this is what I got so far
Code:
#include <stdio.h>
#include <stdlib.h>
int main() {
[Code].....
he problem is that when I print out the three sums at the end of the program I dont get any decimal points but just zeros like something.00 instead of something.50 etc
Can you use data type double or float for an array? ie
double n[];
or
float a;
float m[a];
My code wont accept me changing the data type..will on accept int data type. I get the following error when I try to change the array to double or float..
3310E:C++vector.cpp[Error] invalid types 'double [1000][double]' for array subscript
how can we use modulus operator with double type variables
View 2 Replies View Relatedokay for instance
int x = 4;
double y = 2;
printf("%d", (x / y + 5));
what data type is
(x / y + 5)
??
My code:
#include<cstdio>
#include<iostream>
using namespace std;
main() {
long double j;
scanf("%Lf", &j);
cout<< j;
return 0;
}
If I give any number as input, the output is always 0. why? where's the problem ? p
while (getline(inStream, line))
{
while (inStream >> Student.getId() >> Student.FNAME >> Student.MINIT >> Student.LNAME >> Student.GENDER >> Student.UNITS >> Student.getGpa())
{
while (Student.getId() != id)
{
outStream << line << endl;
}
}
}
This is what I have right now. It shouldn't be a problem, but for some reason I am getting an error trying to >> Student.getGpa()
Error1error C2679: binary '>>' : no operator found which takes a right-hand operand of type 'double' (or there is no acceptable conversion)c:location1301Project 5
I will post more code if needed, but... I just don't know. I have a TON of code so I would rather not if I don't have to.
The following code compiles and runs fine till it reaches line 16 and gets a sigsev violation which I'm not sure about as to why. I have no problem passing the object of type node** into the constructor of base and storing it into the double pointer node** copy;; but when I call the function void pass(node** temp) it crashes.
#include <iostream>
class base;
class node {
private:
node** data;
public:
[Code] .....
I need to write a function that will merge the content of two sorted arrays of type double values. The function should not assume that both its input parameter arrays are the same length.
Here is my program so far - I know there is alot of errors and mistakes:
Code:
#include<stdio.h>
void merge(int firstArray[],int secondArray[],int size) {
int mergedArray[size],i=0,j=0,k=0;
while(i<size||j<size) {
if(i==size) {
[Code]...
My goal is to read a one line file of a comma separated numbers into a floating point array. The numbers have up to 25 positions after the decimal. I'm having two issues with the following code.
1) atof() seems to be returning zeros every time. Why?
2) The last number includes the new line character. How do I get rid of it?
Note that I adapted the scanf command from here: The power of scanf() - [URL], and don't completely understand it.
Code:
#include <stdio.h>
#include <math.h>
//The following will be calculated in the real program.
#define DIM 1
#define N 8
int main()
[Code]......
In the "real" program, N is calculated and known before reading in the file and the file will always have 2 times N numbers.
I would like to convert a float or double variable into unsigned char variable and back.
float number_float = 23.453f;
unsigned char* number_char = (unsigned char*)malloc(sizeof(float));
number_char = reinterpret_cast<unsigned char*> (&number_float);
float* number_float_0 = reinterpret_cast<float*>(&number_char);
I am not getting the same value back.. why?
// this program gives random number output
#include <iostream>
#include <cstdlib>// contains function protype for rand
#include <iomanip>// for setw
using namespace std;
[code]....
what is the effect on output of program of different numbers input to the int data type named seed*/
I'm having some problems with changing an array of numbers of type char to type int. Every time i try to sum 2 array indexed values it returns some letter or symbol. Also, if i change the type of the array in the functions the compiler gives me an error message. I would also like to add that the problem requires that the first two arrays be char so each individual number gets assigned to a different value.
My current code is:
Code:
#include <iostream>
void input(char a[], char b[], int& size_a, int& size_b);
void convert(char a[], int size);
void reverse(char a[], int size);
void add(char a[], char b[], int c[], int size);
int main()
[Code]....
how to convert an element of int type of an array to char type?
View 2 Replies View RelatedI have a function like this:
template<typename T>
void f() {
//...
[Code]....
list contains, in order: A, B and C in any order, D, E
I am thinking it is possible with some clever template and polymorphism combos, but maybe not. As a last resort I know how to make it work by storing static type information in each class, but I'd like to avoid that if possible.
I need to use the type RectangleF as a built in type in c++ ie I need to declare a variable rect as RectangleF rect;
what do I have to include to be able to do this.
Let me put it into the code snippet:
/**
This class build the singleton design pattern.
Here you have full control over construction and deconstruction of the object.
*/
template<class T>
class Singleton
[Code]....
I am getting error at the assertion points when i call to the class as follows:
osgOpenCL::Context *cxt = osgOpenCL::Singleton<osgOpenCL::Context>::getPtr();
I tried commenting assertion statements and then the debugger just exits at the point where getPtr() is called.
How to change an enum type variable to a string type variable?
View 2 Replies View Related#include<iostream>
using namespace std;
int main() {
double x,i;
cout<<"Enter the value of the number
[Code] ....
why I am not getting exact square root if I take x as double,but if I am taking it as int I got the correct result.
I am very new to programming and would like to know where to even start when evaluating a double integral. I wanted to evaluate this double integral: 6x^3 + y^2 +7x from 0 to 1 (for both).
View 1 Replies View RelatedGiven this code
Code:
double x=1.00,y=2,z=4;
if (y/z||++x)
x+=y/z;
printf("%f
",x); So (y/z||++x)
is true if at least one expression is true, that is either (y/z)!=0 or (++x)!=0 or both. I wonder how the comparison is done? Is (y/z) be truncated to integer or 0 be promoted to double?
I'm having a small issue here with my linked list.I built a linked list with strings and it worked perfectly.Now since i'm using strtok() to separate the string.for now here's what i've got:
Code:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
typedef struct dict_word *word;
typedef struct node *Node;
typedef struct double_linked_list *DLL;
}
[code]....
The main is not working properly, I get strange missing parenthesis notices and array errors which I am not understanding. How to identify the errors. Functions are included.
Code:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int menu ();
double change_value (double * value);
[Code] ......
I want to convert string to double. I refered this strtod() - C Library Function Example
Code:
#include <stdio.h>
#include <string.h>
int main() {
const char string[] = "$$GPRMC,013732.000,A,3150.7238,N,11711.7278,E,0.00,0.00,220413,,,A*68";
char term;
const char delims[] = ",";
}
[code]....
How to add double quotes into string.I want to prepare command into following way with string.
awk 'BEGIN {printf "x
%10s %10s
", "Vol", "Current"}{if($1+0==$1){printf "%10.5f %10.5f
", $2, $3}} END {printf "y
"}'
I just wanted to know a way to cut off any remaining zeroes from a double data type. I' trying to calculate cost and output it but it keeps adding a bunch of zeroes on the end. I know there must be a way to
View 1 Replies View RelatedI want to compare two double values
double x = 3072.00000000;
double y = 3072.0000000;
when checking with if its not working
if(x==y) it not working
