I just wanted to know a way to cut off any remaining zeroes from a double data type. I' trying to calculate cost and output it but it keeps adding a bunch of zeroes on the end. I know there must be a way to
View 1 RepliesMy code:
#include<cstdio>
#include<iostream>
using namespace std;
main() {
long double j;
scanf("%Lf", &j);
cout<< j;
return 0;
}
If I give any number as input, the output is always 0. why? where's the problem ? p
I have designed a class called matrixType that has some overloaded operators (+, -, *, and <<); the arithmetic operator functions of which are overloaded as member functions of the class. As an alert mechanism, I want a message displayed when two matrices of dissimilar sizes are added/subtracted OR when two incompatible matrices are being multiplied. Displaying this error message is not the problem. However, I want a scheme where on detecting two matrices’ incompatibility, the operator function returns the error message (a string datatype) instead of what would be an erroneous result (the expected matrixType object).
In other words, what I may be essentially asking is: Is it possible for a function, say,
matrixType matrixType::operator+(const matrixType& otherMatrix) const
{
.
.
.
}
to return a dataType (like a string) other than the expected matrixType?
The following piece of code is supposed to output the binary representation of a given integer and it does exactly that. However, if the given integer is 2, then output is 01. Is there a way to make the program output 0001. I am working on a C program that outputs 4-bit gray code.
#include <stdio.h>
#include <math.h>
int main(void) {
long int n=2;
while (n) {
if (n & 1)
printf("1");
[Code] ......
I'm trying to create a two dimensional array that displays zeroes in a 10 by 10 format. But I don't really know how.I've been playing around and this is what I have so far:
Code:
#include<stdio.h>
int main(void) {
int my_array[10][10]={0};
int i,j;
[code]....
I am looking to eliminate the leading zeroes of the input. The format has to stay the same and output must be as hinted in formatting.
#include <iostream>
#include <iomanip>
#include <fstream>
#include <string>
using namespace std;
void process(ifstream& infile, char&ch, int&dec, int&c, int&w);
int main(){
[code]....
I have made a new data type which named LongDouble
it takes 16 byte to save the number
the first bit for the sign
the next 15 bit for the exponent
the other 112 bit for the mantissa
I have to apply four operation on these numbers , but i have a problem in addition , when the sign for any of the numbers is negative ,how i can perform the operation , also if there is a Mantissa how i can also perform the operation?
if i try to save mantissa in a variable there would a loss of precision ... Here's my code
LongDouble LongDouble::operator+(const LongDouble& olong) {
LongDouble temp;
if (this->sign == 0 && olong.sign == 0) {
temp.exponent = this->exponent + olong.exponent;
[Code] .....
the compiler doesnt accept void functions used with threads (for the first time and all of sudden!?)
#include <cstdlib>
#include <thread>
#include <windows.h>
[Code]....
this is a sigment of my code. Compiler says that the error occurs in line 47 (marked by ***). Leaving out the braces makes it even worse.
coming from Java, my experience with the Classes in C++ is quite limited.
Thats why I am having trouble converting the following (simple!) Java-Program.
Most examples with linked lists I found on the web describe how to implement the LinkedList class itself. But my problem is different: I want to use such a Class (I have a LinkedList class available on my system which is presumably OK).
Code: package main;
import java.util.ArrayList;
public class Main {
public static void main(String[] args) {
BoxList<String> sl = new BoxList<String>(
new ArrayList<ABox<String>>());
sl.getList().add(
new BoxPair2<String>(new BoxPair2<String>(
[code].....
My Fraction.h class looks like :
class Fraction {
int num;
unsigned int den;
public:
Fraction(int = 1,int =1);
//Constants of Datatype
[Code] ....
The implementation Fraction.cpp is as follows :
#include "Fraction.h"
Fraction::Fraction(int n, int d):num(n),den(d){
cout << This is double param constructor <<endl;
}
And the application main.cpp is
int main(){
Fraction f1(3,9);
f1 = Fraction::sc_fUnity; // how to implement this ?
}
How can I write the Fraction.cpp for the constant static member ?
How you would overload an operator for Common Data-types like "char" and "int".
I often use bool arrays to create a multilevel-trigger-systems, when iterating over multiple containers or waiting for two events to occur at the same time.
For example:
I would define..
bool trigger[2] = {0, 0};
And when doing work via a loop, I use it like so:
while(trigger[0] != 1 && trigger[1] != 1)
You can probably see where I'm going with this. I want to be able to use my bool array with the "!" operator.
So if "trigger == 0" (as a whole), it returns false.
How can I achieve this?
Can you create custom operators? Say if I wanted to create "or-gates" or "xor-gates" etc.
How to use static in a class, function and variable.
View 1 Replies View RelatedI am need to compare 2 items from 2 separate drop down lists. These values are of int type. Say for example 2 drop down lists showing years. Now i need to find out these 2 years selected is greater or nearer to the current year.
I tried converting the values i receive from the drop down lists to int variables. But i am getting error then. I gave it like below.
int tmp = Convert.ToInt32(ddl_1.SelectedItem.Text);
this gives an error like this - Input string was not in correct format.
I need to know how to put an item from a drop down list to a variable of int data type.
I have a class that is a template, I have to declare it in my main but i want the user to choose what type of data they will use in the class, I cant just declare myclass my, i have to use myclass<int> my, how can I change so user can select the proper datatype to use in the class.
View 5 Replies View RelatedI have the codes for such a problem where, to create a program that counts how many times the second string appears on the first string. Yes it counts if you put 1 letter only, but if you put 2, it is an error. As an example. If the first string is Harry Partear, and the second string is ar, it must count as 3. Here's the code:
Code:
#include <iostream>
#include <conio.h>
using namespace std;
int main ()
[Code] ....
#include<iostream>
using namespace std;
int main() {
double x,i;
cout<<"Enter the value of the number
[Code] ....
why I am not getting exact square root if I take x as double,but if I am taking it as int I got the correct result.
I am very new to programming and would like to know where to even start when evaluating a double integral. I wanted to evaluate this double integral: 6x^3 + y^2 +7x from 0 to 1 (for both).
View 1 Replies View RelatedGiven this code
Code:
double x=1.00,y=2,z=4;
if (y/z||++x)
x+=y/z;
printf("%f
",x); So (y/z||++x)
is true if at least one expression is true, that is either (y/z)!=0 or (++x)!=0 or both. I wonder how the comparison is done? Is (y/z) be truncated to integer or 0 be promoted to double?
I'm having a small issue here with my linked list.I built a linked list with strings and it worked perfectly.Now since i'm using strtok() to separate the string.for now here's what i've got:
Code:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
typedef struct dict_word *word;
typedef struct node *Node;
typedef struct double_linked_list *DLL;
}
[code]....
The main is not working properly, I get strange missing parenthesis notices and array errors which I am not understanding. How to identify the errors. Functions are included.
Code:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int menu ();
double change_value (double * value);
[Code] ......
this is what I got so far
Code:
#include <stdio.h>
#include <stdlib.h>
int main() {
[Code].....
he problem is that when I print out the three sums at the end of the program I dont get any decimal points but just zeros like something.00 instead of something.50 etc
I want to convert string to double. I refered this strtod() - C Library Function Example
Code:
#include <stdio.h>
#include <string.h>
int main() {
const char string[] = "$$GPRMC,013732.000,A,3150.7238,N,11711.7278,E,0.00,0.00,220413,,,A*68";
char term;
const char delims[] = ",";
}
[code]....
How to add double quotes into string.I want to prepare command into following way with string.
awk 'BEGIN {printf "x
%10s %10s
", "Vol", "Current"}{if($1+0==$1){printf "%10.5f %10.5f
", $2, $3}} END {printf "y
"}'
I want to compare two double values
double x = 3072.00000000;
double y = 3072.0000000;
when checking with if its not working
if(x==y) it not working
I am programming about some numerical problems. I know that vector supplies vector operations. But vector always allocate more memory (used when the size changes). My matrix or array never change size, and the vector operation is just +,-,dot,cross,distance
My question is that should I use vector, or simple double array with new & delete is enough for me?
I'm trying to find a way to accuratley convert a double in the form of a bank account number stored in a file into a string representing the number returned by a file.
View 1 Replies View Related