stuff in files, input and output data, etc..., the question is the following: I output double numbers with:
myFIle << fixed << setprecision(10) << double;
The problem i got is that when a numer is like 193123.2 it prints like 193123.200000..., so finally, ¿how can i print it with any additional 0 that i need?.
Here is code first:
//fp_screen.h
class fp_screen{
public:
double fps;
double xx3;
[Code] .....
fps:1.16922e+006 // this will happen 80%
fps:900 // this is how it should be
if i do cout << "fps:" << (int)screen.fps << endl;
Somethings number is right like 800 or else
put sometimes its 5423423... something.
What is going on here?
I tried writing a program for finding the area of a circle, and I'm wondering why it only works when i define it as 'float', but not as a double?
Code:
#include <stdio.h>
#define pi 3.14159
double
main(void)
[Code] .....
I have a templated class that can either use float or double as type.
My question is now: What do I do with constant numbers in the code?
Let's assume I have a multiplication by 0.5:
In the case of float type, I want: 0.5f
In the case of double type, I want: 0.5
One answer would be to check for every constant the type and doing an if/else, but this is very annoying with lots of constants.
The code using these constants infer their type automatically by the assignment, that's why I have to take care of the constants.
I want a code that can convert floating/double value into string/char array(char arr[]) and also it can be run on Boreland C++ 5.02
Here I've a code but it doesn't show all the numbers. Instead, it's showing in exponential form which I don't want!!
int main() {
char* str = new char[30];
float flt = 2.4567F;
sprintf(str, "%.4g", flt );
cout<<str<<endl; //Exponential form even after 6 digits without decimal
return 0;
}
So I have a double array, where I'm inputting float numbers to certain points in an array. Sometimes, the numbers that are printed out are completely different from what I put in.Here is the part of the code:
Code: .
while( token != NULL ) {
num = atof(token);
test[j][i] = num;
printf( "
%s, i is %d, j is %d
", token,i,j );
printf( "number is %f
value test of i,j is %f
[code]....
Why the float num prints out fine, but when put into an array becomes garbage?I'm taking string values from a csv file and turning them into floats, but no problems seem to crop up there.I reset i when appropriate and increment j when needed, so I don't think my problems are from incorrect array values (though they might be)
Can you use data type double or float for an array? ie
double n[];
or
float a;
float m[a];
My code wont accept me changing the data type..will on accept int data type. I get the following error when I try to change the array to double or float..
3310E:C++vector.cpp[Error] invalid types 'double [1000][double]' for array subscript
I want to get the direct formula for calculating the range of double and float datatypes in c,if any.
View 1 Replies View RelatedI was working on float and double data types and to see the results i wrote this program:
#include <iostream>
#include <iomanip>
#include <fstream>
using namespace std;
int main() {
ofstream outputF("output.txt");
double a = 1;
double outcome;
[Code] ....
Well I understand the part it cannot store infinite numbers. but if you take a look at the output for example (since it is too long i just added some of the outputs)
//---------------------
for the value of : 001
1
//---------------------
for the value of : 002
0.5
//---------------------
for the value of : 003
0.3333333333333333148
[Code] ....
if you look carefully at the value "5" and "10" results. it is awkwardly abnormal. which is something i couldnt understand. also it is the same with value "20", "25", "40", "50" and so on.
I would like to convert a float or double variable into unsigned char variable and back.
float number_float = 23.453f;
unsigned char* number_char = (unsigned char*)malloc(sizeof(float));
number_char = reinterpret_cast<unsigned char*> (&number_float);
float* number_float_0 = reinterpret_cast<float*>(&number_char);
I am not getting the same value back.. why?
I have been reading up, and it seems that all I need to do to finish up the installation of a library is to add in the search path for the library upon compile time.
Of course, I also read that directly copying the lib files can work too, but that may result in the over-writing of necessary files...
I read a more thorough document on mingw's linking processes and discovered that I could create a folder, install the library in that folder, and add the folder as a search path for mingw (so, basically, all i have to do is install all my libraries under that folder).
How would I add my own function to the vector class?
View 3 Replies View RelatedThe problem is that my DataSelector form, which is instigated from the PropertyGrid (by creating a UITypeEditor) has access to the property LinkedDataItem. However I want the DataSelector form, which currently lists all the DataItems in the DataManager, to only list DataItems which are supported by the CustomControl, therefore my DataSelector class also need the "SupportedTypes" property from the Custom Control. How can I do this?
I thought maybe I can use a type converter to reference the custom control itself, instead of just the LinkedDataItem, and just show it as the Linked DataItem, but I am unsure if this is the correct use or how to do this.
For each project in a VS solution it's possible to stipulate per-project folders that get searched in addition to the folders that you've set globally for Visual Studio.
Which folders take priority? Do the project's folders get searched first? Or do the global folder get searched first? Or is it possible to select one set as having priority over the other?
(this is VS 2005 BTW)
I want to include boost directory. What must be in the Additional Include Directories input?
I tried
C:C++boost_1_55_0libsaccumulatorsexample;$(BOOST_ROOT);%(AdditionalIncludeDirectories)
But I am still getting error "Cannot open include file: 'boost/libs/accumulators/lambda/lambda.hpp': No such file or directory" when I include
Code:
#include <boost/libs/accumulators/lambda/lambda.hpp>
The file is placed out side of boost directory of sure.
Remove the break statements from each of the cases. What is the effect on the execution of the program?
Add an additional switch statement that allows for a Passing option for a grade of D or better. Use the sample run given below to model your output.
Sample Run: What grade did you earn in Programming I ? A YOU PASSED! an A - excellent work!
Rewrite the program LastFirst_lab44.cpp using if and else if statements rather than a switch statement. Did you use a trailing else in your new version? If so, what did it correspond to in the original program with the switch statement?
// This program illustrates the use of the Switch statement.
// The break statement causes all subsequent expressions to be executed as well, also known as "falling through".
// The trailing else statement acts just like the default section if none of the options from before work it gets "defaulted" to it.
#include <iostream>
using namespace std;
int main() {
char grade;
cout << "What grade did you earn in Programming I ?" << endl;
[code]....
how do you add an additional switch statement? i tried multiple times and i'm not sure if i don't understand braces enough but it didnt seem doable. also, I'm not sure what the teacher wants me to submit.
I can do the folowing:
float var1 ;
var1 = 9.12345 ;
printf("%.2f",var1) ;
the output will be 9.12. What if I wanted to save that as another separate float with displaying it on screen?
#include <iostream>
#include <string.h>
#include <sstream>
[Code]....
Why would it be cumbersome to maintain an additional pointer to the first node in a doubly linked list?
View 1 Replies View RelatedThis is what my code looks like
class Transaction{
private:
char type;
double amount;
double balance;
string description;
[Code] .....
This part is what I am having trouble with as this section is not printing anything.
for (int i = 0; i < transactions.size(); i++){
cout << transactions[i].gettype() << " ";
cout << transactions[i].getamount() << " ";
cout << transactions[i].getbalance() << " ";
cout << transactions[i].getdescription() << " ";
}
}
Other than the theoretical difference between cout and cerr where the former puts values to the monitor and the latter puts values related to errors to the monitor, is there any real difference here? Why not use cout when you want to send anything to monitor? Why use cerr at all?
View 7 Replies View RelatedAm having a problem with the following program not displaying the cout after the while loop, it doesn't ask if I want to enter another employee but just prompts for the employee payrate again.
#include <iostream>
using namespace std;
int main()
// Parameters: None
// Returns: Zero
// Calls: None
[Code] ....
Iam working with arrays and i cant get to the write solution to cout the characters.
the Question is : Write a program that inputs a character string from the user as an input (using cin.get())and store it in myStr[ ] array.Assume that the length of the input string is less than 100 characters and the string may contain lower case, upper case, and/or symbols.The program should then print the number of lower case, upper case, digits, and symbols along with the characters themselves.
my code :
#include <iostream>
#include <string>
#include<iomanip>
using namespace std;
int main() {
int ctr1=0, ctr2=0, i=0, ctr3=0;
[Code] ...
What i have now, how can i cout the uppercase characters and the lower case characters and the symbol characters !
Finally got to functions. Made a simple one that adds two numbers:
Code: int add(int a, int b){
cout<<"a+b=";
return a+b;
}
It refuses to give an output unless I use cout.
If I just call the function like so: "add(12, 24);", shouldn't it print out a+b=36? It only prints out "a+b=", unless I use "cout<<" ahead of the call.
My simple question is why does it need cout ahead of the call? Shouldn't "return" do its job and print out the number?
i ran the following code in the latest version of code::blocks and it tells me that the objects cout and cin are not declared in this scope. what is the problem?
I used to use Turbo C++ 3.0 and i had no problem whatsoever with that compiler. But now i am trying to move to code::blocks but it is proving very very hard as all the standards have been changed.
I am a school student and thus, we had been told to practice on Turbo C++ 3.0 and now i am unable to unlearn it. Also, if i use printf in place of cout there is no error but i want to use cout as it is what i am comfortable working with.
#include<fstream>
#include<conio.h>
int main() {
using namespace std;
char name[20];
[Code] ....
Is there some document to which i can refer so as to get the latest C++ standards which is C++0x i believe?
I'm trying to build a new project and i installed some new libraries in it but when i try to compile any code it doesn't give me any value just press any key to continue, i didn't make any files but one and even if i tried to do this simple task it doesn't cout any result:
#include<iostream>
using namespace std;
int main() {
cout <<("ha");
system("pause");
return 0;
}