Can you use data type double or float for an array? ie
double n[];
or
float a;
float m[a];
My code wont accept me changing the data type..will on accept int data type. I get the following error when I try to change the array to double or float..
3310E:C++vector.cpp[Error] invalid types 'double [1000][double]' for array subscript
I need to create a main function with a one dimension dynamic array with float data type. The total number of array elements must be controlled by a user input from the keyboard. Test data is three different lengths 3,6,9 of the array. The lengths have to be set up at run time from users input. I understand how to create dynamic array but not where the user inputs the length of the array. How would I implement this?
View 6 Replies View RelatedI was working on float and double data types and to see the results i wrote this program:
#include <iostream>
#include <iomanip>
#include <fstream>
using namespace std;
int main() {
ofstream outputF("output.txt");
double a = 1;
double outcome;
[Code] ....
Well I understand the part it cannot store infinite numbers. but if you take a look at the output for example (since it is too long i just added some of the outputs)
//---------------------
for the value of : 001
1
//---------------------
for the value of : 002
0.5
//---------------------
for the value of : 003
0.3333333333333333148
[Code] ....
if you look carefully at the value "5" and "10" results. it is awkwardly abnormal. which is something i couldnt understand. also it is the same with value "20", "25", "40", "50" and so on.
I would like to convert a float or double variable into unsigned char variable and back.
float number_float = 23.453f;
unsigned char* number_char = (unsigned char*)malloc(sizeof(float));
number_char = reinterpret_cast<unsigned char*> (&number_float);
float* number_float_0 = reinterpret_cast<float*>(&number_char);
I am not getting the same value back.. why?
So I have a double array, where I'm inputting float numbers to certain points in an array. Sometimes, the numbers that are printed out are completely different from what I put in.Here is the part of the code:
Code: .
while( token != NULL ) {
num = atof(token);
test[j][i] = num;
printf( "
%s, i is %d, j is %d
", token,i,j );
printf( "number is %f
value test of i,j is %f
[code]....
Why the float num prints out fine, but when put into an array becomes garbage?I'm taking string values from a csv file and turning them into floats, but no problems seem to crop up there.I reset i when appropriate and increment j when needed, so I don't think my problems are from incorrect array values (though they might be)
okay for instance
int x = 4;
double y = 2;
printf("%d", (x / y + 5));
what data type is
(x / y + 5)
??
I tried writing a program for finding the area of a circle, and I'm wondering why it only works when i define it as 'float', but not as a double?
Code:
#include <stdio.h>
#define pi 3.14159
double
main(void)
[Code] .....
I have a templated class that can either use float or double as type.
My question is now: What do I do with constant numbers in the code?
Let's assume I have a multiplication by 0.5:
In the case of float type, I want: 0.5f
In the case of double type, I want: 0.5
One answer would be to check for every constant the type and doing an if/else, but this is very annoying with lots of constants.
The code using these constants infer their type automatically by the assignment, that's why I have to take care of the constants.
I want a code that can convert floating/double value into string/char array(char arr[]) and also it can be run on Boreland C++ 5.02
Here I've a code but it doesn't show all the numbers. Instead, it's showing in exponential form which I don't want!!
int main() {
char* str = new char[30];
float flt = 2.4567F;
sprintf(str, "%.4g", flt );
cout<<str<<endl; //Exponential form even after 6 digits without decimal
return 0;
}
I m working calculating stuff in files, input and output data, etc..., the question is the following: I output double numbers with:
myFIle << fixed << setprecision(10) << double;
The problem i got is that when a numer is like 193123.2 it prints like 193123.200000..., so finally, ¿how can i print it with any additional 0 that i need?.
I want to get the direct formula for calculating the range of double and float datatypes in c,if any.
View 1 Replies View Relatedok here is the question: Write a function that will initialize a double data array element to 0.0 ?
View 4 Replies View RelatedI have a structure
struct Wine
{
string wineName;
int vintage;
int rating;
double price;
};
how can i store the file data below in an array with the structure type???
Dow Vintage Port ;2011;99;82
Mollydooker Shiraz Carnival of Love ;2012;95;75
Prats & Symington Douro Chryseia ;2011;97;55
Quinta do Vale Meão Douro ;2011;97;76
Leeuwin Chardonnay River Art Series ;2011;96;89
this is what I got so far
Code:
#include <stdio.h>
#include <stdlib.h>
int main() {
[Code].....
he problem is that when I print out the three sums at the end of the program I dont get any decimal points but just zeros like something.00 instead of something.50 etc
I have an assignment where I need to read in a phone number into any array and I can't use the string data type. Assuming I need to use the getline function, how do I do this? I'm guessing it's with the cstring or .c_str() functions? I don't know.
View 4 Replies View Relatedhow can we use modulus operator with double type variables
View 2 Replies View Relatedwhile (getline(inStream, line))
{
while (inStream >> Student.getId() >> Student.FNAME >> Student.MINIT >> Student.LNAME >> Student.GENDER >> Student.UNITS >> Student.getGpa())
{
while (Student.getId() != id)
{
outStream << line << endl;
}
}
}
This is what I have right now. It shouldn't be a problem, but for some reason I am getting an error trying to >> Student.getGpa()
Error1error C2679: binary '>>' : no operator found which takes a right-hand operand of type 'double' (or there is no acceptable conversion)c:location1301Project 5
I will post more code if needed, but... I just don't know. I have a TON of code so I would rather not if I don't have to.
The following code compiles and runs fine till it reaches line 16 and gets a sigsev violation which I'm not sure about as to why. I have no problem passing the object of type node** into the constructor of base and storing it into the double pointer node** copy;; but when I call the function void pass(node** temp) it crashes.
#include <iostream>
class base;
class node {
private:
node** data;
public:
[Code] .....
I need to write a function that will merge the content of two sorted arrays of type double values. The function should not assume that both its input parameter arrays are the same length.
Here is my program so far - I know there is alot of errors and mistakes:
Code:
#include<stdio.h>
void merge(int firstArray[],int secondArray[],int size) {
int mergedArray[size],i=0,j=0,k=0;
while(i<size||j<size) {
if(i==size) {
[Code]...
I'm trying to create a new data type Data declared as int. What comes up to my mind is to create a structure like
Code:
typedef struct Data {
int number;
} Data;
but when I need to use the data I need to go through the structure. Is this a good way to declare a new data type?
I have to convert string to double. i'm using "atof" function to achieve same.
I have string as "0.0409434228722337" and i'm converting with "atof" But i'm getting double value as "0.040943422872233702". Why it adds 02 additionally at the end?
More example :
"0.0409434228722337" converts to "0.040943422872233702"
"0.067187778121134" converts to "0.067187778121133995"
Is there any other possibility to convert string to double without changing data ?
I'm having some problems with changing an array of numbers of type char to type int. Every time i try to sum 2 array indexed values it returns some letter or symbol. Also, if i change the type of the array in the functions the compiler gives me an error message. I would also like to add that the problem requires that the first two arrays be char so each individual number gets assigned to a different value.
My current code is:
Code:
#include <iostream>
void input(char a[], char b[], int& size_a, int& size_b);
void convert(char a[], int size);
void reverse(char a[], int size);
void add(char a[], char b[], int c[], int size);
int main()
[Code]....
how to convert an element of int type of an array to char type?
View 2 Replies View RelatedI am parsing a binary data file by casting a buffer to a struct. It seems to work really well apart from this one double which is always being accessed two bytes off, despite being in the correct place.
Code:
typedef struct InvoiceRow {
uint INVOICE_NUMBER;
...
double GROSS;
...
char VAT_NUMBER[31];
} InvoiceRow;
If I attempt to print GROSS using printf("%f", row->GROSS) I get 0.0000. However, if I change the type of GROSS to char[8] and then use the following code, I am presented with the correct number...
Code:
typedef struct example {
double d;
}
example;
example *blah = (example*)row->GROSS;
printf("%f", blah->d);
What am I doing wrong here.
Code:
#include <stdio.h>
#define N 25
int main () {
int s,min,sec,total,mins;
float speed,splits[N];
[Code] ....
how to covert float value to array get any sessegation to convert the value
View 1 Replies View Related
